All questions of TCS for Interview Preparation Exam

12 programmers take 12 minutes to write 12 lines of code
1 programmer take 12 minutes to write 1 line of code.
(not 1 minute per line of code)
As 1 programmer writes 1 line in 12 minute
Hence, 72 programmers will write 72 lines of code in 12 minutes.

The person next to rightmost person is the leftmost person so :

Solution:
To find the total number of squares on an 8*8 chessboard, we need to consider all possible sizes of squares that can be formed on the board.

1. Squares of size 1*1:
There are 64 such squares on the board.

2. Squares of size 2*2:
There are (7*7) = 49 such squares on the board.

3. Squares of size 3*3:
There are (6*6) = 36 such squares on the board.

4. Squares of size 4*4:
There are (5*5) = 25 such squares on the board.

5. Squares of size 5*5:
There are (4*4) = 16 such squares on the board.

6. Squares of size 6*6:
There are (3*3) = 9 such squares on the board.

7. Squares of size 7*7:
There are (2*2) = 4 such squares on the board.

8. Squares of size 8*8:
There is only 1 such square on the board.

Therefore, the total number of squares on an 8*8 chessboard is:

64 + 49 + 36 + 25 + 16 + 9 + 4 + 1 = 204.

Hence, the correct answer is 204.

Given:
- a and b are mixed in a 3:5 ratio.
- b and c are mixed in an 8:5 ratio.
- The final mixture is 35 liters.

To find: The amount of b in the final mixture.

Let's assume the initial amount of a is 3x and the initial amount of b is 5x. Therefore, the initial amount of c is 0 because it is not mentioned.

The ratio between a and b is 3:5, which can be written as:
a/b = 3/5

Similarly, the ratio between b and c is 8:5, which can be written as:
b/c = 8/5

Since we know the final mixture is 35 liters, the sum of a, b, and c must be 35 liters.
So, a + b + c = 35

Let's solve these equations to find the values of a, b, and c.

1. Solving the ratio a/b = 3/5:
a/b = 3/5
3x/5x = 3/5
Cross-multiplying, we get:
3x * 5 = 5x * 3
15x = 15x
Hence, a = 3x and b = 5x.

2. Solving the ratio b/c = 8/5:
b/c = 8/5
5x/c = 8/5
Cross-multiplying, we get:
5x * 5 = 8 * c
25x = 8c
Hence, c = (25x)/8.

3. Substituting the values of a, b, and c into the equation a + b + c = 35:
3x + 5x + (25x)/8 = 35
Multiplying through by 8 to eliminate the fraction, we get:
24x + 40x + 25x = 280
89x = 280
Dividing both sides by 89, we get:
x = 280/89

Now, substituting the value of x back into b = 5x:
b = 5 * (280/89)
b ≈ 15.73

Therefore, the amount of b in the final mixture is approximately 15.73 liters.
Hence, the correct answer is option B) 15.73.

To find the distance between the starting and ending points, we need to trace the path taken by the man and calculate the total distance covered.

Path Taken:
1. The man goes north for 37 km.
2. Then, he turns left and goes 2 km.
3. Next, he turns right and goes 17 km.
4. Finally, he turns right again and goes 2 km.

Calculating the Distance:
To calculate the distance between the starting and ending points, we need to consider the components of the movement: north and east.

1. North Movement:
The man goes north for 37 km. As he does not change his east direction, there is no eastward movement. Therefore, the distance covered in the north direction is 37 km.

2. East Movement:
The man turns left and goes 2 km, which means he moves 2 km to the east.
Then, he turns right and goes 17 km, which means he moves 17 km to the west.
Finally, he turns right again and goes 2 km, which means he moves 2 km to the east.
So, the total eastward movement is 2 km - 17 km + 2 km = -13 km.

Distance Calculation:
To calculate the distance between the starting and ending points, we can use the Pythagorean theorem. The distance formula is given by:

Distance = √(North Distance^2 + East Distance^2)

Substituting the values, we get:

Distance = √(37^2 + (-13)^2)
Distance = √(1369 + 169)
Distance = √1538
Distance ≈ 39.22 km

Rounding off to the nearest whole number, the distance between the starting and ending points is approximately 39 km. However, none of the given options match this value.

Therefore, it seems there might be an error in the given options as the calculated distance does not match any of them. Please double-check the options.

Understanding the scenario:
The tortoise and the hare are racing along a circle with a diameter of 100 yards. The tortoise starts first and moves at a constant speed. The hare starts later and moves leisurely until it covers 1/3 of its distance.

Meeting point:
The hare and tortoise meet when the hare has covered only 1/8 of the distance. This means that the hare covers 1/8 of the circle's circumference by the time they meet.

Calculating distances:
The tortoise covers 1/3 of the circle's circumference before they meet, which is 1/3 * 2 * π * 50 = 100π/3 yards. The hare covers 1/8 of the circle's circumference when they meet, which is 1/8 * 2 * π * 50 = 25π yards.

Speed ratio:
To tie the race, the hare needs to cover the remaining distance in the same time it took to cover the initial 1/8. The hare should increase its speed by a factor that is the ratio of the remaining distance to the distance covered initially. This ratio is (100 - 25)π / (100 - 25π) = 75π / (100 - 25π) ≈ 30.33.

Therefore, the hare should increase its speed by a factor of approximately 30.33 to tie the race. The correct answer is option 'A'.

To find the number of 5-digit numbers that can be formed using the digits 1, 2, 3, 4, and 5, which are divisible by 4, we need to follow a systematic approach. This question falls under the Quant category and requires a clear understanding of divisibility rules and counting techniques.


A number is divisible by 4 if the last two digits of the number are divisible by 4. Therefore, we need to focus on the last two digits of the 5-digit numbers we are forming.


To solve this problem, we can use the counting principle or multiplication principle. The multiplication principle states that if there are 'n' ways to perform one task and 'm' ways to perform another task, then there are n x m ways to perform both tasks together.


To form a 5-digit number, we need to consider the following:

1. Thousands place: We have 5 options (1, 2, 3, 4, 5) for the thousands place.
2. Hundreds, tens, and units places: We have 5 options (1, 2, 3, 4, 5) for each of these places since repetition is allowed.


Using the multiplication principle, we can calculate the total number of possibilities:

Number of possibilities = Number of options for thousands place x Number of options for hundreds place x Number of options for tens place x Number of options for units place

Number of possibilities = 5 x 5 x 5 x 5

Number of possibilities = 625


Out of the 625 possibilities, not all of them will be divisible by 4. We need to find the number of 5-digit numbers that have their last two digits divisible by 4.


To determine the possible last two digits, we need to consider the following:

1. The tens place can be filled with any of the digits 1, 2, 3, 4, and 5 (5 options).
2. The units place can be filled with any of the digits 1, 2, 3, 4, and 5 (5 options).


Using the multiplication principle, we can calculate the total number of possibilities for the last two digits:

Number of possibilities for last two digits = Number of options for tens place x Number of options for units place

Number of possibilities for last two digits = 5 x 5

Number of possibilities for last two digits = 25


To find the number of 5-digit numbers that are divisible by 4, we need to multiply the number of possibilities for the last two digits by the number of possibilities for the remaining three digits:

Number of 5-digit numbers divisible by 4 = Number of possibilities for last two digits x Number of possibilities for the remaining three digits

Number of 5-digit numbers divisible by 4 = 25 x 625

Number of 5-digit numbers divisible by 4 = 15625

Given,
- Low temperature at night = (1/2) x Higher temperature in a day + (1/3) x (1/2) x Higher temperature in a day
- Sum of low temperature and highest temperature = 100C

To find: Low temperature

Let's assume the higher temperature in a day as 'x'

Then,

Low temperature at night = (1/2)x + (1/3) x (1/2) x x
= (1/2)x + (1/6)x
= (2/3)x

Sum of low and high temperature = Low temperature + Higher temperature = (2/3)x + x = (5/3)x

Given, sum of low and high temperature = 100C

Therefore, (5/3)x = 100C
=> x = (3/5) x 100C
=> x = 60C

Now, substituting the value of x in the equation for low temperature at night, we get

Low temperature at night = (2/3) x 60C
= 40C

Hence, the correct option is A) 40C.

2,
(2*3)+1= 7
(7*3)+3=24
(24*3)+5=77
(77*3)+7=238

Given Information:
The sum of the digits of a two-digit number is 8.
When 18 is added to the number, the digits are reversed.

Solution:

Let's assume the two-digit number is represented by 10a + b, where a and b are the digits.

- The sum of the digits: a + b = 8
- The number after adding 18 and reversing the digits: 10b + a + 18

According to the given information:
10a + b + 18 = 10b + a

Substitute the values of a and b:
10(8 - b) + b + 18 = 10b + 8

80 - 10b + b + 18 = 10b + 8
98 - 9b = 10b + 8
90 = 19b
b = 5

Substitute the value of b back into the equation:
a = 8 - b
a = 8 - 5
a = 3

Therefore, the two-digit number is 10a + b = 10(3) + 5 = 30 + 5 = 35.

Hence, the number is 35.

Solution :

I think.. Question is wrong.. Correct answer is option b. 12kms.... You can do it by pythagoras theorem... X²=(3+8)² + 5² = 121 + 25 =146 X= 12.08 X= 12kms (approx)

If he goes 10 mph then fined 1 time and if he goes 20 mph then fined 2 times so  the speed limit is 15 mph as that has already been given the real speed of the second man is 35 mph so  35-20=15 mph.Think logically and follow me.

Solution:

To count the number of 6s in the numbers from 1 to 100 in T. Nagar, we need to consider each digit of the numbers separately.

1. Counting 6s in units place:

- There are 10 numbers from 1 to 10, out of which only one number (i.e., 6) has 6 in the units place.
- There are 10 numbers from 11 to 20, out of which only one number (i.e., 16) has 6 in the units place.
- Similarly, there will be one number with 6 in the units place in each set of 10 numbers (such as 26, 36, 46, 56, 66, 76, 86, and 96) until we reach 100.

Therefore, there are a total of 9 numbers with 6 in the units place.

2. Counting 6s in tens place:

- There are 10 numbers from 1 to 10, out of which none of the numbers have 6 in the tens place.
- There are 10 numbers from 11 to 20, out of which one number (i.e., 60) has 6 in the tens place.
- Similarly, there will be one number with 6 in the tens place in each set of 10 numbers (such as 16, 26, 36, 46, 56, 66, 76, 86, and 96) until we reach 100.

Therefore, there are a total of 9 numbers with 6 in the tens place.

3. Counting 6s in hundreds place:

- There is only one number (i.e., 60) with 6 in the hundreds place.

Therefore, there is only one number with 6 in the hundreds place.

Overall, we have counted 9 numbers with 6 in the units place, 9 numbers with 6 in the tens place, and 1 number with 6 in the hundreds place. Hence, the total number of 6s in the numbers from 1 to 100 in T. Nagar is:

9 + 9 + 1 = 19

Therefore, the correct answer is option (b) 19.

I am trying to give a solution based on my interpretation.

Let the number be A,
According to question
(1/3)*A=[(1/6)*A]+3
A/3=(A/6)+3
A/3=(A+18)/6 {by taking LCM}
A=3(A+18)/6
A=(A+18)/2
2A=A+18
2A-A=18
A=18
Hence,the value of the number according to question is 18 which is option C) in question
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