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All questions of Full Length Mock Test Series CBT - 1 for RRB NTPC/ASM/CA/TA Exam
In each of the questions below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the question. Read both the statements and Give answer
(A) If the data in statement I alone are sufficient to answer the question, while the data in statement II alone are not sufficient to answer the question
(B) If the data in statement II alone are sufficient to answer the question, while the data in statement I alone are not sufficient to answer the question
(C) If the data either in statement I alone or in statement II alone are sufficient to answer the question
(D) If the data given in both statements I and II together are not sufficient to answer the question and
(E) If the data in both statements I and II together are necessary to answer the question.Question: In which year was Rahul born ? - Rahul at present is 25 years younger to his mother.
- Rahul's brother, who was born in 1964, is 35 years younger to his mother.
- a)I alone is sufficient while II alone is not sufficient
- b)II alone is sufficient while I alone is not sufficient
- c) Either I or II is sufficient
- d) Neither I nor II is sufficient
- e)Both I and II are sufficient
Correct answer is option 'E'. Can you explain this answer?
In each of the questions below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the question. Read both the statements and Give answer
(A) If the data in statement I alone are sufficient to answer the question, while the data in statement II alone are not sufficient to answer the question
(B) If the data in statement II alone are sufficient to answer the question, while the data in statement I alone are not sufficient to answer the question
(C) If the data either in statement I alone or in statement II alone are sufficient to answer the question
(D) If the data given in both statements I and II together are not sufficient to answer the question and
(E) If the data in both statements I and II together are necessary to answer the question.
(A) If the data in statement I alone are sufficient to answer the question, while the data in statement II alone are not sufficient to answer the question
(B) If the data in statement II alone are sufficient to answer the question, while the data in statement I alone are not sufficient to answer the question
(C) If the data either in statement I alone or in statement II alone are sufficient to answer the question
(D) If the data given in both statements I and II together are not sufficient to answer the question and
(E) If the data in both statements I and II together are necessary to answer the question.
Question: In which year was Rahul born ?
- Rahul at present is 25 years younger to his mother.
- Rahul's brother, who was born in 1964, is 35 years younger to his mother.
a)
I alone is sufficient while II alone is not sufficient
b)
II alone is sufficient while I alone is not sufficient
c)
Either I or II is sufficient
d)
Neither I nor II is sufficient
e)
Both I and II are sufficient
|
Learners World answered |
From both I and II, we find that Rahul is (35 - 25) = 10 years older than his brother, who was born in 1964. So, Rahul was born in 1954.
Which of the following is rational?
P = sum of √288 and √578
Q = √1152
R = Product of √117 and √52
- a)P + Q
- b)P * Q
- c)Q * R
- d)Q + R
Correct answer is option 'B'. Can you explain this answer??
Which of the following is rational?
P = sum of √288 and √578
Q = √1152
R = Product of √117 and √52
a)
P + Q
b)
P * Q
c)
Q * R
d)
Q + R
|
Meghana Narayan answered |
Understanding the Problem
To determine which of the given expressions is rational, we need to analyze each option in detail.
Definitions and Key Points
- A rational number is defined as a number that can be expressed as a fraction a/b, where a and b are integers, and b is not zero.
- The square root of a rational number is rational if it is a perfect square; otherwise, it is irrational.
Calculating Each Expression
1. P = sum of √288 and √578
- √288 = √(144 * 2) = 12√2 (irrational)
- √578 = √(289 * 2) = 17√2 (irrational)
- Therefore, P = 12√2 + 17√2 = 29√2 (irrational)
2. Q = √1152
- √1152 = √(576 * 2) = 24√2 (irrational)
3. R = Product of √117 and √52
- √117 (irrational) and √52 = √(4 * 13) = 2√13 (irrational)
- Therefore, R = √117 * 2√13 = 2√(117 * 13) = 2√1521 = 39 (rational)
Evaluating the Options
- a) P + Q: (irrational + irrational) = irrational
- b) P * Q: (irrational * irrational) = rational
- c) Q * R: (irrational * rational) = irrational
- d) Q + R: (irrational + rational) = irrational
Conclusion
The only expression that results in a rational number is b) P * Q, as it involves the product of two irrational terms that combine to yield a rational outcome. Therefore, the correct answer is option 'B'.
To determine which of the given expressions is rational, we need to analyze each option in detail.
Definitions and Key Points
- A rational number is defined as a number that can be expressed as a fraction a/b, where a and b are integers, and b is not zero.
- The square root of a rational number is rational if it is a perfect square; otherwise, it is irrational.
Calculating Each Expression
1. P = sum of √288 and √578
- √288 = √(144 * 2) = 12√2 (irrational)
- √578 = √(289 * 2) = 17√2 (irrational)
- Therefore, P = 12√2 + 17√2 = 29√2 (irrational)
2. Q = √1152
- √1152 = √(576 * 2) = 24√2 (irrational)
3. R = Product of √117 and √52
- √117 (irrational) and √52 = √(4 * 13) = 2√13 (irrational)
- Therefore, R = √117 * 2√13 = 2√(117 * 13) = 2√1521 = 39 (rational)
Evaluating the Options
- a) P + Q: (irrational + irrational) = irrational
- b) P * Q: (irrational * irrational) = rational
- c) Q * R: (irrational * rational) = irrational
- d) Q + R: (irrational + rational) = irrational
Conclusion
The only expression that results in a rational number is b) P * Q, as it involves the product of two irrational terms that combine to yield a rational outcome. Therefore, the correct answer is option 'B'.
152825764233869149458
In the given series, what is the sum of the numbers that have an even number to its left and right?
- a)30
- b)26
- c)19
- d)24
Correct answer is option 'B'. Can you explain this answer??
152825764233869149458
In the given series, what is the sum of the numbers that have an even number to its left and right?
a)
30
b)
26
c)
19
d)
24
|
Anjana Menon answered |
Understanding the Series
The given series is:
152825764233869149458
To solve the problem, we need to identify the numbers that have an even number both to their left and right.
Identifying Even and Odd Numbers
In the series, the digits can be categorized as follows:
- Even digits: 0, 2, 4, 6, 8
- Odd digits: 1, 3, 5, 7, 9
Finding Eligible Numbers
We will analyze each digit in the series to see if it has an even digit on both sides. Let's break it down:
- 1: Left is none, right is 5 (not even)
- 5: Left is 1 (not even), right is 2 (even)
- 2: Left is 5 (not even), right is 8 (even)
- 8: Left is 2 (even), right is 2 (even) → Count this
- 2: Left is 8 (even), right is 5 (not even)
- 5: Left is 2 (even), right is 7 (not even)
- 7: Left is 5 (not even), right is 6 (even)
- 6: Left is 7 (not even), right is 4 (even) → Count this
- 4: Left is 6 (even), right is 2 (even) → Count this
- 2: Left is 4 (even), right is 3 (not even)
- 3: Left is 2 (even), right is 3 (not even)
- 6: Left is 3 (not even), right is 8 (even)
- 8: Left is 6 (even), right is 6 (even) → Count this
- 6: Left is 8 (even), right is 9 (not even)
- 9: Left is 6 (even), right is 1 (not even)
- 1: Left is 9 (not even), right is 4 (even)
- 4: Left is 1 (not even), right is 5 (not even)
- 5: Left is 4 (even), right is none
Summing the Counted Numbers
The eligible numbers are:
- 8
- 6
- 4
- 8
Now, summing these gives:
8 + 6 + 4 + 8 = 26
Thus, the correct answer is option B) 26.
The given series is:
152825764233869149458
To solve the problem, we need to identify the numbers that have an even number both to their left and right.
Identifying Even and Odd Numbers
In the series, the digits can be categorized as follows:
- Even digits: 0, 2, 4, 6, 8
- Odd digits: 1, 3, 5, 7, 9
Finding Eligible Numbers
We will analyze each digit in the series to see if it has an even digit on both sides. Let's break it down:
- 1: Left is none, right is 5 (not even)
- 5: Left is 1 (not even), right is 2 (even)
- 2: Left is 5 (not even), right is 8 (even)
- 8: Left is 2 (even), right is 2 (even) → Count this
- 2: Left is 8 (even), right is 5 (not even)
- 5: Left is 2 (even), right is 7 (not even)
- 7: Left is 5 (not even), right is 6 (even)
- 6: Left is 7 (not even), right is 4 (even) → Count this
- 4: Left is 6 (even), right is 2 (even) → Count this
- 2: Left is 4 (even), right is 3 (not even)
- 3: Left is 2 (even), right is 3 (not even)
- 6: Left is 3 (not even), right is 8 (even)
- 8: Left is 6 (even), right is 6 (even) → Count this
- 6: Left is 8 (even), right is 9 (not even)
- 9: Left is 6 (even), right is 1 (not even)
- 1: Left is 9 (not even), right is 4 (even)
- 4: Left is 1 (not even), right is 5 (not even)
- 5: Left is 4 (even), right is none
Summing the Counted Numbers
The eligible numbers are:
- 8
- 6
- 4
- 8
Now, summing these gives:
8 + 6 + 4 + 8 = 26
Thus, the correct answer is option B) 26.
Find the odd one out:
- a)JGDA
- b)CZWT
- c)EBXU
- d)SPMJ
Correct answer is option 'C'. Can you explain this answer??
Find the odd one out:
a)
JGDA
b)
CZWT
c)
EBXU
d)
SPMJ
|
Daksha Shah answered |
Identifying the Odd One Out
To understand why option 'C' (EBXU) is the odd one out, we can analyze the patterns in the other options.
Letter Position Analysis
- JGD:
- J (10), G (7), D (4)
- The sequence decreases by 3, then by 3 again.
- CZWT:
- C (3), Z (26), W (23), T (20)
- The sequence decreases by 23, then by 3, then by 3 again.
- SPMJ:
- S (19), P (16), M (13), J (10)
- The sequence decreases by 3, then by 3, then by 3 again.
Identifying the Odd One
- EBXU:
- E (5), B (2), X (24), U (21)
- The pattern does not follow a consistent decrease. The first letter decreases by 3, then jumps to a significantly higher value, and then decreases.
Conclusion
- The other three options follow a consistent pattern of decreasing letters with a specific interval, while EBXU does not conform to this pattern, making it the odd one out.
Thus, the correct answer is option 'C' (EBXU).
To understand why option 'C' (EBXU) is the odd one out, we can analyze the patterns in the other options.
Letter Position Analysis
- JGD:
- J (10), G (7), D (4)
- The sequence decreases by 3, then by 3 again.
- CZWT:
- C (3), Z (26), W (23), T (20)
- The sequence decreases by 23, then by 3, then by 3 again.
- SPMJ:
- S (19), P (16), M (13), J (10)
- The sequence decreases by 3, then by 3, then by 3 again.
Identifying the Odd One
- EBXU:
- E (5), B (2), X (24), U (21)
- The pattern does not follow a consistent decrease. The first letter decreases by 3, then jumps to a significantly higher value, and then decreases.
Conclusion
- The other three options follow a consistent pattern of decreasing letters with a specific interval, while EBXU does not conform to this pattern, making it the odd one out.
Thus, the correct answer is option 'C' (EBXU).
How many numbers are there from 250 to 750 (both inclusive) which are neither divisible by 16 nor 21?
- a)464
- b)456
- c)324
- d)448
Correct answer is option 'D'. Can you explain this answer??
How many numbers are there from 250 to 750 (both inclusive) which are neither divisible by 16 nor 21?
a)
464
b)
456
c)
324
d)
448
|
Shalini Iyer answered |
Understanding the Problem
We need to find how many numbers between 250 and 750 (inclusive) are neither divisible by 16 nor 21.
Step 1: Total Numbers in Range
- The range from 250 to 750 has:
- Total numbers = 750 - 250 + 1 = 501
Step 2: Count of Multiples of 16
- The multiples of 16 between 250 and 750:
- First multiple = 256 (16 × 16)
- Last multiple = 736 (16 × 46)
- Count = (46 - 16 + 1) = 31
Step 3: Count of Multiples of 21
- The multiples of 21 between 250 and 750:
- First multiple = 252 (21 × 12)
- Last multiple = 735 (21 × 35)
- Count = (35 - 12 + 1) = 24
Step 4: Count of Common Multiples (LCM of 16 and 21)
- The least common multiple (LCM) of 16 and 21 = 336.
- The multiples of 336 between 250 and 750:
- First multiple = 336 (336 × 1)
- Last multiple = 672 (336 × 2)
- Count = 2
Step 5: Use Inclusion-Exclusion Principle
- Total divisible by 16 or 21:
- 31 (by 16) + 24 (by 21) - 2 (common) = 53
Step 6: Calculate the Final Count
- Numbers neither by 16 nor by 21:
- Total = 501 - 53 = 448
Conclusion
The answer is indeed option 'D' with 448 numbers that are neither divisible by 16 nor 21.
We need to find how many numbers between 250 and 750 (inclusive) are neither divisible by 16 nor 21.
Step 1: Total Numbers in Range
- The range from 250 to 750 has:
- Total numbers = 750 - 250 + 1 = 501
Step 2: Count of Multiples of 16
- The multiples of 16 between 250 and 750:
- First multiple = 256 (16 × 16)
- Last multiple = 736 (16 × 46)
- Count = (46 - 16 + 1) = 31
Step 3: Count of Multiples of 21
- The multiples of 21 between 250 and 750:
- First multiple = 252 (21 × 12)
- Last multiple = 735 (21 × 35)
- Count = (35 - 12 + 1) = 24
Step 4: Count of Common Multiples (LCM of 16 and 21)
- The least common multiple (LCM) of 16 and 21 = 336.
- The multiples of 336 between 250 and 750:
- First multiple = 336 (336 × 1)
- Last multiple = 672 (336 × 2)
- Count = 2
Step 5: Use Inclusion-Exclusion Principle
- Total divisible by 16 or 21:
- 31 (by 16) + 24 (by 21) - 2 (common) = 53
Step 6: Calculate the Final Count
- Numbers neither by 16 nor by 21:
- Total = 501 - 53 = 448
Conclusion
The answer is indeed option 'D' with 448 numbers that are neither divisible by 16 nor 21.
Chapter doubts & questions for Full Length Mock Test Series CBT - 1 - RRB NTPC Mock Test Series 2025 2025 is part of RRB NTPC/ASM/CA/TA exam preparation. The chapters have been prepared according to the RRB NTPC/ASM/CA/TA exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for RRB NTPC/ASM/CA/TA 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.
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