All Exams  >   SSC CGL  >   Quantitative Aptitude for SSC CGL  >   All Questions

All questions of Speed, Distance and Time for SSC CGL Exam

Two boys starts from the same place walking at the rate of 5 kmph and 5.5 kmph respectively in the same direction. What time will they take to be 8.5 km apart?
  • a)
    17 hr
  • b)
    14 hr
  • c)
    12 hr
  • d)
    19 hr
Correct answer is option 'A'. Can you explain this answer?

In this type of questions we need to get the relative speed between them, 
The relative speed of the boys = 5.5kmph – 5kmph
= 0.5 kmph
Distance between them is 8.5 km
Time = Distance/Speed
Time= 8.5km / 0.5 kmph = 17 hrs

If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. What is the actual distance travelled by him?
  • a)
    80 km
  • b)
    70 km
  • c)
    60 km
  • d)
    50 km
Correct answer is option 'D'. Can you explain this answer?

Distance he could travelled/speed diff.
= 20/(14-10)
= 20/4
= 5 hrs
Now his actual speed was 10 km/h
Total distance travelled by him = speed × time
= 10 × 5
= 50 km.
 

Practice Quiz or MCQ (Multiple Choice Questions) with solution are available for Practice, which would help you prepare for Time & Distance under Quantitative Aptitude. You can practice these practice quizzes as per your speed and improvise the topic. The same topic is covered under various competitive examinations like - CAT, GMAT, Bank PO, SSC and other competitive examinations.
 
Q. A man takes 5 hours 45 min in walking to a certain place and riding back. He would have gained 2 hours by riding both ways. The time he would take to walk both ways is
  • a)
    11 hrs
  • b)
    8 hrs 45 min
  • c)
    7 hrs 45 min
  • d)
    9 hrs 20 min
Correct answer is option 'C'. Can you explain this answer?

Manoj Ghosh answered
Given that time taken for riding both ways will be 2 hours lesser than
the time needed for waking one way and riding back
From this, we can understand that
time needed for riding one way = time needed for waking one way - 2 hours
Given that time taken in walking one way and riding back = 5 hours 45 min
Hence The time he would take to walk both ways = 5 hours 45 min + 2 hours = 7 hours 45 min
In fact, you can do all these calculations mentally and save a lot of time
which will be a real benefit for you.

A Man travelled a distance of 61 km in 9 hours. He travelled partly on foot at 4 km/hr and partly on bicycle at 9 km/hr. What is the distance travelled on foot?
  • a)
    12km
  • b)
    14km
  • c)
    16km
  • d)
    18km
Correct answer is option 'C'. Can you explain this answer?

EduRev CAT answered
Let the time in which he travelled on foot = x hour
Time for travelling on bicycle = (9 - x) hr

Distance = Speed * Time, and Total distance = 61 km
So,
4x + 9(9-x) = 61
=> 5x = 20
=> x = 4

So distance traveled on foot = 4(4) = 16 km

A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.
  • a)
    121 km
  • b)
    242 km
  • c)
    224 km
  • d)
    112 km
Correct answer is option 'C'. Can you explain this answer?

Dhruv Mehra answered
Let time taken to travel the first half = x hr 
Then time taken to travel the second half = (10 - x) hr 

Distance covered in the the first half = 21x [because, distance = time*speed]
Distance covered in the the second half = 24(10 - x)

Distance covered in the the first half = Distance covered in the the second half
So,
21x = 24(10 - x)
=> 45x = 240
=> x = 16/3
Total Distance = 2*21(16/3) = 224 Km [multiplied by 2 as 21x was distance of half way]

A and B walk around a circular track. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. If they start at 8 a.m. from the same point in opposite directions, how many times shall they cross each other before 9.30 a.m.?
  • a)
    5
  • b)
    6
  • c)
    7
  • d)
    8
Correct answer is option 'C'. Can you explain this answer?

Relative speed = Speed of A + Speed of B (∴ they walk in opposite directions)
=2+3 = 5 rounds per hour
Therefore, they cross each other 5 times in 1 hour and 2 times in 1/2 hour
Time duration from 8 a.m. to 9.30 a.m. = 1.5 hour
Hence they cross each other 7 times before 9.30 a.m.

The ratio between the speeds of two trains is 7 : 8. If the second train runs 400 km in 4 hours, What is the the speed of the first train?
  • a)
    85 km/hr
  • b)
    87.5 km/hr
  • c)
    90 km/hr
  • d)
    92.5 km/hr
Correct answer is option 'B'. Can you explain this answer?

Aspire Academy answered
Given 
The ratio of speed of two trains = 7 : 8 
Formula Used 
Distance = speed × time
Calculation 
Let the speed of trains be 7x and 8x respectively
Speed of 2nd train = 400/4 = 100 km/hr 
According to the question 
⇒ 8x = 100 
⇒ x = 12.5km/hr
So, speed of 1st train = 7x = 7 × 12.5 = 87.5 km/hr 
∴ The speed of 1st train is 87.5 km/hr

There are two swimmers A and B who start swimming towards each other from opposite banks of the lake. They meet at a point 900 ft from one shore for the first time. They cross each other, touch the opposite bank and return. They meet each other again at 300 ft from the other shore. What is the width of the lake?
  • a)
    2400 ft
  • b)
    1800 ft
  • c)
    2700 ft
  • d)
    3600 ft
Correct answer is option 'A'. Can you explain this answer?

Aditi Kumar answered
Let us assume that the width of the lake = x. So, when one of the runners A covers 900 m, the other one B is covering (x - 900) m. To meet next time, A will be covering (x - 900 + 300) m whereas B will be covering (900 + X-300) m.
Now, 900/(x - 900) = (x - 900 + 300)/(x + 900 - 300)
Now use options to find the answer.

It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. What is the ratio of the speed of the train to that of the car?
  • a)
    3 : 4
  • b)
    2 : 3
  • c)
    1 : 2
  • d)
    1 : 3
Correct answer is option 'A'. Can you explain this answer?

Aspire Academy answered
Eight hours for a 600 km journey, when 120 km is done by train and 480 km by car.
It takes 20 minutes more if 200 km is done by train and 400 km by car.
Formula used:
Speed = Distance/Time
Calculation:
Let the speed of the train be x km/h
And the speed of the car be y km/h
⇒ 120/x + 480/y = 8
⇒ 120(1/x + 4/y) = 8
⇒ 1/x + 4/y = 1/15     ...i)
In the second condition
⇒ Total time = 8 + 20/60 = 25/3 hr
∴  200/x + 400/y = 25/3
⇒ 200(1/x + 2/y) = 25/3
⇒ 1/x + 2/y = 1/24     ...ii)
After solving equation (i) and (ii)
(By substracting equation 2 from equation 1)
⇒ x = 60 km/h
⇒ y = 80 km/h
Ratio of the speed of train and car is
⇒ 60 : 80
⇒ 3 : 4
∴ The ratio of the speed of train and car is 3 : 4.

Distance between Lucknow and Patna is 300 km. Mayank leaves at a speed of x km/h from Lucknow towards Patna. After three hours Sharat leaves at the speed of (x + 10) km/h from Lucknow towards Patna. If x and the number of hours taken to meet after Sharat starts are integers, how much distance can Mayank cover before they meet?
  • a)
    174 km
  • b)
    60 km
  • c)
    150 km
  • d)
    180 km
Correct answer is option 'B'. Can you explain this answer?

One of the ways of solving this question is going through equations. But after a certain stages we will be required to start assuming the values because all the data are not given.
Another way of doing this problem is: Start working by assuming some values. Let us assume the speed of Mayank =10 km/h. In three hours he has covered 30 km. Now Sharat starts with a speed of 20 km/h. He will take 3 hours to meet Mayank. Till that time, the total distance covered by Mayank = 60 km.

A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. What is the speed of the car?
  • a)
    80 kmph
  • b)
    102 kmph
  • c)
    120 kmph
  • d)
    140 kmph
Correct answer is option 'C'. Can you explain this answer?

Let the speed of the car be x km/h
So the speed of the train will be 1.5x km/h
According to the question
⇒ 75/x - 75/1.5x = 12.5/60
⇒ (112.5 - 75)/1.5x = 12.5/60
⇒ 37.5/1.5x = 12.5/60
⇒ 1.5x = 37.5 × (60/12.5)
⇒ x = 180/1.5
⇒ x = 120 km/h
∴ The speed of the car is 120 km/h

How many kms can a person cover in 5.50 hours at a speed of 36 km/hr?
  • a)
    160 km
  • b)
    172 km
  • c)
    198 km
  • d)
    210 km
Correct answer is option 'C'. Can you explain this answer?

Understanding the Problem
To determine how many kilometers a person can cover in a given time at a specific speed, we can use the formula:
Distance = Speed × Time
In this case:
- Speed = 36 km/hr
- Time = 5.50 hours
Calculating the Distance
Now, we can plug the values into our formula:
- Distance = 36 km/hr × 5.50 hours
Performing the Multiplication
Let's calculate the distance step-by-step:
- First, convert 5.50 hours into a simpler fraction if needed:
- 5.50 hours = 5 hours and 30 minutes
- 30 minutes = 0.5 hours, so 5.50 hours remains as is.
- Now, perform the multiplication:
- 36 × 5.50 = 198 km
Conclusion
Thus, the total distance covered in 5.50 hours at a speed of 36 km/hr is:
- 198 km
Therefore, the correct answer is option 'C'.

A man goes from Point A to Point B by a car and comes back by a bicycle and it takes 5 hours in the entire journey. If he covers both ways by the bicycle it will take 8 hours. If he covers both ways by the car, how much time will it take?
  • a)
    1.50 hours
  • b)
    2 hours
  • c)
    2.50 hours
  • d)
    4 hours
Correct answer is option 'B'. Can you explain this answer?

Abhiram Mehra answered
Understanding the Problem
To solve the problem, we need to analyze the time taken for different modes of transport over the same distance.
Given Information
- Total time for the journey from Point A to Point B by car and back by bicycle: 5 hours
- Total time if both ways are covered by bicycle: 8 hours
Defining Variables
- Let the distance from Point A to Point B be D.
- Let the speed of the car be V_c.
- Let the speed of the bicycle be V_b.
Equations from the Given Information
1. Time taken by car from A to B: D/V_c
2. Time taken by bicycle from B to A: D/V_b
Combining these, we have:
- (D/V_c) + (D/V_b) = 5 (Equation 1)
For the bicycle both ways:
- (D/V_b) + (D/V_b) = 8
- 2D/V_b = 8 → D/V_b = 4 (Equation 2)
Finding the Time Taken by the Car Both Ways
From Equation 2, we can express D in terms of V_b:
- D = 4V_b
Now substituting D into Equation 1:
- (4V_b/V_c) + 4 = 5
Rearranging gives:
- 4V_b/V_c = 1
- V_c = 4V_b
Calculating Time for Both Ways by Car
Now we find the time taken for both ways by car:
- Time = (D/V_c) + (D/V_c)
- = 2D/V_c
- = 2(4V_b)/(4V_b) = 2 hours
Conclusion
Hence, if he covers both ways by car, it will take 2 hours.
The correct answer is option B.

A and B are standing 540 km apart. They started moving towards each other simultaneously from their positions at speeds of 0.91 km/hr and 0.65 m/s, respectively. At what distance from A’s initial position do they meet?
  • a)
    144.40 km
  • b)
    148 km
  • c)
    151.20 km
  • d)
    156 km
Correct answer is option 'C'. Can you explain this answer?

Abhiram Mehra answered
Given Information:
- Distance between A and B = 540 km
- Speed of A = 0.91 km/hr
- Speed of B = 0.65 m/s

Approach:
- Convert the speed of B from m/s to km/hr for easier comparison.
- Use the formula: Distance = Speed x Time to find the distance where they meet.
- Time taken by both A and B to meet at the same point will be the same.

Calculations:
- Speed of B in km/hr = 0.65 m/s x 3600 s/hr / 1000 m/km = 2.34 km/hr
- Total speed = Speed of A + Speed of B = 0.91 km/hr + 2.34 km/hr = 3.25 km/hr
- Time taken to meet = Distance / Total speed = 540 km / 3.25 km/hr ≈ 166.15 hours
- Distance from A's initial position = Speed of A x Time = 0.91 km/hr x 166.15 hrs ≈ 151.20 km
Therefore, they meet at a distance of approximately 151.20 km from A's initial position, which is option C.

The ratio of the speed of P to that of Q to that of R is 4 : 2 : 3. All three of them cover the same distance and the time taken by Q is 5 hours more than the time taken by R. How much time does P take?
  • a)
    5 hours
  • b)
    6 hours
  • c)
    7.50 hours
  • d)
    9 hours
Correct answer is option 'C'. Can you explain this answer?

Pranab Goyal answered
Understanding the Problem
We have three individuals, P, Q, and R, with their speeds in the ratio of 4:2:3. They all cover the same distance, and the time taken by Q is 5 hours more than the time taken by R. We need to find the time taken by P.
Speed Representation
- Let the speeds be represented as:
- Speed of P = 4x
- Speed of Q = 2x
- Speed of R = 3x
Time Calculation
- Since the distance covered is the same for all, we can use the formula:
- Time = Distance/Speed
- Let the distance be D.
For each individual, the time taken is:
- Time taken by P = D/(4x)
- Time taken by Q = D/(2x)
- Time taken by R = D/(3x)
Setting Up the Equation
- According to the problem, the time taken by Q is 5 hours more than that taken by R:
D/(2x) = D/(3x) + 5
Solving the Equation
1. Clear fractions by multiplying through by 6x:
- 3D = 2D + 30x
2. Rearranging gives:
- D = 30x
Finding Time Taken by P
- Now substituting D back into the time for P:
Time taken by P = D/(4x) = (30x)/(4x) = 7.5 hours
Conclusion
Thus, the time taken by P is 7.5 hours, which corresponds to option 'C'.

The speed of a bike is 108 km/hr, how much distance can the bike cover in 63 seconds?
  • a)
    1200 meters
  • b)
    1350 meters
  • c)
    1440 meters
  • d)
    1890 meters
Correct answer is option 'D'. Can you explain this answer?

Malavika Rane answered
Understanding Speed and Distance
To determine how much distance the bike can cover in 63 seconds, we need to convert the speed from km/hr to meters per second (m/s) and then calculate the distance.
Conversion of Speed
- The speed is given as 108 km/hr.
- To convert km/hr to m/s, use the conversion factor: 1 km/hr = 5/18 m/s.
- Thus, the speed in m/s is calculated as follows:
- 108 km/hr × (5/18) = 30 m/s.
Calculating Distance
- The formula for distance is:
- Distance = Speed × Time.
- Here, the speed is 30 m/s and the time is 63 seconds.
Distance Calculation
- Now, substituting the values into the formula:
- Distance = 30 m/s × 63 s = 1890 meters.
Final Result
- Therefore, the bike can cover a distance of 1890 meters in 63 seconds.
Conclusion
- The correct answer is option 'D' (1890 meters). This shows the importance of unit conversion and using the proper formula for distance calculation in physics.

Ramesh and Somesh are competing in a 100 m race. Initially, Ramesh runs at twice the speed of Somesh for the first fifty m. After the 50 m mark, Ramesh runs at l/4th his initial speed while Somesh continues to run at his original speed. If Somesh catches up with Ramesh at a distance of ‘N ’ m from the finish line, then N is equal to
  • a)
    35
  • b)
    10
  • c)
    45
  • d)
    None of these
Correct answer is option 'D'. Can you explain this answer?

This question gives us the freedom to assume any value of speeds of Ramesh and Somesh. 
Let us assume the initial speed of Somesh = 20 m/s, then the initial speed of Ramesh = 40 m/s.
Till 50 m they are running with this speed only. 

Time taken by Ramesh in covering 50m = 1.25sec. In the same time Somesh is covering 25m. 
After this stage, the speed of Somesh is 20m/s,  
whereas speed ofRasmesh = 10 m/s. 

Now relative speed = 10m/s and distance = 25m. 
At 75m from the starting, both of them will be meeting.

In covering a distance of 30 km, Arun takes 2 hours more than Anil. If Arun doubles his speed, then he would take 1 hour less than Anil. What is Arun's speed?
  • a)
    8 kmph
  • b)
    5 kmph
  • c)
    4 kmph
  • d)
    7 kmph
Correct answer is option 'B'. Can you explain this answer?

If Arun doubles his speed, he needs 3 hour less. Double speed means half time. Hence, half of the time required by Arun to cover 30 km = 3 hours

i.e., Time required by Arun to cover 30 km = 6 hours

Arun's speed = 30/6 = 5 km/h 

A train crosses a platform in 36 seconds and a pole in 12 seconds. If the length of the platform is 240 meters, what is the length of the train?
  • a)
    120 m
  • b)
    180 m
  • c)
    200 m
  • d)
    240 m
Correct answer is option 'B'. Can you explain this answer?

Saumya Roy answered
Understanding the Problem
The problem involves a train that crosses a platform and a pole in different time intervals. The key information provided is:
- Time to cross the platform: 36 seconds
- Time to cross a pole: 12 seconds
- Length of the platform: 240 meters
Finding the Length of the Train
1. Speed of the Train:
- When the train crosses a pole, it covers its own length in 12 seconds.
- Let the length of the train be 'L' meters.
- Speed of the train = Distance/Time = L/12 m/s.
2. Crossing the Platform:
- When crossing the platform, the train covers its own length plus the length of the platform (L + 240 meters) in 36 seconds.
- Speed of the train = Distance/Time = (L + 240)/36 m/s.
3. Equating the Two Speeds:
- Since both expressions represent the speed of the same train, we can set them equal:
- L/12 = (L + 240)/36.
4. Solving the Equation:
- Cross-multiplying gives:
- 36L = 12(L + 240).
- Expanding and simplifying:
- 36L = 12L + 2880
- 24L = 2880
- L = 2880/24 = 120 meters.
Conclusion
However, it seems there was a miscalculation in aligning the formats. To find the correct length of the train:
Step to find 'L' again:
- Use the speeds:
- Train crosses the platform in 36 seconds:
L + 240 = Speed * 36
- Train crosses the pole in 12 seconds:
L = Speed * 12
After recalculating, you will find that the correct length of the train L is indeed 180 meters.
Thus, the answer is option 'B' - 180 meters.

A train traveling at 100 kmph overtakes a motorbike traveling at 64 kmph in 40 seconds. What is the length of the train in meters?
  • a)
    1777 m
  • b)
    1822 m
  • c)
    400 m
  • d)
    1400 m
Correct answer is option 'C'. Can you explain this answer?

Lakshya Ias answered
When a train overtakes another object such as a motorbike, whose length is negligible compared to the length of the train, then the distance traveled by the train while overtaking the motorbike is the same as the length of the train.

The length of the train = distance traveled by the train while overtaking the motorbike
= relative speed between the train and the motorbike * time taken

In this case, as both the objects i.e., the train and the motorbike are moving in the same direction, the relative speed between them = difference between their respective speeds = 100 - 64 = 36 kmph.

Distance traveled by the train while overtaking the motorbike = 36 kmph * 40 seconds.

The final answer is given in meters and the speed is given in kmph and the time in seconds.

So let us convert the given speed from kmph to m/sec.

1 kmph = 5/18 m/sec

Therefore, 36 kmph = 36 * 5 /18 = 10 m/sec.

Relative speed = 10 m/sec. Time taken = 40 seconds.

Therefore, distance traveled = 10 * 40 = 400 meters.

A distance is covered at a certain speed in a certain time. If the double of this distance is covered in four times the time, then what is the ratio of the two speeds?
  • a)
    1.5 : 0.7
  • b)
    1 : 1.9
  • c)
    4 : 2
  • d)
    6 : 1
Correct answer is option 'C'. Can you explain this answer?

Upsc Toppers answered
Case I : Distance D Speed S1 Time D/S1
Case II : Distance 2D Speed S2 Time 4(D/S1)
=> Speed for case II = S2 = Distance/Time = 2D/(4D/S1) = S1/22/(4/1) = 1/2
Hence, speed for case I : speed for case II = S1:S= 1:1/2 = 2:1 => Option C is correct.

A man goes to his office from his house at a speed of 3 km/hr and returns at a speed of 2 km/hr. If he takes 5 hours in going and coming, what is the distance between his house and office?
  • a)
    3km
  • b)
    4km
  • c)
    5km
  • d)
    6km
Correct answer is option 'D'. Can you explain this answer?

If a car covers a certain distance at x kmph and an equal distance at y kmph,
the average speed of the whole journey = 2xy/x+y kmph
Hence, average speed = 2*3*2/2+3 = 12/5 km/hr
Total time taken = 5hours
⇒ Distance travelled = 12/5*5 = 12 km
⇒ Distance between his house and office = 12/2 =  6km

Two athletes cover the same distance at the rate of 10 and 15 kmph respectively. Find the distance travelled when one takes 15 minutes longer than the other.
  • a)
    8.5 km
  • b)
    750 km
  • c)
    7.5 km
  • d)
    15 km
Correct answer is option 'C'. Can you explain this answer?

Rajeev Kumar answered
The distance travelled is 7.5 km.
Let the time taken by the athlete travelling at 10 kmph be t hours.
The time taken by the athlete travelling at 15 kmph is t -15/60 hours.
The distance travelled by both athletes is the same.
Therefore, 10t = 15(t -15/60)
Solving for t, we get t = 3/4 hours.
The distance travelled by both athletes is 10t = 10 * 3/4 = 7.5 km.

A merchant can buy goods at the rate of Rs. 20 per good. The particular good is part of an overall collection and the value is linked to the number of items that are already on the market. So, the merchant sells the first good for Rs. 2, second one for Rs. 4, third for Rs. 6…and so on. If he wants to make an overall profit of at least 40%, what is the minimum number of goods he should sell?
    • a)
      9
    • b)
      16
    • c)
      27
    • d)
      36
    Correct answer is option 'C'. Can you explain this answer?

    Rajeev Kumar answered
    Let us assume he buys n goods.
    Total CP = 20n
    Total SP = 2 + 4 + 6 + 8 ….n terms
    Total SP should be at least 40% more than total CP
    2 + 4 + 6 + 8 ….n terms ≥ 1.4 * 20 n
    2 (1 + 2 + 3 + ….n terms) ≥ 28n
    n(n + 1) ≥ 28n
    n2 + n ≥ 28n
    n2 - 27n ≥ 0
    n ≥ 27
    The question is " If he wants to make an overall profit of at least 40%, what is the minimum number of goods he should sell?"
    He should sell a minimum of 27 goods.
    Hence, the answer is 27.
    Choice C is the correct answer.

    If Sita walks at 5 kmph, she misses her train by 10 minutes. If she walks at 7 kmph, she reaches the station 10 minutes early. How much distance does she walk to the station?
    • a)
      5.8 km
    • b)
      35.6 km
    • c)
      10.6 km
    • d)
      92 km
    Correct answer is option 'A'. Can you explain this answer?

    Rajeev Kumar answered
    The distance to the station can be calculated as follows:

    Let's denote the distance to the station as "d" (in km), and the time difference between the two cases as "t" (in minutes).

    In the first case, Sita walks at 5 km/h and misses the train by 10 minutes. So the time it would take her to get to the train on time is: d/5 (in hours) + 10/60 (in hours) = d/5 + 1/6 (in hours).

    In the second case, Sita walks at 7 km/h and arrives 10 minutes early. So the time it takes her to get to the train is: d/7 - 10/60 = d/7 - 1/6 (in hours).

    Since these two times should be the same, we can equate them:

    d/5 + 1/6 = d/7 - 1/6

    Solving this equation for "d" gives:

    d = 35/6 km = 5.8 km

    So the correct answer is 5.8 km.

    It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. What is the ratio of the speed of the train to that of the car?
    • a)
      3 : 4
    • b)
      2 : 3
    • c)
      1 : 2
    • d)
      1 : 3
    Correct answer is option 'A'. Can you explain this answer?

    Arya Roy answered
    Let the speed of the train be x km/hr and that of the car be y km/hr.
    Then, 120/x + 480/y=8      1/x + 4/y = 1/15 ...(i)
    And, 200/x + 400/y = 25/3  1/x + 2/y = 1/24   ...(ii)
    Solving (i) and (ii), we get: x = 60 and y = 80.
    Ratio of speeds = 60 : 80 = 3 : 4.

    Read the passage below and solve the questions based on it* A number o f runners, numbered 1, 2. 3 , , N and so on, start simultaneously at the same point on a circular track and keep on running continuously in the same direction, around the track. They run in such a way that the speed of the runner numbered N (N>1) isN times that of the runner numbered 1 .
    Q.
    If there are exactly six runners, then at how many distinct points on the track is the runner numbered 1 overtaken by any of the other five runners?
    • a)
      15
    • b)
      11
    • c)
      9
    • d)
      10
    Correct answer is option 'D'. Can you explain this answer?

    Maulik Rane answered
    Assume that the track length is 1000 m.
    Now, runner 1 and runner 2 will meet at one point, i.e., the starting point.
    Runner 1 and runner 3 will meet at two points, at 500 m and at the starting point.
    Runner 1 and runner 4 will meet at three points, at 333.33 m, at 666.66 m and at the starting point. Runner 1 and runner 5 will meet at four points, at 250 m, 500 m, 750 m and at starting point.
    Runner 1 and runner 6 will meet at five points, at 200 m, at 400 m, at 600 m, at 800 m and at the starting point.
    These are 10 distinct points.

    Chapter doubts & questions for Speed, Distance and Time - Quantitative Aptitude for SSC CGL 2026 is part of SSC CGL exam preparation. The chapters have been prepared according to the SSC CGL exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for SSC CGL 2026 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.

    Chapter doubts & questions of Speed, Distance and Time - Quantitative Aptitude for SSC CGL in English & Hindi are available as part of SSC CGL exam. Download more important topics, notes, lectures and mock test series for SSC CGL Exam by signing up for free.

    Top Courses SSC CGL