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All questions of Number System for SSC CGL Exam
In a three digit number the digit in the unit’s place is twice the digit in the ten’s place and 1.5 times the digit in the hundred’s place. If the sum of all the three digits of the number is 13, what is the number?- a)356
- b)456
- c)436
- d)626
- e)516
Correct answer is option 'C'. Can you explain this answer?
In a three digit number the digit in the unit’s place is twice the digit in the ten’s place and 1.5 times the digit in the hundred’s place. If the sum of all the three digits of the number is 13, what is the number?
a)
356
b)
456
c)
436
d)
626
e)
516
 | Bank Exams India answered |
100a + 10b + c
c = 2b → b = c/2
c = 1.5a → a = c/1.5
c/1.5 + c/2 + c = 13
6.5c = 39
c = 6, b = 3, a = 4 ⇒ 436
c = 2b → b = c/2
c = 1.5a → a = c/1.5
c/1.5 + c/2 + c = 13
6.5c = 39
c = 6, b = 3, a = 4 ⇒ 436
Sum of three consecutive odd numbers & three consecutive even numbers together is 231. Difference between the smallest odd number and the smallest even number is 11. What is the sum of the largest even number and largest odd number?- a)71
- b)91
- c)101
- d)81
- e)Can not be determined
Correct answer is option 'D'. Can you explain this answer?
Sum of three consecutive odd numbers & three consecutive even numbers together is 231. Difference between the smallest odd number and the smallest even number is 11. What is the sum of the largest even number and largest odd number?
a)
71
b)
91
c)
101
d)
81
e)
Can not be determined
| | Kendrika answered |
Let the three odd numbers be x, (x + 2), (x + 4) and
The three even numbers be (x + 11), (x + 13) and (x + 15)
Then,
⇔ x + (x + 2) + (x + 4) + (x + 11) + (x + 13) + (x + 15) = 231
⇔ 6x + 45 = 231
⇔ 6x = 186
⇔ x = 31
∴ Required sum :
= (x + 4) + (x + 15)
= 2x + 19
= 2 × 31 + 19
= 62 + 19
= 81
The three even numbers be (x + 11), (x + 13) and (x + 15)
Then,
⇔ x + (x + 2) + (x + 4) + (x + 11) + (x + 13) + (x + 15) = 231
⇔ 6x + 45 = 231
⇔ 6x = 186
⇔ x = 31
∴ Required sum :
= (x + 4) + (x + 15)
= 2x + 19
= 2 × 31 + 19
= 62 + 19
= 81
A number when divided by 143 leaves 31 as remainder. What will be the remainder
when the same number is divided by 13 ?- a)0
- b)1
- c)3
- d)5
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
A number when divided by 143 leaves 31 as remainder. What will be the remainder
when the same number is divided by 13 ?
when the same number is divided by 13 ?
a)
0
b)
1
c)
3
d)
5
e)
None of these
 | Abhishek answered |
Number is = x
x = divisor + remainder
x = 143 + 31
x = 174
when the same number is decided by 13
remainder= 174÷13
= 5 Ans.
x = divisor + remainder
x = 143 + 31
x = 174
when the same number is decided by 13
remainder= 174÷13
= 5 Ans.
The sum of two even numbers is six more than twice of the smaller number. If the difference between these two numbers is 6, If the larger number lies between 15 to 25 Which is the smaller number?- a)16
- b)6
- c)24
- d)12
- e)Can not be determined
Correct answer is option 'D'. Can you explain this answer?
The sum of two even numbers is six more than twice of the smaller number. If the difference between these two numbers is 6, If the larger number lies between 15 to 25 Which is the smaller number?
a)
16
b)
6
c)
24
d)
12
e)
Can not be determined
 | Kavya Saxena answered |
If 12 is smaller number then larger number is 18
Sum = (12+18) = 30
Twice of the smaller number = 24.
The sum of two even numbers is six more than twice of the smaller number.
Therefore Number 12 satisfy both the conditions.
Sum = (12+18) = 30
Twice of the smaller number = 24.
The sum of two even numbers is six more than twice of the smaller number.
Therefore Number 12 satisfy both the conditions.
If 4 is added to the numerator of a fraction it becomes 1/3 and if 3 is added to the denominator it becomes 1/6 then find the difference between numerator and denominator is- a)20
- b)21
- c)22
- d)24
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
If 4 is added to the numerator of a fraction it becomes 1/3 and if 3 is added to the denominator it becomes 1/6 then find the difference between numerator and denominator is
a)
20
b)
21
c)
22
d)
24
e)
None of these
 | Aisha Gupta answered |
(a +4)/b = 1/3 and a/(b+3) = 1/6 solve both the equations, u will get a = 5 and b = 27
The sum of digits of a two digit number is 6. The ratio of the original number to the number formed by interchanging its digits is 4 : 7. Find the number.- a)60
- b)15
- c)42
- d)33
- e)24
Correct answer is option 'E'. Can you explain this answer?
The sum of digits of a two digit number is 6. The ratio of the original number to the number formed by interchanging its digits is 4 : 7. Find the number.
a)
60
b)
15
c)
42
d)
33
e)
24
 | Target Study Academy answered |
Let the number is 10x+y
So x+y = 6
And (10x+y)/(10y+x) = 4/7
Solve, 2x = y and from above we have x+y = 6
Solve both equations, x = 2, y = 4
So x+y = 6
And (10x+y)/(10y+x) = 4/7
Solve, 2x = y and from above we have x+y = 6
Solve both equations, x = 2, y = 4
A certain number of two digits is three times the sum of its digits. If 45 is added to it, the digits are reversed. The number is _______- a)16
- b)72
- c)63
- d)27
- e)Can not be determined
Correct answer is option 'D'. Can you explain this answer?
A certain number of two digits is three times the sum of its digits. If 45 is added to it, the digits are reversed. The number is _______
a)
16
b)
72
c)
63
d)
27
e)
Can not be determined
 | KS Coaching Center answered |
A certain number of two digits is three times the sum of its digits only 27 satisfies this condition.
27 + 45 = 72
Therefore Ans is – 27
27 + 45 = 72
Therefore Ans is – 27
When a number is added to 20 percent of the second number, we get 150 percent of the second number. Find the ratio between the first and second number?- a)13:9
- b)12:10
- c)13:10
- d)17:10
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
When a number is added to 20 percent of the second number, we get 150 percent of the second number. Find the ratio between the first and second number?
a)
13:9
b)
12:10
c)
13:10
d)
17:10
e)
None of these
| | Bank Exams India answered |
a + (20/100)*b = (150/100)*b
a:b = 13:10
a:b = 13:10
The sum of the digits of two-digit number is 5. If the digit is reversed, the number is decreased by 27. Find the numbers ?- a)15,51
- b)41, 14
- c)30, 31
- d)32, 23
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
The sum of the digits of two-digit number is 5. If the digit is reversed, the number is decreased by 27. Find the numbers ?
a)
15,51
b)
41, 14
c)
30, 31
d)
32, 23
e)
None of these
 | Naroj Boda answered |
Let the number be (10a + b)
given, a +b = 5 and (10a + b) – (10b +a) = 27
a – b = 3 and a +b = 5
given, a +b = 5 and (10a + b) – (10b +a) = 27
a – b = 3 and a +b = 5
If the positions of the digits of a two digit number are interchanged, the number obtained is smaller than the original number by 27. If the digits of the number are in the ratio of 1:2, what is the original number?- a)16
- b)32
- c)63
- d)48
- e)Can not be determined
Correct answer is option 'C'. Can you explain this answer?
If the positions of the digits of a two digit number are interchanged, the number obtained is smaller than the original number by 27. If the digits of the number are in the ratio of 1:2, what is the original number?
a)
16
b)
32
c)
63
d)
48
e)
Can not be determined
 | Divey Sethi answered |
original number – 10x + y
(10x + y) – (10y + x) = 27
9(x – y) = 27
x – y = 3
y/x = 1/2
x = 2y
y = 3, x = 6 →63
(10x + y) – (10y + x) = 27
9(x – y) = 27
x – y = 3
y/x = 1/2
x = 2y
y = 3, x = 6 →63
When 1 is added to the numerator of a fraction it becomes 1/4 and 1 is subtracted from the denominator of that fraction it becomes 1/5. Find the fraction.- a)4/19
- b)3/16
- c)5/17
- d)2/15
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
When 1 is added to the numerator of a fraction it becomes 1/4 and 1 is subtracted from the denominator of that fraction it becomes 1/5. Find the fraction.
a)
4/19
b)
3/16
c)
5/17
d)
2/15
e)
None of these
| | KS Coaching Center answered |
Let fraction = x/y
Then (x+1)/y = 1/4
And x/(y-1) = 1/5
Solve both equations, x = 3, y = 16
Then (x+1)/y = 1/4
And x/(y-1) = 1/5
Solve both equations, x = 3, y = 16
On dividing a certain number by 357, the remainder is 39. On dividing the same number by 17, what will be the remainder ?- a)5
- b)3
- c)7
- d)6
Correct answer is option 'A'. Can you explain this answer?
On dividing a certain number by 357, the remainder is 39. On dividing the same number by 17, what will be the remainder ?
a)
5
b)
3
c)
7
d)
6
 | Ssc Cgl answered |
Let the given number be N
Therefore N = 357k + 39
Then,
357 k + 39 = ( 17 x 21k ) + ( 17 x 2 ) + 5
∴ Required remainder = 5
Therefore N = 357k + 39
Then,
357 k + 39 = ( 17 x 21k ) + ( 17 x 2 ) + 5
∴ Required remainder = 5
A number is divided by 2, 3, 4, 5 or 6, reminder in each case is one. But the number is exactly divisible by 7. The number lies between 250 and 350, the sum of digits of the number will be- a)4
- b)7
- c)6
- d)10
- e)Can not be determined
Correct answer is option 'A'. Can you explain this answer?
A number is divided by 2, 3, 4, 5 or 6, reminder in each case is one. But the number is exactly divisible by 7. The number lies between 250 and 350, the sum of digits of the number will be
a)
4
b)
7
c)
6
d)
10
e)
Can not be determined
 | Preeti Khanna answered |
To solve this problem, we need to find a number that satisfies the following conditions:
- When divided by 2, 3, 4, 5, or 6, the remainder is 1.
- The number is divisible by 7.
- The number lies between 250 and 350.
Let's start by finding the least common multiple (LCM) of 2, 3, 4, 5, and 6, which is the smallest number divisible by all of these numbers.
LCM(2, 3, 4, 5, 6) = 60
We need to find a number of the form 7k, where k is an integer, that leaves a remainder of 1 when divided by 60. The numbers in this sequence can be expressed as 60n + 1, where n is an integer.
Now, let's find the first few numbers of the form 60n + 1 that are divisible by 7 and lie between 250 and 350:
- For n = 4: 60(4) + 1 = 241 (not divisible by 7)
- For n = 5: 60(5) + 1 = 301 (divisible by 7)
So, the number we're looking for is 301.
Now, let's find the sum of its digits: 3 + 0 + 1 = 4
Therefore, the sum of the digits of the number is 4.
Sum of eight consecutive odd numbers is 656. Average of four consecutive even numbers is 87. What is the sum of the largest even number and largest odd number?- a)171
- b)191
- c)101
- d)181
- e)179
Correct answer is option 'E'. Can you explain this answer?
Sum of eight consecutive odd numbers is 656. Average of four consecutive even numbers is 87. What is the sum of the largest even number and largest odd number?
a)
171
b)
191
c)
101
d)
181
e)
179
| | Preeti Khanna answered |
odd numbers — x-8, x-6, x-4, x-2, x, x+2, x+4, x+6
x-8 + x-6 + x-4 + x-2 + x + x+2 + x+4 + x+6 = 656
8x – 8 =656
x = 83
Even numbers — y-2, y, y+2, y+4
4y + 4 = 87 * 4
y = 86
sum of the largest even number and odd number = 89 + 90 = 179
x-8 + x-6 + x-4 + x-2 + x + x+2 + x+4 + x+6 = 656
8x – 8 =656
x = 83
Even numbers — y-2, y, y+2, y+4
4y + 4 = 87 * 4
y = 86
sum of the largest even number and odd number = 89 + 90 = 179
A number is multiplied by 561, and the result obtained is 32,582. But it was found that both 2 in the number are wrong, what should be the correct answer?- a)33,583
- b)37,587
- c)39,589
- d)36,586
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
A number is multiplied by 561, and the result obtained is 32,582. But it was found that both 2 in the number are wrong, what should be the correct answer?
a)
33,583
b)
37,587
c)
39,589
d)
36,586
e)
None of these
| | Kavya Saxena answered |
561 = 3*11*17
So the number must be divided by 3, 11 and 17
Only B option is divided by all.
So the number must be divided by 3, 11 and 17
Only B option is divided by all.
Two numbers such that the sum of twice the first number and thrice the second number is 100 and the sum of thrice the first number and twice the second number is 120. Which is larger number?- a)64
- b)72
- c)65
- d)32
- e)None of the Above
Correct answer is option 'D'. Can you explain this answer?
Two numbers such that the sum of twice the first number and thrice the second number is 100 and the sum of thrice the first number and twice the second number is 120. Which is larger number?
a)
64
b)
72
c)
65
d)
32
e)
None of the Above
| | Anaya Patel answered |
2x + 3y = 100 –(i)
3x + 2y = 120 –(ii)
By Solving eqn (i) and (ii)
x = 32, y = 12
3x + 2y = 120 –(ii)
By Solving eqn (i) and (ii)
x = 32, y = 12
Three numbers are in the ratio 4:3:5. If the difference between thrice the third number and the sum of first and second number is 64. Find the difference between the first and third number?- a)4
- b)8
- c)12
- d)16
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
Three numbers are in the ratio 4:3:5. If the difference between thrice the third number and the sum of first and second number is 64. Find the difference between the first and third number?
a)
4
b)
8
c)
12
d)
16
e)
None of these
 | Cstoppers Instructors answered |
15x – (7x) = 64, we get x = 8
difference between first and third number = 5x – 4x = x = 8
difference between first and third number = 5x – 4x = x = 8
The difference between the digits of a two digit number is 5. Also the original number is 18 more than two times the number obtained by reversing its digits. Find the original number.- a)94
- b)61
- c)72
- d)49
- e)27
Correct answer is option 'C'. Can you explain this answer?
The difference between the digits of a two digit number is 5. Also the original number is 18 more than two times the number obtained by reversing its digits. Find the original number.
a)
94
b)
61
c)
72
d)
49
e)
27
 | Ravi Singh answered |
Let number is 10x+y
Then x-y = 5 or y-x = 5
Now given that, 10x+y = 2(10y+x) + 18 Solve, 8x – 19y = 18
Now solve: 8x – 19y = 18 and x-y = 5. In this y = 2, x = 7
And also solve; 8x – 19y = 18 and y-x = 5. In this y come to be negative which is not possible so discard this
So number is 10*7 + 2
Then x-y = 5 or y-x = 5
Now given that, 10x+y = 2(10y+x) + 18 Solve, 8x – 19y = 18
Now solve: 8x – 19y = 18 and x-y = 5. In this y = 2, x = 7
And also solve; 8x – 19y = 18 and y-x = 5. In this y come to be negative which is not possible so discard this
So number is 10*7 + 2
What is th unit digit in ( 365x659x771 ) ?- a)6
- b)4
- c)2
- d)1
Correct answer is option 'B'. Can you explain this answer?
What is th unit digit in ( 365x659x771 ) ?
a)
6
b)
4
c)
2
d)
1
| | Ssc Cgl answered |
Unit digit in 34 = 1
∴ Unit digit in ( 34 )16 = 1
∴ Unit digit in 365 = 3
Unit digit in 659 = 6
Unit digit in 771 = 3
∴ Required unit digit = Unit digit in ( 3 x 6 x 3 )
= Unit digit in 54
= 4
∴ Unit digit in ( 34 )16 = 1
∴ Unit digit in 365 = 3
Unit digit in 659 = 6
Unit digit in 771 = 3
∴ Required unit digit = Unit digit in ( 3 x 6 x 3 )
= Unit digit in 54
= 4
A number gets reduced to its two-third when 24 is subtracted from it. Find oneeighth of the number?- a)7
- b)8
- c)9
- d)10
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
A number gets reduced to its two-third when 24 is subtracted from it. Find oneeighth of the number?
a)
7
b)
8
c)
9
d)
10
e)
None of these
 | Yash Patel answered |
a – 24 = 2a/3
we get a = 72
so one-eighth of the number = 72/8 = 9
we get a = 72
so one-eighth of the number = 72/8 = 9
The number obtained by interchanging the two digits of a two digit number is less than the original number by 27. If the difference between the two digits of the number is 3, then what is the original number?- a)64
- b)72
- c)65
- d)73
- e)None of the Above
Correct answer is option 'E'. Can you explain this answer?
The number obtained by interchanging the two digits of a two digit number is less than the original number by 27. If the difference between the two digits of the number is 3, then what is the original number?
a)
64
b)
72
c)
65
d)
73
e)
None of the Above
| | Kavya Saxena answered |
original number – 10x + y
(10x + y) – (10y + x) = 27
9(x – y) = 27
x – y = 3
All the given options not follow the condition.
(10x + y) – (10y + x) = 27
9(x – y) = 27
x – y = 3
All the given options not follow the condition.
If 1x5x01 is divisible by 11, then the value of x is- a)6
- b)4
- c)8
- d)9
Correct answer is option 'C'. Can you explain this answer?
If 1x5x01 is divisible by 11, then the value of x is
a)
6
b)
4
c)
8
d)
9
 | Learnpro Institute answered |
When a number is divisible by 11, then sum of numbers at even place - sum of numbers at odd place = 0 or divisible by 11.
( x + x + 1 ) - ( 1+ 5 + 0 ) = 11
⇒ 2x - 5 = 11
∴ x = 8
( x + x + 1 ) - ( 1+ 5 + 0 ) = 11
⇒ 2x - 5 = 11
∴ x = 8
The sum of 4 consecutive even number is 284. What would be the smallest number ?- a)72
- b)74
- c)68
- d)66
Correct answer is option 'C'. Can you explain this answer?
The sum of 4 consecutive even number is 284. What would be the smallest number ?
a)
72
b)
74
c)
68
d)
66
 | Arnav Saini answered |
Understanding the Problem
To find the smallest of four consecutive even numbers that sum up to 284, we first define the numbers.
Defining the Numbers
Let:
- The first even number be x.
- The second even number be x + 2.
- The third even number be x + 4.
- The fourth even number be x + 6.
Setting Up the Equation
The sum of these four numbers can be expressed as:
- x + (x + 2) + (x + 4) + (x + 6) = 284.
Combining the terms, we get:
- 4x + 12 = 284.
Solving the Equation
To find x:
- Subtract 12 from both sides:
- 4x = 284 - 12
- 4x = 272.
- Divide both sides by 4:
- x = 272 / 4
- x = 68.
Conclusion
The smallest of the four consecutive even numbers is x, which is 68.
Checking the Numbers
To ensure accuracy:
- The numbers are:
- 68 (first number)
- 70 (second number)
- 72 (third number)
- 74 (fourth number).
- Their sum is:
- 68 + 70 + 72 + 74 = 284.
Thus, the smallest number is indeed 68, confirming option 'C'.
To find the smallest of four consecutive even numbers that sum up to 284, we first define the numbers.
Defining the Numbers
Let:
- The first even number be x.
- The second even number be x + 2.
- The third even number be x + 4.
- The fourth even number be x + 6.
Setting Up the Equation
The sum of these four numbers can be expressed as:
- x + (x + 2) + (x + 4) + (x + 6) = 284.
Combining the terms, we get:
- 4x + 12 = 284.
Solving the Equation
To find x:
- Subtract 12 from both sides:
- 4x = 284 - 12
- 4x = 272.
- Divide both sides by 4:
- x = 272 / 4
- x = 68.
Conclusion
The smallest of the four consecutive even numbers is x, which is 68.
Checking the Numbers
To ensure accuracy:
- The numbers are:
- 68 (first number)
- 70 (second number)
- 72 (third number)
- 74 (fourth number).
- Their sum is:
- 68 + 70 + 72 + 74 = 284.
Thus, the smallest number is indeed 68, confirming option 'C'.
If the number 10*47* is divisible by both 5 and 11, then the missing digits are respectively- a)1 and 5
- b)6 and 0
- c)5 and 0
- d)2 and 5
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
If the number 10*47* is divisible by both 5 and 11, then the missing digits are respectively
a)
1 and 5
b)
6 and 0
c)
5 and 0
d)
2 and 5
e)
None of these
| | Cstoppers Instructors answered |
Check the options in the number 10x47y
all numbers will be divisible by 5 because in end it is 5 and 0
for number to be divisible by 11, (y+4+0) – (7+x+1) should be divisible by 11
from option A, y = 5, x = 1 gives (y+4+0) – (7+x+1) as 0 which is divisible by 11
all numbers will be divisible by 5 because in end it is 5 and 0
for number to be divisible by 11, (y+4+0) – (7+x+1) should be divisible by 11
from option A, y = 5, x = 1 gives (y+4+0) – (7+x+1) as 0 which is divisible by 11
When a number is multiplied by 13 and 13 is added to the product, the resultant is divisible by 5. Find the smallest product possible?- a)85
- b)130
- c)65
- d)90
- e)105
Correct answer is option 'C'. Can you explain this answer?
When a number is multiplied by 13 and 13 is added to the product, the resultant is divisible by 5. Find the smallest product possible?
a)
85
b)
130
c)
65
d)
90
e)
105
| | Alok Verma answered |
13x + 13 which is divisible by 5, or 13(x+1) should be divisible by 5. The smallest value of x = 4 to be put here to make it divisible by 5. So the number is 13(4+1)
The number of prime numbers between 0 and 50 is- a)13
- b)14
- c)15
- d)16
Correct answer is option 'C'. Can you explain this answer?
The number of prime numbers between 0 and 50 is
a)
13
b)
14
c)
15
d)
16
| | Ssc Cgl answered |
prime numbers between 0 and 50 are 2 3 5 7 11 13 17 19 23 29 31 37 41 43 and 47
∴ required number of prime number is 15
∴ required number of prime number is 15
A number when divided by 5 leaves a remainder 4. What is the remainder when the square of the same number is divided by 5?- a)1
- b)2
- c)4
- d)3
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
A number when divided by 5 leaves a remainder 4. What is the remainder when the square of the same number is divided by 5?
a)
1
b)
2
c)
4
d)
3
e)
None of these
| | Preeti Khanna answered |
Le the number be 5a + 4
square of the number = 25a2 + 16 + 40a
so remainder = 1 (16 divided by 5 leaves a remainder 1)
square of the number = 25a2 + 16 + 40a
so remainder = 1 (16 divided by 5 leaves a remainder 1)
Kavya attends 40 questions and get 96 marks. If 3 marks are given for each correct answer and 1 mark is deducted for each wrong answer, find the number of question she attended correct?- a)15
- b)34
- c)32
- d)36
- e)33
Correct answer is option 'B'. Can you explain this answer?
Kavya attends 40 questions and get 96 marks. If 3 marks are given for each correct answer and 1 mark is deducted for each wrong answer, find the number of question she attended correct?
a)
15
b)
34
c)
32
d)
36
e)
33
 | Faizan Khan answered |
Let she attend x correct answers out of 40, then incorrect = 40-x
So x*3 – (40-x)*1 = 96
Solve, x = 34
So x*3 – (40-x)*1 = 96
Solve, x = 34
When a number is divided by 527 gives the remainder as 21. When the same number is divided by 17, the remainder will be?- a)2
- b)3
- c)4
- d)7
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
When a number is divided by 527 gives the remainder as 21. When the same number is divided by 17, the remainder will be?
a)
2
b)
3
c)
4
d)
7
e)
None of these
| | Anaya Patel answered |
Let the number be 527a + 21
when divided by 17, 527a is divisible by 17 and leaves remainder as 4 when 21 is divided by 17
when divided by 17, 527a is divisible by 17 and leaves remainder as 4 when 21 is divided by 17
The sum of the digits of a two-digit number is 6. If the digits are reversed, the number is decreased by 36. Find the number?- a)15
- b)51
- c)24
- d)42
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
The sum of the digits of a two-digit number is 6. If the digits are reversed, the number is decreased by 36. Find the number?
a)
15
b)
51
c)
24
d)
42
e)
None of these
| | Aarav Sharma answered |
Solution:
Let the tens digit be x and the units digit be y.
Given, x+y=6
Also, on reversing the digits, the new number becomes 10y + x, which is 36 less than the original number.
Therefore, the equation becomes 10x + y = 10y + x - 36
Simplifying this equation, we get 9x - 9y = 36
Dividing both sides by 9, we get x - y = 4
Now we have two equations with two variables, which can be solved simultaneously to obtain the values of x and y.
x + y = 6
x - y = 4
Adding both the equations, we get:
2x = 10
x = 5
Substituting the value of x in any one of the equations, we get:
y = 1
Therefore, the required number is 51, which is option B.
Let the tens digit be x and the units digit be y.
Given, x+y=6
Also, on reversing the digits, the new number becomes 10y + x, which is 36 less than the original number.
Therefore, the equation becomes 10x + y = 10y + x - 36
Simplifying this equation, we get 9x - 9y = 36
Dividing both sides by 9, we get x - y = 4
Now we have two equations with two variables, which can be solved simultaneously to obtain the values of x and y.
x + y = 6
x - y = 4
Adding both the equations, we get:
2x = 10
x = 5
Substituting the value of x in any one of the equations, we get:
y = 1
Therefore, the required number is 51, which is option B.
Find the sum of first 84 even numbers- a)7140
- b)7540
- c)6720
- d)8832
Correct answer is option 'A'. Can you explain this answer?
Find the sum of first 84 even numbers
a)
7140
b)
7540
c)
6720
d)
8832
| | Ssc Cgl answered |
Sum of first n even numbers = n( n +1 )
Given n = 84
∴ Required sum = 84 ( 84 + 1 )
= 84 x 85
= 7140
Given n = 84
∴ Required sum = 84 ( 84 + 1 )
= 84 x 85
= 7140
How many numbers between -11 and 11 are multiple of 2 or 3- a)11
- b)12
- c)15
- d)None of these
Correct answer is option 'C'. Can you explain this answer?
How many numbers between -11 and 11 are multiple of 2 or 3
a)
11
b)
12
c)
15
d)
None of these
 | EduRev SSC CGL answered |
Number between 0 and 11 which are multiple of 2 or 3
= 11/2 + 11/3 - 11/6 = 5 + 3 - 1
= 7
Number between 0 and -11 which are multiple of 2 or 3
= 11/2 + 11/3 - 11/6 = 5 + 3 - 1
= 7
∴ Number be 15, including 0
= 11/2 + 11/3 - 11/6 = 5 + 3 - 1
= 7
Number between 0 and -11 which are multiple of 2 or 3
= 11/2 + 11/3 - 11/6 = 5 + 3 - 1
= 7
∴ Number be 15, including 0
The ratio between a two-digit number and the sum of the digits of that number is 3:1. If the digit in the unit’s place is 5 more than digit at ten’s place, what is the number?- a)17
- b)27
- c)36
- d)34
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
The ratio between a two-digit number and the sum of the digits of that number is 3:1. If the digit in the unit’s place is 5 more than digit at ten’s place, what is the number?
a)
17
b)
27
c)
36
d)
34
e)
None of these
| | Kavya Saxena answered |
Let the two-digit number be 10a + b
(10a + b)/(a+b) = 3/1, 7a = 2b
And also given b = 5 + a
7a = 2(5+a)
7a =10 + 2a
5a = 10
a = 2
b = 5 + a
b = 5 + 2
b = 7
so number 10a + b = 10x2 + 7 = 27
Solve both equations to get the number
(10a + b)/(a+b) = 3/1, 7a = 2b
And also given b = 5 + a
7a = 2(5+a)
7a =10 + 2a
5a = 10
a = 2
b = 5 + a
b = 5 + 2
b = 7
so number 10a + b = 10x2 + 7 = 27
Solve both equations to get the number
If N, N + 2, and N + 4 are prime numbers, then the number of possible solutions for N are- a)1
- b)2
- c)3
- d)None of these
Correct answer is option 'A'. Can you explain this answer?
If N, N + 2, and N + 4 are prime numbers, then the number of possible solutions for N are
a)
1
b)
2
c)
3
d)
None of these
| | EduRev SSC CGL answered |
When N is a natural number, then there is only one possible case that N, N + 2, N + 4 are prime numbers.
When N = 3, then N, N + 2, N + 4 = 3, 5, 7 all are primes.
When N = 3, then N, N + 2, N + 4 = 3, 5, 7 all are primes.
195 + 215 is divisible by- a)Only 10
- b)Only 20
- c)Both 10 and 20
- d)Neither 10 nor 20
Correct answer is option 'C'. Can you explain this answer?
195 + 215 is divisible by
a)
Only 10
b)
Only 20
c)
Both 10 and 20
d)
Neither 10 nor 20
 | Iq Funda answered |
We can check divisibility of 195 + 215 by 10 by adding the unit digit of 95 + 15 which is equal to 9 + 1 = 10.
So it must be divisible by 10.
Now, for divisibility by 20 we add 19 and 21 which is equal to 40. So, it is clear that it is also divisible by 20.
So 195 + 215 is divisible by both 10 and 20
So it must be divisible by 10.
Now, for divisibility by 20 we add 19 and 21 which is equal to 40. So, it is clear that it is also divisible by 20.
So 195 + 215 is divisible by both 10 and 20
How many rational numbers are there between 1 and 1000 ?- a)998
- b)999
- c)1000
- d)infinite
Correct answer is option 'D'. Can you explain this answer?
How many rational numbers are there between 1 and 1000 ?
a)
998
b)
999
c)
1000
d)
infinite
| | EduRev SSC CGL answered |
There can be infinite number of rational numbers between 1 and 1000.
The sum of the digits of a two digit number is 10, when the number is reversed, the number increases by 72.Find the number.- a)64
- b)82
- c)19
- d)37
Correct answer is option 'C'. Can you explain this answer?
The sum of the digits of a two digit number is 10, when the number is reversed, the number increases by 72.Find the number.
a)
64
b)
82
c)
19
d)
37
| | Ssc Cgl answered |
By checking options
91-19=72
Or
Let the number be xy
So 10x + y = 10 ..... (i)
When the number is reversed the new number is yx
So (10y + 10 ) - ( 10x +y ) = 72 ....(ii)
From Eqs. (i) & (ii)
x = 1 and y =9
∴number = 19
91-19=72
Or
Let the number be xy
So 10x + y = 10 ..... (i)
When the number is reversed the new number is yx
So (10y + 10 ) - ( 10x +y ) = 72 ....(ii)
From Eqs. (i) & (ii)
x = 1 and y =9
∴number = 19
Two different numbers are divided by the same divisor and left remainder 11 and 17 respectively and when their sum was divided by the same divisor, remainder was 4. What is the divisor?- a)20
- b)24
- c)25
- d)26
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
Two different numbers are divided by the same divisor and left remainder 11 and 17 respectively and when their sum was divided by the same divisor, remainder was 4. What is the divisor?
a)
20
b)
24
c)
25
d)
26
e)
None of these
 | Jatin Nambiar answered |
Let the divisor = D
so, first number = D*a + 11 and second number = D*b +17
so sum of numbers = D*(a + b) + 28
given that remainder is 4 so, the number is 24
so, first number = D*a + 11 and second number = D*b +17
so sum of numbers = D*(a + b) + 28
given that remainder is 4 so, the number is 24
Sum of first 15 multiple of 8 is- a)960
- b)660
- c)1200
- d)1060
Correct answer is option 'A'. Can you explain this answer?
Sum of first 15 multiple of 8 is
a)
960
b)
660
c)
1200
d)
1060
 | T.S Academy answered |
First 15 multiple of 8 are 8, 16, 24, ......, 120
Sum = 8 (1 + 2 + 3 + 4 ......+ 15)
= 8 [ n(n + 1) / 2]
= 8 x 15 x 8
960
Sum = 8 (1 + 2 + 3 + 4 ......+ 15)
= 8 [ n(n + 1) / 2]
= 8 x 15 x 8
960
Find the least number which must be subtracted from 103876 to make the obtained number divisible by 16.- a)5
- b)4
- c)3
- d)7
- e)9
Correct answer is option 'B'. Can you explain this answer?
Find the least number which must be subtracted from 103876 to make the obtained number divisible by 16.
a)
5
b)
4
c)
3
d)
7
e)
9
| | Target Study Academy answered |
- Divide 103876 by 16.
- The quotient is 6492 with a remainder of 4.
- To make 103876 divisible by 16, subtract the remainder.
- Therefore, subtract 4 from 103876.
- The resulting number, 103872, is divisible by 16.
Answer: b) 4
- The quotient is 6492 with a remainder of 4.
- To make 103876 divisible by 16, subtract the remainder.
- Therefore, subtract 4 from 103876.
- The resulting number, 103872, is divisible by 16.
Answer: b) 4
If the places of last two-digits of a three digit number are interchanged, a new number greater than the original number by 36 is obtained. What is the difference between the last two digits of that number?- a)2
- b)3
- c)4
- d)7
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
If the places of last two-digits of a three digit number are interchanged, a new number greater than the original number by 36 is obtained. What is the difference between the last two digits of that number?
a)
2
b)
3
c)
4
d)
7
e)
None of these
| | Anaya Patel answered |
let the number be 100a + 10b + c
(100a + 10b +c) – (100a + 10c +b) = 36
b – c = 4
(100a + 10b +c) – (100a + 10c +b) = 36
b – c = 4
The difference between two numbers is 2577. The quotient and remainder are respectively 26 and 2 when the larger number is divided by the smaller one. What is the largest number?- a)2594
- b)2680
- c)2851
- d)2654
- e)2632
Correct answer is option 'B'. Can you explain this answer?
The difference between two numbers is 2577. The quotient and remainder are respectively 26 and 2 when the larger number is divided by the smaller one. What is the largest number?
a)
2594
b)
2680
c)
2851
d)
2654
e)
2632
| | Kavya Saxena answered |
Smaller no = x, then larger = x+2577
Now x+2577 = 26x + 2
Solve, x = 103
So larger no is = 103+2577
Now x+2577 = 26x + 2
Solve, x = 103
So larger no is = 103+2577
Find the product of place value and face value of 5 in 65231- a)28000
- b)25000
- c)27000
- d)26000
Correct answer is option 'B'. Can you explain this answer?
Find the product of place value and face value of 5 in 65231
a)
28000
b)
25000
c)
27000
d)
26000
 | Ishaan Roy answered |
Understanding Face Value and Place Value
To find the product of the place value and face value of the digit 5 in the number 65231, we need to clarify two concepts: face value and place value.
Face Value
- The face value of a digit is the digit itself, irrespective of its position in the number.
- For the digit 5 in 65231, the face value is 5.
Place Value
- The place value of a digit depends on its position in the number.
- In 65231, the digit 5 is in the thousands place.
- Therefore, its place value is calculated as:
5 (digit) x 1000 (place value of thousands) = 5000.
Calculating the Product
- Now, we need to find the product of the place value and face value of 5:
Place Value = 5000
Face Value = 5
- Product = Place Value x Face Value
Product = 5000 x 5 = 25000.
Conclusion
- The correct answer is indeed option B: 25000.
This answer is confirmed through a straightforward application of the definitions of face value and place value, leading to a clear and concise calculation.
To find the product of the place value and face value of the digit 5 in the number 65231, we need to clarify two concepts: face value and place value.
Face Value
- The face value of a digit is the digit itself, irrespective of its position in the number.
- For the digit 5 in 65231, the face value is 5.
Place Value
- The place value of a digit depends on its position in the number.
- In 65231, the digit 5 is in the thousands place.
- Therefore, its place value is calculated as:
5 (digit) x 1000 (place value of thousands) = 5000.
Calculating the Product
- Now, we need to find the product of the place value and face value of 5:
Place Value = 5000
Face Value = 5
- Product = Place Value x Face Value
Product = 5000 x 5 = 25000.
Conclusion
- The correct answer is indeed option B: 25000.
This answer is confirmed through a straightforward application of the definitions of face value and place value, leading to a clear and concise calculation.
The sum of the digits of two-digit number is 14 and the difference between the two digits number is 2. What is the product of the two digits of the two-digit number ?- a)56
- b)48
- c)45
- d)None of the above
Correct answer is option 'B'. Can you explain this answer?
The sum of the digits of two-digit number is 14 and the difference between the two digits number is 2. What is the product of the two digits of the two-digit number ?
a)
56
b)
48
c)
45
d)
None of the above
| | Ssc Cgl answered |
Let be the ten's digit be x and unit's digit be y.
So the two digit number = 10x + y ( where x > y )
According to question
x + y = 14 ....(i)
x - y = 2 ....(ii)
So the two digit number = 10x + y ( where x > y )
According to question
x + y = 14 ....(i)
x - y = 2 ....(ii)
Solving Eqs. (i) and (ii), we get
x = 8 and y = 6
∴ Required product = 8 x 6 = 48
x = 8 and y = 6
∴ Required product = 8 x 6 = 48
What will be remainder when 19100 is divided by 20 ?- a)19
- b)29
- c)3
- d)1
Correct answer is option 'D'. Can you explain this answer?
What will be remainder when 19100 is divided by 20 ?
a)
19
b)
29
c)
3
d)
1
| | Ssc Cgl answered |
19100 = ( 20 -1 )100
⇒ ( -1 )100 / 20
⇒ 1 / 20
∴ Required Remainder = 1
⇒ ( -1 )100 / 20
⇒ 1 / 20
∴ Required Remainder = 1
How many numbers are there up to 1000 which are divisible by 4, 6 and 8 together?- a)39
- b)40
- c)41
- d)42
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
How many numbers are there up to 1000 which are divisible by 4, 6 and 8 together?
a)
39
b)
40
c)
41
d)
42
e)
None of these
| | Rhea Reddy answered |
LCM of 4,6 and 8 is 24
Divide 1000 by 24, we get quotient = 41 and 16 as remainder
so 41 numbers are there which are divisible by 4,6 and 8 together.
Divide 1000 by 24, we get quotient = 41 and 16 as remainder
so 41 numbers are there which are divisible by 4,6 and 8 together.
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