All questions of Clock and Calendar for SSC CGL Exam
Calculating the Clock's Loss:
To determine how much a clock loses per day when its hands coincide every 64 minutes, we need to calculate the time gained by the clock in 64 minutes when it should show 65 minutes.
Calculating the Time Gained:
In 64 minutes, the clock loses 1 minute. So, in 1 minute, it loses 1/64 minutes.
Therefore, in 24 hours (1440 minutes), the clock will lose 1440/64 = 22.5 minutes.
Converting Minutes to Hours:
To convert 22.5 minutes to hours, we divide by 60 (since 1 hour = 60 minutes).
22.5 minutes = 22.5/60 = 45/120 = 3/8 hours.
Expressing the Loss in Fraction Form:
So, the clock loses 3/8 hours per day.
Converting the Fraction to a Decimal:
To express this as a decimal, we divide 3 by 8:
3 ÷ 8 = 0.375
Converting the Decimal to a Rational Number:
The decimal 0.375 can be expressed as a rational number:
0.375 = 375/1000 = 3/8
Therefore, the clock loses 3/8 hours per day, which is equivalent to 256/11 minutes.
Conclusion:
Thus, the clock loses 256/11 minutes per day when its hands coincide every 64 minutes. The correct answer is option 'A' (256/11).
Total hours from Monday 10.00 AM to Friday 3.00 PM =101 Hours.
The clock loses 6 minutes every hour. In 101 hours it will lose 101 x 6 =606 minutes. i.e. 10 hours 06 minutes.
To find the actual time, calculate 10 hours 6 min backwards from Friday 3.00 PM which is 4 .54 AM
Hence, the actual time would be 4 .54 AM when clock shows 3.00 PM on Friday.
An hours + C hours = B hours … (I)
A, C and B can’t possess values greater than or equal to 24 B minutes + A minutes = C minutes … (ii)
From the above two equations, it is assumed that no value of A satisfies both the equations.
Hence, option 1 is the correct answer.
Understanding Calendar Year Repeats
When determining which future year has the same calendar as 2007, we need to consider two key factors: the day of the week for January 1st and whether or not the year is a leap year.
Days of the Week and Leap Years
- 2007 is a common year: It has 365 days.
- January 1, 2007, was a Monday.
To find the next years with the same starting day and leap year status, we can analyze the following years:
Calculating Subsequent Years
1. 2014:
- Days from 2007 to 2014 = 7 years (2008 is a leap year).
- Total additional days = 5 (common years) + 2 (leap years) = 7 days.
- January 1, 2014, is a Wednesday (not the same).
2. 2016:
- Days from 2007 to 2016 = 9 years (2008 and 2012 are leap years).
- Total additional days = 7 (common years) + 2 (leap years) = 9 days.
- January 1, 2016, is a Friday (not the same).
3. 2017:
- Days from 2007 to 2017 = 10 years (2008 and 2012 are leap years).
- Total additional days = 8 (common years) + 2 (leap years) = 10 days.
- January 1, 2017, is a Sunday (not the same).
4. 2018:
- Days from 2007 to 2018 = 11 years (2008 and 2012 are leap years).
- Total additional days = 9 (common years) + 2 (leap years) = 11 days.
- January 1, 2018, is a Monday (same as 2007).
Conclusion
The calendar for the year 2007 will be the same for the year 2018 because both years start on the same day of the week and share the same leap year status. Thus, the correct answer is option D: 2018.