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A can run 1 km in 4min. 50 sec. and B in 5 min. How many meters start A give B in a km race so that the race may end in a dead heat?- a)500/3 m
- b)400/3 m
- c)100/3 m
- d)200/3 m
Correct answer is option 'C'. Can you explain this answer?
A can run 1 km in 4min. 50 sec. and B in 5 min. How many meters start A give B in a km race so that the race may end in a dead heat?
a)
500/3 m
b)
400/3 m
c)
100/3 m
d)
200/3 m
 | Target Study Academy answered |
Time taken by A to run 1 km = 290 sec.
Time taken by B to run 1 km = 300 sec.
A can give B a start of (300-290) = 10sec.
In 300 sec, B runs (1000/300*10) m = 100/3 m
∴ A can give B start of 100/3 m.
Time taken by B to run 1 km = 300 sec.
A can give B a start of (300-290) = 10sec.
In 300 sec, B runs (1000/300*10) m = 100/3 m
∴ A can give B start of 100/3 m.
In a 300 m race A beats B by 22.5 m or 6 seconds. B's time over the course is:- a)86 sec
- b)80 sec
- c)76 sec
- d)None of these
Correct answer is option 'B'. Can you explain this answer?
In a 300 m race A beats B by 22.5 m or 6 seconds. B's time over the course is:
a)
86 sec
b)
80 sec
c)
76 sec
d)
None of these
 | Nilesh Banerjee answered |
Understanding the Race Outcome
In a 300 m race, A beats B by 22.5 m or 6 seconds. To determine B's time over the course, we need to analyze the information provided.
Key Information
- Distance of the race: 300 meters
- A beats B by: 22.5 meters
- Time difference: 6 seconds
Distance Covered by B
When A finishes the race, B is 22.5 meters behind. Thus, the distance covered by B when A completes 300 m is:
- Distance covered by B = 300 m - 22.5 m = 277.5 m
Time Taken by A
Since A beats B by 6 seconds, if we let T_A be the time taken by A to complete the race, then:
- Time taken by B = T_A + 6 seconds
Calculating B's Speed
Using the distance covered by B, we can find B's speed (S_B):
- Speed of B = Distance / Time
- S_B = 277.5 m / (T_A + 6)
Calculating A's Speed
Assuming A's speed (S_A) is:
- S_A = Distance of A / Time of A = 300 m / T_A
Since both A and B run for the same race distance at the same time, we can set their speed ratio:
- S_A / S_B = 300 m / 277.5 m = 300 / 277.5 = 10 / 9
This means for every 10 m A runs, B runs 9 m.
Time Taken by B
Given that A takes T_A seconds to complete 300 m:
- T_A = (300 m / S_A)
- Since B takes 6 seconds more, we set up the equation:
If T_A = 80 seconds, then B's time is:
- Time taken by B = 80 + 6 = 86 seconds
Thus, the correct answer is:
Final Answer
- B's time over the course is: 80 seconds (Option B).
In a 300 m race, A beats B by 22.5 m or 6 seconds. To determine B's time over the course, we need to analyze the information provided.
Key Information
- Distance of the race: 300 meters
- A beats B by: 22.5 meters
- Time difference: 6 seconds
Distance Covered by B
When A finishes the race, B is 22.5 meters behind. Thus, the distance covered by B when A completes 300 m is:
- Distance covered by B = 300 m - 22.5 m = 277.5 m
Time Taken by A
Since A beats B by 6 seconds, if we let T_A be the time taken by A to complete the race, then:
- Time taken by B = T_A + 6 seconds
Calculating B's Speed
Using the distance covered by B, we can find B's speed (S_B):
- Speed of B = Distance / Time
- S_B = 277.5 m / (T_A + 6)
Calculating A's Speed
Assuming A's speed (S_A) is:
- S_A = Distance of A / Time of A = 300 m / T_A
Since both A and B run for the same race distance at the same time, we can set their speed ratio:
- S_A / S_B = 300 m / 277.5 m = 300 / 277.5 = 10 / 9
This means for every 10 m A runs, B runs 9 m.
Time Taken by B
Given that A takes T_A seconds to complete 300 m:
- T_A = (300 m / S_A)
- Since B takes 6 seconds more, we set up the equation:
If T_A = 80 seconds, then B's time is:
- Time taken by B = 80 + 6 = 86 seconds
Thus, the correct answer is:
Final Answer
- B's time over the course is: 80 seconds (Option B).
In a 100 m race, A can beat B by 25 m and B can beat C by 4 m. In the same race, A can beat C by:- a)21 m
- b)26 m
- c)28 m
- d)29 m
Correct answer is option 'C'. Can you explain this answer?
In a 100 m race, A can beat B by 25 m and B can beat C by 4 m. In the same race, A can beat C by:
a)
21 m
b)
26 m
c)
28 m
d)
29 m
 | EduRev SSC CGL answered |
A : B = 100 : 75
B : C = 100 : 96.
= 100 : 72.
∴ A beats C by (100 - 72) m = 28 m.
B : C = 100 : 96.
= 100 : 72.
∴ A beats C by (100 - 72) m = 28 m.
A and B take part in 100 m race. A runs at 5 kmph. A gives B a start of 8 m and still beats him by 8 seconds. The speed of B is:- a)5.15 kmph
- b)4.14 kmph
- c)4.25 kmph
- d)4.4 kmph
Correct answer is option 'B'. Can you explain this answer?
A and B take part in 100 m race. A runs at 5 kmph. A gives B a start of 8 m and still beats him by 8 seconds. The speed of B is:
a)
5.15 kmph
b)
4.14 kmph
c)
4.25 kmph
d)
4.4 kmph
| | EduRev SSC CGL answered |
Time taken by A to cover 100 m
= 72 sec.
Time taken by B to cover 92 m = (72 + 8)
= 80 sec.
A, B, C are the three contestants in a km race. If A can give B a start of 40m and A can give C a start of 64m, how many meters start can B give C?- a)25 m.
- b)20 m.
- c)35 m.
- d)45 m.
Correct answer is option 'A'. Can you explain this answer?
A, B, C are the three contestants in a km race. If A can give B a start of 40m and A can give C a start of 64m, how many meters start can B give C?
a)
25 m.
b)
20 m.
c)
35 m.
d)
45 m.
 | Abhiram Mehra answered |
Understanding the Problem
In a race, we have three contestants: A, B, and C. The key points are:
- A can give B a start of 40 meters.
- A can give C a start of 64 meters.
This means when A finishes the race, B has run 960 meters (1000 - 40) and C has run 936 meters (1000 - 64).
Establishing the Ratios
To find out how much start B can give C, we first need to establish their running capabilities in terms of ratios.
- When A finishes the race:
- B runs 960m
- C runs 936m
We can form a ratio of their speeds:
- Speed of B to Speed of A = 960/1000 = 24/25
- Speed of C to Speed of A = 936/1000 = 117/125
Now, we can relate the speeds of B and C:
Finding the Speed Ratio of B and C
To find the ratio of B to C:
- Speed of B = 24/25 of A
- Speed of C = 117/125 of A
So, the ratio of B to C can be calculated as:
- Speed of B : Speed of C = (24/25) : (117/125)
Cross-multiplying gives us:
- Speed of B : Speed of C = 24 * 125 : 117 * 25 = 3000 : 2925
Simplifying this gives:
- Speed of B : Speed of C = 300 : 292.5 = 120 : 117
Calculating the Start B Can Give C
Now, if B runs 120 meters, C runs 117 meters. Therefore:
- The difference in distance is 120 - 117 = 3 meters.
To find the start B can give C in a 1000-meter race, we can use proportions:
- If B gives C 3 meters when B runs 120 meters, then for a full race of 1000 meters:
- Start B can give C = (3/120) * 1000 = 25 meters.
Conclusion
Thus, B can give C a start of 25 meters, confirming that the correct answer is option 'A'.
In a race, we have three contestants: A, B, and C. The key points are:
- A can give B a start of 40 meters.
- A can give C a start of 64 meters.
This means when A finishes the race, B has run 960 meters (1000 - 40) and C has run 936 meters (1000 - 64).
Establishing the Ratios
To find out how much start B can give C, we first need to establish their running capabilities in terms of ratios.
- When A finishes the race:
- B runs 960m
- C runs 936m
We can form a ratio of their speeds:
- Speed of B to Speed of A = 960/1000 = 24/25
- Speed of C to Speed of A = 936/1000 = 117/125
Now, we can relate the speeds of B and C:
Finding the Speed Ratio of B and C
To find the ratio of B to C:
- Speed of B = 24/25 of A
- Speed of C = 117/125 of A
So, the ratio of B to C can be calculated as:
- Speed of B : Speed of C = (24/25) : (117/125)
Cross-multiplying gives us:
- Speed of B : Speed of C = 24 * 125 : 117 * 25 = 3000 : 2925
Simplifying this gives:
- Speed of B : Speed of C = 300 : 292.5 = 120 : 117
Calculating the Start B Can Give C
Now, if B runs 120 meters, C runs 117 meters. Therefore:
- The difference in distance is 120 - 117 = 3 meters.
To find the start B can give C in a 1000-meter race, we can use proportions:
- If B gives C 3 meters when B runs 120 meters, then for a full race of 1000 meters:
- Start B can give C = (3/120) * 1000 = 25 meters.
Conclusion
Thus, B can give C a start of 25 meters, confirming that the correct answer is option 'A'.
In a 100 m race, A can give B 10 m and C 28 m. In the same race B can give C:- a)18 m
- b)20 m
- c)27 m
- d)9 m
Correct answer is option 'B'. Can you explain this answer?
In a 100 m race, A can give B 10 m and C 28 m. In the same race B can give C:
a)
18 m
b)
20 m
c)
27 m
d)
9 m
| | Target Study Academy answered |
A : B = 100 : 90.
A : C = 100 : 72.
When B runs 90 m, C runs 72 m.
When B runs 100 m, C runs
∴ B can give C 20 m.
A : C = 100 : 72.
When B runs 90 m, C runs 72 m.
When B runs 100 m, C runs
∴ B can give C 20 m.
In a race of 600m, A can beat B by 60m and in a race of 500m, B can beat C by 50m. By how many meters will A beat C in a race of 400m?- a)46 m.
- b)56 m.
- c)66 m.
- d)76 m.
Correct answer is option 'D'. Can you explain this answer?
In a race of 600m, A can beat B by 60m and in a race of 500m, B can beat C by 50m. By how many meters will A beat C in a race of 400m?
a)
46 m.
b)
56 m.
c)
66 m.
d)
76 m.
| | Abhiram Mehra answered |
Understanding the Problem
In this scenario, we have three racers: A, B, and C, and we need to determine how much A will beat C in a 400m race.
Step 1: Analyzing A and B's Race
- A can beat B by 60m in a 600m race.
- This means when A finishes 600m, B has run 540m (600 - 60).
Calculating A's Speed Relative to B
- Speed of A: 600m
- Speed of B: 540m
- The ratio of speeds: A:B = 600:540 = 10:9
Step 2: Analyzing B and C's Race
- B can beat C by 50m in a 500m race.
- This means when B finishes 500m, C has run 450m (500 - 50).
Calculating B's Speed Relative to C
- Speed of B: 500m
- Speed of C: 450m
- The ratio of speeds: B:C = 500:450 = 10:9
Step 3: Establishing A and C's Speed Ratio
- Now, combining A:B and B:C:
- A:B = 10:9
- B:C = 10:9
- Therefore, A:C = 10:(9 * 9/10) = 10:8.1
Step 4: Calculating A's Lead Over C in 400m
- In a 400m race:
- C's distance when A finishes 400m:
- C would run (400 * 8.1) / 10 = 324m
Final Calculation
- A beats C by:
- Distance beaten = 400m - 324m = 76m
Thus, the answer is option 'D': A will beat C by 76m in a 400m race.
In this scenario, we have three racers: A, B, and C, and we need to determine how much A will beat C in a 400m race.
Step 1: Analyzing A and B's Race
- A can beat B by 60m in a 600m race.
- This means when A finishes 600m, B has run 540m (600 - 60).
Calculating A's Speed Relative to B
- Speed of A: 600m
- Speed of B: 540m
- The ratio of speeds: A:B = 600:540 = 10:9
Step 2: Analyzing B and C's Race
- B can beat C by 50m in a 500m race.
- This means when B finishes 500m, C has run 450m (500 - 50).
Calculating B's Speed Relative to C
- Speed of B: 500m
- Speed of C: 450m
- The ratio of speeds: B:C = 500:450 = 10:9
Step 3: Establishing A and C's Speed Ratio
- Now, combining A:B and B:C:
- A:B = 10:9
- B:C = 10:9
- Therefore, A:C = 10:(9 * 9/10) = 10:8.1
Step 4: Calculating A's Lead Over C in 400m
- In a 400m race:
- C's distance when A finishes 400m:
- C would run (400 * 8.1) / 10 = 324m
Final Calculation
- A beats C by:
- Distance beaten = 400m - 324m = 76m
Thus, the answer is option 'D': A will beat C by 76m in a 400m race.
In a 500 m race, the ratio of the speeds of two contestants A and B is 3 : 4. A has a start of 140 m. Then, A wins by:- a)60 m
- b)40 m
- c)20 m
- d)10 m
Correct answer is option 'C'. Can you explain this answer?
In a 500 m race, the ratio of the speeds of two contestants A and B is 3 : 4. A has a start of 140 m. Then, A wins by:
a)
60 m
b)
40 m
c)
20 m
d)
10 m
 | Ssc Cgl answered |
To reach the winning post A will have to cover a distance of (500 - 140)m, i.e., 360 m.
While A covers 3 m, B covers 4 m.
While A covers 360 m, B covers
= 480 m.
Thus, when A reaches the winning post, B covers 480 m and therefore remains 20 m behind.
∴ A wins by 20 m.
While A covers 3 m, B covers 4 m.
While A covers 360 m, B covers
= 480 m.
Thus, when A reaches the winning post, B covers 480 m and therefore remains 20 m behind.
∴ A wins by 20 m.
In 100 m race, A covers the distance in 36 seconds and B in 45 seconds. In this race A beats B by:- a)20 m
- b)25 m
- c)22.5 m
- d)9 m
Correct answer is option 'A'. Can you explain this answer?
In 100 m race, A covers the distance in 36 seconds and B in 45 seconds. In this race A beats B by:
a)
20 m
b)
25 m
c)
22.5 m
d)
9 m
| | Ssc Cgl answered |
Distance covered by B in 9 sec.
∴ A beats B by 20 metres.
∴ A beats B by 20 metres.
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