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All questions of Arithmetic Progressions for SSC CGL Exam
The d for the series of numbers -12, –6, 0, 6… is- a)–2
- b)6
- c)8
- d)-1
Correct answer is option 'B'. Can you explain this answer?
The d for the series of numbers -12, –6, 0, 6… is
a)
–2
b)
6
c)
8
d)
-1
 | Nilesh Banerjee answered |
Understanding the Series
The series given is -12, -6, 0, 6, ...
This series is an arithmetic progression (AP), where each term increases by a constant value, known as the common difference (d).
Identifying the Common Difference (d)
To find the common difference (d), we can subtract any term from the term that follows it.
- Start with the first two terms:
- -6 - (-12) = -6 + 12 = 6
- Now check the next two terms:
- 0 - (-6) = 0 + 6 = 6
- Finally, check the last two terms:
- 6 - 0 = 6
Conclusion
Since we consistently find that the difference between consecutive terms is 6, we can conclude that the common difference (d) for the series is:
Correct Answer: b) 6
This means that each term in the series increases by 6 from the previous term, confirming that the correct choice is option 'B'.
The series given is -12, -6, 0, 6, ...
This series is an arithmetic progression (AP), where each term increases by a constant value, known as the common difference (d).
Identifying the Common Difference (d)
To find the common difference (d), we can subtract any term from the term that follows it.
- Start with the first two terms:
- -6 - (-12) = -6 + 12 = 6
- Now check the next two terms:
- 0 - (-6) = 0 + 6 = 6
- Finally, check the last two terms:
- 6 - 0 = 6
Conclusion
Since we consistently find that the difference between consecutive terms is 6, we can conclude that the common difference (d) for the series is:
Correct Answer: b) 6
This means that each term in the series increases by 6 from the previous term, confirming that the correct choice is option 'B'.
a and a(2) are -3 and 4, find the a(21) of the series.- a)26
- b)95
- c)137
- d)-43
Correct answer is option 'C'. Can you explain this answer?
a and a(2) are -3 and 4, find the a(21) of the series.
a)
26
b)
95
c)
137
d)
-43
 | EduRev SSC CGL answered |
a = -3 and a(2) = 4
a = -3
d = 4 - a = 4 - (-3) = 7
a(21)=a + (21-1) x d
= -3 + (20) x 7
= -3 + 140
= 137
a = -3
d = 4 - a = 4 - (-3) = 7
a(21)=a + (21-1) x d
= -3 + (20) x 7
= -3 + 140
= 137
Find the sum of the first 5 terms of the AP: 10, 6, 2…- a)–320
- b)512
- c)10
- d)–960
Correct answer is option 'C'. Can you explain this answer?
Find the sum of the first 5 terms of the AP: 10, 6, 2…
a)
–320
b)
512
c)
10
d)
–960
 | Target Study Academy answered |
AP: 10, 6, 2, …
a = 10, d = - 4
Sum of first n terms = S(n) = (n/2) x [2a + (n – 1) x d]
S5 = (5/2) x [2 x (10) + (5 – 1) x (-4)]
= (5/2) x [20 + 4 x (-4)]
= (5/2) x (20 – 16)
= (5/2) x (4)
= 5 x 2
= 10
a = 10, d = - 4
Sum of first n terms = S(n) = (n/2) x [2a + (n – 1) x d]
S5 = (5/2) x [2 x (10) + (5 – 1) x (-4)]
= (5/2) x [20 + 4 x (-4)]
= (5/2) x (20 – 16)
= (5/2) x (4)
= 5 x 2
= 10
What will be the 99th term from the end of the AP 500, 489, 478, 467… – 1139?- a)1078
- b)1123
- c)12
- d)-61
Correct answer is option 'D'. Can you explain this answer?
What will be the 99th term from the end of the AP 500, 489, 478, 467… – 1139?
a)
1078
b)
1123
c)
12
d)
-61
 | Ssc Cgl answered |
In this case since we have to find the 99th term from the end.
We will consider the first term to be -1139 and the common difference will be 11
Now, a = -1139, d = 11 and n = 99
T99 = a + (n – 1)d
T99 = -1139 + (99 – 1)11
T99 = -1139 + 1078 = -61
The value of 99th term from the end is -61.
We will consider the first term to be -1139 and the common difference will be 11
Now, a = -1139, d = 11 and n = 99
T99 = a + (n – 1)d
T99 = -1139 + (99 – 1)11
T99 = -1139 + 1078 = -61
The value of 99th term from the end is -61.
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