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All questions of Triangles for Class 9 Exam

If two isosceles triangles have a common base, then the line joining their vertices will
  • a)
    Bisect them at acute angle
  • b)
    Bisect them at obtuse angle
  • c)
    Bisect them at right angle
  • d)
    NOT
Correct answer is option 'C'. Can you explain this answer?

Rajesh Yadav answered
Explanation:

To understand why the line joining the vertices of two isosceles triangles with a common base bisects them at a right angle, let's consider the properties of isosceles triangles.

Properties of Isosceles Triangles:
1. In an isosceles triangle, the two sides opposite the equal angles are of equal length.
2. The angles opposite the equal sides of an isosceles triangle are equal.

Given:
We have two isosceles triangles with a common base.

To Prove:
The line joining their vertices bisects the triangles at a right angle.

Proof:
Let's label the triangles as ABC and ABD, where AB is the common base and AC = BC and AD = BD.

Now, let's draw the line joining the vertices C and D.

Step 1:
Since AC = BC and AD = BD, we can conclude that triangles ABC and ABD are congruent by the Side-Side-Side (SSS) congruence criterion.

Step 2:
Using the congruence of the triangles, we can say that angle BAC is congruent to angle BAD and angle ABC is congruent to angle ABD.

Step 3:
Since angles BAC and BAD are congruent, and angles ABC and ABD are congruent, we can conclude that angle CAB is congruent to angle DAB.

Step 4:
When two angles are congruent, they are called vertically opposite angles. Vertically opposite angles are always equal.

Step 5:
Since angle CAB and angle DAB are vertically opposite angles and congruent, we can conclude that the line joining the vertices C and D bisects the triangles ABC and ABD at a right angle.

Hence, the correct answer is option 'C' - The line joining the vertices of two isosceles triangles with a common base bisects them at a right angle.

If one angle of the triangle is equal to the sum of the other two angles then the triangle is
  • a)
    Acute angled triangle
  • b)
    Isosceles/ equilateral triangle  
  • c)
    Obtuse angled triangle
  • d)
    Right angled triangle 
Correct answer is option 'D'. Can you explain this answer?

Nilofer Singh answered
Answer:

Explanation:
In a triangle, the sum of all angles is always 180 degrees. Let's assume the three angles of the triangle are A, B, and C.

Given:
One angle (let's assume A) is equal to the sum of the other two angles (B and C).

To prove:
The triangle is a right-angled triangle.

Proof:
Let's assume that angle A is equal to the sum of angles B and C.
So, A = B + C

Now, let's assume that the triangle is not a right-angled triangle. In this case, the sum of angles B and C would be less than 90 degrees (acute-angled triangle) or greater than 90 degrees (obtuse-angled triangle).

Case 1: Acute-angled triangle
If the sum of angles B and C is less than 90 degrees, it means that angle A (which is equal to B + C) would also be less than 90 degrees. However, this contradicts the given condition that angle A is equal to the sum of angles B and C. Therefore, an acute-angled triangle cannot satisfy the given condition.

Case 2: Obtuse-angled triangle
If the sum of angles B and C is greater than 90 degrees, it means that angle A (which is equal to B + C) would also be greater than 90 degrees. However, this again contradicts the given condition that angle A is equal to the sum of angles B and C. Therefore, an obtuse-angled triangle cannot satisfy the given condition.

Hence, the only possibility left is that the triangle is a right-angled triangle, where the sum of angles B and C is equal to 90 degrees. In this case, angle A (which is equal to B + C) would also be equal to 90 degrees.

Therefore, the correct answer is option 'D' - Right-angled triangle.

In a ΔABC,∠A = 50°, ∠B = 60°. The longest side of the triangle will be
  • a)
    AB
  • b)
    BC
  • c)
    CA
  • d)
    None of these 
Correct answer is option 'A'. Can you explain this answer?

Avani Shah answered
Understanding Triangle Properties
In triangle ABC, we are given the angles:
- Angle A = 50°
- Angle B = 60°
To determine the longest side, we need to utilize the property that states: the side opposite the largest angle is the longest side.
Calculating Angle C
First, we calculate the third angle (C) using the triangle angle sum property:
- Angle C = 180° - (Angle A + Angle B)
- Angle C = 180° - (50° + 60°) = 70°
Now we have all angles in triangle ABC:
- Angle A = 50°
- Angle B = 60°
- Angle C = 70°
Identifying the Longest Side
Next, we compare the angles to determine which is the largest:
- Angle A = 50°
- Angle B = 60°
- Angle C = 70° (Largest angle)
The side opposite the largest angle (Angle C) is side AB.
Conclusion
Since side AB is opposite the largest angle (70°), it is the longest side of triangle ABC.
Thus, the correct answer is:
- a) AB
This aligns with the triangle inequality property, confirming that side AB is indeed the longest side in triangle ABC.

Side QR of a triangle PQR is produced both ways and the measures of exterior angles formed are 86° and 124°. The measure of  ∠P is :
  • a)
    30°
  • b)
    40°
  • c)
    60°
  • d)
    80°
Correct answer is option 'A'. Can you explain this answer?

∠PQX and ∠PRY are exterior angles for ΔPQR

∴ ∠P + ∠PRY = 86° ...(i)
∠P + ∠PQX = 124° ...(ii)
Adding (i) and (ii)
 2∠P +∠PRX + ∠PQX = 210°
⇒∠P + (∠P +∠PRX + ∠PQX) = 210°
⇒ ∠P + 180° = 210°
⇒ ∠P = 30°

P is a point equidistant from two lines l and m intersecting at point A, then
  • a)
    ∠BAP = ∠APC
  • b)
    ∠CAP = ∠BPA
  • c)
    ∠CAP = ∠BAP
  • d)
    None of there 
Correct answer is option 'C'. Can you explain this answer?

In Δs ABP and ACP

PC = PB (Given)
∠ACP = ∠ABP = 90°
AP = AP (common)
∴ ΔABP ≅ ΔACP
(By R-H-S congruence criterion)
⇒ ∠BAP = ∠CAP (C.P.C.T)

In ΔABC, AB = AC, and the bisect are of angles B and C intersect at point O, then the ray AO
  • a)
    will bisect ∠A
  • b)
    will not bisect ∠A
  • c)
    AO = CO
  • d)
    AO = BO
Correct answer is option 'A'. Can you explain this answer?


∵ ∠B = ∠C

⇒ OB = OC ...(i)
(sides opposite to equal angles are equal)
Now,
In Δs ABO and ACO
AO = AO (common)
AB = AC (given)
OB = OC (From (i))
∴ ΔABO ≅ ΔACO
(By R-H-S congruence criterion)
∴ ∠BAO = ∠CAO = ∠A/2 (C.P.C.T)

The sum of all the exterior angles of a triangle is
  • a)
    180°
  • b)
    360°
  • c)
    540°
  • d)
    270°
Correct answer is option 'B'. Can you explain this answer?

 In ΔABC

∠ABC + ∠ACB +∠BAC = 180°
Now,
using exterior angle theorem 
∠ACB + ∠ABC = ∠BAP ...(i)
∠ABC + ∠BAC = ∠ACQ ...(ii)
∠ACB + ∠BAC = ∠ABR ...(iii)
Adding Eqns (i), (ii) and (iii), we get
2 (∠ABC + ∠BAC +∠ABC)
= ∠BAP + ∠ACQ + ∠ABR
⇒ Sum of all exterior angle = 2 × 180° = 360°

PQRS is a square and SRT is an equilateral triangle. The measure of ∠TQR is:
  • a)
    25°
  • b)
    55°
  • c)
    15°
  • d)
    35°
Correct answer is option 'C'. Can you explain this answer?

In ΔS PTS and QTR
(TR = TS = SR = PQ = QR = PS)
TR = TR (given)
PS = QR (given)
∠PST = ∠QRT
= 90°  +  60° = 150°
(Square)  (equilateral Δ)
∴ ΔPTS = ΔQTR
(By R-H-S congruence criterion)
TP = TQ (C.P.C.T)
∴ ∠TPS = ∠TQR (C.P.C.T)
Now,
In ΔTQR
TR = RQ
∴ ∠RTQ = ∠RQT, and
∠RTQ + ∠RQT +∠R = 180°
⇒ 2∠RQT + 90° + 60° = 180°

Find x in the given figure
  • a)
    120°
  • b)
    135°
  • c)
    150°
  • d)
    110°
Correct answer is option 'C'. Can you explain this answer?


Constructing a line PQ || BC,
∠APQ = ∠ABC = 55°
∵ ∠AQL is an exterior angle for DAPQ
∴ ∠APQ + 25° = a
⇒ a = 25° + 55° = 80°
b = 70° (Alternate opposite ∠s)
∴ x = a + b = 70° + 80° = 150°

AN is the bisector of ∠A and AM ⊥ BC. Then a measure of ∠MAN is:
  • a)
    35°
  • b)
    30°
  • c)
    20°
  • d)
    25°
Correct answer is option 'C'. Can you explain this answer?

Here ∠BAC = 180° -(75° +35°) = 70°

(∵ AN is the angle bisector of ∠A)
Now, in DANC,
∠ANC + ∠CAN + ∠NAC = 180°
⇒ ∠ANC +35° + 35° = 180°
⇒ ∠ANC = 110°
∵ ∠ANC is an exterior angle for ΔAMN 
∵ ∠ANC + ∠MAN = 110°
⇒ ∠MAN = 110°- ∠AMN 
= 110° - 90° = 20°

The value of x in the adjoining figure will be:
  • a)
    120°
  • b)
    90°
  • c)
    65°
  • d)
    80°
Correct answer is option 'A'. Can you explain this answer?

∵ ∠DBC is the exterior angle for ∠DAB
∴ ∠ADB + ∠DAB = ∠DBC
⇒ ∠DBC = 25° + 55° = 80° 
∵ ∠x is an exterior angle for ∠EBC
∴ ∠EBC +∠ECB = x
⇒ 80° +  40° = x
⇒ x = 120°

The value of  x from the adjoining figure will be:
  • a)
    41°
  • b)
    45°
  • c)
    42°
  • d)
    48°
Correct answer is option 'C'. Can you explain this answer?

∠ABC + ∠A = ∠ACD
⇒ ∠ACD = ∠ABC + 84°

⇒ ∠ECD = ∠EBC + 42° ...(i)
∵ ∠ECD is an exterior angle for ∠EBC
∴ ∠ECD =∠EBC = x ...(ii)
Comparing (i) and (ii), we get
x = 42°

If the length of three of the altitudes of a triangle are equal, then the triangle must be a/an
  • a)
    Isosceles triangle
  • b)
    Equilateral triangle
  • c)
    Scalene triangle
  • d)
    Right triangle
Correct answer is option 'B'. Can you explain this answer?

In Δs BEC and CFB

BC = BC (Common)
BE = CF (Given)
∠BEC = ∠CFB = 90°
∴ ΔBEC = ∠CFB = 90°
(By R-H-S congruence criterion)
∠B =∠C (C-P-C-T)
∴ AB = AC ...(i)
Similarly in Δs ADC and C + A 
⇒ ∠A = ∠C
∴ AB = BC ...(ii)
Using (i) and (ii) 
AB = BC = AC  (Δ should be equilateral)

AB and CD are parallel lines and transversal EF intersects them at P and Q respectively. If ∠APR = 25°, ∠RQC = 30° and ∠CQF = 65° then
  • a)
    p = 55°, q = 40°
  • b)
    p = 50°, q = 45°
  • c)
    p = 35°, q = 60°
  • d)
    p = 60°, q = 35°
Correct answer is option 'A'. Can you explain this answer?

∠APR + ∠CQF = 65°
(corresponding ∠s)
∠APR + ∠OPQ = 65°
⇒ 25° + Q = 65°
⇒ Q = 40°
∵ ∠OQF is on exterior angle for DPOQ
∴ q + DPOQ = 65° + 30°
⇒ p + q = 65°
⇒ p = 95° - 40° = 55°

ABC is an isosceles such that AB = AC and AD is the median to base BC. Then, ∠BAD =
  • a)
    40°
  • b)
    50°
  • c)
    60°
  • d)
    100°
Correct answer is option 'B'. Can you explain this answer?

In  Δs ABD and ACD,
AB = AC (Given)
AD = AD (Common)
BD = CD (∵ AC is median)
∴ ΔABD ≅ ΔACD
[By S-S-S congruence criterion]

In ΔABC, AC >AB and AD is the bisector of ∠A. Then 
  • a)
    ∠ADC < 2∠ADB
  • b)
    ∠ADC < ∠ADB
  • c)
    ∠ADC > ∠ADB
  • d)
    ∠ADC = ∠ADB
Correct answer is option 'C'. Can you explain this answer?

In ΔABC, A

∵ AC > AB
∴ ∠ABC = ∠ACB
⇒ - ∠ABC < -∠ACB
⇒ 180° - ∠ABC < 180° - ∠ACB
⇒ 180° - ∠ABC - x  < 180° - ∠ACB - x 
⇒ ∠ADB < ∠ADC.

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