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All questions of Capacity for Primary 2 Exam
Soni can cycle from point A to point B and return to point A in 10 minutes. She can cycle and walk back in 18 minutes. It will take ___ mins for her to walk there and walk back.- a)15 minutes
- b)26 minutes
- c)30 minutes
- d)36 minutes
Correct answer is option 'B'. Can you explain this answer?
Soni can cycle from point A to point B and return to point A in 10 minutes. She can cycle and walk back in 18 minutes. It will take ___ mins for her to walk there and walk back.
a)
15 minutes
b)
26 minutes
c)
30 minutes
d)
36 minutes
 | Priyanka Sharma answered |
Soni can cycle from point A to point B and return to point A in 10 minutes.
so for 1 round with cycle it would take 5 minutes
She can cycle and walk back in 18 minutes.
it would take 18 - 5 minutes to walk , so 13 minutes for walk
It will take 26 mins for her to walk there and walk back.
so for 1 round with cycle it would take 5 minutes
She can cycle and walk back in 18 minutes.
it would take 18 - 5 minutes to walk , so 13 minutes for walk
It will take 26 mins for her to walk there and walk back.
The postage for sending a parcel by foreign mail is Rs.136. What is the maximum possible weight of the parcel?- a)1.21 kg
- b)1.22 kg
- c)2.21 kg
- d)2.12 kg
Correct answer is option 'A'. Can you explain this answer?
The postage for sending a parcel by foreign mail is Rs.136. What is the maximum possible weight of the parcel?a)
1.21 kg
b)
1.22 kg
c)
2.21 kg
d)
2.12 kg
 | Rohini Seth answered |
The postage for sending a parcel by foreign mail is Rs.136.
The maximum weight of the parcel is 1.21kg
Tank A contains 6 times as much water as Tank B. How much water must Mohan transfer from Tank A to Tank B so that each tank contains 70 litres of water?- a)50 litres
- b)60 litres
- c)75 litres
- d)120 litres
Correct answer is option 'A'. Can you explain this answer?
Tank A contains 6 times as much water as Tank B. How much water must Mohan transfer from Tank A to Tank B so that each tank contains 70 litres of water?
a)
50 litres
b)
60 litres
c)
75 litres
d)
120 litres
 | Aditi Sharma answered |
Let quantity of water in tank B be x litres.
Then quantity of water in the tank A=6x litres
Total water in both the tanks =x+6x
=140 liters
⇒7x=140⇒x=20
∴ Water in tank B=20 litres
⇒ Water in tank A=20×6=120 litres
So, quantity of water to be transferred from tank A to tank B, so that each tank contains 70 litres= 70 −20=50 litres
Therefore, 50 liters of water should be transferred.
Then quantity of water in the tank A=6x litres
Total water in both the tanks =x+6x
=140 liters
⇒7x=140⇒x=20
∴ Water in tank B=20 litres
⇒ Water in tank A=20×6=120 litres
So, quantity of water to be transferred from tank A to tank B, so that each tank contains 70 litres= 70 −20=50 litres
Therefore, 50 liters of water should be transferred.
It takes 30 minutes to walk __________.- a)One gram
- b)One litre
- c)One metre
- d)One kg
Correct answer is option 'C'. Can you explain this answer?
It takes 30 minutes to walk __________.
a)
One gram
b)
One litre
c)
One metre
d)
One kg
| | Avinash Patel answered |
It takes 30 minutes to walk one meter.
Mrs. Reeta had 17.85 m of ribbon. She cut 11 smaller pieces each of length 0.45 m from it. How many metres of ribbon were left?- a)3.15 m
- b)12.90 m
- c)8.85 m
- d)17.5 m
Correct answer is option 'B'. Can you explain this answer?
Mrs. Reeta had 17.85 m of ribbon. She cut 11 smaller pieces each of length 0.45 m from it. How many metres of ribbon were left?
a)
3.15 m
b)
12.90 m
c)
8.85 m
d)
17.5 m
| | Manoj Desai answered |
To find out how many meters of ribbon were left, we need to subtract the total length of the smaller pieces cut from the original length of ribbon.
1. Calculate the total length of the smaller pieces:
- Mrs. Reeta cut 11 smaller pieces each of length 0.45 m.
- So, the total length of the smaller pieces = 11 * 0.45 = 4.95 m
2. Subtract the total length of the smaller pieces from the original length of ribbon:
- Original length of ribbon = 17.85 m
- Total length of smaller pieces = 4.95 m
- Remaining length of ribbon = Original length of ribbon - Total length of smaller pieces
= 17.85 m - 4.95 m
= 12.90 m
Therefore, there were 12.90 meters of ribbon left.
Hence, the correct answer is option B) 12.90 m.
1. Calculate the total length of the smaller pieces:
- Mrs. Reeta cut 11 smaller pieces each of length 0.45 m.
- So, the total length of the smaller pieces = 11 * 0.45 = 4.95 m
2. Subtract the total length of the smaller pieces from the original length of ribbon:
- Original length of ribbon = 17.85 m
- Total length of smaller pieces = 4.95 m
- Remaining length of ribbon = Original length of ribbon - Total length of smaller pieces
= 17.85 m - 4.95 m
= 12.90 m
Therefore, there were 12.90 meters of ribbon left.
Hence, the correct answer is option B) 12.90 m.
Kamal draws a quadrilateral with sides 4.6cm, 8.4cm, 7.3cm and 4.7cm. What is the perimeter of the quadrilateral?- a)26cm
- b)27.5cm
- c)25cm
- d)24cm
Correct answer is option 'C'. Can you explain this answer?
Kamal draws a quadrilateral with sides 4.6cm, 8.4cm, 7.3cm and 4.7cm. What is the perimeter of the quadrilateral?
a)
26cm
b)
27.5cm
c)
25cm
d)
24cm
 | Learning Education answered |
Perimeter of the quadrilateral = a + b + c + d
Perimeter of the quadrilateral = 4.6 + 8.4 + 7.3 + 4.7 = 25
Perimeter of the quadrilateral = 4.6 + 8.4 + 7.3 + 4.7 = 25
How many 
do you need to balance the last set-up? If 
- a)8
- b)7
- c)10
- d)6
Correct answer is option 'D'. Can you explain this answer?
How many do you need to balance the last set-up? If
do you need to balance the last set-up? If a)
8
b)
7
c)
10
d)
6
| | Priyanka Sharma answered |
Balls required will be 6
5 for balancing the triangle and one for the other.
A tailor had a piece of cloth 7 m long. He cut 5 smaller pieces of cloth each 3/4 m from it. How many metres of cloth were left?- a)
m - b)
m - c)
m - d)
m
Correct answer is option 'C'. Can you explain this answer?
A tailor had a piece of cloth 7 m long. He cut 5 smaller pieces of cloth each 3/4 m from it. How many metres of cloth were left?
a)
mb)
mc)
md)
m  | Freak Artworks answered |
Length of 5 smaller pieces = 
∴ cloth left with tailor =
meters
∴ cloth left with tailor =
metersA rope is 6.45 m long. If 2.80 m of the rope is cut off, what length of rope remains?- a)
- 3.45 m
- b)
- 3.65 m
- c)
- 4.15 m
- d)
- 4.55 m
Correct answer is option 'B'. Can you explain this answer?
A rope is 6.45 m long. If 2.80 m of the rope is cut off, what length of rope remains?
a)
- 3.45 m
b)
- 3.65 m
c)
- 4.15 m
d)
- 4.55 m
| | Hiral Chatterjee answered |
Understanding the Problem
To find out how much rope remains after cutting a portion off, we need to perform a simple subtraction.
Initial Length of the Rope
- The total length of the rope before cutting is 6.45 meters.
Length Cut Off
- The length of rope that is cut off is 2.80 meters.
Calculation
To find the remaining length, we subtract the length cut from the initial length:
- Remaining Length = Initial Length - Length Cut Off
- Remaining Length = 6.45 m - 2.80 m
Performing the Calculation
- Start by aligning the numbers:
6.45
- 2.80
______
- Subtract the numbers column by column:
1. Hundredths Place: 5 - 0 = 5
2. Tenths Place: 4 - 8: Since 4 is less than 8, we borrow 1 from the units place (making it 5), turning 4 into 14. Thus, 14 - 8 = 6.
3. Units Place: 5 - 2 = 3.
Putting it all together gives us 3.65 meters.
Conclusion
The remaining length of rope after cutting off 2.80 meters from the original 6.45 meters is:
- 3.65 meters, which corresponds to option b.
To find out how much rope remains after cutting a portion off, we need to perform a simple subtraction.
Initial Length of the Rope
- The total length of the rope before cutting is 6.45 meters.
Length Cut Off
- The length of rope that is cut off is 2.80 meters.
Calculation
To find the remaining length, we subtract the length cut from the initial length:
- Remaining Length = Initial Length - Length Cut Off
- Remaining Length = 6.45 m - 2.80 m
Performing the Calculation
- Start by aligning the numbers:
6.45
- 2.80
______
- Subtract the numbers column by column:
1. Hundredths Place: 5 - 0 = 5
2. Tenths Place: 4 - 8: Since 4 is less than 8, we borrow 1 from the units place (making it 5), turning 4 into 14. Thus, 14 - 8 = 6.
3. Units Place: 5 - 2 = 3.
Putting it all together gives us 3.65 meters.
Conclusion
The remaining length of rope after cutting off 2.80 meters from the original 6.45 meters is:
- 3.65 meters, which corresponds to option b.
A shopkeeper mixed 4.75 kg of hazelnuts with 0.75 kg of raisins. He packed the mixture equally into 5 boxes. What is the weight of each box?- a)1.25 kg
- b)1.1 kg
- c)1.55 kg
- d)1.2 kg
Correct answer is option 'B'. Can you explain this answer?
A shopkeeper mixed 4.75 kg of hazelnuts with 0.75 kg of raisins. He packed the mixture equally into 5 boxes. What is the weight of each box?
a)
1.25 kg
b)
1.1 kg
c)
1.55 kg
d)
1.2 kg
| | Aditi Sharma answered |
weight of hazelnut = 4.75kg
weight of raisins = 0.75 kg
total weight = 4.75 +0.75 = 5.5kg
No of box = 5
therefore weight of each box = total weight / no of box
= 5.5kg/ 5
= 1.1kg
What is the mass 20 such
?
- a)60 kg
- b)160 kg
- c)80 kg
- d)180 kg
Correct answer is option 'B'. Can you explain this answer?
What is the mass 20 such?
?a)
60 kg
b)
160 kg
c)
80 kg
d)
180 kg
 | Learning Enablers answered |
- On left side 12 balls
- On right side 7 balls and 40 kg
- So as both side weigth are equal so equating them
- Let x be the weight of a single ball
- 12x=7x+40
- 5x=40
- x=8
- The mass of 20 such balls will be 160kg
Question: Convert into centimetres of 26 m 6 cm- a)2606 cm
- b)20 cm
- c)2066 cm
- d)206 cm
Correct answer is option 'A'. Can you explain this answer?
Question: Convert into centimetres of 26 m 6 cm
a)
2606 cm
b)
20 cm
c)
2066 cm
d)
206 cm
 | Stoneridge Institute answered |
- To convert meters to centimetres, remember that 1 meter equals 100 centimetres.
- First, convert 26 meters into centimetres: 26 x 100 = 2600 cm.
- Add the remaining 6 centimeters: 2600 + 6 cm = 2606 cm.
- Therefore, the total length in centimetres is 2606 cm.
- First, convert 26 meters into centimetres: 26 x 100 = 2600 cm.
- Add the remaining 6 centimeters: 2600 + 6 cm = 2606 cm.
- Therefore, the total length in centimetres is 2606 cm.
hrs in seconds.
=15600sec.
How much postage is needed to send a local mail of weight 310 g?- a)Rs. 22.50
- b)Rs. 25
- c)Rs. 30
- d)Rs. 27.50
Correct answer is option 'B'. Can you explain this answer?
How much postage is needed to send a local mail of weight 310 g?
a)
Rs. 22.50
b)
Rs. 25
c)
Rs. 30
d)
Rs. 27.50
| | Avinash Patel answered |
390g would be split in 60g and 250g
and 250g = 5 x 50g
so for first 60g 12.5Rs and for every 50g x 2.5
12.50 + 5 × 2.5 = Rs.25
and 250g = 5 x 50g
so for first 60g 12.5Rs and for every 50g x 2.5
12.50 + 5 × 2.5 = Rs.25
Rajesh bought 13 kg of peanuts. He saved 195 by using a store coupon. How much did he save per kg of peanuts?- a)Rs. 15
- b)Rs. 18
- c)Rs. 20
- d)Rs. 10
Correct answer is option 'A'. Can you explain this answer?
Rajesh bought 13 kg of peanuts. He saved 195 by using a store coupon. How much did he save per kg of peanuts?
a)
Rs. 15
b)
Rs. 18
c)
Rs. 20
d)
Rs. 10
 | Torcia Education answered |
Total money saved by him = 195
Saving per kg = 195/13 = 15
Saving per kg = 195/13 = 15
What is the capacity of the
?
- a)12 litres
- b)24 litres
- c)20 litres
- d)18 litres
Correct answer is option 'B'. Can you explain this answer?
What is the capacity of the?
?a)
12 litres
b)
24 litres
c)
20 litres
d)
18 litres
| | Stoneridge Institute answered |
- 1 bucket = 4 jugs
- 2 jugs = 3 litres
- If 2 jugs = 3 litres, then:
Another 2 jugs will also be 3 litres. - So, 4 jugs = 3 litres + 3 litres = 6 litres.
Therefore, 1 bucket = 6 litres. - The container has 4 buckets.
Each bucket is 6 litres, so:
4 buckets = 6 litres × 4 = 24 litres.
What goes in circle 2750cm
28 m- a)<
- b)>
- c)=
- d)≥
Correct answer is option 'A'. Can you explain this answer?
What goes in circle 2750cm28 m
28 ma)
<
b)
>
c)
=
d)
≥
| | Aditi Sharma answered |
28 m is larger becuase 1m = 1000 cm
Thus 28 m = 2800 cm which is greater than 2750cm
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