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All questions of Linear Equations in One Variable for Class 10 Exam

If x2 - 7x + 1 = 0 then find the value of (x + 1/x).
  • a)
    3
  • b)
    7
  • c)
    -7
  • d)
    -3
Correct answer is option 'B'. Can you explain this answer?

Orion Classes answered
Given:
x2 - 7x + 1 = 0
Calculation:
x2 - 7x + 1 = 0
Dividing by x:
⇒ x - 7 + 1/x = 0
⇒ x + 1/x = 7
∴ Value of x + 1/x = 7 

The solution of equation 10x + 26 = 0 is a / an________.
  • a)
    Rational Number
  • b)
    Irrational Number
  • c)
    Negative integer
  • d)
    Positive integer
Correct answer is option 'A'. Can you explain this answer?

Orion Classes answered
Given:
The given equation is 10x + 26 = 0
Concept:
Rational numbers are the numbers that can be written in the form of p/q, where q is not equal to zero. 
Calculation:
10x + 26 = 0
⇒ 10x = -26
⇒ x = (-26)/10
⇒ x = -13/5
∴ 10x + 26 = 0 is a rational number.

A total of 324 notes comprising of Rs. 20 and Rs. 50 denominations make a sum of Rs. 12450. The number of Rs. 20 notes is
  • a)
    200
  • b)
    144
  • c)
    125
  • d)
    110
Correct answer is option 'C'. Can you explain this answer?

David Owens answered
Total Notes and Their Value
To solve the problem, we need to set up a system of equations based on the given information about the notes.
Given Data
- Total number of notes = 324
- Total amount = Rs. 12450
- Denominations = Rs. 20 and Rs. 50
Let’s Define Variables
- Let x = number of Rs. 20 notes
- Let y = number of Rs. 50 notes
Setting Up Equations
1. From the total number of notes:
- x + y = 324
2. From the total value of the notes:
- 20x + 50y = 12450
Simplifying the Equations
- From the first equation, we can express y in terms of x:
- y = 324 - x
- Now substitute y in the second equation:
- 20x + 50(324 - x) = 12450
Expanding and Simplifying
- Distributing the 50:
- 20x + 16200 - 50x = 12450
- Combining like terms:
- -30x + 16200 = 12450
- Rearranging gives:
- -30x = 12450 - 16200
- -30x = -3750
- Dividing both sides by -30 results in:
- x = 125
Conclusion
The number of Rs. 20 notes is 125, which corresponds to option 'C'.
Verification
- If x = 125, then:
- y = 324 - 125 = 199
- Checking the total value:
- Total value = 20(125) + 50(199) = 2500 + 9950 = 12450, which is correct.
Thus, the answer is confirmed!

The sum of three consecutive number is 126. Find the highest number?
  • a)
    41
  • b)
    42
  • c)
    43
  • d)
    44
Correct answer is option 'C'. Can you explain this answer?

Ayesha Joshi answered
Let the three consecutive number be x, x + 1, x + 2
⇒ x + (x + 1) + (x + 2) = 126
⇒ 3x + 3 = 126
⇒ 3x = 123
⇒ x = 41
∴ Highest number = x + 2 = 41 + 2 = 43

Difference of two numbers is 50% of the smaller number. If greater number is 120, then find sum of both numbers is:
  • a)
    250
  • b)
    220
  • c)
    200
  • d)
    150
Correct answer is option 'C'. Can you explain this answer?

Ayesha Joshi answered
Given:
Greater number = 120
Calculation:
Let smaller number be x
According to the question
120 – x = x × (50/100)
⇒ 120 – x = x/2
⇒ 240 – 2x = x
⇒ x + 2x = 240
⇒ 3x = 240
⇒ x = 240/3
⇒ x = 80
∴ Sum of both numbers = 120 + 80 = 200

A man has equal number of five, ten and twenty rupee notes amounting to Rs. 385. Find the total number of notes?
  • a)
    13
  • b)
    33
  • c)
    15
  • d)
    31
Correct answer is option 'B'. Can you explain this answer?

Orion Classes answered
Given:
Number of Five rupee note = Number of Ten rupee note = Number of Twenty rupee note
Calculation:
Let the equal number of five, ten and twenty rupee notes be x
⇒ 5x + 10x + 20x = 385
⇒ 35x = 385
⇒ x = 385/35 = 11
Total number of notes = 11 notes of Rs 5 + 11 notes of Rs 10 + 11 Rs of 20 =  33 notes
Check:
11 notes of Rs 5 + 11 notes of Rs 10 + 11 Rs of 20 = 11 × 5 + 11 × 10 + 11 × 20 = 55 + 110 + 220 = Rs. 385
Total number of notes = 11 × 3 = 33 
Therefore the correct answer is 33.
Alternate Method:
Since the number of Rs 5, Rs 10, and Rs 20 notes are equal, the ratio of the number of notes is = 1 ∶ 1 ∶ 1
Or, we can say, the total number of notes must be multiple of 3.
 Only two options are multiple of 3, others can be eliminated.
option 2 : 33. That means the number of notes of each dimension is 33/3 = 11.
5 × 11 + 11 × 10 + 11 × 20 = 385
∴ The total number of notes is 33.

Find x:
  • a)
    3
  • b)
    4
  • c)
    5
  • d)
    1
Correct answer is option 'D'. Can you explain this answer?

Ayesha Joshi answered
⇒ -22x – 26 = 8 - 56x
⇒ 56x - 22x = 26 + 8
⇒ 34x = 34
∴ x = 1

If x6 + x5 + x4 + x3 + x2 + x + 1 = 0, then find the value of x5054 + x6055 - 7
  • a)
    9
  • b)
    5
  • c)
    -9
  • d)
    -5
Correct answer is option 'D'. Can you explain this answer?

Orion Classes answered
Given:
x6 + x5 + x4 + x3 + x2 + x + 1 = 0
Calculation:
Considering the given equation
x6 + x5 + x4 + x3 + x2 + x + 1 = 0      -----(1)
In equation (1) multiplying by x
x7 + x6 + x5 + x4 + x3 + x2 + x = 0      -----(2)
Equation (2) – (1)
⇒ x7 - 1 = 0
⇒ x7 = 1
x5054 + x6055 - 7
⇒ (x7)722 + (x7)865 – 7
⇒ (1)722 + (1)865 – 7
⇒ 1 + 1 – 7
⇒ - 5
∴ Required value is – 5

If 80% of my age 6 years ago is the same as 60% of my age after 10 years. What is the product of digits of my present age?
  • a)
    24
  • b)
    20
  • c)
    30
  • d)
    15
Correct answer is option 'B'. Can you explain this answer?

Let's assume the present age as 'x'.

Given that 80% of the age 6 years ago is the same as 60% of the age after 10 years, we can write the equation as:

0.8(x - 6) = 0.6(x + 10)

Simplifying this equation:

0.8x - 4.8 = 0.6x + 6

Subtracting 0.6x from both sides:

0.2x - 4.8 = 6

Adding 4.8 to both sides:

0.2x = 10.8

Dividing both sides by 0.2:

x = 54

Therefore, the present age is 54.

To find the product of the digits of the present age, we can multiply the digits together:

Product = 5 * 4 = 20

Hence, the product of the digits of the present age is 20, which corresponds to option B.

If the sum and product of two numbers is 34 and 288 respectively, find the sum of their cubes.
  • a)
    9236
  • b)
    9928
  • c)
    9854
  • d)
    8352
Correct answer is option 'B'. Can you explain this answer?

Owen Foster answered
Let's assume the two numbers as x and y.
We are given that the sum of the two numbers is 34, so we can write the equation as:
x + y = 34 ...(1)

We are also given that the product of the two numbers is 288, so we can write the equation as:
xy = 288 ...(2)

To find the sum of their cubes, we need to find the values of x and y first.

Solving the equations:
From equation (1), we can express y in terms of x:
y = 34 - x

Substituting this value of y in equation (2), we get:
x(34 - x) = 288

Expanding the equation:
34x - x^2 = 288

Rearranging the equation:
x^2 - 34x + 288 = 0

Now we can solve this quadratic equation to find the values of x.

Factoring the equation:
(x - 16)(x - 18) = 0

Setting each factor equal to zero:
x - 16 = 0 or x - 18 = 0

Solving for x, we have two possible solutions:
x = 16 or x = 18

Now we can find the corresponding values of y:
For x = 16, y = 34 - 16 = 18
For x = 18, y = 34 - 18 = 16

So the two numbers are 16 and 18.

Finding the sum of their cubes:
16^3 + 18^3 = 4096 + 5832 = 9928

Hence, the sum of their cubes is 9928, which corresponds to option (b).

Rajeev was to earn Rs. 500 and a free holiday for seven weeks’ work. He worked for only 5 weeks and earned Rs. 50 and a free holiday. What was the value of the holiday?
  • a)
    Rs. 1,075
  • b)
    Rs. 1,850
  • c)
    Rs. 1,550
  • d)
    Rs. 1,675
Correct answer is option 'A'. Can you explain this answer?

Orion Classes answered
Given:
500 + 1 holiday = 7 weeks      ----(1)
50 + 1 holiday = 5 weeks      ----(2)
⇒ From (1) - (2)
450 = 2 weeks
1 week = 225 Rs.
⇒ From (1), 500 + 1 holiday = 7 × 225
1 holiday = 1575 - 500
1 holiday = 1075 Rs.

If y2 = y + 7, then what is the value of y3?
  • a)
    8y + 7
  • b)
    y + 14
  • c)
    y + 2
  • d)
    4y + 7
Correct answer is option 'A'. Can you explain this answer?

Given: y^2 = y - 7

To find: The value of y^3

Solution:
To find the value of y^3, we need to multiply y^2 by y.

y^2 * y = (y - 7) * y

Expanding the equation:

y^3 = y * y - 7 * y

Simplifying further:

y^3 = y^2 - 7y

But we already know that y^2 = y - 7.

Substituting this value into the equation:

y^3 = (y - 7) - 7y

Simplifying again:

y^3 = y - 7 - 7y

Combining like terms:

y^3 = -6y - 7

Therefore, the value of y^3 is -6y - 7.

Answer:
The correct option is (A) 8y - 7.

A is 5 years older than B and 10 years younger than C. If the sum of ages of A, B and C together after 5 years is 80 years. Find the present age of B.
  • a)
    15 years
  • b)
    20 years
  • c)
    30 years
  • d)
    25 years
Correct answer is option 'A'. Can you explain this answer?

Ayesha Joshi answered
Let the age of B be x years
So, the age of A = (x + 5)
And the age of C = (x + 5 +10) = (x + 15)
Now, age of B after 5 years = (x + 5)
Age of A after 5 years = (x + 5) + 5 = (x + 10)
 Age of C after 5 years = (x + 15) + 5 = (x + 20)
according to question,
sum of their ages after 5 years = 80
So, (x + 5) + (x + 10) + (x + 20) = 80
⇒ 3x + 35 = 80 
⇒ 3x = 45
So, x = 15
∴ present age of B = 15 years

A woman had only 50 paisa and 1 rupee coins in her purse. The total number of coins were 120 and the total amount was Rs.100. So the number of 1 rupee coins are_______.
  • a)
    60
  • b)
    70
  • c)
    80
  • d)
    90
Correct answer is option 'C'. Can you explain this answer?

Ayesha Joshi answered
Total number of coin = 120 
Total amount = Rs 100 
Calculation 
Let the number of coins of 50 p and Re 1 be x and y 
According to question 
x + y = 120       ----(1)
x/2 + y = 100      ----(2) 
Subtract equation (2) 
By solving (1) and (2) from equation (1)
⇒ x - x/2 = 120 - 100
⇒ x/2 = 20
We get x = 40 and y = 80 
So number of coins of Rs 1 = 80 
∴ The required answer is 80 
 

When you reverse the digits of the number 13, the number increases by 18. How many other two‐digit numbers increase by 18 when their digits are reversed?
  • a)
    5
  • b)
    6
  • c)
    7
  • d)
    8
Correct answer is option 'B'. Can you explain this answer?

Ayesha Joshi answered
Calculation:
Let the unit digit be x and tens digit be y
According to the question,
⇒ 10y + x - (10x + y) = 18
⇒ 9y - 9x = 18
⇒ y - x = 2
It means that difference of digits of two-digit numbers is 2.
∴ Six cases other than (13, 31) are possible
(24, 42) (35, 53) (46, 64) (57, 75) (68, 86) (79, 97)
Mistake Points:
Here we cannot take (20, 2)
Because 2 is not a two-digit number. Normally we do not write numbers from 1 - 9  as 01, 02, 03, 04, 05, 06, 07, 08, and 09.

Find the product of two consecutive numbers where four times the first number is 10 more than thrice the second number.
  • a)
    210
  • b)
    182
  • c)
    306
  • d)
    156
Correct answer is option 'B'. Can you explain this answer?

Gabriel Rivera answered
To find the product of two consecutive numbers, we need to let the first number be represented by x, and the second number be represented by x+1.

Given that four times the first number is 10 more than thrice the second number, we can form the equation:

4x = 3(x+1) + 10

Now, let's solve the equation step by step:

4x = 3x + 3 + 10 (Distribute 3 to x+1)
4x - 3x = 13 (Combine like terms)
x = 13 (Divide both sides by x)

So, the first number is 13 and the second number is 13+1 = 14.

To find the product of these two consecutive numbers:

Product = 13 * 14 = 182

Therefore, the correct answer is option B) 182.

In 10 years, a father will be twice as old as his son. Five years ago, the father was three times as old as his son. Find their current ages.
  • a)
    50 , 20
  • b)
    50 , 10
  • c)
    40 , 12
  • d)
    55 , 12
Correct answer is option 'A'. Can you explain this answer?

Understanding the Problem
To solve the problem, we need to set up equations based on the information given about the ages of the father and son.
Step 1: Define Variables
- Let F = Father's current age
- Let S = Son's current age
Step 2: Set Up Equations
1. In 10 years:
- F + 10 = 2(S + 10)
- This implies that in 10 years, the father will be twice as old as his son.
2. Five years ago:
- F - 5 = 3(S - 5)
- This indicates that five years ago, the father was three times as old as his son.
Step 3: Simplify the Equations
From the first equation:
- F + 10 = 2S + 20
- Rearranging gives: F = 2S + 10 - 10
- So, F = 2S + 10
From the second equation:
- F - 5 = 3S - 15
- Rearranging gives: F = 3S - 15 + 5
- So, F = 3S - 10
Step 4: Solve the System of Equations
Now we have two expressions for F:
1. F = 2S + 10
2. F = 3S - 10
Set them equal to each other:
- 2S + 10 = 3S - 10
Rearranging gives:
- 10 + 10 = 3S - 2S
- 20 = S
Now substitute S back to find F:
- F = 2(20) + 10 = 40 + 10 = 50
Conclusion
Thus, the current ages are:
- Father's age = 50 years
- Son's age = 20 years
The correct answer is option 'A': 50, 20.

If 1/3rd of the first of the three consecutive odd numbers is 2 more than 1/5th of the third number, then the second number is?
  • a)
    21
  • b)
    23
  • c)
    25
  • d)
    19
Correct answer is option 'B'. Can you explain this answer?

Avery Martin answered
To solve this problem, let's assume the first odd number as x.

First Odd Number: x
Second Odd Number: x + 2 (since the numbers are consecutive odd numbers)
Third Odd Number: x + 4 (since the numbers are consecutive odd numbers)

According to the given information:
1/3rd of the first number is 2 more than 1/5th of the third number.

Mathematically, this can be represented as:

1/3 * x = (1/5 * (x + 4)) + 2

Now, let's solve this equation step by step.

Step 1: Simplify the equation

1/3 * x = 1/5 * (x + 4) + 2

Step 2: Multiply both sides of the equation by the least common multiple (LCM) of 3 and 5, which is 15, to eliminate the fractions.

15 * (1/3 * x) = 15 * (1/5 * (x + 4) + 2)

5x = 3(x + 4) + 30

Step 3: Distribute on the right side of the equation

5x = 3x + 12 + 30

Step 4: Combine like terms

5x = 3x + 42

Step 5: Subtract 3x from both sides of the equation

5x - 3x = 42

2x = 42

Step 6: Divide both sides of the equation by 2

x = 42/2

x = 21

Now that we have the value of x, we can find the second number by adding 2 to the first number.

Second Odd Number = x + 2 = 21 + 2 = 23

Therefore, the second number is 23, which matches with option B.

In a group of 100 students, each student offers exactly 8 subjects, and exactly 10 students take each subject. Find the total number of different subjects.
  • a)
    Exactly 80
  • b)
    May be 50
  • c)
    At most 30
  • d)
    At least 90
Correct answer is option 'A'. Can you explain this answer?

Step 1 — Count student–subject pairs: each of the 100 students offers 8 subjects, so total pairs = 100 × 8 = 800.
Step 2 — Relate to subjects: each subject is taken by 10 students, so if S is the number of subjects, total pairs = 10 × S.
Step 3 — Equate and solve: 10 × S = 800, hence S = 800 ÷ 10 = 80.
Answer: a) Exactly 80

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