All questions of IC Engine for Mechanical Engineering Exam

The three way catalytic converter cannot control the following emission
  • a)
    PM emission
  • b)
    HC emission
  • c)
    CO emission
  • d)
    NOx emission
Correct answer is option 'A'. Can you explain this answer?

Sagarika Dey answered
Catalytic converters are called three way converters because it reduces the concentration of CO, HC and NOx in the exhaust (three concentrations).

The indicator on an engine is used to determine:
  • a)
    IHP and Mean indicative pressure
  • b)
    BHP
  • c)
    Speed
  • d)
    Temperature
Correct answer is option 'A'. Can you explain this answer?

Yash Patel answered
The device which measures the variations of the pressure in the cylinder over a part or full cycle is called an indicator and the plot of such information obtained is called an indicator diagram. This shows the mean effective pressure and indicated horse power.

Engine of different cylinder dimensions, power and speed are compared on the basis of
  • a)
    Maximum pressure
  • b)
    Fuel consumption
  • c)
    Mean effective pressure
  • d)
    Unit power
Correct answer is option 'C'. Can you explain this answer?

For any particular engine, operating at a given speed and power output, there will be a specific mean effective pressure, mep. This mep is used as a basis to compare the performance.

The engine of a car has three cylinder with total displacement of 770 cc. The compression ratio is 8.7. What is the clearance volume of each cylinder?
  • a)
    34.4 cc
  • b)
    33.33 cc
  • c)
    32.33 cc
  • d)
    35.2 cc
Correct answer is option 'B'. Can you explain this answer?

To find the clearance volume of each cylinder, we need to understand the concept of compression ratio and displacement.

Compression Ratio:
The compression ratio is the ratio of the total volume of the cylinder when the piston is at the bottom dead center (BDC) to the total volume when the piston is at the top dead center (TDC). It is an important parameter that affects the performance and efficiency of an engine.

Displacement:
The displacement of an engine is the total volume swept by all the pistons in all the cylinders during one complete cycle. It is usually measured in cubic centimeters (cc) or liters.

Given Data:
Number of cylinders (n) = 3
Total displacement (D) = 770 cc
Compression ratio (CR) = 8.7

Calculations:
The displacement of each cylinder can be calculated by dividing the total displacement by the number of cylinders:
Displacement per cylinder = Total displacement / Number of cylinders
Displacement per cylinder = 770 cc / 3
Displacement per cylinder = 256.67 cc

The clearance volume (CV) can be calculated using the formula:
CV = (Displacement per cylinder) / (Compression ratio - 1)

Substituting the given values into the formula:
CV = 256.67 cc / (8.7 - 1)
CV = 256.67 cc / 7.7
CV ≈ 33.33 cc

Therefore, the clearance volume of each cylinder is approximately 33.33 cc.

Which gas will produce the highest efficiency in an ideal Otto cycle for same compression ratio?
  • a)
    Air
  • b)
    Carbon dioxide
  • c)
    Helium
  • d)
    Oxygen
Correct answer is option 'C'. Can you explain this answer?

Meghana Desai answered
The efficiency of Otto cycle is given as η=1−(1r)γ−1η=1−(1r)γ−1
Higher the value of γ more will be the efficiency for same compression ratio. The value of γ for the different type of gases is given below
 
γ monoatomic > γdiatomic > γtriatomic
So out of given options Helium is mono atomic, so efficiency will be highest for Helium for a given compression ratio.

The intake charge in a diesel engine consist of
  • a)
    Air alone
  • b)
    Air + lubricating oil
  • c)
    Air + fuel
  • d)
    Air + fuel + lubricating oil
Correct answer is option 'A'. Can you explain this answer?

Priyanka Shah answered
In diesel engine intake is only air. The air is compressed and then the fuel is injected to the high pressure and temperature compressed air.

Mean effective pressure at a given compression ratio is maximum when the air-fuel ratio is
  • a)
    Higher than stoichiometric
  • b)
    Lower than stoichiometric
  • c)
    Equal to stoichiometric
  • d)
    None of the above
Correct answer is option 'A'. Can you explain this answer?

Understanding Mean Effective Pressure (MEP)
Mean Effective Pressure (MEP) is a crucial parameter in internal combustion engines, representing the average pressure in the combustion chamber throughout the power stroke. It directly influences the engine's performance and efficiency.
Impact of Air-Fuel Ratio on MEP
The air-fuel ratio (AFR) affects the combustion process within an engine, impacting the MEP significantly. Here’s how different ratios play a role:
  • Higher than Stoichiometric: When the AFR is higher than the stoichiometric value (the ideal ratio for complete combustion), there is an excess of air. This allows for more complete combustion, resulting in higher thermal efficiency and consequently higher MEP. The engine can extract more energy from the fuel, leading to improved performance.
  • Lower than Stoichiometric: A lower AFR results in a rich mixture (more fuel than air). While this can increase power output temporarily, it leads to incomplete combustion, producing excess hydrocarbons and carbon monoxide. This inefficiency lowers the MEP due to wasted fuel and energy.
  • Equal to Stoichiometric: At the stoichiometric ratio, combustion is optimal, but the energy extraction potential is not maximized compared to a richer mixture. Thus, while performance is decent, it does not reach the peak levels achievable with a higher AFR.

Conclusion
In summary, MEP is maximized at higher than stoichiometric air-fuel ratios due to improved combustion efficiency, resulting in better engine performance and energy extraction. Balancing the AFR is vital for optimizing engine operation and efficiency.

For the same peak pressure and heat input
  • a)
     
    ηOtto>ηDual>ηDiesel
  • b)
     
    ηOtto>ηDiesel>ηDual
  • c)
     
    ηDiesel>ηDual>ηOtto
  • d)
     
    ηDiesel>ηOtto>ηDual
Correct answer is option 'C'. Can you explain this answer?

Mahesh Nair answered
Otto cycle ⇒ 1 - 2 - 3 - 4
Diesel cycle 1 - 2’ - 3’ - 4’
It is clear from T - s diagram that the heat rejected by the Diesel cycle (area below 4’ - 1) is less than the heat rejection by the Otto cycle (area below 4 - 1); hence the diesel cycle is more efficient than Otto cycle for the condition of same maximum pressure heat input. The dual cycle efficiency lies between the Otto and Diesel cycle.

Which is the wrong assumption for calculation of air standard efficiency?
  • a)
    All processes are reversible
  • b)
    Specific heat remains constant at all temperatures
  • c)
    No account of the mechanism of heat transfer is considered
  • d)
    Gases dissociate at higher temperatures
Correct answer is option 'D'. Can you explain this answer?

Nidhi Patel answered
To simplify analysis, the following assumptions are made for calculation of air standard efficiency:
1. The working fluid is air, which continuously circulates in a closed loop and always behaves as an ideal gas.
2. All the processes that make up the cycle are internally reversible.
3. The combustion process is replaced by a heat - addition process from an external source.
4. The exhaust process is replaced by a heat - rejection process that restores the working fluid to its initial state.

Exhaust gas recirculation has the disadvantage of
  • a)
    Decreasing thermal efficiency
  • b)
    Increasing HC emission
  • c)
    Both a and b
  • d)
    Increasing aldehydes
Correct answer is option 'C'. Can you explain this answer?

Exhaust gas recirculation (EGR) is a technique used in internal combustion engines to reduce nitrogen oxide (NOx) emissions. It works by recirculating a portion of the engine's exhaust gas back into the intake manifold, where it mixes with the fresh air-fuel mixture before entering the combustion chamber.

Decreasing thermal efficiency:
- One disadvantage of EGR is that it can decrease the thermal efficiency of the engine. This is because when the exhaust gas is recirculated, it displaces a portion of the fresh air-fuel mixture in the combustion chamber, leading to a lower combustion efficiency.
- The presence of exhaust gas reduces the oxygen concentration in the combustion chamber, which affects the combustion process and can result in incomplete fuel combustion.
- Incomplete combustion leads to the production of less useful work and increases the fuel consumption, thereby reducing the thermal efficiency of the engine.

Increasing HC emission:
- Another disadvantage of EGR is that it can increase the emission of hydrocarbon (HC) pollutants. HC emissions are a result of incomplete combustion, and as mentioned earlier, the presence of exhaust gas in the combustion chamber can lead to incomplete combustion.
- The recirculated exhaust gas contains unburned hydrocarbons, which can further contribute to the HC emissions.

Both a and b:
- Therefore, the correct answer is option 'c' - EGR has the disadvantages of decreasing thermal efficiency and increasing HC emissions.
- The decrease in thermal efficiency and increase in HC emissions are two significant drawbacks of using EGR in internal combustion engines.
- These disadvantages need to be carefully considered when implementing EGR systems, and engineers should strive to find a balance between reducing NOx emissions and maintaining optimal engine performance and efficiency.

Increasing aldehydes:
- The option 'd' - increasing aldehydes - is not a correct answer because EGR does not have any direct influence on the production of aldehydes.
- Aldehydes are organic compounds that can be formed during the combustion process, but their formation is not specifically attributed to the use of EGR. Other factors such as fuel composition, combustion conditions, and catalyst efficiency can contribute to the production of aldehydes.

In conclusion, while exhaust gas recirculation has the advantages of reducing NOx emissions, it also has the disadvantages of decreasing thermal efficiency and increasing HC emissions. These drawbacks should be taken into consideration when implementing EGR systems in internal combustion engines.

The compression ratio for petrol engines is:
  • a)
    3 to 6
  • b)
    8 to 10
  • c)
    20 to 30
  • d)
    15 to 20
Correct answer is option 'B'. Can you explain this answer?

Aditya Jain answered
The normal range of compression ratio for diesel engine is 16 to 20 whereas for spark ignition engines it is 6 to 10. Due to higher compression ratios used in diesel engines the efficiency of a diesel engine is more than that of the gasoline engine.

By higher octane number of SI fuel, it means that fuel has
  • a)
    Higher heating value
  • b)
    Higher flash point
  • c)
    Lower volatility
  • d)
    Longer ignition delay
Correct answer is option 'D'. Can you explain this answer?

Disha Nambiar answered
Higher octane is related only to longer ignition delay which prevents knocking. High octane fuel itself don’t increase the power or enhance any other property of fuel

Detonation in the SI engine becomes severe during
  • a)
    Low load and high speed
  • b)
    High load and high speed
  • c)
    Low load and low speed
  • d)
    High load and low speed
Correct answer is option 'D'. Can you explain this answer?

Pritam Das answered
Detonation in SI engine will become severe at high load and low speed because at higher loads, the temperature of cylinder and combustion chamber walls will be higher and hence temperature of the end charge will be more which increases knocking tendency in SI engine.
And at lower engine speed, longer will be the absolute time for the flame to traverse the cylinder which increases the time available for pre flame reactions hence the tendency to knock increases.

Knocking in spark ignition engine can be reduced by
  • a)
    Increasing the compression ratio
  • b)
    Increasing the inlet air temperature
  • c)
    Increasing the coolant water temperature
  • d)
    Retarding the spark advance 
Correct answer is option 'D'. Can you explain this answer?

Factors affecting knocking in SI engine:
i) Compression ratio:- Higher compression ratio will result in higher temperature of the charge, tendency to knock will increase.
ii) Inlet air temperature:- The effect of inlet air temp is same as compression ratio. High inlet temp of the air fuel mixture will increase knocking.
iii) Advancing the spark:- Advancing the spark will result in more compression during sparking. The increase in temperature during the sparking will be higher. Hence tendency to knock will increase and so by retarding the spark, the tendency to knock will decrease.
iv) Coolant water temperature:- By increasing coolant water temperature, less heat will be carried from the engine which will increase the engine temperature. So the knocking will increase.

For CI engines, fuels most preferred are
  • a)
    Naphthalene
  • b)
    Paraffins
  • c)
    Olefins
  • d)
    Aromatics
Correct answer is option 'B'. Can you explain this answer?

Ashish Pillai answered
For CI engines, the normal paraffin’s are the best fuels and aromatics are the least desirable.
For SI engines the aromatics are the best fuel and the paraffins are least desirable.
The reason for this is normal paraffins exhibit the poorest antiknock quality when used in SI engines. But the antiknock quality improves with the increasing number of carbon atoms and the compactness of the molecular structure. The aromatics offer the best resistance to knocking in SI Engines.

Brake specific fuel consumption is defined as
  • a)
    Fuel consumption per hour
  • b)
    Fuel consumption per km
  • c)
    Fuel consumption per b.p
  • d)
    Fuel consumption per brake power hour
Correct answer is option 'D'. Can you explain this answer?

Dipika Nambiar answered
The meaning of bsfc is how much fuel is consume in one hour to produce one kilowatt brake power(i.e. power available at engine shaft not power produce into engine block).
It is used to measure fuel efficiency and also to compare internal combustion engine on basis of shaft power.

Morse test is carried out to determine ______ of an engine:
  • a)
    I.H.P.
  • b)
    F.H.P.
  • c)
    B.H.P.
  • d)
    Efficiency
Correct answer is option 'A'. Can you explain this answer?

Athira Pillai answered
Morse test is a very useful test designed for multi cylinder engines. Its primary objective is to determine the indicated power developed by each cylinder. The indicated power is the sum of break horse power plus the frictional power losses.

With increase in compression ratio, flame speed
  • a)
    Increases
  • b)
    Decreases
  • c)
    Remains the same
  • d)
    First decreases and then increases
Correct answer is option 'A'. Can you explain this answer?

Suyash Kumar answered
Increased compression ratio reduces the clearance volume and therefore increases the density of the cylinder gases during burning. This increases the peak pressure and temperature and the total combustion duration is reduced. Thus engines having higher compression ratio have higher flame speed.

Octane number of gasoline is a measure of its:
  • a)
    Knocking tendency
  • b)
    Ignition delay
  • c)
    Ignition temperature
  • d)
    Smoke point
Correct answer is option 'A'. Can you explain this answer?

An octane number is a measure of the knocking tendency of gasoline fuels in spark ignition engines. The ability of a fuel to resist auto-ignition during compression and prior to the spark ignition gives it a high octane number. Two octane tests can be performed for gasoline.

The adiabatic flame temperature of a reaction is controlled by
  • a)
    Pressure regulation
  • b)
    Changing the masses of reactants
  • c)
    The amount of excess air supplied
  • d)
    Changing the reactor volume
Correct answer is option 'C'. Can you explain this answer?

For a combustion process that takes place adiabatically with no shaft work, the temperature of the products is referred to as the adiabatic flame temperature. This is the maximum temperature that can be achieved for given reactants. The maximum adiabatic flame temperature for a given fuel and oxidizer combination occurs with a stoichiometric mixture (correct proportions such that all fuel and all oxidizer are consumed). The amount of excess air can be tailored as part of the design to control the adiabatic flame temperature.

The process scavenging is relevant in
  • a)
    Four-stroke engine
  • b)
    Two-stroke engine
  • c)
    Petrol engine
  • d)
    Diesel engine
Correct answer is option 'B'. Can you explain this answer?

Sravya Tiwari answered
Scavenging is the process whereby air at a pressure greater than that of atmospheric pressure is used to push the exhaust gas out of the cylinder of an engine. Unlike the 4 stroke engine, a two stroke diesel engine does not use the piston to push out the exhaust gas, instead, air enters the cylinder around bottom dead centre and sweeps or scavenges the exhaust gas from the cylinder

A fuel is a mixture of 60% methane and 30% carbon mono-oxide and 10% oxygen by volume. Calculate the stoichiometric oxygen needed.
  • a)
    1.35 m3
  • b)
    1.25 m3
  • c)
    1 m3
  • d)
    2 m3
Correct answer is option 'B'. Can you explain this answer?

Anshul Sharma answered
CH4 + 202 → CO2 + 2 H2O
∴ 1 m3 of methane requires 2 m3 of oxygen
∴ 0.6 m3 of methane requires 1.2 m3 of oxygen
2 CO + O2 → 2 CO2
1 m3 of CO requires 0.5 m3 of oxygen, so 0.3 m3 of CO requires 0.15 m3 of oxygen
∴ Total oxygen requires = 1.2 + 0.15 = 1.35 m3
Oxygen already present = 0.1 m3
∴ Stoichiometric oxygen needed = 1.25 m3

An SI engine sometimes continues to run for a very small period even after the ignition is switched off. This phenomenon is called
  • a)
    Over burning
  • b)
    Pull up period
  • c)
    Dieseling
  • d)
    Throttle sticking
Correct answer is option 'C'. Can you explain this answer?

Raghav Saini answered
Dieseling is the phenomenon in which an SI engine sometimes continues to run for a very small period even after the ignition is switched off. Dieseling may take place due to following reasons:
  • Engine overheating
  • Too high spark plug heat range
  • High engine idling speed
  • Oil entry into the cylinder
  • Increase in compression ratio due to carbon deposits
  • Incorrect adjustment of idle fuel-air mixture
  • Sticking of throttle
  • Requirement of tune up of engine

What is the number of cycles completed per second for a four stroke diesel engine running at 6000 rpm?
  • a)
    50
  • b)
    500
  • c)
    6000
  • d)
    3000
Correct answer is option 'A'. Can you explain this answer?

Hiral Jain answered
To determine the number of cycles completed per second for a four-stroke diesel engine running at 6000 rpm, we need to understand the concept of engine cycles and the relationship between engine speed and cycle frequency.

Engine Cycles:
A four-stroke engine goes through four different strokes to complete one cycle. These strokes are:

1. Intake Stroke: The intake valve opens, and the piston moves downward, drawing in air and fuel mixture into the cylinder.
2. Compression Stroke: The intake and exhaust valves are closed, and the piston moves upward, compressing the air-fuel mixture.
3. Power Stroke: At the top of the compression stroke, the fuel is ignited by a spark plug. The expanding gases push the piston downward, generating power.
4. Exhaust Stroke: The exhaust valve opens, and the piston moves upward, pushing the burnt gases out of the cylinder.

Cycle Frequency:
The cycle frequency is the number of cycles completed per second. It is directly related to the engine speed, which is measured in revolutions per minute (rpm). The formula to calculate the cycle frequency is:

Cycle Frequency = Engine Speed (rpm) / 2

Explanation:
In the given scenario, the engine speed is 6000 rpm. By using the formula, we can calculate the cycle frequency as follows:

Cycle Frequency = 6000 rpm / 2
Cycle Frequency = 3000 cycles per minute

Since the question asks for the number of cycles completed per second, we need to convert the cycle frequency from minutes to seconds:

Cycles per second = (3000 cycles per minute) / (60 seconds per minute)
Cycles per second = 50 cycles per second

Therefore, the correct answer is option A) 50. The four-stroke diesel engine running at 6000 rpm completes 50 cycles per second.

Octane number of natural gas is
  • a)
    60 - 80
  • b)
    80 - 100
  • c)
    > 100
  • d)
    < 60
Correct answer is option 'C'. Can you explain this answer?

Octane number of natural gas is around 110 which makes it a very good SI engine fuel. Because of this high octane number the flame speed is higher and engine can operate with high compression ratio.

________ is a transmission dynamometer -
  • a)
    Hydraulic dynamometer
  • b)
    Prony brake dynamometer
  • c)
    Rope brake dynamometer
  • d)
    None of the above
Correct answer is option 'D'. Can you explain this answer?

Pritam Jain answered
A dynamometer is a device used for measuring the torque and brake power required to operate a driven machine. It has a device to measure the frictional resistance.
Following are the two types of dynamometers, used for measuring the brake power of an engine.
1. Absorption dynamometers: The entire energy or power produced by the dynamometer is absorbed by the friction resistances of the brake and is transformed into heat, during the process of measurement.
Example: Prony brake dynamometer, Rope brake dynamometer, Hydraulic dynamometer
2. Transmission dynamometers: The energy is not wasted in friction but is used for doing work. The energy or power produced by the engine is transmitted through the dynamometer to some other machines where the power developed is suitably measured.
Example: Epicyclic-train dynamometer, Belt transmission dynamometer, Torsion dynamometer.

The combustion in a compression ignition engine is ________.
  • a)
    heterogeneous
  • b)
    homogeneous
  • c)
    laminar
  • d)
    turbulent
Correct answer is option 'A'. Can you explain this answer?

Pankaj Joshi answered
Homogeneous compression ignition is a form of internal combustion in which air and fuel are well mixed at the point of combustion. On the other hand, in heterogenous combustion engine, the air and fuel are not mixed till the point of combustion. In CI engines or diesel engine, only air is compressed and then the fuel is injected at the last stage. So no proper mixing before combustion takes place. So the CI engines are heterogenous combustion engines.

The magneto in an automobile is basically a/an
  • a)
    AC generator
  • b)
    DC generator
  • c)
    Magnetic coil
  • d)
    Transformer
Correct answer is option 'B'. Can you explain this answer?

magneto is a special type of electric generator. It is mounted on the engine and replaces all the components of the coil ignition system except the spark plug. A magneto, when rotated by the engine, is capable of producing very high voltage and does not need a battery as a source of external energy.

In SI engines, maximum flame speed is obtained when the equivalence ratio is between
  • a)
    1.1 and 1.2
  • b)
    1.0 and 1.1
  • c)
    1.2 and 1.3
  • d)
    Less than 1.0
Correct answer is option 'A'. Can you explain this answer?

Sai Reddy answered
The ratio of actual fuel air ratio to stoichiometric fuel air ratio is called equivalence ratio.
The highest flame velocities are obtained with somewhat richer mixture of equivalence ratio 1.1 to 1.2. When the mixture is made leaner or richer the flame speed decreases. Less thermal energy is released in case of lean mixture resulting in lower flame temperature. Very rich mixture leads to the incomplete combustion which results again in the release of less thermal energy.

Volumetric efficiency is a measure of 
  • a)
    Speed
  • b)
    Power
  • c)
    Maximum power
  • d)
    Breathing capacity
Correct answer is option 'D'. Can you explain this answer?

Anshul Basu answered
Volumetric efficiency is defined as the ratio of actual volume flow rate of air into the system to the rate at which the volume is displaced by the system.
It indicates the breathing capacity of the system. It is to be noted that the utilization of the air is that determines the power output of the engine. Intake system must be designed in such a way that the engine must be able to take in as much air as possible.

An SI engine sometimes continues to run for a very small period even after the ignition is switched off. This phenomenon is called
  • a)
    Over burning
  • b)
    Pull up period
  • c)
    Dieseling
  • d)
    Throttle sticking
Correct answer is option 'C'. Can you explain this answer?

Neha Mukherjee answered
Dieseling is the phenomenon in which an SI engine sometimes continues to run for a very small period even after the ignition is switched off. Dieseling may take place due to following reasons:
  • Engine overheating
  • Too high spark plug heat range
  • High engine idling speed
  • Oil entry into the cylinder
  • Increase in compression ratio due to carbon deposits
  • Incorrect adjustment of idle fuel-air mixture
  • Sticking of throttle
  • Requirement of tune up of engine

Chapter doubts & questions for IC Engine - Mock Test Series for SSC JE Mechanical Engineering 2025 2025 is part of Mechanical Engineering exam preparation. The chapters have been prepared according to the Mechanical Engineering exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for Mechanical Engineering 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.

Chapter doubts & questions of IC Engine - Mock Test Series for SSC JE Mechanical Engineering 2025 in English & Hindi are available as part of Mechanical Engineering exam. Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.

Top Courses Mechanical Engineering

Signup to see your scores go up within 7 days!

Study with 1000+ FREE Docs, Videos & Tests
10M+ students study on EduRev