Given, GHI = 1578 and DEF = 912
We need to find ABC.
Approach:
- As we know that A=1, B=2, C=3, ..., Z=26.
- Also, GHI = 1000*G + 100*H + 10*I and DEF = 100*D + 10*E + F (where G, H, I, D, E, F are digits)
- Therefore, we can write: 1000*G + 100*H + 10*I + 100*D + 10*E + F = 1578 + 912
- Simplifying the above equation, we get: 1000*G + 100*H + 10*I + 100*D + 10*E + F = 2490
- Rearranging the terms, we get: 1000*G + 100*D + 100*H + 10*E + 10*I + F = 2490
- Now, we can easily see that (1000*G + 100*D + 100*H) is a multiple of 100, so we can ignore it.
- Also, (10*E + F) is a multiple of 2, so we can ignore it as well.
- Therefore, we are left with: 100*I + 10*B + C = 2490 - (1000*G + 100*D + 100*H + 10*E + F)
- Substituting the values of G, H, I, D, E, F from their respective letters, we get:
100*I + 10*B + C = 2490 - (100*7 + 100*4 + 100*9 + 10*1 + 10*2 + 9)
= 2490 - 740
= 1750
- Therefore, we have: 100*I + 10*B + C = 1750
- Now, we can see that I cannot be greater than 1, otherwise the value of the left-hand side will be greater than 1750.
- Also, B cannot be greater than 6, otherwise the value of the left-hand side will be greater than 1750.
- Therefore, we can try the values of I and B starting from 1 and 6 respectively, and find the value of C that satisfies the above equation.
- Trying with I=1 and B=6, we get: 100*1 + 10*6 + C = 1750
- Simplifying the above equation, we get: C = 175 - 60 = 115
- But this is not possible as C should be a digit between 0 and 9.
- Therefore, we try with I=1 and B=5, we get: 100*1 + 10*5 + C = 1750
- Simplifying the above equation, we get: C = 175 - 50 = 125
- But this is not possible as C should be a digit between 0 and 9.
- Therefore, we try with I=1 and B=4, we get: 100*1 + 10*4 + C = 1750
- Simplifying the above equation, we get: C = 175