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BEL Trainee Engineer Electrical Mock Test - 1 - Electrical Engineering (EE) MCQ


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30 Questions MCQ Test BEL Trainee Engineer Electrical Mock Test Series 2024 - BEL Trainee Engineer Electrical Mock Test - 1

BEL Trainee Engineer Electrical Mock Test - 1 for Electrical Engineering (EE) 2024 is part of BEL Trainee Engineer Electrical Mock Test Series 2024 preparation. The BEL Trainee Engineer Electrical Mock Test - 1 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The BEL Trainee Engineer Electrical Mock Test - 1 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for BEL Trainee Engineer Electrical Mock Test - 1 below.
Solutions of BEL Trainee Engineer Electrical Mock Test - 1 questions in English are available as part of our BEL Trainee Engineer Electrical Mock Test Series 2024 for Electrical Engineering (EE) & BEL Trainee Engineer Electrical Mock Test - 1 solutions in Hindi for BEL Trainee Engineer Electrical Mock Test Series 2024 course. Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free. Attempt BEL Trainee Engineer Electrical Mock Test - 1 | 100 questions in 120 minutes | Mock test for Electrical Engineering (EE) preparation | Free important questions MCQ to study BEL Trainee Engineer Electrical Mock Test Series 2024 for Electrical Engineering (EE) Exam | Download free PDF with solutions
BEL Trainee Engineer Electrical Mock Test - 1 - Question 1

Fourier transform of a discrete and aperiodic sequence is:

Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 1

Let F(ω) is the Fourier transform of f(t).

BEL Trainee Engineer Electrical Mock Test - 1 - Question 2

The closed loop transfer function is . What will be the open loop DC gain if unity feedback system is considered for closed loop system?

Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 2

The closed-loop transfer function (CLTF) for unity feedback is given by:

Rearranging the above to get the Open Loop transfer function G(s), we get:

Putting s = 0, we get the DC gain as:

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BEL Trainee Engineer Electrical Mock Test - 1 - Question 3

The output saturation voltages of the Schmitt trigger circuit shown in the figure is ±15 V. The input trip point voltages are

Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 3

Applying KCL at V+,

⇒ 5V+ - 8 = V0

From the fig. V+ = Vin

⇒ 5Vin = V0 + 8

Given Vsat = ±15 volts

So, for positive saturation, V0 = +15 V

⇒ V+ = Vin = 4.6 V

Now, for negative saturation, V0 = -15 V

⇒ V+ = Vin = -1.4 V

BEL Trainee Engineer Electrical Mock Test - 1 - Question 4
The unit step response for a relaxed system is c(t) = 1 – e-3t; t ≥ 0; What will be its transfer function?
Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 4

Concept:

The transfer function is defined as the ratio of Laplace transform of the output to the Laplace transform of the input by assuming initial conditions are zero.

TF = L[output]/L[input]

For unit impulse input i.e. r(t) = δ(t)

⇒ R(s) = δ(s) = 1

Now transfer function = C(s)

Therefore, transfer function is also known as impulse response of the system.

Transfer function = L[IR]

IR = L-1 [TF]

Calculation:

c(t) = 1 – e-3t

Applying Laplace transform, i.e. time domain into s- domain

Input is unit step, i.e. r(t) = u(t)

Transfer function
BEL Trainee Engineer Electrical Mock Test - 1 - Question 5

The three characteristics shown in the given graphs, represent which of the following motors?

Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 5

In a DC motor, T ∝ ϕIa

In series motor, ϕ ∝ Ia

⇒ T ∝ (Ia)2

In shunt motor, ϕ is constant

⇒ T ∝ Ia

The characteristic of DC series and shunt motor are shown below.

Characteristics of DC series motor:

Characteristics of DC shunt motor:

BEL Trainee Engineer Electrical Mock Test - 1 - Question 6

A circuit with a resistor, inductor, and capacitor in parallel is at resonant of f0 Hz. If all the component values are now doubled the new resonant frequency is:

Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 6

Concept:

In a parallel resonance circuit at the resonating frequency reactance will be ∞ and a combination of L & C will be open-circuited but however the LC combination work by exchanging their previously stored energy.

At the resonance:

IL = -jQ0I and,

IC = +jQ0I.

This is “current amplification”

‘Q0’ indicates the quality factor, ‘I’ indicates the source current, ‘IL‘ indicates the inductive current at the resonance and ‘IC’ indicates the capacitive current at the resonance

Analysis:

The general parallel RLC circuit is mentioned below

The Laplace domain of the above parallel RLC circuit is

Finding resonance frequency (fr)

Admittance (Y) calculation is easy in a parallel circuit and it is inversely proportional to the impedance

Comparing the equation (i) with Y = G ± jBnet we get

At the resonance, the imaginary part will be zero. So making 

After solving it,

We get  Radians/sec

Resonating frequency

Application:

For a parallel RLC circuit

When all components get doubled then-new resonant frequency (f0') becomes,

BEL Trainee Engineer Electrical Mock Test - 1 - Question 7

For the measurement of high resistances following methods are used:

1. Loss of Charge Method

2. Direct Deflection Method

3. Substitution Method

Which of the following is/are correct?

Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 7

The Measurement of Resistance according to classification is shown below:

BEL Trainee Engineer Electrical Mock Test - 1 - Question 8
What is the composition of carbon resistance?
Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 8

Carbon:

  • Carbon has approximate characteristics for resistance due to which carbon had been used in resistor construction for over a century.
  • One of the main reasons is that resistors made out of carbon are regarded as highly reliable, that is, they don't fail often. They are also very effective at high energy levels.
  • Carbon resistors can be found in two forms - carbon composition and carbon film.

Carbon composition resistors:

It contain both solid carbon (graphite) and a clay additive to help with durability and were formed with properly separated carbon black.

They are less common today due to their higher cost and lower reliability in high humidity applications.

  • Because carbon resistors hold up well at high energy levels, they are often utilized in power supply applications.
  • This includes both high voltage uses, like you would see being used by an electrical utility provider, and lower voltage applications, like a simple power strip-style surge protector or other home electronics.

Carbon film resistors:

  • These are often used in devices involving x-rays and lasers and have some use with radar and welding technology as well.
  • And chances are you probably have at least a few electronic devices in your home containing a carbon film resistor, perhaps even the surge protector your computer or cell phone is currently plugged in to.
BEL Trainee Engineer Electrical Mock Test - 1 - Question 9
A wattmeter reads 25.34 W. The absolute error in measurement is - 0.11 W. What is the true value of power:
Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 9

Given that,

Measured value = 25.34 W

Absolute error = - 0.11 W

Absolute error = Measured value – true value

⇒ -0.11 = 25.34 – true value

⇒ 25.34 + 0.11 = 25.45 W
BEL Trainee Engineer Electrical Mock Test - 1 - Question 10

Which of the following is digital transducer?

Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 10

Analog transducer: It converts the input signal into an output signal, which is a continuous function of time.

Ex: Thermistor, strain gauge, LVDT, thermocouple

Discrete transducer: It converts the input signal into the output signal, in the form of pulses i.e. it gives the discrete output.

Ex: Encoder, digital resolvers, digital tachometers, hall effect sensors, limit switches

Encoder:

It is a digital transducer which generates pulses corresponding to the angular rotation of the shaft.

They are further classified into two category

  • Incremental encoder
  • Absolute type optical encoder

Incremental encoder

It generates equally spaced pulses base on angular rotation of shaft

Absolute type optical encoder

sIt generates directly binary logic based on angular rotation of the shaft.

BEL Trainee Engineer Electrical Mock Test - 1 - Question 11

An amplifier has open loop gain of 50, input and output impedance of 1 kΩ and 0.5 kΩ respectively. A negative feedback circuit with a factor of 0.8 is connected to the amplifier in current shunt configuration. The input and output impedances with feedback are _____ and _____ respectively

Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 11

Concept:

The comparison of different feedback configuration is as follows:


Calculation:

Open loop gain (A) = 50

Input impedance (Ri)= 1 kΩ

Output impedance (Ro)= 0.5 kΩ

Negative Feedback factor (β) = 0.8

The amplifier is connected in current shunt configuration:

Rif = Ri / (1 + A) = 1000 / {1 + (50 × 0.8)} Ω = 24.39 Ω

Rof = Ro (1 + A) = 0.5{1 + (50 × 0.8)} kΩ = 20.5 kΩ

BEL Trainee Engineer Electrical Mock Test - 1 - Question 12
Which of the following conditions must be used for avoiding local hot spots in SCR?
Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 12
  • When a thyristor or SCR is forward biased and is turned on by gate pulse, the conduction of anode current begins in the immediate neighbourhood of the gate cathode junction.
  • Thereafter, the anode current spread over the entire gate cathode junction area.
  • The thyristor or SCR is designed in such a way to permit the speared of current in the entire junction are as soon as possible.
  • But in case, the rate of rise of anode current di/dt is more than the spread velocity of the current in the junction area, then there will a chance for the formation of local hot spot.
  • Since the current rises in the vicinity of the gate to cathode junction, hot spot may be formed in that region.
  • This hot spot formation is harmful for the SCR and may damage it
  • Local spot heating is avoided by ensuring that the conduction spreads to the whole area very rapidly or the di/dt value must be maintained below a threshold (limiting) value.
  • This is done by means of connecting an inductor in series with the thyristor.
BEL Trainee Engineer Electrical Mock Test - 1 - Question 13

A single-phase fully controlled rectifier has an average voltage of ‘P’ volts when α = 0°. Its output voltage when α = 30° is:

Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 13

Concept:

In a single-phase fully controlled rectifier, the average output voltage is given by

Where Vis the maximum value of supply voltage

α is firing angle

Calculation:

At α = 0°, the average output voltage (Vo) = P volts

At α = 30°, the average output voltage will be

BEL Trainee Engineer Electrical Mock Test - 1 - Question 14

Find the node voltage Vb in the given network.

Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 14

By using source transformation, the parallel combination of 2 A current source and 20 ohm resistance can be replaced by a series combination of 40 V voltage source with 20 ohm resistance

Now, the given circuit becomes

 

Now by applying KVL in the left most loop, we get

40 + 20 I + 10 + 30 (5 + I) = 0

50 I = – 200

⇒ I = – 4 A

Now Voltage across node ‘b’ can be calculated as

Vb = 30 (5 + I) = 30 (5 – 4)

Vb = 30 V

BEL Trainee Engineer Electrical Mock Test - 1 - Question 15
The main purpose of Accumulator register of 8085 is
Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 15

Registers in 8085 are primarily used to store temporary data.

General Purpose Registers:

  • There are six 8-bit registers B, C, D, E, H, L. Each register contains 8 flip-flops hence, each register can store a maximum of 8 bit (1 Byte) of data.
  • For storing data greater than 8 bits, these registers are used in pairs. There are three register pairs: BC pair, D – E pair, HL pair
  • Each register pair can store a maximum of 16 bits of data (2 Byte).

Accumulator:

  • It is an 8-bit register that contains 8 flip-flops. It can store a maximum of 8 bits of data.
  • The importance of the accumulator is that, in most of the 8-bit arithmetic and logical operations, the microprocessor will always take the first 8-bit number from the accumulator.

Temporary Registers:

  • There are three 8-bit registers W, X, and Z.
  • Each register can store a maximum of 8 bits of data.
  • These registers cannot be used or accessed by the programmer.
  • These registers can be used only by the microprocessor for executing its operation i.e., the microprocessor will use these registers for the temporary storage of data.
  • For storing 16-bit data W – Z pair can be used by the microprocessor.
BEL Trainee Engineer Electrical Mock Test - 1 - Question 16

In a 8085 microprocessor the first machine cycle of an instruction is

Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 16

The time required by the microprocessor to complete an operation of accessing memory or input/output devices is called Machine Cycle

The 4 steps involved in machine cycle in order are:

Fetch

decode

execute

store

In execution of any instruction first cycle is op-code fetch cycle.

After that depending upon the given instruction the memory read/write and I/O read/ write cycle occurs.

BEL Trainee Engineer Electrical Mock Test - 1 - Question 17

For the negative feedback amplifier shown in the given figure, the gain with feedback is 100. What is the gain without feedback?

Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 17

Concept:

For the negative feedback amplifier, the closed-loop gain is given by:

For the positive feedback amplifier, the closed-loop gain is given by:

Where AOL is the open-loop gain

β is the gain of the feedback

Calculation:

The gain of feedback (β) = 0.009

Gain with feedback = 100

⇒ 0.9 AOL + 100 = AOL

⇒ AOL = 1000

Gain without feedback or open-loop gain (AOL) = 1000

BEL Trainee Engineer Electrical Mock Test - 1 - Question 18

If all the sequence voltages at the fault point in a power system are equal, then the fault is

Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 18

Double Line to line Ground Fault (LLG):

  • In double line-to-ground fault, the two lines come in contact with each other along with the ground.
  • The probability of such types of faults is nearly 10%.
  • All sequence networks are connected in parallel.

Ia0 + Ia1 + Ia2 = 0

Va0 = Va1 = Va2

IF = 3Ia0

Additional Information

BEL Trainee Engineer Electrical Mock Test - 1 - Question 19

Directions: In this question, a phrase in the sentence is given in underlined. You are required to pick the option that best describes the meaning of the phrase, in the given context of the sentence.

You definitely cracked them up with your witty jokes and timely sense of humour.

Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 19

The idiom crack someone up can be used to imply that you actually make someone laugh with something. It is regarding bringing a smile on the faces of people. Among the given options we can easily choose option D since it gives us the correct meaning of the phrase in underlined whereas the rest can be eliminated from consideration.

This makes option D the correct choice among the given options.

BEL Trainee Engineer Electrical Mock Test - 1 - Question 20

Direction: Choose the option closest in meaning to the OPPOSITE of the word given in capitals.

ENGENDER

Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 20

Engender is to cause or create.

BEL Trainee Engineer Electrical Mock Test - 1 - Question 21

What is the use of MS Powerpoint?

Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 21

The correct answer is the Presentation program.

Key Points

  • Microsoft PowerPoint
    • It is a powerful slide show presentation program. Hence, Option 4 is correct.
    • It is a standard component of the company's Microsoft Office suite software and is bundled together with Word, Excel, and other office productivity tools.
    • The program uses slides to convey information rich in multimedia.

Additional Information

BEL Trainee Engineer Electrical Mock Test - 1 - Question 22
In the domain name .org implies:
Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 22

Domain Name:

  • It resolves to the hostname of an IP address.
  • It utilizes a hierarchical naming pattern and a distributed database of IP addresses and associated names.
  • Domain names are symbolic strings associates with an IP address.
  • Domain names are bifurcated into 2 main categories:- i) Generic top-level domains which represent the sponsored designated agencies, ii) ccTLD's (Country code top-level domains which represent the Nation designation.
  • The top generic level domains currently in the world are:-
  1. .aero - air transport industry
  2. .asia - Asian Pacific region
  3. .biz - business but all user
  4. .cat - catan linguistic and cultural community
  5. .com - commerce unit
  6. .coop - cooperatives
  7. .edu - Higher educational institutions
  8. .gov - Government departments
  9. .info - informational sites
  10. .int - International organizations
  11. .job - Employment related portals
  12. .mil - US Military department
  13. .mobi - Mobile users
  14. .museum - Museaum/historical sites
  15. .name - Individuals
  16. .net - networks but unresttricted/all purpose
  17. .org - organizations
  18. .pro - Professional service providers
  19. .tel - Online directory 
  20. .travel - Travel industry
BEL Trainee Engineer Electrical Mock Test - 1 - Question 23

The full form of HTML is:

Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 23

The full form of HTML is Hypertext Markup Language.

 Key Points

  1.  HTML, in a full hypertext markup language, a formatting system for displaying material retrieved over the Internet.
  2. Each retrieval unit is known as a Web page (from World Wide Web), and such pages frequently contain hypertext links that allow related pages to be retrieved.
  3. HTML is the markup language for encoding Web pages.
BEL Trainee Engineer Electrical Mock Test - 1 - Question 24

Which of the following fields CANNOT be left blank while sending an email?

Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 24

Key Points
The To field is, according to the rules of email etiquette, meant for the main recipient(s) of your email. To be more precise, this field should be used to include the recipients who are required to take action in response to the email.

Hence the correct answer is To.

Additional Information
Cc stands for carbon copy which means that whose address appears after the Cc: header would receive a copy of the message.

  • Bcc stands for blind carbon copy which is similar to that of Cc except that the Email address of the recipients specified in this field does not appear in the received message header and the recipients in the To or Cc fields will not know that a copy sent to these address.
  • The subject line of an email is the single line of text people see when they receive your email. This one line of text can often determine whether an email is opened or sent straight to trash, so make sure it's optimized toward your audience.
BEL Trainee Engineer Electrical Mock Test - 1 - Question 25

The resolution of a printer is measured in ________.

Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 25

The correct answer is DPI (dots per inch).

  • The resolution of a printer is measured in DPI.

Key Points

  • The resolution of a printer 
    • In printing, the term Resolution refers to the sharpness and detail of images.
    • Higher resolution means more image detail.
    • Lower resolution means less image detail.
    • Common measures of resolution include
      • Pixels per inch (PPI).
      • Dots per inch (DPI).

Additional Information

  • Difference PPI and DPI
  • Dots per inch (DPI)
    • DPI refers to the number of printed dots contained within one inch of an image printed by a printer.
  • Pixels per inch (PPI) 
    • PPI refers to the number of pixels contained within one inch of an image displayed on a computer monitor.
BEL Trainee Engineer Electrical Mock Test - 1 - Question 26

Which of the following is a soft copy output device ?

Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 26

The correct answer is the Visual Display Unit (VDU).

  •  A Visual Display Unit (VDU) is also referred to as a Monitor and VDU (video display unit), a monitor is an output device that displays video images and text.
  • A monitor is made up of circuitry, a screen, a power supply, buttons to adjust screen settings, and a casing that holds all of these components.
  • Like most early TVs, the first computer monitors were comprised of a CRT (cathode ray tube) and a fluorescent screen.
  • Today, all monitors are created using flat panel display technology, usually backlit with LEDs (light-emitting diode).

Important Point

  • Soft copy output devices give screen displayed output that is lost when the computer is shut off.
  • Once the soft copy is printed or burned, it is referred to as a hard copy.
  • Audio Output is a type of soft copy.

Additional Information 

BEL Trainee Engineer Electrical Mock Test - 1 - Question 27

Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

Question -

14 : 9 :: 26 : ?

Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 27

14 = (2 x 9 - 4)

26 = (2 x 15 - 4)

? = 15

BEL Trainee Engineer Electrical Mock Test - 1 - Question 28

Directions: Each of the following consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the question.

Among six persons – Rishi, Sanjay, Komal, Usha, Vijay and Tarak, each of different heights. Who is the tallest?
Statement I:
Tarak is taller than only one person. Komal is taller than Rishi but shorter than Vijay.
Statement II: Rishi is taller than both Tarak and Sanjay. Vijay is not the tallest.

Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 28

Checking Statement I:

Using the above references, we get the information:
 
_ > _ > _ > _ > Tarak > _

Vijay > Komal > Rishi

Here, we cannot merge the above inferences to form a single arrangement of the order of heights of these persons.

So, we cannot say who among these persons is the tallest.

Hence, data in statement I alone is not sufficient.

Checking Statement II:

Using the above references, we get the information:

Rishi > Tarak/Sanjay

So, we cannot say who among these persons is the tallest.

Hence, data in statement II alone is not sufficient.

Checking Statements I and II:

Using the above reference, we get the following arrangement:

Usha > Vijay > Komal > Rishi > Tarak > Sanjay

Clearly, both statements I and II together are sufficient to answer the question.

Hence, Option D is correct.

BEL Trainee Engineer Electrical Mock Test - 1 - Question 29

Direction: Study the following information carefully and answer the given questions besides.

Six person A, B, C, D, E and F sit around a triangular table. One person sits at each corner of the table facing away from the centre while one person sits at the middle of each edge facing toward the centre.
Three persons sit between C and D, who is not facing the centre. F sits third to the left of C. A is not an immediate neighbour of D. A sits second to the left of E.

Q. What is the position of B with respect to D?

Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 29

From the common explanation, we get B sits second to the left of D.
Hence, Option D is correct.
Final Arrangement:

Common explanation:
References:

Six person A, B, C, D, E and F sit around a triangular table.
One person sits at each corner of the table facing away from the centre while one person sits at the middle of each edge facing toward the centre.
Inferences:
So, we need to arrange as follows to accommodate the information as stated in the question,

References:
Three persons sit between C and D, who is not facing the centre.
Inferences:
From the above reference, we get two different cases:
Case 1:

Case 2:

References:
F sits third to the left of C.
A sits second to the left of E.
A is not an immediate neighbour of D.
Inferences:
So, from this case 2 will be eliminated as A is not an immediate neighbour of D.
Case 1:

Case 2: (Eliminated)

Hence, Case 1 is the final arrangement.

BEL Trainee Engineer Electrical Mock Test - 1 - Question 30

'Indolence' is related to 'Work' in the same way as 'Taciturn' is related to:

Detailed Solution for BEL Trainee Engineer Electrical Mock Test - 1 - Question 30

As 'Indolence' and 'Work' are opposite to each other in the same way 'Taciturn' and 'speak' are opposite to each other.

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