BITSAT Logical Reasoning Test - 5 - JEE MCQ

E is the neighbour of A and D. G is the neighbour of D and C.

F is sitting to the immediate right of A. So, possibility 2 is eliminated.

FBC are sitting in a sequence.

E is the immediate neighbour of A and D. G is the immediate neighbour of D and C.

F is sitting to the immediate right of A. So, possibility 2 is eliminated.

F and C are the immediate neighbours of B.

In the coding, first letter is exchanged with fifth letter and then fourth letter is shifted to front.
So GRADIENT is coded as DIRAGENT.

In DHEG, as D is the fourth letter of the English alphabet, it is replaced by the fifth letter from behind. H is the eight letter of the English alphabet, so it is replaced by the tenth letter from behind. E is the fifth letter from front, so it is replaced by the eighth letter from behind.

So,
C >> 3 + 1 = 4 = W
I >> 9 + 2 = 11 = P
B >> 2 + 3 = 5 = V
F >> 6 + 4 = 10 = Q

(4, 17, 288)
4₂ + 1 = 17
17² - 1 = 288
(3, 10, 99)
3² + 1 = 10
10² - 1 = 99
Similarly,
2² + 1 = 5
5² - 1 = 24
Hence (2, 5, 24) is the required solution.

In the given codes we can observe a pattern for the first alphabet of each alphanumeric sets given that there is an increment of +3 position value.Q →⁺³ U →⁺³ Y →⁺³ C
For the numbers in the alphanumeric sets, the numbers are at a gap of 111 meaning the fourth value should have the number 553 + 111 = 664. And only by these two criteria we can determine that the correct option whose first alphabet is C and numbers as 664 is this option.
T →⁺⁴ X →⁺³ A→⁺² C

The given series is
ADG, GJM,___.
By analyzing the given series we can say that here in every next term we have to add 6 in the first letter, the second letter as well as in the third letter.

Therefore, the next term will be MPS.
Hence, the correct answer is MPS.

The elements of series I and series II respectively, which are exactly in the middle of the seventh element from the left end and the sixth element from the right end in series I and II:
In series 1: Seventh element from left end: u
Sixth element from the right: 1

In series 2:
Seventh element for left end: J
Sixth element from the right: 1

Hence, the correct answer is sQ.

If we look at the series closely, the first letter of each set is a letter in reverse order of the English alphabet series.
The last three alphabets of each set are written in the form below but in reverse order:
ABC, DEF, GHI : CBA, FED, IHG.
Therefore, the fourth set of alphabets will be JKL: LKJ.
Hence, the fourth set in the series is WLKJ.

One letter is missing between the two letters of each term (B is missing between A and C) and two letters are missing between the last and first letters of two consecutive terms (D and E are missing between C and F).
So, on following the same pattern, we can conclude that the next term will be UW. Hence, option (C) is correct.

Given series:
BD, FH, JL, NP, ?
By observing the given series, we can find that 2 is added to the place value of the first letter of each pair to get the second letter of the pair and 2 is added to the second letter of each pair to get the first letter of the next pair.
The pattern is shown below:

So, by following this pattern, we can conclude that the next term will be RT.
Hence, this is the correct answer.

As in the first figure;
(9 × 10) − (4 × 8) = 90 − 32 = 58
Similarly, following the same pattern, we get;
(15 × 10) − (9 × 8) = 150 − 72 = 78 
Hence, the correct answer is 78.

The relation between letters of the words given in this series has been shown in the figure below

It is clear from the figure that there is a gap of +2 , −1  and −2 between the respective letters of the successive words.
Next word in the series will also follow this pattern as indicated in the figure below

So, the missing word will be LGQ.

The given series is L_NO_ _MLLM_OO_ML .
Now, the given series will be divided into four parts or make a pair of four characters each.
L_NO / _ _ML / LM_O / O_ML
The first and third parts are in sequence i.e., LMNO  and the second and fourth parts are in reverse i.e., ONML.
The correct sequence is LMNO / ONML / LMNO / ONML.
Hence, option D is the correct answer.

Given series:
Z A Y B X C _____
According to the given series, the first, third, and fifth letters of the series are in reverse alphabetical order while second, fourth and sixth letters are in alphabetical order.
Therefore, in the blank space of the series there should be the next letter of the reverse alphabetical order which is W.
Hence, W is the answer.

Give numbers series- 4, 5, 6, 9, 8, 13, 10, ...
Odd positioned numbers are 4, 6, 8, 4 , 6 , 8 , and 10.
4 + 2 = 6 ; 6 + 2 = 8 ; 8 + 2 = 10
The difference between odd positioned numbers is 2.
Even positioned numbers are 5, 9, and 13.
5 + 4 = 9 ; 9 + 4 = 13
The difference between even positioned numbers is 4. Here, the missing number is even positioned. Thus, next number will be 13 + 4 = 17 .

Given series is,
319, 320, 347, 472, 815, ?

As per given number series in the question, we found the following pattern of the series:
⇒ 0(+3) → 3(+5) → 8(+7) → 15(+9) → 24(+11) → 35(+13) → 48
From the above series pattern, we can clearly see that difference of two consecutive numbers is increasing by 2. Hence, 48 is the answer.

Considering the difference between two terms we find that the first and second term differ by 35 , the second and third  term differ by 28, the third and fourth term differ by 21, the fourth and fifth term differ by 14. Observing the difference we conclude that the difference between the terms are decreasing and they are equal to the multiples of 7 in order. Considering this rule the difference between the fifth and sixth term should be 7. Hence, the next term will be, (11−7) = 4