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Bihar STET Paper 2 Chemistry Mock Test - 5 - Bihar PGT/TGT/PRT MCQ


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30 Questions MCQ Test Bihar STET Mock Test Series 2024 - Bihar STET Paper 2 Chemistry Mock Test - 5

Bihar STET Paper 2 Chemistry Mock Test - 5 for Bihar PGT/TGT/PRT 2024 is part of Bihar STET Mock Test Series 2024 preparation. The Bihar STET Paper 2 Chemistry Mock Test - 5 questions and answers have been prepared according to the Bihar PGT/TGT/PRT exam syllabus.The Bihar STET Paper 2 Chemistry Mock Test - 5 MCQs are made for Bihar PGT/TGT/PRT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Bihar STET Paper 2 Chemistry Mock Test - 5 below.
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Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 1

What is the correct order of reactivity of the followings in hydrolysis reaction at elevated temperature?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 1

(II) is most reactive as it forms aromatic carbocation (III) is next most reactive as it forms allylic carbocation. (I) is least reactive as it forms least stable cyclopropyl carbocation.

Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 2

Which is the most suitable reagent for the following transformation?

 

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 2

Wolff-Kishner reduction is suitable for reduction of carbonyls containing olefinic bonds. If Clemmensen reduction is done, HCI also attacks olefinic bonds.

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Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 3

Hardness of water is due to the presence of:

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 3

Permanent hardness in water is hardness due to the presence of the chlorides, nitrates and sulphates of calcium and magnesium, which will not be precipitated by boiling. The lime scale can build up on the inside of the pipe restricting the flow of water or causing a blockage.

Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 4

Why some of the physical properties of solids show different values when measured along different directions in the same crystals?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 4
  • Crystalline solids are anisotropic in nature, that is, some of their physical properties like electrical resistance or refractive index show different values when measured along with different directions in the same crystals.
  • This arises from different arrangements of particles in different directions.
Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 5

The total number of tetrahedral voids in the face-centred unit cell is

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 5

(b) Unit cell of fee is divided into eight small cubes. Each cube has four atoms at alternate positions. When joined to each other, they make a regular tetrahedron.
Thus, number of tetrahedral void in small cube = 1 and in eight cubes, voids = 8.

Note  If number of atoms in a cube = N, then, number of octahedral voids = N and number of tetrahedral voids = 2N

Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 6

Which does not form dihalide when treated with ethylene glycol?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 6

(d) PI3 does not form di iodide with vicinal diols.

Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 7

An unsaturated hydrocarbon on jcomplete hydrogenation gives 1-isopropyl-3 methylcyclohexane, after ozonolysis it gives one mole of formaldehyde, one mole of acetone and one mole of 2,4-Dioxohexanedial. The possible structures of the hydrocarbon maybe

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 7

The correct answer is Option A.

Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 8

The best set of reagents for the following transformation is 

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 8

Aloxy mercuration - demercuration brings about Markownikoff’s addition of alcohols at   without any rearrangement.

Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 9

In Bohr series of lines of hydrogen spectrum, third line from the red end corresponds to where one of the following inter-orbit jumps of electron for Bohr orbits in an atom of hydrogen.                [AIEEE- 2003]

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 9

The electron has minimum energy in the first orbit and its energy increases as n increases. Here n represents number of orbit, i.e. 1st, 2nd, 3rd .... The third line from the red end corresponds to yellow region i.e. 5. In order to obtain less energy electron tends to come in 1st or 2nd orbit. So jump may be involved either 5 → 1 or 5 → 2.

Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 10

Dinucleotide is obtained by joining two nucleotides together by phosphodiester linkage. Between which carbon atoms of pentose sugars of nucleotides are these linkages present?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 10

The correct answer is option A
Nucleotides are joined together by phosphodiester linkage between 5′ and 3′ carbon atoms of pentose sugar.
 

Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 11

The physical properties of isotopes differ due to:

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 11

The physical properties of isotopes of the same element are not identical because the atomic mass and mass number differ. This affects physical properties such as density and temperature of change of state, eg. boiling and melting point.

*Multiple options can be correct
Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 12

Direction (Q. Nos. 15-16) This section contains  a paragraph, wach describing theory, experiments, data etc. three Questions related to paragraph have been given.Each question have only one correct answer among the four given options (a),(b),(c),(d)

The complex [Fe(H2O)5NO]2+ is formed in the ring-test for nitrate ion when freshly prepared FeSO4 solution is added to aqueous solution of followed by the addition of conc. H2SO4. NO exists as NO(nitrosyl).

Q.Oxidation number of the Fe in the ring is

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 12

Let, oxidation number of Fe = x

Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 13

Which of the following statement is true about Langmuir’s adsorption?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 13

Langmuir isotherm assume monolayer formation only.

Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 14

Heat of hydrogenation of ethene is x1 and that of benzene is x2. The resonance energy of benzene is

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 14

Energy of ethene =x1
Number of ethene in benzene=3.
Therefore, Observed energy of hydrogenation of benzene =3x1
Calculated energy of hydrogenation of benzene =x2 (Given)
Therefore, 
Resonance energy = observed - calculated =3x1−x2

Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 15

Correct IUPAC name of the co,pound 

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 15

Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 16

The quantum number which specifies the location of an electron as well as energy is      

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 16

According to the given sets of options, only option d is correct. The reason or exceptional configuration of Cr is stability of half-filled d subshell. If the Aufbau principle was not followed then the configuration of Cr be [Ar] 3d6. So, if the Aufbau principle won’t be followed, then the options won’t have an electron in their 4s subshell.
 

*Multiple options can be correct
Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 17

Direction (Q. Nos. 16-18) This section contains 4 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or  MORE THANT ONE  is correct.

Q. Set of species with identical bond order is/are

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 17

isoelectronic species will generally have identical bond order:

Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 18

Hot carbon reacts with steam to produce an equimolar mixture of CO(g)and H2(g) known as water gas

    

Q. 
Energy released , if water gas is used as fuel is

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 18


For this, we will add combustion reactions of both CO and H2 as both combined will give us energy.
ΔrH = -283 kJ+ (-242 kJ) = -525 kJ

Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 19

The dispersion of one liquid in another liquid is called as:

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 19

The colloidal dispersion of a liquid in a liquid is called emulsion.
In these systems, one liquid is dispersed in another  liquid immiscible with it.
For example, milk is an emulsion of oil in water. The particles of liquid fat are dispersed in water.
Cod Liver oil is an emulsion of water in oil. consists of particles of water dispersed in oil.

Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 20

The order of solubility of lithium halides in non polar solvents follows the order.

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 20

As the size of the anion increases from  to , the covalent character increase and hence the solubility in non-polar solvent increases. 

Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 21

Determinants of individual differences in human beings relate to  

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 21

Determinants of Individual differences in human beings relate to both heredity and environment interacting together. By heredity we mean the influence of factors inherent in the child himself from the time he is conceived. Environment also plays a key role in the individual's development.

Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 22
Methods used to organize classroom activities and instruction, creating a happy and productive learning environment are known as
Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 22

Classroom management: Classroom management refers to the actions and strategies teachers use to solve the problems of order in classrooms.

It involves activities such as:

  • stating a set of ground rules for the classroom and organizing instruction
  • taking charge of the classroom activities
  • creating a productive learning environment
  • planning strategies to deal with potential problems

NOTE:

Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 23

It is said that a teacher is a friend, philosopher and guide because

  1. a teacher imparts high values to pupils
  2. a teacher spends a lot of time with the students
  3. a teacher is a reformer

Choose from the options given below:

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 23

It is said that a teacher is a friend, philosopher and guide because a teacher plays all these vital roles in respect of pupils. It is based on the intent and capacity that a teacher possesses, exposed to which, a student is influenced to make a positive difference in his own life as well as in the society and the world at large.

Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 24

_____ motives deal with the need to reach satisfying feeling states and to obtain personal goals.

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 24

Affective motives deal with the need to reach satisfying feeling states and obtain personal goals. Maslow's theory deals with all types of needs. His Hierarchy of Needs Theory includes Psychological needs (food, air, water.) Safety needs (personal security, health.) Love and Belonging need (friendship, intimacy.) Esteem needs (respect, status.
Hence, this is the correct answer.

Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 25
The highest production and largest reserves of manganese ore lies in the state
Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 25

The correct answer is Odisha.

Key Points

  • India is the world's fifth-largest producer of manganese after China, Gabon, South Africa, and Australia.
  • Manganese is not found as a free element in nature. It is usually found in combination with iron.
  • The most important manganese ore is pyrolusite.
  • Manganese is primarily used in the iron and steel industry.
  • It is the essential raw material for manufacturing steel alloys.
  • 6 kilograms of manganese ore is required for manufacturing one tonne of steel.
  • State-wise reserves of Manganese:
    • Odisha (44%),
    • Karnataka (22%),
    • Madhya Pradesh (13%), etc.
Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 26

Recently, India surpassed which country to become the fourth-largest equity market globally?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 26

India recently overtook Hong Kong as the world’s fourth-largest equity market, boasting a total market value of $4.33 trillion, surpassing Hong Kong’s $4.29 trillion. The leading global stock markets are currently the U.S., China, and Japan. This milestone underscores India’s rising prominence in the global financial arena, propelled by a robust GDP, political stability, foreign investments, and its appeal as an alternative to China. Meanwhile, Hong Kong grapples with challenges like COVID-19 restrictions, regulatory crackdowns, a property crisis, and geopolitical tensions, affecting its attractiveness to investors.

Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 27

Where will the 27th World Investment Conference (WIC) be hosted by Invest India?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 27

Invest India will host the 27th World Investment Conference (WIC) in New Delhi from December 11-14, 2023, providing a platform for global collaboration and discussions on shaping the future of investments.

Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 28

Directions: Answer the following question by selecting the most appropriate option.
How much percentage of water in the oceans is drinkable?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 28

This is the correct option because ocean water is not fit for drinking.

Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 29

Directions: Answer the following question by selecting the most appropriate option.
Which of the following is/are a biodegradable waste?

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 29

This is the correct option because none of the above is biodegradable. Biodegradable waste includes any organic matter in waste which can be broken down into carbon dioxide, water, methane or simple organic molecules by micro-organisms and other living things using composting, aerobic digestion, anaerobic digestion or similar processes.

Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 30

In a triangle ABC, incentre is O and ∠BOC = 110o, then the measure of ∠BAC

Detailed Solution for Bihar STET Paper 2 Chemistry Mock Test - 5 - Question 30

As given,
∠BOC = 110o
And, we know incentre of a triangle is a point where angle bisector of triangles meet.
So, which means ∠OCB =∠OBC
∠BOC +∠OCB+∠OBC = 180o
⇒∠OCB + ∠OBC = 180o − 110o
⇒∠OCB +∠OBC = 70o

Since, ∠ABC = 2∠OBC
∠ACB = 2∠OCB
So, ∠ABC+∠ACB = 2 × 70o
⇒∠ABC + ∠ACB = 140o
Now, in triangle ABC.
∠ABC +∠BAC +∠ACB = 180o
⇒∠BAC  +140o = 180o
⇒∠BAC = 180o − 140o
⇒∠BAC = 40o
Hence, the correct answer is 40o.

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