All Courses
Get the App Signup / Login
Sign in Open App
RPSC RAS (Rajasthan) Exam  >  RPSC RAS (Rajasthan) Tests  >  RAS RPSC Prelims Preparation - Notes, Study Material & Tests  >  Boat And Stream - MCQ Test(1) - RPSC RAS (Rajasthan) MCQ

Boat And Stream - MCQ Test(1) - RPSC RAS (Rajasthan) MCQ


Test Description

16 Questions MCQ Test RAS RPSC Prelims Preparation - Notes, Study Material & Tests - Boat And Stream - MCQ Test(1)

Boat And Stream - MCQ Test(1) for RPSC RAS (Rajasthan) 2024 is part of RAS RPSC Prelims Preparation - Notes, Study Material & Tests preparation. The Boat And Stream - MCQ Test(1) questions and answers have been prepared according to the RPSC RAS (Rajasthan) exam syllabus.The Boat And Stream - MCQ Test(1) MCQs are made for RPSC RAS (Rajasthan) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Boat And Stream - MCQ Test(1) below.
Solutions of Boat And Stream - MCQ Test(1) questions in English are available as part of our RAS RPSC Prelims Preparation - Notes, Study Material & Tests for RPSC RAS (Rajasthan) & Boat And Stream - MCQ Test(1) solutions in Hindi for RAS RPSC Prelims Preparation - Notes, Study Material & Tests course. Download more important topics, notes, lectures and mock test series for RPSC RAS (Rajasthan) Exam by signing up for free. Attempt Boat And Stream - MCQ Test(1) | 16 questions in 25 minutes | Mock test for RPSC RAS (Rajasthan) preparation | Free important questions MCQ to study RAS RPSC Prelims Preparation - Notes, Study Material & Tests for RPSC RAS (Rajasthan) Exam | Download free PDF with solutions
Boat And Stream - MCQ Test(1) - Question 1
Save

A man's speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is:

Detailed Solution for Boat And Stream - MCQ Test(1) - Question 1

Option B

Explanation :Man's speed with the current = 15 km/hr=>speed of the man + speed of the current = 15 km/hrspeed of the current is 2.5 km/hrHence, speed of the man = 15 ‐ 2.5 = 12.5 km/hrman's speed against the current = speed of the man ‐ speed of the current= 12.5 ‐ 2.5 = 10 km/hr

Boat And Stream - MCQ Test(1) - Question 2
Save

In one hour, a boat goes 14 km/hr along the stream and 8 km/hr against the stream. The speed ofthe boat in still water (in km/hr) is:

Detailed Solution for Boat And Stream - MCQ Test(1) - Question 2

Option B

Explanation :Let the speed downstream be a km/hr and the speed upstream be b km/hr, thenSpeed in still water =1/2(a+b) km/hr and Rate of stream =1/2(a−b) km/hrSpeed in still water = 1/2(14+8) kmph = 11 kmph.

1 Crore+ students have signed up on EduRev. Have you? Download the App
Boat And Stream - MCQ Test(1) - Question 3
Save

A boatman goes 2 km against the current of the stream in 2 hour and goes 1 km along the currentin 20 minutes. How long will it take to go 5 km in stationary water?

Detailed Solution for Boat And Stream - MCQ Test(1) - Question 3

Option A

Explanation :Speed upstream = 2/2=1 km/hrSpeed downstream = 1/(20/60)=3 km/hrSpeed in still water = 1/2(3+1)=2 km/hrTime taken to travel 5 km in still water = 5/2= 2 hour 30 minutes

Boat And Stream - MCQ Test(1) - Question 4
Save

Speed of a boat in standing water is 14 kmph and the speed of the stream is 1.2 kmph. A manrows to a place at a distance of 4864 km and comes back to the starting point. The total time taken by him is:
Detailed Solution for Boat And Stream - MCQ Test(1) - Question 4

Speed downstream = (14 + 1.2) = 15.2 kmph

Speed upstream = (14 ‐ 1.2) = 12.8 kmph

Total time taken = 4864/15.2+4864/12.8 = 320 + 380 = 700 hours

Boat And Stream - MCQ Test(1) - Question 5
Save

 A man's speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is:
Detailed Solution for Boat And Stream - MCQ Test(1) - Question 5

Man's speed with the current = 15 km/hr
=> speed of the man + speed of the current = 15 km/hr

speed of the current is 2.5 km/hr
Hence, speed of the man = 15 - 2.5 = 12.5 km/hr

man's speed against the current = speed of the man - speed of the current
= 12.5 - 2.5 = 10 km/hr

Boat And Stream - MCQ Test(1) - Question 6
Save

A boat covers a certain distance downstream in 1 hour, while it comes back in 11⁄2 hours. If thespeed of the stream be 3 kmph, what is the speed of the boat in still water?
Detailed Solution for Boat And Stream - MCQ Test(1) - Question 6

Option B

Explanation :Let the speed of the boat in still water = x kmphGiven that speed of the stream = 3 kmphSpeed downstream = (x+3) kmphSpeed upstream = (x‐3) kmphHe travels a certain distance downstream in 1 hour and come back in 11⁄2 hour.ie, distance travelled downstream in 1 hour = distance travelled upstream in 11⁄2 hoursince distance = speed × time, we have(x+3)×1=(x−3)*3/2=> 2(x + 3) = 3(x‐3)=> 2x + 6 = 3x ‐ 9=> x = 6+9 = 15 kmph

Boat And Stream - MCQ Test(1) - Question 7
Save

A boat can travel with a speed of 22 km/hr in still water. If the speed of the stream is 5 km/hr, find the time taken by the boat to go 54 km downstream
Detailed Solution for Boat And Stream - MCQ Test(1) - Question 7

Option D

Explanation :Speed of the boat in still water = 22 km/hrspeed of the stream = 5 km/hrSpeed downstream = (22+5) = 27 km/hrDistance travelled downstream = 54 kmTime taken = distance/speed=54/27 = 2 hours

Boat And Stream - MCQ Test(1) - Question 8
Save

A boat running downstream covers a distance of 22 km in 4 hours while for covering the samedistance upstream, it takes 5 hours. What is the speed of the boat in still water?
Detailed Solution for Boat And Stream - MCQ Test(1) - Question 8

Option B

Explanation :Speed downstream = 22/4 = 5.5 kmphSpeed upstream = 22/5 = 4.4 kmphSpeed of the boat in still water = (½) x (5.5+4.42) = 4.95 kmph

Boat And Stream - MCQ Test(1) - Question 9
Save

A man takes twice as long to row a distance against the stream as to row the same distance infavor of the stream. The ratio of the speed of the boat (in still water) and the stream is:
Detailed Solution for Boat And Stream - MCQ Test(1) - Question 9

Option A

Explanation :Let speed upstream = xThen, speed downstream = 2xSpeed in still water = (2x+x)2=3x/2Speed of the stream = (2x−x)2=x/2Speed of boat in still water: Speed of the stream = 3x/2:x/2 = 3 : 1

Boat And Stream - MCQ Test(1) - Question 10
Save

A motorboat, whose speed in 15 km/hr in still water goes 30 km downstream and comes back in atotal of 4 hours 30 minutes. The speed of the stream (in km/hr) is:
Detailed Solution for Boat And Stream - MCQ Test(1) - Question 10

Option C

Explanation :Speed of the motor boat = 15 km/hr

Let speed of the stream = v

Speed downstream = (15+v) km/hrSpeed upstream = (15‐v) km/hr

Time taken downstream = 30/(15+v)

Time taken upstream = 30/(15−v)

total time = 30/(15+v)+30/(15−v)

It is given that total time is 4 hours 30 minutes = 4.5 hour = 9/2 hour

i.e.,30/(15+v)+30/(15−v)=9/2⇒

1(15+v)+1(15−v)=(9/2)×30=3/20

⇒(15−v+15+v)/(15+v)(15−v)=3/20

⇒30/(15*15−v*v)=3/20

⇒30/(225−v*v)=3/20

⇒10/(225−v* v)=1/20

⇒225−v* v =200

⇒v* v =225−200=25

⇒v=5 km/hr

Boat And Stream - MCQ Test(1) - Question 11
Save

A man rows to a place 48 km distant and come back in 14 hours. He finds that he can row 4 km with the stream in the same time as 3 km against the stream. The rate of the stream is:

A. 1 km/hr. B. 2 km/hr.

C. 1.5 km/hr. D. 2.5 km/hr
Detailed Solution for Boat And Stream - MCQ Test(1) - Question 11

Option A

Explanation :Assume that he moves 4 km downstream in x hours

Then, speed downstream = distance/time=4/x km/hrGiven that he can row 4 km with the stream in the same time as 3 km against the stream

i.e., speed upstream = 3/4of speed downstream=> speed upstream = 3/x km/hr

He rows to a place 48 km distant and come back in 14 hours

=>48/(4/x)+48/(3/x)=14

==>12x+16x=14

=>6x+8x=7=>14x=7

=>x=1/2

Hence, speed downstream = 4/x=4/(1/2) = 8 km/hr

speed upstream = 3/x=3/(1/2) = 6 km/hr

Now we can use the below formula to find the rate of the stream

Let the speed downstream be a km/hr and the speed upstream be b km/hr, thenSpeed in still water =1/2*(a+b) km/hr

Rate of stream =12*(a−b) km/hr

Hence, rate of the stream = ½*(8−6)=1 km/hr

Boat And Stream - MCQ Test(1) - Question 12
Save

A boat running upstream takes 8 hours 48 minutes to cover a certain distance, while it takes 4hours to cover the same distance running downstream. What is the ratio between the speed of theboat and speed of the water current respectively?
Detailed Solution for Boat And Stream - MCQ Test(1) - Question 12

Option C

Explanation :Let the rate upstream of the boat = x kmphand the rate downstream of the boat = y kmph

Distance travelled upstream in 8 hrs 48 min = Distance travelled downstream in 4 hrs.Since distance = speed × time, we havex×(8*4/5)=y×4x×(44/5)=y×4x×(11/5)=y‐‐‐ (equation 1)

Now consider the formula given belowLet the speed downstream be a km/hr and the speed upstream be b km/hr, thenSpeed in still water =1/2(a+b) km/hr

Rate of stream =1/2(a−b) km/hrHence, speed of the boat = (y+x)/2speed of the water = (y−x)/2Required Ratio = (y+x)/2:(y−x)/2=(y+x):(y−x)=(11x/5+x):(11x/5−x)(Substituted the value of y from equation 1)= (11x+5x):(11x−5x)=16x:6x=8:3

Boat And Stream - MCQ Test(1) - Question 13
Save

. A man can row at 5 kmph in still water. If the velocity of current is 1 kmph and it takes him 1 hourto row to a place and come back, how far is the place?
Detailed Solution for Boat And Stream - MCQ Test(1) - Question 13

Option C

Explanation :Speed in still water = 5 kmphSpeed of the current = 1 kmphSpeed downstream = (5+1) = 6 kmphSpeed upstream = (5‐1) = 4 kmphLet the requited distance be x kmTotal time taken = 1 hour=>x/6+x/4=1=> 2x + 3x = 12=> 5x = 12=> x = 2.4 km

Boat And Stream - MCQ Test(1) - Question 14
Save

A man can row three‐quarters of a kilometer against the stream in 111⁄4 minutes and down thestream in 71⁄2 minutes. The speed (in km/hr) of the man in still water is:
Detailed Solution for Boat And Stream - MCQ Test(1) - Question 14

Option B

Explanation :Distance = 3/4 kmTime taken to travel upstream = 111⁄4 minutes= 45/4 minutes = 45/(4×60) hours = 3/16 hoursSpeed upstream = Distance/Time= (3/4)/ (3/16) = 4 km/hrTime taken to travel downstream = 71⁄2minutes = 15/2 minutes = 15/2×60 hours = 1/8 hoursSpeed downstream = Distance/Time= (3/4)/ (1/8) = 6 km/hrRate in still water = (6+4)/2=10/2=5 kmph

Boat And Stream - MCQ Test(1) - Question 15
Save

A boat takes 90 minutes less to travel 36 miles downstream than to travel the same distanceupstream. If the speed of the boat in still water is 10 mph, the speed of the stream is:
Detailed Solution for Boat And Stream - MCQ Test(1) - Question 15

Option D

Explanation :Speed of the boat in still water = 10 mphLet speed of the stream be x mphThen, speed downstream = (10+x) mphspeed upstream = (10‐x) mphTime taken to travel 36 miles upstream ‐ Time taken to travel 36 miles downstream= 90/60 hours=>36/(10−x)−36/(10+x)=3/2 =>12/(10−x)−12/(10+x)=1/2 =>24(10+x)−24(10−x)=(10+x)(10−x)=>240+24x−240+24x=(100−x* x) =>48x=100− (x* x) => x* x +48x−100=0=>(x+50)(x−2)=0 =>x = ‐50 or 2; Since x cannot be negative, x = 2 mph

Boat And Stream - MCQ Test(1) - Question 16
Save

At his usual rowing rate, Rahul can travel 12 miles downstream in a certain river in 6 hours lessthan it takes him to travel the same distance upstream. But if he could double his usual rowing ratefor his 24‐mile round trip, the downstream 12 miles would then take only one hour less than theupstream 12 miles. What is the speed of the current in miles per hour?
Detailed Solution for Boat And Stream - MCQ Test(1) - Question 16

Option D

Explanation :Let the speed of Rahul in still water be x mphand the speed of the current be y mphThen, Speed upstream = (x ‐ y) mphSpeed downstream = (x + y) mphDistance = 12 milesTime taken to travel upstream ‐ Time taken to travel downstream = 6 hours⇒12/(x−y)−12/(x+y)=6⇒12(x+y)−12(x−y)=6(x*x−y*y)⇒24y=6(x*x−y*y)⇒4y= x*x−y*y⇒x * x =(y* y +4y)⋯(Equation 1)Now he doubles his speed. i.e., his new speed = 2xNow, Speed upstream = (2x ‐ y) mphSpeed downstream = (2x + y) mphIn this case, Time taken to travel upstream ‐ Time taken to travel downstream = 1 hour⇒12/(2x−y)−12/(2x+y)=1⇒12(2x+y)−12(2x−y)=4*x* x –y* y⇒24y=4*x* x –y* y⇒4*x* x = y* y +24y⋯(Equation 2)(Equation 1 × 4)⇒4x* x =4(y* y +4y)⋯(Equation 3)(From Equation 2 and 3, we have)y* y +24y=4(y* y +4y) ⇒y* y +24y=4y* y +16y ⇒3y* y =8y ⇒3y=8y=8/3 mph i.e., speed of the current = 8/3 mph=2*2/3 mph

109 docs|21 tests
Join Course
Information about Boat And Stream - MCQ Test(1) Page
In this test you can find the Exam questions for Boat And Stream - MCQ Test(1) solved & explained in the simplest way possible. Besides giving Questions and answers for Boat And Stream - MCQ Test(1), EduRev gives you an ample number of Online tests for practice

Top Courses for RPSC RAS (Rajasthan)

Download as PDF

Top Courses for RPSC RAS (Rajasthan)

Important Questions for Boat And Stream - MCQ Test(1)

Find all the important questions for Boat And Stream - MCQ Test(1) at EduRev.Get fully prepared for Boat And Stream - MCQ Test(1) with EduRev's comprehensive question bank and test resources. Our platform offers a diverse range of question papers covering various topics within the Boat And Stream - MCQ Test(1) syllabus. Whether you need to review specific subjects or assess your overall readiness, EduRev has you covered. The questions are designed to challenge you and help you gain confidence in tackling the actual exam. Maximize your chances of success by utilizing EduRev's extensive collection of Boat And Stream - MCQ Test(1) resources.

Boat And Stream - MCQ Test(1)

Prepare for the Boat And Stream - MCQ Test(1) within the RPSC RAS (Rajasthan) exam with comprehensive MCQs and answers at EduRev. Our platform offers a wide range of practice papers, question papers, and mock tests to familiarize you with the exam pattern and syllabus. Access the best books, study materials, and notes curated by toppers to enhance your preparation. Stay updated with the exam date and receive expert preparation tips and paper analysis. Visit EduRev's official website today and access a wealth of videos and coaching resources to excel in your exam.

Online Tests for Boat And Stream - MCQ Test(1) RAS RPSC Prelims Preparation - Notes, Study Material & Tests

Practice with a wide array of question papers that follow the exam pattern and syllabus. Our platform offers a user-friendly interface, allowing you to track your progress and identify areas for improvement. Access detailed solutions and explanations for each test to enhance your understanding of concepts. With EduRev's Online Tests, you can build confidence, boost your performance, and ace Boat And Stream - MCQ Test(1) with ease. Join thousands of successful students who have benefited from our trusted online resources.
© EduRev
Education Revolution
Follow Us
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup