Capacitance MSQ for Physics - Free MCQ Test with solutions

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Capacitance MSQ - Question 1

A parallel plate capacitor is charged from a cell and then isolated from it. The separation between the plates is now increased

A.
The force of attraction between the plates will decrease
B.
The energy stored in the capacitor will increase
C.
The potential difference between the plates will decrease
D.
The field in the region between the plates will not change

Detailed Solution: Question 1

The correct answers are: The field in the region between the plates will not change, The energy stored in the capacitor will increase

*Multiple options can be correct

Capacitance MSQ - Question 2

In the figure initial status of capacitance and their connection is shown. Which of the following is correct about this circuit :

A.
Total charge flown from A to D is –30µC
B.
Total charge flown from A to D is 30µC
C.
Final total electrical energy of the capacitors will be 0
D.
Final charge on each capacitor will be 0

Detailed Solution: Question 2

Final potential difference = 0
Final charge = 0
Charge flow 30µc from A to D

The correct answers are: Final charge on each capacitor will be 0, Final total electrical energy of the capacitors will be 0, Total charge flown from A to D is 30µC

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*Multiple options can be correct

Capacitance MSQ - Question 3

Capacitor C₁ of the capacitance 1μF and capacitor C₂of capacitance 2μF are separately charged fully by a common battery. The two capacitors are then separately allowed to discharge through equal resistors at time t = 0.

A.
the current in the two discharging circuits at t = 0 are equal but non zero.
B.
the current in each of the two discharging circuits is zero at t = 0.
C.
capacitor C₁ loses 50% of its initial charge sooner than C₂ loses 50% of its initial charge
D.
the current in the two discharging circuits at t = 0 are unequal

Detailed Solution: Question 3

The instantaneous charge on the capacitor is q(t) = q₀[1 – e^–^t^/^R ^C] = CV[1 – e^–^t^/^R ^C]

The correct answers are: the current in the two discharging circuits at t = 0 are equal but non zero., capacitor C₁ loses 50% of its initial charge sooner than C₂ loses 50% of its initial charge

*Multiple options can be correct

Capacitance MSQ - Question 4

Capacitance of a parallel plate air capacitor depends on

A.
Thickness of conducting plates
B.
Area of the conducting plates
C.
Distance of separation between the conducting plates
D.
Charge on the conducting plates

Detailed Solution: Question 4

For parallel plate air capacitor C = (ε0A) / d Which clearly shows that capacitance does not depend on charge on both the conducting plates. Hence answer is (a), (b) and (c)

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Capacitance MSQ - Question 5

A parallel plate capacitor of capacitance 10µF is connected to a cell of emf 10 Volt and fully charged. Now a dielectric slab (k = 3) of thickness equal to the gap between the plates, is very slowly inserted to completely fill in the gap, keeping the cell connected. During the filling process:

A.
the increase in charge on the capacitor is 200µC.
B.
the heat produced is 0.
C.
energy supplied by the cell = increase in stored potential energy + work done on the person who is filling the dielectric slab + heat produced.
D.
energy supplied by the cell = increase in stored potential energy + work done on the person who is filling the dielectric slab.

Detailed Solution: Question 5

Charge on capacitor before insertion of dielectric slab = 100µC
Charge on capacitor after insertion of dielectric slab = 300µC
Increase in charge on the capacitor = 300 – 100 = 200µC
Heat produced = 0
Energy supplied by the cell = increase in stored potential energy + work done on the person who filling the dielectric slab + heat produced.

The correct answers are: the increase in charge on the capacitor is 200µC. , the heat produced is 0., energy supplied by the cell = increase in stored potential energy + work done on the person who is filling the dielectric slab., energy supplied by the cell = increase in stored potential energy + work done on the person who is filling the dielectric slab + heat produced.

*Multiple options can be correct

Capacitance MSQ - Question 6

A parallel plate capacitor is charged and then the battery is disconnected. When the plates of the capacitor are brought closer, then

A.
the potential difference between the plates decreases
B.
the electric field between the plates decreases
C.
energy stored in the capacitor decreases
D.
the capacitance increases

Detailed Solution: Question 6

The correct answers are: energy stored in the capacitor decreases, the potential difference between the plates decreases, the capacitance increases

*Multiple options can be correct

Capacitance MSQ - Question 7

The plates of a parallel plate capacitor with no dielectric are connected to a voltage source. Now a dielectric of dielectric constant K is inserted to fill the whole space between the plates with voltage source remaining connected to the capacitor.

A.
the energy stored in the capacitor will become K-times
B.
the electric field inside the capacitor will decrease K-times
C.
the force of attraction between the plates will become K²-times
D.
the charge on the capacitor will become K-times.

Detailed Solution: Question 7

(A)

As potential difference source between the plates is connected, potential difference remains constant. But capacitance C becomes KC hence energy stored is increased by factor K.
(B) Electric field is not changed.
(C) Charge on each plate is increased by factor K hence force between them increases by factor K².
For effect of the medium, they must completely lie in the medium.
(D) Q = CV
Hence charge becomes KQ as C becomes KC and V remain unchanged.

The correct answers are: the energy stored in the capacitor will become K-times, the force of attraction between the plates will become K²-times, the charge on the capacitor will become K-times.

*Multiple options can be correct

Capacitance MSQ - Question 8

A capacitor (without dielectric) is discharging through a resistor. At some instant a dielectric is inserted between the plates, then which of the following is not true.

A.
Just after the insertion of the dielectric, current will increase
B.
Just after the insertion of the dielectric, charge on capacitor will increase.
C.
Just after the insertion of the dielectric, energy stored in the capacitor will increase.
D.
After the insertion of the dielectric, time constant will increase

Detailed Solution: Question 8

Let the capacitance before insertion of dielectric be C and the resistance be R.

∴
∵ Just after insertion of dielectric the capacitance increases.
∴ The charge just after insertion of dielectric remains same, but the current decreases.

The energy stored in capacitor is hence energy decrease

The correct answers are: Just after the insertion of the dielectric, current will increase, Just after the insertion of the dielectric, charge on capacitor will increase., Just after the insertion of the dielectric, energy stored in the capacitor will increase.

*Multiple options can be correct

Capacitance MSQ - Question 9

A parallel plate capacitor of capacitance C has charges on its plates initially as shown in the figure. Now at t = 0, the switch S is closed. Select the correct alternative(s) for this circuit diagram.

A.
In steady state the charges on the outer surfaces of plates A and B will be same in magnitude and opposite in sign.
B.
The work done by the cell by the time steady state is reached is
C.
In steady state the charges on the outer surfaces of plates A and B will be same in magnitude and sign.
D.
In steady state the charges on the inner surfaces of the plates A and B will be same in magnitude and opposite in sign.

Detailed Solution: Question 9

Suppose charge flown through the battery is Q, then charge distribution will be as :

The electric field in the region between A and B is

∴ Potential difference between the plates,

The correct answers are: In steady state the charges on the outer surfaces of plates A and B will be same in magnitude and sign., In steady state the charges on the inner surfaces of the plates A and B will be same in magnitude and opposite in sign., The work done by the cell by the time steady state is reached is

*Multiple options can be correct

Capacitance MSQ - Question 10

The figure shows, a graph of the current in a discharging circuit of a capacitor through a resistor of resistance 10Ω.

A.
The total heat produced in the circuit will be Joules.
B.
The capacitance of the capacitor is Farad.
C.
The initial potential difference across the capacitor is 100volt.
D.
The thermal power in the resistor will decrease with a time constant second.

Detailed Solution: Question 10

V₀ = I₀R = 10 × 10 = 100 volts (since, I₀ = 10amp from figure)
Also : I = I₀e^–^t^/^RC
Taking log :

Thermal power in the resistor will decrease with a time constant second.
The correct answers are: The initial potential difference across the capacitor is 100volt., The capacitance of the capacitor is Farad., The total heat produced in the circuit will be Joules., The thermal power in the resistor will decrease with a time constant second.

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Capacitance MSQ - Free MCQ Test with solutions for Physics

MCQ Practice Test & Solutions: Capacitance MSQ (10 Questions)

A parallel plate capacitor is charged from a cell and then isolated from it. The separation between the plates is now increased

In the figure initial status of capacitance and their connection is shown. Which of the following is correct about this circuit :

Capacitor C₁ of the capacitance 1μF and capacitor C₂of capacitance 2μF are separately charged fully by a common battery. The two capacitors are then separately allowed to discharge through equal resistors at time t = 0.

Capacitance of a parallel plate air capacitor depends on

A parallel plate capacitor of capacitance 10µF is connected to a cell of emf 10 Volt and fully charged. Now a dielectric slab (k = 3) of thickness equal to the gap between the plates, is very slowly inserted to completely fill in the gap, keeping the cell connected. During the filling process:

A parallel plate capacitor is charged and then the battery is disconnected. When the plates of the capacitor are brought closer, then

The plates of a parallel plate capacitor with no dielectric are connected to a voltage source. Now a dielectric of dielectric constant K is inserted to fill the whole space between the plates with voltage source remaining connected to the capacitor.

A capacitor (without dielectric) is discharging through a resistor. At some instant a dielectric is inserted between the plates, then which of the following is not true.

A parallel plate capacitor of capacitance C has charges on its plates initially as shown in the figure. Now at t = 0, the switch S is closed. Select the correct alternative(s) for this circuit diagram.

The figure shows, a graph of the current in a discharging circuit of a capacitor through a resistor of resistance 10Ω.

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Topic wise Tests for IIT JAM Physics

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Capacitance MSQ - Free MCQ Test with solutions for Physics

MCQ Practice Test & Solutions: Capacitance MSQ (10 Questions)

A parallel plate capacitor is charged from a cell and then isolated from it. The separation between the plates is now increased

In the figure initial status of capacitance and their connection is shown. Which of the following is correct about this circuit :

Capacitor C1 of the capacitance 1μF and capacitor C2 of capacitance 2μF are separately charged fully by a common battery. The two capacitors are then separately allowed to discharge through equal resistors at time t = 0.

Capacitance of a parallel plate air capacitor depends on

A parallel plate capacitor of capacitance 10µF is connected to a cell of emf 10 Volt and fully charged. Now a dielectric slab (k = 3) of thickness equal to the gap between the plates, is very slowly inserted to completely fill in the gap, keeping the cell connected. During the filling process:

A parallel plate capacitor is charged and then the battery is disconnected. When the plates of the capacitor are brought closer, then

The plates of a parallel plate capacitor with no dielectric are connected to a voltage source. Now a dielectric of dielectric constant K is inserted to fill the whole space between the plates with voltage source remaining connected to the capacitor.

A capacitor (without dielectric) is discharging through a resistor. At some instant a dielectric is inserted between the plates, then which of the following is not true.

A parallel plate capacitor of capacitance C has charges on its plates initially as shown in the figure. Now at t = 0, the switch S is closed. Select the correct alternative(s) for this circuit diagram.

The figure shows, a graph of the current in a discharging circuit of a capacitor through a resistor of resistance 10Ω.

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Topic wise Tests for IIT JAM Physics

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Capacitor C₁ of the capacitance 1μF and capacitor C₂of capacitance 2μF are separately charged fully by a common battery. The two capacitors are then separately allowed to discharge through equal resistors at time t = 0.