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Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 JEE Physics


MCQ Practice Test & Solutions: Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 (30 Questions)

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Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 60 minutes
  • - Number of Questions: 30

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Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 1

The young's modulus of material of a thin ring shaped elastic body is Y. The mass of ring is m, area of cross section is A, It's initial radius is R. Ring is a little elongated, then left alone. At what time will ring circumference be same as it was initially. Neglect loss of energy.


Detailed Solution: Question 1


Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 2

A slightly conical wire of length L and end radii r1 and r2 is stretched by two forces F, F applied parallel to length in opposite directions and normal to end faces. If Y denotes the Young’s modulus, then extension produced is

Detailed Solution: Question 2


Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 3

A block is executing SHM with a time period of 1 sec. and energy of 1 J. What is the mass (in kg) of the block? The amplitude is 10 cm. (Take π2 = 10)

Detailed Solution: Question 3

Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 4

A steel wire (Y = 200 GPa) of cross-sectional area = 1 mm2 is stretched by a force = 1000 N. The percentage increases in length of the wire is

Detailed Solution: Question 4


Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 5

A wire of length '2m' is clamped horizontally between two fixed support. A mass m = 5 kg is hanged from middle of wire. The vertical depression in wire in equilibrium is (young modulus of wire = 2.4 × 109 N/m2, crosssectional area = 1 cm2) -

Detailed Solution: Question 5


Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 6

If there is no change in the volume of wire on stretching, then poisson's ratio for the material of wire is -

Detailed Solution: Question 6


Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 7

If the ratio of lengths, radii and Young’s moduli of steel and brass wires in the figure are a,b and c respectively, then the corresponding ratio of increase in their lengths is


Detailed Solution: Question 7


Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 8

Blood is flowing at the rate of 100 cm3/s in a capillary of cross sectional area 0.25 m2. The velocity of flow is -

Detailed Solution: Question 8


Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 9

If the compressibility of water is σ per unit atmospheric pressure, then the decrease in volume (V) due to atmospheric pressure P will be -

Detailed Solution: Question 9


Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 10

The stress versus strain graphs for wires of two materials A and B as shown is the figure. If Yand YB are the young’s modulus of the materials, then-


Detailed Solution: Question 10


Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 11

A wire suspended vertically from one of its ends is stretched by attaching a weight of 200N to the lower end. The weight stretches the wire by 1mm. Then the elastic energy stored in the wire-

Detailed Solution: Question 11


Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 12

Two wires are made of the same material and have the same volume. However wire 1 has cross-sectional area A and wire 2 has crosssectional area 3A. if the length of wire 1 increases by Δx on applying force F, how much force is needed to stretch wire 2 by the same amount ?

Detailed Solution: Question 12


Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 13


Detailed Solution: Question 13


Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 14

Two wires of the same radius and material and having lengths in the ratio 8.9 : 7.6 are stretched by the same force. The strains produced in the two cases will be in the ratio -

Detailed Solution: Question 14


Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 15

A uniform metal rod of 2 mm2 cross section is heated from 0ºC to 20ºC. The coefficient of linear expansion of the rod is 12 × 10–6/ºC, its Young's modulus is 1011 N/m2. The energy stored per unit volume of the rod is -

Detailed Solution: Question 15


Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 16


Detailed Solution: Question 16


Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 17

The ratio of diameters of two wires of same material in n : 1. The length of each wire is 4m. on applying the same load, the increase in length of thin wire will be (n > 1) -

Detailed Solution: Question 17


Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 18

A metal rod of Young's modulus 2 × 1010 Nm–2 undergoes an elastic strain of 0.06%. The energy per unit volume stored in J m–3 is -

Detailed Solution: Question 18


Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 19

In order to twist one end of a wire, 2m long and 4 mm in diameter, though 45º, the torque required is -(η = 5 × 1010 Nm–2)

Detailed Solution: Question 19


Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 20

Detailed Solution: Question 20

Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 21

Two wires of the same radius and material have their length in the ratio 1 : 2. If these are stretched by same force and strain produced in the two wires will be in the ratio -

Detailed Solution: Question 21


Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 22

Two bodies of masses 2kg and 3kg are connected by a metal wire of cross section 0.04 mm2. Breaking stress of metal wire is 2.5 GPa. The maximum force F that can be applied to 3kg block so that wire does not break is : (Neglect friction)


Detailed Solution: Question 22

F – T = 3a

T = 2a

T = 2.5 × 109 × 4 × 10–8

T = 100 N

T = 2a

100 = 2a

a = 50 N

F = 5 × 50

F = 250 N

Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 23

You hang a flood lamp from the end of a vertical steel wire. The flood lamp stretches the wire 0.18 mm and the stress is proportional to the strain. How much would it have stretched if the wire were twice as long?

Detailed Solution: Question 23

F/A = e/L
F/A = 0.18/l ( let the length be l)
F/A = x/2l
0.18/L = x/2l
0.18×2l = xl
0.36l = xl
x = 0.36

Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 24

Stress is

Detailed Solution: Question 24

Stress is defined as the amount of force applied over a specific area. It measures how concentrated that force is, which can help in understanding how materials behave under pressure.

Formula: Stress can be calculated using the formula: Stress = Force / Area.

Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 25

Columns are loaded in

Detailed Solution: Question 25

When columns are subjected to loads, they can experience different types of stress. Here are the key types:

  • Shear: This stress occurs when forces act parallel to the surface of the column.
  • Hydraulic stress: This type of stress is generated by fluid pressure within the column, which isn't typically a primary concern for structural columns.
  • Axial tension: This stress happens when the column is pulled along its length, causing it to elongate.
  • Axial compression: This stress occurs when the column is pushed along its length, leading to shortening or buckling.

In this context, the most relevant stress type for columns is axial compression, as it directly relates to how columns support vertical loads.

Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 26

The S.I unit of stress is

Detailed Solution: Question 26

Stress has its own SI unit called the Pascal. 1 Pascal (Pa) is equal to 1 N/m2. In imperial units stress is measured in pound force per square inch which is often shortened to "psi". The dimension of stress is same as that of pressure.

Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 27

Material is said to be ductile if

Detailed Solution: Question 27

Material is considered ductile when it can undergo significant plastic deformation before breaking. This means:

  • It can stretch and change shape without immediately snapping.
  • A considerable amount of deformation occurs between the elastic limit and the point of fracture.
  • It does not lose much of its cross-sectional area when it fails.

In contrast, if a material fractures quickly after exceeding the elastic limit or breaks suddenly with little elongation, it is not classified as ductile.

Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 28

In constructing a large mobile, an artist hangs an aluminum sphere of mass 6.0 kg from a vertical steel wire 0.50 m long and 2.5 × 10−3 cm2in cross-sectional area. On the bottom of the sphere he attaches a similar steel wire, from which he hangs a brass cube of mass 10.0 kg. Compute the elongation.

Detailed Solution: Question 28

Answer
Upper wire ≈1.6 mm, Lower wire ≈1.0 mm.

Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 29

volume strain is defined

Detailed Solution: Question 29

Volume strain refers to the change in volume of an object due to external forces. It is calculated as:

  • The ratio of the change in volume (ΔV) to the original volume (V).

This means that volume strain measures how much the volume has changed compared to how much it was before the change occurred.

Chapter Test: Elasticity (Mechanical Properties of Solids) - 2 - Question 30

A steel wire of length 4.7 m and cross-sectional area 3.0 × 10−5 m2 stretches by the same amount as a copper wire of length 3.5 m and cross-sectional area of 4.0 × 10−5 m2 under a given load. What is the ratio of the Young’s modulus of steel to that of copper?

Detailed Solution: Question 30

Length of the steel wire, L1 = 4.7 m

Area of cross-section of the steel wire, A= 3.0×10−5 m2

Length of the copper wire, L= 3.5 m

Area of cross-section of the copper wire, A= 4.0 × 10−5 m2

Change in length = ΔL= ΔL= ΔL

Force applied in both the cases = F

Young's modulus of the steel wire:

 
⇒ nearly equal to 1.8.

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