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Chapter Test: Thermodynamics -2 JEE Physics Free MCQs


MCQ Practice Test & Solutions: Chapter Test: Thermodynamics -2 (30 Questions)

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Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 60 minutes
  • - Number of Questions: 30

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Chapter Test: Thermodynamics -2 - Question 1

Detailed Solution: Question 1


Chapter Test: Thermodynamics -2 - Question 2


Detailed Solution: Question 2

Chapter Test: Thermodynamics -2 - Question 3

A mixture of 8gm of helium and 14gm of nitrogen is enclosed in a vessel of constant volume at 300K. The quantity of heat absorbed by the mixture to double the root mean velocity of its molecules is –

(R = universal gas constant )

Detailed Solution: Question 3

Chapter Test: Thermodynamics -2 - Question 4

One mole of ideal monoatomic gas is taken along a cyclic process as shown in the figure. Process

1 → 2 shown is 1/4th part of a circle as shown by dotted line process 2 → 3 is isochoric while

3 → 1 is isobaric. If efficiency of the cycle is n% where n is an integer. Find n.


Detailed Solution: Question 4


Chapter Test: Thermodynamics -2 - Question 5


Detailed Solution: Question 5


Chapter Test: Thermodynamics -2 - Question 6

n moles of an ideal gas undergoes a process A to B as shown. Maximum temperature of gas during the process is –


Detailed Solution: Question 6


Chapter Test: Thermodynamics -2 - Question 7


Detailed Solution: Question 7


Chapter Test: Thermodynamics -2 - Question 8

An ideal gas is expanded so that amount of heat given is equal to the decrease in internal energy. The gas undergoes the process TV1/5 = constant. The adiabatic compressibility of gas when pressure is P, is –

Detailed Solution: Question 8


Chapter Test: Thermodynamics -2 - Question 9

The pressure volume graph of an ideal gas cycle is shown in the fig. The adiabatic process is described by


Detailed Solution: Question 9


Chapter Test: Thermodynamics -2 - Question 10

In a given process of an ideal gas, dW = 0 and dQ < 0. Then for the gas –

Detailed Solution: Question 10


Chapter Test: Thermodynamics -2 - Question 11

The molar heat capacity for the process is xR, where R is gas constant, when 10 J of heat added to a monoatomic ideal gas, then gas performs a work of 5 J on its surrounding, then x is.

Detailed Solution: Question 11


Chapter Test: Thermodynamics -2 - Question 12

The figure shows two isotherms at temperatures T1 and T2. A gas is taken from one isotherm to another isotherm through different processes. Then change in internal energy ΔU has relation -


Detailed Solution: Question 12

Internal energy depends only on state but not on the process. Hence its change is same for all the processes between two same states

Chapter Test: Thermodynamics -2 - Question 13


Detailed Solution: Question 13


Chapter Test: Thermodynamics -2 - Question 14

For one complete cycle of a thermodynamic process on a gas as shown in the P-V diagram. Which of the following is correct ?


Detailed Solution: Question 14

ΔEint = 0, for a complete cycle and for given cycle work done is negative, so from first law of thermodynamics Q will be negative i.e. Q < 0.

Chapter Test: Thermodynamics -2 - Question 15

The ratio of two specific heats of CO, CP/CV is-

Detailed Solution: Question 15


Chapter Test: Thermodynamics -2 - Question 16

1 mole of a monoatomic and 2 mole of diatomic gas are mixed, Now the resulting gas is taken through a process in which molar heat capacity was found 3R. Polytropic constant in the process is -

Detailed Solution: Question 16


Chapter Test: Thermodynamics -2 - Question 17

For an ideal gas graph is shown for three processes. Processes 1, 2, and 3 are respectively –



Detailed Solution: Question 17


Chapter Test: Thermodynamics -2 - Question 18


Detailed Solution: Question 18

Chapter Test: Thermodynamics -2 - Question 19

In an adiabatic expansion of air the volume increases by 5%. What is the percentage change in pressure ? [(1.05)7/5 = 1.07]

Detailed Solution: Question 19


Chapter Test: Thermodynamics -2 - Question 20

A carnot engine works between ice point and steam point. It is desired to increase efficiency by 20%, by changing temperature of sink to –

Detailed Solution: Question 20

Chapter Test: Thermodynamics -2 - Question 21

Pressure versus temperature graph of an ideal gas is as shown in figure corresponding density (ρ) versus volume (V) graph will be -


Detailed Solution: Question 21


Chapter Test: Thermodynamics -2 - Question 22


Detailed Solution: Question 22


Chapter Test: Thermodynamics -2 - Question 23


Detailed Solution: Question 23


Chapter Test: Thermodynamics -2 - Question 24

Find the amount of work done to increase the temperature of one mole of an ideal gas by 30ºC if it is expanding under the condition V ∝ T2/3 -

Detailed Solution: Question 24


Chapter Test: Thermodynamics -2 - Question 25

Kelvin- Planck statement states that

Detailed Solution: Question 25

It works on the principle that no machine is 100% efficient. For instance if taking an ideal machine into consideration, work can be completely converted to heat. Now if the conditions are reversed, all heat cannot be converted to equal amount of work until and unless backed up by an external force.

Chapter Test: Thermodynamics -2 - Question 26

For proper utilization of exergy, it is desirable to make first law efficiency ____ and the source and use temperatures should ____.

Detailed Solution: Question 26

If first law efficiency is close to unity, the all the energy carried in by heat transfer is used and no heat is lost to the surroundings.

Chapter Test: Thermodynamics -2 - Question 27

If the door of refrigerator is left open inside a closed room, what would happen to the temperature of the room?

Detailed Solution: Question 27

If you leave the door open, heat is merely recycled from the room into the refrigerator, then back into the room. A net room temperature increase would result from the heat of the motor that would be constantly running to move energy around in a circle.

Chapter Test: Thermodynamics -2 - Question 28

Refrigerator transfers heat from the cold cooling coils to warm surroundings, which law of thermodynamics favour this process

Detailed Solution: Question 28

Refrigerator follows the principle of Clausius statement of second law of thermodynamics. It does not violate second law of thermodynamics because it takes energy to transfer heat from low temperature body to high temperature body. Electrical work is given to refrigerator to extract heat from low temperature body and to transfer it to higher temperature body. If any refrigerator is transferring heat from low temperature body to higher temperature body without any external energy then we can say that it violates second law of thermodynamics. But in actual it takes energy to do.

Chapter Test: Thermodynamics -2 - Question 29

What amount of work is needed to freeze 1 gm of water at 0˚C in a refrigerator .The temperature of surroundings is 320 K?

Detailed Solution: Question 29

None

Chapter Test: Thermodynamics -2 - Question 30

The coefficient of performance of a refrigerator is given by

Detailed Solution: Question 30

A is the correct answer.

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