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Chemical Bonding & Periodicity - GATE Chemistry MCQ


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20 Questions MCQ Test GATE Chemistry Mock Test Series - Chemical Bonding & Periodicity

Chemical Bonding & Periodicity for GATE Chemistry 2024 is part of GATE Chemistry Mock Test Series preparation. The Chemical Bonding & Periodicity questions and answers have been prepared according to the GATE Chemistry exam syllabus.The Chemical Bonding & Periodicity MCQs are made for GATE Chemistry 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Chemical Bonding & Periodicity below.
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*Answer can only contain numeric values
Chemical Bonding & Periodicity - Question 1

The number of species having 3c-2e- bond among following is/are____
Al2(CH3)6, AI2(CH3)4CI2,(MgH2)2, AI(BH4)3, BeCI2(in solid)


Detailed Solution for Chemical Bonding & Periodicity - Question 1

Species in which ligands are electron deficient (one electron) form 3c–2e– bonding.

*Answer can only contain numeric values
Chemical Bonding & Periodicity - Question 2

The percentage s-character in lone pair in PH3 molecule having bond angle 92º is _____________


Detailed Solution for Chemical Bonding & Periodicity - Question 2



Hence, s-character in lone pair 100-9.6 = 90.4%

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Chemical Bonding & Periodicity - Question 3

Correct order of ionization energy among following is/are
 (I) N2 > N > O    (II) N > O > O2    (III) N> O> NO    (IV) N2 > C2 > O2

Detailed Solution for Chemical Bonding & Periodicity - Question 3

Energy required for removing electron from orbitals follows the order ABMO < A.O. < B.M.O.

Chemical Bonding & Periodicity - Question 4

Species having highest vp-o value is 

Detailed Solution for Chemical Bonding & Periodicity - Question 4

As the electronegativity of substituted vP-O also increases

Chemical Bonding & Periodicity - Question 5

Correct order of bond angle from following?

Detailed Solution for Chemical Bonding & Periodicity - Question 5

Energy required for removing electron from orbitals follows the order ABMO < A.O. <B.M.O.

Chemical Bonding & Periodicity - Question 6

The HOMO in  molecule 

Detailed Solution for Chemical Bonding & Periodicity - Question 6

Molecular orbital diagram of 

Hence both are gerade.

Chemical Bonding & Periodicity - Question 7

Correct set of point group for BrF5,  and [BrF6]+ respectively are-

Detailed Solution for Chemical Bonding & Periodicity - Question 7



Chemical Bonding & Periodicity - Question 8

The correct statement is

Detailed Solution for Chemical Bonding & Periodicity - Question 8

Lesser the electronegativity of surrounding atom more s-character in that bond. Hence, more bond angle.

*Answer can only contain numeric values
Chemical Bonding & Periodicity - Question 9

The maximum number of atoms that may lie in the same plane in molecule P(CH3)3(CF3)2 is _______


Detailed Solution for Chemical Bonding & Periodicity - Question 9

*Answer can only contain numeric values
Chemical Bonding & Periodicity - Question 10

Number of molecule that show fluxional behavior among. CH4,CF4,PCI5,PF5,BrF5,SF6,XeO3 is _________


*Answer can only contain numeric values
Chemical Bonding & Periodicity - Question 11

The number of anions having perfect Oh geometry among
[SbCI6]3-, [SeCI6]2-,[TeBr6]2-,[BrF6]-,[IF6]-,[CIF6]-,[SeF6]2- is/are__________


Detailed Solution for Chemical Bonding & Periodicity - Question 11

Lesser the difference between size of central and surrounding atom lesser will be stereochemical activity of lone pair. Hence, perfect geometry.

Chemical Bonding & Periodicity - Question 12

HOMO and LUMO in BeH2 molecules respectively are 

Detailed Solution for Chemical Bonding & Periodicity - Question 12

Molecular orbital diagram of BeH2.

Chemical Bonding & Periodicity - Question 13

 

Regarding following compounds A,B,C and D

Correct statement(s) is/are

Detailed Solution for Chemical Bonding & Periodicity - Question 13

More the S-character in C-O bond = more will be strength of bond. Hence, more will be vc-o value. Hence, more ionization energy and lesser the dipole moment.

Chemical Bonding & Periodicity - Question 14

The ionisation potential of hydrogen atom is 13.6 eV. The first ionisation potential of a sodium atom, assuming that the energy of its outer electron can be represented by a H-atom like model with an effective nuclear charge of 1.84, is

Detailed Solution for Chemical Bonding & Periodicity - Question 14


Chemical Bonding & Periodicity - Question 15

In salt [Et4N]2[InCI5] and [NH3(CH2)5(NH3)][TiCI5], structures of anions respectively are

Detailed Solution for Chemical Bonding & Periodicity - Question 15

The structures of anions in two different salts, [Et4N]2[InCl5] and [NH3(CH2)5NH3][TiCl5].

For [Et4N]2[InCl5], the anion is [InCl5]2-. Indium (In) typically forms a trigonal bipyramidal structure with five chloride ions because it can accommodate five ligands around it.

For [NH3(CH2)5NH3][TiCl5], the anion is [TiCl5]2-. Titanium (Ti) in the +4 oxidation state usually forms a square pyramidal structure with five ligands due to its d^0 configuration.

Therefore, the correct answer is:

Option A: Trigonal bipyramidal and square pyramidal.

Chemical Bonding & Periodicity - Question 16

Select the correct  statement regarding [Ph3MeP][AI(BH4)4]
(I) At 298 anion show one signal in 1H NMR
(II) At 298 anion show two signal in 1H NMR
(III) At 298 a quintet is observed in 11B NMR
(IV) At 298 a triplet of triplet is observed in 11B NMR

Detailed Solution for Chemical Bonding & Periodicity - Question 16

Structure of [AI(BH4)4]-

At 298 terminal and bridging hydrogens are involved in dynamic process. Hence, one signal in 1H NMR. 11B NMR will be a quintet regarding 4 equivalent H.

Chemical Bonding & Periodicity - Question 17

The ground state terms for H+2 and No respectively.

Detailed Solution for Chemical Bonding & Periodicity - Question 17





Hence, 2πg

Chemical Bonding & Periodicity - Question 18

29Si NMR spectrum of X[Ph3SiH2] shows

Detailed Solution for Chemical Bonding & Periodicity - Question 18

Structure of X[Ph3,SiH2]

Hence, triplet

Chemical Bonding & Periodicity - Question 19

Geometry and point group regarding [ZrMe6]2-

Detailed Solution for Chemical Bonding & Periodicity - Question 19

 perfect trigonal prismatic geometry

perfect trigonal prismatic geometry has D3h point group.

*Answer can only contain numeric values
Chemical Bonding & Periodicity - Question 20


The final dioxygen (B) undergo Diels Alder reaction unlike normal dioxygen(A). The value of spin multiplicity which  represent ground state term of dioxygen (B) is __________


Detailed Solution for Chemical Bonding & Periodicity - Question 20


2s + 1 = 1, Ml =2 
Hence 1Δg

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