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Classification of Elements and Periodicity in Properties - 1 - JEE MCQ


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30 Questions MCQ Test Chemistry for JEE Main & Advanced - Classification of Elements and Periodicity in Properties - 1

Classification of Elements and Periodicity in Properties - 1 for JEE 2024 is part of Chemistry for JEE Main & Advanced preparation. The Classification of Elements and Periodicity in Properties - 1 questions and answers have been prepared according to the JEE exam syllabus.The Classification of Elements and Periodicity in Properties - 1 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Classification of Elements and Periodicity in Properties - 1 below.
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Classification of Elements and Periodicity in Properties - 1 - Question 1

 Which is the correct order of ionic sizes (At. No. : Ce = 58, Sn = 50, Yb = 70 and Lu = 71)                [AIEEE-2002]

Detailed Solution for Classification of Elements and Periodicity in Properties - 1 - Question 1

Generally as we move from left to right in a period, there is regular decrease in atomic radii and in a group as the atomic number increases the atomic radii also increases. Thus the atomic radius of Sn should be less than lanthanides. La > Sn. But due to lanthanide contraction, in case of lanthanides there is a continuous decrease in size with increase in atomic number. Hence the atomic radius follow the given trend:

Ce > Sn > Yb > Lu. 

Classification of Elements and Periodicity in Properties - 1 - Question 2

The reduction in atomic size with increase in atomic number is a characteristic of elements of -                              [AIEEE-2003]

Detailed Solution for Classification of Elements and Periodicity in Properties - 1 - Question 2

With increase in atomic number i.e. in moving down a group, the number of the principal shell increases and therefore, the size of the atom increases. But in case of f ­block elements there is a steady decrease in atomic size with increase in atomic number due to lanthanide contraction. As we move through the lanthanide series, 4f electrons are being added one at each step.

The mutual shielding effect of f electrons is very little. This is due to the shape of the f ­orbitals. The nuclear charge, however increases by one at each step. Hence, the inward pull experienced by the 4f electrons increases. This causes a reduction in the size of the entire 4fn shell.

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Classification of Elements and Periodicity in Properties - 1 - Question 3

The atomic numbers of vanadium (V). Chromium (Cr), manganese (Mn) and iron (Fe) respectively 23, 24, 25 and 26. Which one of these may be expected to have the higher second ionization enthalpy ?  

[AIEEE-2003]

Detailed Solution for Classification of Elements and Periodicity in Properties - 1 - Question 3

The electronic configurations are as follows;

V:(Ar)3d34s2

Cr:(Ar)3d54s1

Mn:(Ar)3d54s2

Fe:(Ar)3d64s2

The second ionization of Cr means removal of electron from the stable configuration of 3d5.

The highest second ionization enthalpy is Cr

Hence a is the correct answer.

Classification of Elements and Periodicity in Properties - 1 - Question 4

Which one of the following sets of ions represents the collection of isoelectronic species ?           [AIEEE-2004]

Detailed Solution for Classification of Elements and Periodicity in Properties - 1 - Question 4

Isoelectronic species are those which have same number of electrons.

K+ = 19 – 1 = 18 ; Ca2+ = 20 – 2 = 18

Sc3+ = 21 – 3 = 18 ; Cl = 17 + 1 = 18

Thus all these ions have 18 electrons in them.

Classification of Elements and Periodicity in Properties - 1 - Question 5

lanthanoid contraction is caused due to -                              [AIEEE-2006]

Detailed Solution for Classification of Elements and Periodicity in Properties - 1 - Question 5

The Lanthanide Contraction is caused by a poor shielding effect of the 4f electrons. Gd because as atomic number increases, the atomic radius decreases. These electrons are do not shield good, causing a greater nuclear charge.

Classification of Elements and Periodicity in Properties - 1 - Question 6

The increasing order of the ionic radii of the given isoelectronic species is:

Detailed Solution for Classification of Elements and Periodicity in Properties - 1 - Question 6

For isoelectronic species, as the z/e decreases, ionic radius increases
such as ionic radii ∝ 1/z.

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Classification of Elements and Periodicity in Properties - 1 - Question 12

Choose the correct order of the following:

Detailed Solution for Classification of Elements and Periodicity in Properties - 1 - Question 12

(A) For more polarity electronegativity difference should be  more E.N. (P) ≈ E.N. (H)

N–H > As–H > Sb–H > P–H is the order, (B) and (C) more is the size is gaseous phase less is hydration thus less is

hydrated size ∴ more is ionic mobility.

(D) Lattice energy depends on charge of cation and anion and internuclear distance thus order

MgO > SrO > NaF

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