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DSE Odisha TGT Science PCM Mock Test - 5 - OTET MCQ


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30 Questions MCQ Test DSE Odisha TGT Mock Test Series 2024 - DSE Odisha TGT Science PCM Mock Test - 5

DSE Odisha TGT Science PCM Mock Test - 5 for OTET 2024 is part of DSE Odisha TGT Mock Test Series 2024 preparation. The DSE Odisha TGT Science PCM Mock Test - 5 questions and answers have been prepared according to the OTET exam syllabus.The DSE Odisha TGT Science PCM Mock Test - 5 MCQs are made for OTET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for DSE Odisha TGT Science PCM Mock Test - 5 below.
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DSE Odisha TGT Science PCM Mock Test - 5 - Question 1

What was the inflation rate in the Eurozone in September?

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 1

The inflation rate in the Eurozone fell to 4.3% in September, from 5.2% in August. This is the lowest level of inflation in the Eurozone since October 2021. The ECB is expected to continue raising interest rates to bring inflation back to its target level of 2%.

DSE Odisha TGT Science PCM Mock Test - 5 - Question 2

Who among the following initiated Ganga dynasty in Odisha?

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 2

Anantavarman Chodagangadev (Option B) is the ruler who initiated the Ganga dynasty in Odisha. He is known for his significant contributions to the region, including the construction of the famous Jagannath Temple in Puri.
Raja Rajadeva-I (Option A) was a later ruler and not the initiator of the Ganga dynasty in Odisha.
Vajarahasta-V (Option C) is not historically associated with the Ganga dynasty in Odisha.
Kamarnava (Option D) is also not known as the initiator of the Ganga dynasty in Odisha.
So, the correct answer is Option B: Anantavarman Chodagangadev.

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DSE Odisha TGT Science PCM Mock Test - 5 - Question 3

According to the text, who audits the PM-CARES Fund?

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 3
The PM-CARES Fund is not audited by the CAG but is audited by an independent auditor outside the government.
DSE Odisha TGT Science PCM Mock Test - 5 - Question 4

Which factor plays a crucial role in determining the development of railway routes in India?

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 4

The topography of an area and the potential for passenger and freight traffic are crucial factors that influence the development and expansion of railway routes in India. Technological advancements, political decisions, and funding availability may have secondary influences, but the primary consideration is based on topographical and traffic factors.

DSE Odisha TGT Science PCM Mock Test - 5 - Question 5
Which is the National Animal of India?
Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 5
The tiger was declared the national animal of India in 1973. It symbolizes power, bravery, and is often referred to as the Lord of the jungle.
DSE Odisha TGT Science PCM Mock Test - 5 - Question 6

Which among the following wildlife sanctuary is located along the sea coast of Odisha?

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 6

The Balukhand-Konark Wildlife Sanctuary is located on Odisha's seacoast. This location is ideal for the development of ecotourism.

DSE Odisha TGT Science PCM Mock Test - 5 - Question 7
Which river originates from the Gangotri glacier in Uttarakhand?
Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 7
The Ganga River originates from the Gangotri glacier in Uttarakhand. It is a major river in the Indian subcontinent and holds great cultural and religious significance.
DSE Odisha TGT Science PCM Mock Test - 5 - Question 8

The average weight of A, B and C is 72 kg. When D joins them, the new average becomes 68 kg. When E joins, A, B, C and D, the average of all five becomes 70 kg. What is the weight of E?

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 8

The average weight of A, B, C and D = 68 kg
The average weight of A, B, C, D and E = 70 kg
So the answer = 70 × 5 – 68 × 4 = 78 kg
Hence, Option A is correct.

DSE Odisha TGT Science PCM Mock Test - 5 - Question 9

Which Answer figure will complete the Question figure?

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 9

DSE Odisha TGT Science PCM Mock Test - 5 - Question 10

The average weight of a group of 15 persons increases by 2 kg when a person weighing 40 kg is replaced by Saurabh. What is the weight of Saurabh?

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 10

Combined weight of the group increases by = 2 × 15 = 30 kg
So the answer = 40 + 30 = 70 kg
Hence, Option C is correct.

DSE Odisha TGT Science PCM Mock Test - 5 - Question 11

Charts tips can

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 11
Explanation:
Charts tips can:
- Show the formatting of a data label: This means that charts can display the style, font, color, and other formatting options applied to the labels that represent data points.
- Show the name of a data series: Charts can also display the names or labels of the different data series or categories being represented. This helps in understanding the context and organization of the data.
- Show the value of a data point: Charts are used to visualize data, and one of the key elements they can display is the actual value of each data point. This allows users to easily interpret and compare the data.
- Both b and c: This option implies that charts can show both the name of a data series and the value of each data point.
In conclusion, charts can provide various types of information such as formatting, data series names, and data point values. This makes them effective tools for visualizing and analyzing data.
DSE Odisha TGT Science PCM Mock Test - 5 - Question 12

______ was the first step in the evolution of Ethernet from a coaxial cable bus to hub managed, twisted pair network.

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 12
Evolution of Ethernet from a Coaxial Cable Bus to Hub Managed, Twisted Pair Network
The first step in the evolution of Ethernet from a coaxial cable bus to a hub managed, twisted pair network was the introduction of the Star LAN. Here is a detailed explanation of this evolution:
1. Coaxial Cable Bus:
- Initially, Ethernet networks were based on a coaxial cable bus topology.
- In this setup, all devices were connected to a single cable, forming a bus-like structure.
- Data was transmitted over the cable, and each device could listen to the data being transmitted.
2. Limitations of Coaxial Cable Bus:
- The coaxial cable bus had limitations in terms of distance, speed, and scalability.
- It had a limited maximum distance for data transmission.
- As the network grew, the signal quality degraded, leading to performance issues.
- The bus topology was also susceptible to collisions, resulting in data collisions and network congestion.
3. Introduction of Star LAN:
- To overcome the limitations of the coaxial cable bus, the Star LAN topology was introduced.
- In the Star LAN, each device is connected to a central device called a hub or switch using twisted pair cables.
- The hub or switch acts as a central point for data transmission and management.
4. Advantages of Star LAN:
- The Star LAN topology addressed the limitations of the coaxial cable bus.
- It allowed for longer cable distances, as the hub or switch could regenerate and amplify the signal.
- Each device had its own dedicated connection to the hub or switch, eliminating the signal degradation issues of the bus topology.
- The star topology also reduced the likelihood of collisions, improving network performance and reliability.
5. Further Evolution:
- After the introduction of the Star LAN, Ethernet continued to evolve.
- Ring LAN and Mesh LAN are other network topologies that were developed, but they did not directly lead to the hub managed, twisted pair network evolution.
- Ring LAN uses a ring topology, and Mesh LAN employs multiple direct connections between devices.
In conclusion, the first step in the evolution of Ethernet from a coaxial cable bus to a hub managed, twisted pair network was the introduction of the Star LAN topology. This topology addressed the limitations of the coaxial cable bus and provided improved performance, scalability, and reliability for Ethernet networks.
DSE Odisha TGT Science PCM Mock Test - 5 - Question 13

Primary classes (Classes I to V) will consist of which of the following stages according to NEP, 2020?

A. Preparatory Stage

B. Middle Stage

C. Foundational Stage

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 13

Key Points 

  • The curricular and pedagogical structure and the curricular framework for school education will therefore be guided by a 5 + 3 + 3 + 4 design, consisting of the stages:
    • Foundational (3 years of preschool + Grades 1-2):- The Foundational Stage will consist of play/activity-based learning. It will also include a focus on good behavior, courtesy, ethics, personal and public hygiene/cleanliness, teamwork, cooperation, etc. 
    • Preparatory (Grades 3- 5):-  The Preparatory Stage will transition gradually from play-based learning to more formal but interactive classroom learning, with the introduction of some (light) textbooks, in order to lay a solid groundwork across subjects, including reading, writing, speaking, physical education, art, languages, science, and mathematics.
    • Middle (Grades 6-8):- The Middle Stage will see the introduction of subject teachers for learning/discussion of the more abstract concepts in each subject that students will be ready for at this stage, across the sciences, mathematics, arts, social sciences, and humanities.
    • High school (Grades 9-12 in two phases, i.e. 9 and 10 in the first and 11 and 12 in the second) stages respectively, with an option of exiting at Class 10 and re-entering in the next phase:- The High School (or Secondary) Stage will comprise of four years of multidisciplinary study, building on the subject-oriented pedagogical and curricular style of the Middle Stage, but with greater depth, greater critical thinking, greater attention to life aspirations, and greater flexibility and student choice.

Thus, it is concluded that Primary classes (Classes I to V) will consist of  Preparatory and  Foundational Stages according to NEP, 2020.

DSE Odisha TGT Science PCM Mock Test - 5 - Question 14

Directions: Answer the following question by selecting the most appropriate option.
A school gives preference to girls while preparing students for a state level solo-song competition. This reflects

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 14

Preference to one sex over the other is called gender bias. Here the school prefers girls for the competition, thereby reflecting gender bias.

DSE Odisha TGT Science PCM Mock Test - 5 - Question 15

The modern consensus regarding the sending of disciplinary cases to the principal's office is that

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 15

School principal fulfils many roles and dealing with students' disruptive behaviour is among the least preferred by them. So, the teacher must try to discipline the students using various means like assigning responsibility to the undisciplined, finding out the underlying cause of his behaviour, and so on. Only after she has done everything without any effect on the student should she send the student to the principal.

DSE Odisha TGT Science PCM Mock Test - 5 - Question 16

Which of the following strategies is associated to the idea of formative assessment?

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 16

Assessment is integral to the teaching-learning process which helps in facilitating student learning and improving instruction.

  • Formative assessment is goal-centered that is, it focuses attention on successful teaching and learning of important learning goals and standards.
  • It identifies the learning gaps and deficiencies in teaching.
  • In this form of assessment, a teacher embeds various forms of assessment all through the teaching and learning process. 
  • Therefore, it is an ongoing assessment that allows teachers to monitor students on a day-to-day basis and modify their teaching based on what the students need to be successful.

For example, during a teaching in a class teacher ask questions, the teacher says to discuss among peer groups, observe children as they work on their tasks, a teacher receives feedback from students during teaching etc.

DSE Odisha TGT Science PCM Mock Test - 5 - Question 17

Learners are asked to listen to a set of five sentences from their Environmental Studies textbook as the teacher reads out the sentences twice. Then the learners are asked to discuss in their groups to recall/recreate the sentence, not necessarily the exact sentence, but nearer to the sentences read out. What is this task known as?

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 17

This task is known as paragraph dictation.

DSE Odisha TGT Science PCM Mock Test - 5 - Question 18

To develop critical thinking in the students, the teacher introduces the topic of plastic bag usage. In which of the following ways can a child develop his critical thinking?

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 18

Critical thinking is a process that challenges an individual to use reflective, reasonable, rational thinking to gather, interpret, and evaluate information in order to derive a judgment.

DSE Odisha TGT Science PCM Mock Test - 5 - Question 19
According to NEP‐2020, National Research Foundation (NRF) may be established to
Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 19

The NRF (National Research Foundation) will be governed, independently of the government, by a rotating Board of Governors consisting of the very best researchers and innovators across fields.

Key Points

  •  The goal of the NRF will be to enable a culture of research to permeate through our universities.
  • The primary activities of the NRF will be to:
    •  fund competitive, peer-reviewed grant proposals of all types and across all disciplines.
    •  seed, grow and facilitate research at academic institutions.
    • act as a liaison between researchers and relevant branches of government as well as industry; so as to allow breakthroughs to be optimally brought into policy and/or implementation.
    • recognize outstanding research and progress.

Thus, it is concluded that According to NEP‐2020, National Research Foundation (NRF) may be established to enable a culture of research to permeate through universities.

DSE Odisha TGT Science PCM Mock Test - 5 - Question 20

In junior section, Mrs Singh is teaching about Earth, its shape and rotation, by using a globe. In such teaching, learning takes place by

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 20

In junior section, Mrs Singh is teaching about Earth, its shape and rotation by using a globe. In such teaching, learning take place by observation. Students observe the globe to get knowledge.

Observational learning is the learning that occurs through observation of the behavior of others. It is a form of social learning which takes various forms, based on various processes.

DSE Odisha TGT Science PCM Mock Test - 5 - Question 21

Radha is a biology teacher and teaches complex things related to the body. What will be the best way adopted by her to teach the subject?

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 21

A picture will be the best teaching aid to teach the subject of biology. A number of pictures can be used to teach each of the processes individually.

DSE Odisha TGT Science PCM Mock Test - 5 - Question 22

Drift is the random motion of the charged particles within a conductor,

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 22

The electrons in a conductor have random velocities and when an electric field is applied, they suffer repeated collisions and in the process move with a small average velocity, opposite to the direction of the field. This is equivalent to positive charge flowing in the direction of the field.

DSE Odisha TGT Science PCM Mock Test - 5 - Question 23

In an atom electrons revolves around the nucleus along a path of radius 0.72Å making 9.4×1018 revolution per second. The equivalent current is (e = 1.6×10−19C)

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 23

Radius of electron orbit
r = 0.72Å = 0.72 × 10−10m
Frequency of revolution of electron in orbit of given atom
v = 9.4 × 1018 rev/s
(where T is time period of revolution of electron in orbit)
∴ Then equivalent current is
I = e/T = ev = 1.6 × 10−19 × 9.4 × 1018
= 1.504A

DSE Odisha TGT Science PCM Mock Test - 5 - Question 24

Use the formula λm T = 0.29 cmK to obtain the characteristic temperature range for λm=5×10-7m

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 24

A body at temperature T produces a continuous spectrum of wavelengths. For a black body, the wavelength corresponding to maximum intensity of radiation is given according to Planck's law by the relation, m=0.29cmK/T. For m=106m,T=2900K.Temperatures for other wavelengths can be found. These numbers tell us the temperature ranges required for obtaining radiations in different parts of the electromagnetic spectrum. Thus, to obtain visible radiation, say  =5×107m, the source should have a temperature of about 6000K. A lower temperature will also produce this wavelength but not the maximum intensity.

DSE Odisha TGT Science PCM Mock Test - 5 - Question 25

The power of biconvex lens is 10 dioptre and the radius of curvature of each surface is 10 cm. Then the refractive index of the material of the lens is

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 25

Power of lens, P (in dioptre) = 100/f(in cm)
∴  f  = 100/10 = 10 cm
For biconvex lens, R1 = + R, R2 = -R =  According to lens makers formula

DSE Odisha TGT Science PCM Mock Test - 5 - Question 26

Direction of the conventional current

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 26

Current flows in a conductor due to the flow of negatively charged electrons. However, the direction of conventional current is taken to be opposite to the direction of flow of electrons. It can therefore be considered as the direction in which positive charges move.

DSE Odisha TGT Science PCM Mock Test - 5 - Question 27

Suppose the elements X and Y combine to form two compounds XY2 and X3Y2. When 0.1 mole of XY2 weighs 10 g and 0.05 mole of X3Y2 weighs 9 g, the atomic weights of X and Y are

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 27

Let atomic weight of x = Mx

atomic weight of y = My

we know,

mole = weight /atomic weight

a/c to question,

mole of xy2 = 0.1

so,

0.1 = 10g/( Mx +2My)

Mx + 2My = 100g -------(1)

for x3y2 ; mole of x3y2 = 0.05

0.05 = 9/( 3Mx + 2My )

3Mx + 2My = 9/0.05 = 9× 20 = 180 g ---(2)

solve eqns (1) and (2)

2Mx = 80

Mx = 40g/mol

and My = 30g/mole

DSE Odisha TGT Science PCM Mock Test - 5 - Question 28

The number of elements know at that time when Mendeleev arranged them in the periodic table was-

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 28

Mendeleev arranged all 63 elements; which were discovered till his time; in the order of their increasing relative atomic masses in a tabular form. It is known as Mendeleev's Periodic Table. He divided the table in eight columns and seven rows. The columns are known as groups and rows are known as periods.

DSE Odisha TGT Science PCM Mock Test - 5 - Question 29

The Value of (n2 + n1) and for He+ ion in atomic spectrum are 4 and 8 respectively. The wavelength of emitted photon when electron jump from n2 to n1 is

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 29


DSE Odisha TGT Science PCM Mock Test - 5 - Question 30

Which of the following complex will give white precipitate with barium chloride solution?

Detailed Solution for DSE Odisha TGT Science PCM Mock Test - 5 - Question 30

Since the reagent is BaCl2(aq), displacement reaction will take place. The resulting solution, if insoluble in water, will form a white precipitate. Both BaNO2 and BaCl2 are soluble in water and hence will not form a precipitate. BaSO4, however, is insoluble in water and hence forms a white precipitate.

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