DSSSB TGT/PGT/PRT Exam  >  DSSSB TGT/PGT/PRT Tests  >  DSSSB PGT Mock Test Series 2024  >  DSSSB PGT Chemistry Mock Test - 4 - DSSSB TGT/PGT/PRT MCQ

DSSSB PGT Chemistry Mock Test - 4 - DSSSB TGT/PGT/PRT MCQ


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30 Questions MCQ Test DSSSB PGT Mock Test Series 2024 - DSSSB PGT Chemistry Mock Test - 4

DSSSB PGT Chemistry Mock Test - 4 for DSSSB TGT/PGT/PRT 2024 is part of DSSSB PGT Mock Test Series 2024 preparation. The DSSSB PGT Chemistry Mock Test - 4 questions and answers have been prepared according to the DSSSB TGT/PGT/PRT exam syllabus.The DSSSB PGT Chemistry Mock Test - 4 MCQs are made for DSSSB TGT/PGT/PRT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for DSSSB PGT Chemistry Mock Test - 4 below.
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DSSSB PGT Chemistry Mock Test - 4 - Question 1

How many times are the hands of a clock at right angles in a day?  

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 1

Hands will be at right angle twice every hour except from 2 to 4 and 8 to 10 where hands will be at right angle only thrice instead of four times.
Thus, hands will be at right angle 22 times in 12 hours or 44 times in 24 hrs.

DSSSB PGT Chemistry Mock Test - 4 - Question 2

Acids taste

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 2

Acids taste sour due to their acidic properties and interaction with the taste buds on our tongues. The sour taste is a result of the release of hydrogen ions and their interaction with specific receptors on our taste buds. Carbon dioxide is incombustible and also does not support burning. Hence, it is used in fire extinguishers.

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DSSSB PGT Chemistry Mock Test - 4 - Question 3

Direction: Read the following passages carefully and answer the question that follows.
The ancient Harappan Civilization emerged, flourished and collapsed under a steadily weakening monsoon, according to new research findings, that scientists say, provide the strongest evidence yet to link its risk and fall to changing climate. A team of scientists has combined multiple sets of date to show that weakening monsoon and reduced river water initially stimulated intensive agriculture and urbanisation, but later precipitated the decline and collapse of the subcontinent's earliest cities. The scientist said their research also suggests that a larger river, summed to be the mythical Saraswati, which once watered the Harappan Civilization's heartland between the suggests it was a glacier fed river with origins in the Himalyas. The findings appear today in the US Journal Proceedings of the National Academy of Science

Q. What was the controversy in the passage?

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 3

The controversy is about the monsoon fed river and the glacier fed river.

DSSSB PGT Chemistry Mock Test - 4 - Question 4

Direction: In many of the process control applications, the purpose of control system is to keep the output (controlled variable) almost constant in spite of changes in load. Mostly in continuous processes the set point remains constant for longer time. Such an operation is called 'Regulator Operation'. The set point generated, and the actual values from sensors are given to a controller. The controller compares both the signals, generates error signal which is utilized to generate a final signal as controller output. The controller output is finally utilized to physically change the values of manipulated variable to achieve stability. The above action is achieved with the help of final control elements. They are operatable either with electrical, pneumatic or with hydraulic signals. The system that serves good for servo operation will generally not be the best for regulator operation. Large capacity or inertia helps to minimize error here, whereas it makes the system sluggish in case of servo operation.

Q. What is the purpose of the control system?

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 4

it is stated clearly in the first line of the passage that the purpose of control system is to keep the out constant inspite of changes in load.

DSSSB PGT Chemistry Mock Test - 4 - Question 5

By selling a cap for ₹ 29.75, a man gains 6.25%. What will be the CP of the cap?

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 5

The SP = 106.25% of the CP. Thus, CP = 29.75/1.0625
= ₹ 28.

DSSSB PGT Chemistry Mock Test - 4 - Question 6

A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 6

DSSSB PGT Chemistry Mock Test - 4 - Question 7

रचनाकार में कौन सा समास है?

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 7

‘रचनाकार’ अर्थात रचना को करने वाला।
जिस समास का उत्तरपद प्रधान हो और पूर्वपद गौण एवं 'को' चिह्न का लोप हो उसे कर्म तत्पुरुष समास कहते हैं। अत: यह कर्म तत्पुरूष समास का उदाहरण है।
उदाहरण:
शाकाहरी = शाक को खाने वाला।

DSSSB PGT Chemistry Mock Test - 4 - Question 8

अत्याधिक का विलोम शब्द है:

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 8

‘अत्याधिक’ अर्थात भरपूर मात्रा।
‘स्वल्प’ अर्थात कम।
‘अग्रणी’ अर्थात जो सबसे आगे रहता हो।
‘जलचर’ अर्थात जल में विचरने वाले जीव।
‘जिजीविषु’ अर्थात अधिक समया तक जीते रहने को इच्छुक।

DSSSB PGT Chemistry Mock Test - 4 - Question 9

नीचे दिए गए वाक्य का प्रकार बताइये। 
मुसीबत आ जाए तो भागना उचित नहीं।

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 9

दो वाक्यों में एक वाकया प्रधान और दूसरा वाक्य गौण हो तथा आपस में (कि, जो, क्योंकि, जितना -उतना, जैसा -वैसा, जब -तब, जहाँ -वहाँ, जिधर -उधर )से जुड़े होते है, "तो" मिश्र वाक्य का योजक चिन्ह है। अतः दिया गया वाक्य मिश्र वाक्य है।

DSSSB PGT Chemistry Mock Test - 4 - Question 10

निम्नलिखित शब्दों में स्त्रीलिंग का चयन कीजिए।

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 10

सुशीला स्त्रीलिंग शब्द है। स्त्रीलिंग शब्द है जैसे- प्रार्थना, वेदना, प्रस्तावना, रचना, घटना इत्यादि। (इ) उकारान्त संज्ञाएँ। जैसे- वायु, रेणु, रज्जु, जानु, मृत्यु, आयु, वस्तु, धातु इत्यादि। अपवाद- मधु, अश्रु, तालु, मेरु, हेतु, सेतु इत्यादि।

DSSSB PGT Chemistry Mock Test - 4 - Question 11

In scientific notation for such numbers, any number can be represented in the form N × 10n where

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 11

n can vary from to 10 and can be +ve or –ve.

DSSSB PGT Chemistry Mock Test - 4 - Question 12

Type of stoichiometric defect shown by ZnS is

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 12

ZnS shows Frenkel defect.

DSSSB PGT Chemistry Mock Test - 4 - Question 13

Coordination numbers in a square close packed structure and hexagonal close packed structure respectively, are

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 13

(c) Close packing in two-dimensions can be Type I A A A ...... ty p e The second row may be ^ placed in contact with the first one such that the spheres of A the second row are exactly . above those of the first row.
The spheres of the two rows A are aligned horizontally as well as vertically. In this arrangement, each sphere is in contact with four of its neighbours.
Thus, its coordination number = 4 and is called square close packing in two-dimensions.
Atom A (•) is in contact with four others.

Type II ABAB... type The second row may be placed above the first in a staggered manner such that its spheres fit in the depressions of the first row.
First row arrangement: A type Second row arrangement: 8 type Third row arrangement: A type and so on There is less free space and packing is more efficient than the square close packing. Each sphere is in contact with six of its neighbours and coordination number = 6 in two-dimensions. It is called two dimensional hexagonal close-packing. Voids formed in this case are triangular in shape. If the apex of the triangles downward in the first row, it is upward in the second row.

 

DSSSB PGT Chemistry Mock Test - 4 - Question 14

Hydrogen bonding occurs in which type of crystalline solids?

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 14

Molecular solids consist of atoms or molecules held to each other by dipole-dipole interactions, London dispersion forces, hydrogen bonds, or any combination of these. 

Additional Information: Hydrogen bonding refers to the formation of Hydrogen bonds, which are a special class of attractive intermolecular forces that arise due to the dipole-dipole interaction between a hydrogen atom that is bonded to a highly electronegative atom and another highly electronegative atom which lies in the vicinity of the hydrogen atom. 

DSSSB PGT Chemistry Mock Test - 4 - Question 15

Dalton's atomic theory could not explain one of the following

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 15

Dalton’s atomic theory stated that atoms were indivisible. However, the discovery of subatomic particles (such as protons, electrons, and neutrons) disproved this postulate.

DSSSB PGT Chemistry Mock Test - 4 - Question 16

Calculate the wavelength (in nanometer) associated with a proton moving at 1.0×103ms-1 (Mass of proton = 1.67×10-27kg and h = 6.63×10-34Js)

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 16

Given mp = 1.67×10-27kg
h = 6.63×10-34Js
v = 1.0×103ms-1

We know wavelength λ = h/mv
∴λ = 6.63×10-34/(1.67×10-27 × 1.0×103)
= 0.40×10-10
≈ 0.40nm

Hence, Option (B) is the Correct Answer.

DSSSB PGT Chemistry Mock Test - 4 - Question 17

The number of radial nodes for 3p orbital is:

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 17
  • Number of radial nodes = n - l – 1

where n = principal quantum number, l = azimuthal quantum number

  • For 3p orbital, n = 3 – 1 – 1 = 1
  • Number of radial nodes = 3 – 1 – 1 = 1. 
DSSSB PGT Chemistry Mock Test - 4 - Question 18

1 mole N2 and 3 mol H2 are placed in a closed container at a pressure of 4 atm. The pressure falls to 3 atm at the same temperature when the following equilibrium is attained.

N2(g) + 3H2(g)  2NH3(g). The equilibrium constant Kp for dissociation of NH3 is :

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 18





 

DSSSB PGT Chemistry Mock Test - 4 - Question 19

A solution with pH 2.0 is more acidic than the one with pH 6.0 by a factor of :

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 19

[H+]1 = 10–2 ; [H+]2 = 10–6

DSSSB PGT Chemistry Mock Test - 4 - Question 20

Study of rate of chemical reaction is known as

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 20

Chemical Kinetics deals with rate of a Chemical reactions.

DSSSB PGT Chemistry Mock Test - 4 - Question 21

 At equilibrium:

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 21

The correct answer is option A

E cell is 0 in equilibrium, that is Ecathode becomes equal to E anode ……….
EZero cell becomes zero when both the electrodes are of the same metal but of different concentration i.e for concentration cell……
We know that EZero cell is - Ezerocathode -E zeroanode (since cathode and anode are same ) so EZero =0
 

DSSSB PGT Chemistry Mock Test - 4 - Question 22

An aqueous solution is 34% H3P04 by mass and has density 1.209 g mL -1 Molarity (I), molality (II) and normality (III) respectively, are

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 22

100g H3P04 aqueous solution has 34g H3P04

DSSSB PGT Chemistry Mock Test - 4 - Question 23

If one assumes the volumes are additive, what is  in a solution obtained by mixing 275 mL of 0.200 M KN03, 325 mL of 0.40 M Mg(N03)2 and 400 mL H20?

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 23

DSSSB PGT Chemistry Mock Test - 4 - Question 24

A solution was made by dissolving 2 g of a solute in 100 g of acetone. The solution boiled at 56.95° C. The boiling point of pure acetone is 55.95° C, and the Kb =1.71°C/m. What is the molecular weight of the solute?

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 24

The correct answer is Option B.
 
∆Tb =(Kb × 1000 × W2) / M2 × W1
⇒ M2 = (Kb × 1000 × W2) / ∆Tb × W1
= (1.71 × 1000 × 2) / 1 × 100
= 34.2g

DSSSB PGT Chemistry Mock Test - 4 - Question 25

Dipole moment of   is 1.5 D. Thus, dipole moment 

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 25

 If one considers following molecule, it is 


Symmetrical and thus
In the given species

DSSSB PGT Chemistry Mock Test - 4 - Question 26

The enthalpies of fusion for all reactions are

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 26

The enthalpies of fusion for all reactions are always positive because melting of a solid is an endothermic process in which heat is supplied to the reaction Hence the sum of enthalpies of the product is greater than the sum of enthalpies of the reactant.

DSSSB PGT Chemistry Mock Test - 4 - Question 27

Electron gain enthalpy is most negative for:

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 27

The negative electron gain enthalpy of fluorine is less than that of chlorine. It is due to small size of fluorine atom. As a result, there are strong interelectronic repulsions in the relatively small 2p orbitals of fluorine and thus, the incoming electron does not experience much attraction.

DSSSB PGT Chemistry Mock Test - 4 - Question 28

Which of the following gaseous molecule is monoatomic?

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 28

Cl, O, and N forms Cl2, O2 and N2 respectively to satisfy octet rule but He has noble gas configuration so do not form any compound and exist as monoatomic gas.

DSSSB PGT Chemistry Mock Test - 4 - Question 29

Requirement of macronutrient per acre of the land is

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 29

Requirement of macronutrient per acre of the land is 5 to 200 kg

DSSSB PGT Chemistry Mock Test - 4 - Question 30

Which of the following statements is correct about Enzymes?

Detailed Solution for DSSSB PGT Chemistry Mock Test - 4 - Question 30

The correct answer is option A
 
Higher temperatures  speed up the effect of enzyme activity, while lower temperatures decrease the rate of an enzyme reaction. if the temperature is too high, an enzyme will denature, which causes the shape of the enzyme to change. If the enzyme's shape changes, it cannot bind to the substrate.

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