EMRS Exam  >  EMRS Test  >   Junior Secretariat Assistant Exam Mock Test Series 2026  >  EMRS Junior Secretariat Assistant Mock Test - 9 - EMRS MCQ

EMRS Junior Secretariat Assistant Exam Mock Test - 9 Free Online Test 2026


Full Mock Test & Solutions: EMRS Junior Secretariat Assistant Mock Test - 9 (130 Questions)

You can boost your EMRS 2026 exam preparation with this EMRS Junior Secretariat Assistant Mock Test - 9 (available with detailed solutions).. This mock test has been designed with the analysis of important topics, recent trends of the exam, and previous year questions of the last 3-years. All the questions have been designed to mirror the official pattern of EMRS 2026 exam, helping you build speed, accuracy as per the actual exam.

Mock Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 150 minutes
  • - Total Questions: 130
  • - Analysis: Detailed Solutions & Performance Insights
  • - Sections covered: Reasoning, Quantitative Aptitude, General Awareness, English, Hindi, Computer Awareness

Sign up on EduRev for free and get access to these mock tests, get your All India Rank, and identify your weak areas to improve your marks & rank in the actual exam.

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 1

Four positions of a dice are given below. Identify which number is on the face opposite 2.

 

Detailed Solution: Question 1


Figure I says 3 and 4 cannot be opposite to 2.
Figure II says 1 and 3 cannot be opposite to 2.
Figure IV says 6 and 4 cannot be opposite to 2.
Overall, 1, 3, 4 and 6 cannot be opposite to 2.
So, 5 must be opposite face to 2.

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 2

From the given answer figures, select the one in which the question figure is hidden/embedded.

Detailed Solution: Question 2

The question figure is hidden in the answer 1).
Hence, 1) is the answer. 

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 3

A piece of paper is folded and punched as shown below in the question figures. From the given answer figures, indicate how it will appear when opened.

Detailed Solution: Question 3


Now if we will open paper as it is folded in given question figure then it will appear as it is shown in above question figure.
Hence, image of option 1) is correct answer.

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 4

The writer can get good ideas only when he constantly rejuvenates himself. This rejuvenation comes from new experiences that the writer must take part in. 

Q. Which of the following supports the thought?

Detailed Solution: Question 4

Option 1 is the correct answer. The central idea of the sentence is to convey the need for good writers to break monotony and take new experiences, thereby regenerating new ideas. Option 2 is the exact opposite of the idea of taking up new experiences. Option 3 and 4 talk about travelling which is nowhere conveyed in the above sentence.

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 5

Select the odd letters from the given alternatives.

Detailed Solution: Question 5


→ In VW, W is the next alphabet from V, not previous.

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 6

Select the related letters from the given alternatives.
AD : N : : BD : ?

Detailed Solution: Question 6

Position of A = 1, D = 4 and N = 14 in English alphabets.
→ AD = N ⇒ 14 = 14
Similarly,
Position of B = 2, D = 4 and X = 24 in English alphabets.
→ BD = X ⇒ 24 = 24
Hence, “X” is the correct answer. 

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 7

If a = √2 + 1, b = √2 – 1, then the value of 

Detailed Solution: Question 7

Given,
a = √2 + 1
b = √2 – 1
Given expression is,

= 2/2
= 1

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 8

If (x - 2) and (x + 3) are the factors of x2 + k1x + k2 then

Detailed Solution: Question 8

If (x - 2) and (x + 3) are the factors of the equation, then that means that
⇒ x – 2 = 0
 ⇒ x = 2
Similarly,
⇒ x + 3 = 0
⇒ x = -3
Putting the value of one of the x in the equation such that the value is zero.
⇒ x2 + k1x + k2
Putting the value of ‘x’ as 2, we get
⇒ (2)2 + k1(2) + k= 0
⇒ 4 +2k1+ k= 0
Putting the value of ‘x’ as -3, we get
⇒ (-3)2 + k1(-3) + k= 0
⇒ 9 -3k1+ k= 0
Subtracting both the equations:
⇒ 4 +2 k1+ k- (9 -3 k1+ k2) = 0
⇒ 4 +2 k1+ k- 9 + 3 k1- k= 0
⇒ 5 k- 5 = 0
⇒ 5 k= 5
⇒ k= 1
Putting the value of k= 1,
⇒ 4 +2 k1+ k= 0
⇒ 4 +2 (1)+ k= 0
⇒ 4 +2 + k= 0
⇒ 6 + k= 0
⇒ k= -6
Alternate method:-
(x – 2) and (x + 3) are factors of x2 + k1x + k2
∴ (x – 2)(x + 3) = x2 + k1x + k2
⇒ x2 + x – 6 = x2 + k1x + k2
Comparing, we get, k1 = 1 and k2 = - 6

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 9

In a Δ PQR, ∠RPQ = 90°, PR = 8 cm and PQ = 6 cm, then the radius of the circumcircle of Δ PQR is

Detailed Solution: Question 9


Pythagoras theorem,
Hypotenuse2 = perpendicular2 + base2
Area of a triangle = abc/4R
Where, a, b and c are sides of the triangle and R is the radius of circumcircle.
Area of the triangle PQR = ½ × PQ × PR
Where PR = 8cm, PQ = 6cm
Area of triangle =12×8×6=24cm2=12×8×6=24cm2
Now, using Pythagoras theorem, a+ b2 = c2
⇒ c= (8)2 + (6)2 = 64 + 36 = 100 = (10)2
⇒ c = 10
Radius 

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 10

Directions: Study the following table carefully and answer the questions.

Q. Earnings on 150 kg of paddy sold by farmer B are approximately what percent of the earnings on the same amount of rice sold by the same farmer?

Detailed Solution: Question 10

Given,
Price per kg of paddy sold by farmer B = 25
Price per kg of rice sold by farmer B = 36
∴ Earning on 150 kg of paddy by farmer B = 150 × 25 = Rs. 3750
Earning on 150 kg of rice by farmer B = 150 × 36 = Rs. 5400
∴ Required per cent
= (3750/5400) × 100
= 3750/54 = 69.44%

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 11

A kite is flying at a height of 80 m from the level ground, attached to a string inclined at 30° to the horizontal. The length of the string is?

Detailed Solution: Question 11


From the diagram,
Height of the kite = AB = 80 m
Angle of inclination of the string with horizontal = ∠ ACB = 30°
Length of the string = AC
From ΔABC,
sin ∠ACB = Perpendicular/Hypotenuse
⇒ sin 30° = AB/AC
⇒ 1/2 = 80/AC
⇒ AC = 160 m

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 12

An emulsion is a colloidal solution of

Detailed Solution: Question 12

Emulsion is a fine dispersion of minute droplets of one liquid in another in which it is not soluble or miscible.

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 13

Uber Cup is associated with

Detailed Solution: Question 13

The Uber Cup, sometimes called the World Team Championships for Women, is a major international badminton competition contested by women's national badminton teams. First held in 1956–1957 and contested at three year intervals, it has been contested every two years since 1984.

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 14

What is the minimum age required to become a sarpanch?

Detailed Solution: Question 14

The minimum age required to become a sarpanch is 21 years.

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 15

Classes comprising Fungi, Bacteria, Protists constitute the category called?

Detailed Solution: Question 15

Fungi, Bacteria, and Protists belong to the Kingdom category.

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 16

Foam is a colloidal solution in which _______ is the dispersed phase and _______ is the dispersion medium.

Detailed Solution: Question 16

In foam, gas is the dispersed phase, and liquid is the dispersion medium.

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 17

Which one of the following is a solution that is concentrated more than its saturated solution at a particular temperature?

Detailed Solution: Question 17

A supersaturated solution is one that is concentrated more than its saturated solution at a particular temperature.

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 18

What is the maximum age for an Indian citizen to join Atal Pension Yojana (APY)?

Detailed Solution: Question 18

The maximum age for an Indian citizen to join Atal Pension Yojana (APY) is 40 years.

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 19

Who won the women’s singles in Indonesia masters title?

Detailed Solution: Question 19

Saina Nehwal won the women's singles in the Indonesia Masters title.

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 20

By the time we get there, they __________ all the food.

Detailed Solution: Question 20

The sentence uses the past perfect tense to show an action completed before another past action.

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 21

Choose the option that best corrects the sentence:

Salt is often added to food to make it taste better.

Detailed Solution: Question 21

Option A is correct because the statement is a general statement about a substance (salt) and the noun is also a non-countable hence it does not need an article. Options A and B are incorrect because the noun is a non-countable noun. Option D is incorrect because the 'salt' is being referred to in general, not in specific terms.

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 22

OBEYING 

Detailed Solution: Question 22

The antonym of  OBEYING is  Refusing

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 23

Passage

  1. The report, progress on household drinking water, sanitation and hygiene (2000-2017): Special focus on inequalities, is the most recent publication by the WHO/UNICEF Joint Monitoring Programme, which tracks global progress in achieving the water and sanitation portion of the UN’s Sustainable Development Goals (SDGs).
  2. The 17 SDGs aim is to “end poverty in all its forms everywhere” by 2030. Goal 6 calls for universal access to safe and adequate access to drinking water and sanitation services.
  3. According to the new report, progress has been made since 2000, yet billions of people are still underserved. The report delineates between access to basic services, which has greatly improved, and access to “safely managed” services, which is inadequate in many parts of the world. Only about 45 per cent of the global population has access to safely- managed sanitation services. In 2017, an estimated 673 million people continued to openly defecate, most of them in 61 “high burden” countries where the practice remained common among more than 5 per cent of the population.
  4. To qualify as being “safely managed”, drinking water must meet three criteria: be accessible on the premises, be available for at least 12 hours per day, and be free from E. coli, arsenic, or fluoride contamination. Sanitation is considered safely managed when facilities are not shared with other households, and waste is safely treated on-site or at an off-site facility.
  5. In 2017, an estimated 5.3 billion people had access to safely-managed drinking water. Of that number, 1.4 billion used basic services, 206 million used limited services, 435 used unimproved sources, and the remaining 144 million relied on untreated surface water.
  6. Poor and rural populations are at the greatest risk of being left behind. In 2017, urban access to basic drinking water services was at 97 per cent, while rural coverage was at 81 per cent.
  7. In terms of sanitation, an estimated 2.1 billion people gained access to basic services between 2000 and 2017, but 2 billion remain without access.
  8. The report also focuses on improvements in eliminating open defecation. Between 2000 and 2017, the global rate of open defecation fell from 21 percent to 9 per cent.

Q. What is the percentage of population which has access to sanitation services?

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 24

Passage

  1. The report, progress on household drinking water, sanitation and hygiene (2000-2017): Special focus on inequalities, is the most recent publication by the WHO/UNICEF Joint Monitoring Programme, which tracks global progress in achieving the water and sanitation portion of the UN’s Sustainable Development Goals (SDGs).
  2. The 17 SDGs aim is to “end poverty in all its forms everywhere” by 2030. Goal 6 calls for universal access to safe and adequate access to drinking water and sanitation services.
  3. According to the new report, progress has been made since 2000, yet billions of people are still underserved. The report delineates between access to basic services, which has greatly improved, and access to “safely managed” services, which is inadequate in many parts of the world. Only about 45 per cent of the global population has access to safely- managed sanitation services. In 2017, an estimated 673 million people continued to openly defecate, most of them in 61 “high burden” countries where the practice remained common among more than 5 per cent of the population.
  4. To qualify as being “safely managed”, drinking water must meet three criteria: be accessible on the premises, be available for at least 12 hours per day, and be free from E. coli, arsenic, or fluoride contamination. Sanitation is considered safely managed when facilities are not shared with other households, and waste is safely treated on-site or at an off-site facility.
  5. In 2017, an estimated 5.3 billion people had access to safely-managed drinking water. Of that number, 1.4 billion used basic services, 206 million used limited services, 435 used unimproved sources, and the remaining 144 million relied on untreated surface water.
  6. Poor and rural populations are at the greatest risk of being left behind. In 2017, urban access to basic drinking water services was at 97 per cent, while rural coverage was at 81 per cent.
  7. In terms of sanitation, an estimated 2.1 billion people gained access to basic services between 2000 and 2017, but 2 billion remain without access.
  8. The report also focuses on improvements in eliminating open defecation. Between 2000 and 2017, the global rate of open defecation fell from 21 percent to 9 per cent.

Q. Which country has maximum access to basic drinking water?

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 25

‘अधि’ उपसर्ग युक्त कौन-सा शब्द नहीं है ?

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 26

दिए गए समरूपी भिन्नार्थक शब्दों के सही विकल्प वाले समूह बताइये।

चिर-चीर-

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 27

Type of software that can be described as “end-user” software

Detailed Solution: Question 27

Application software is often described as "end-user" software because it is designed for users to perform specific tasks.

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 28

______________ utility identifies non-essential files on the hard disk and erases them only when the user allows their erasure.

Detailed Solution: Question 28

Disk Cleanup utility identifies non-essential files and allows the user to delete them to free up disk space.

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 29

Which of these operating systems does not have a graphical user interface?

Detailed Solution: Question 29

MS-DOS (Microsoft Disk Operating System) does not have a graphical user interface.

EMRS Junior Secretariat Assistant Mock Test - 9 - Question 30

ALU performs two types of operations,_____

Detailed Solution: Question 30

ALU (Arithmetic Logic Unit) performs arithmetic and logical operations.

View more questions
10 tests
Information about EMRS Junior Secretariat Assistant Mock Test - 9 Page
In this test you can find the Exam questions for EMRS Junior Secretariat Assistant Mock Test - 9 solved & explained in the simplest way possible. Besides giving Questions and answers for EMRS Junior Secretariat Assistant Mock Test - 9, EduRev gives you an ample number of Online tests for practice
Download as PDF