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EmSAT Chemistry Mock Test- 2 - EmSAT Achieve MCQ


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30 Questions MCQ Test Mock Tests for EmSAT Achieve 2024 - EmSAT Chemistry Mock Test- 2

EmSAT Chemistry Mock Test- 2 for EmSAT Achieve 2024 is part of Mock Tests for EmSAT Achieve 2024 preparation. The EmSAT Chemistry Mock Test- 2 questions and answers have been prepared according to the EmSAT Achieve exam syllabus.The EmSAT Chemistry Mock Test- 2 MCQs are made for EmSAT Achieve 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for EmSAT Chemistry Mock Test- 2 below.
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EmSAT Chemistry Mock Test- 2 - Question 1

The nature of inter-molecular forces among benzene molecules is

Detailed Solution for EmSAT Chemistry Mock Test- 2 - Question 1
Intermolecular Forces - Benzene. There are three different types of intermolecular forces, dipole interaction, hydrogen bonding, and dispersion forces. The only one that occurs with Benzene is dispersion forces because it is a non-polar molecule.
EmSAT Chemistry Mock Test- 2 - Question 2

The geometrical isomerism is shown

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EmSAT Chemistry Mock Test- 2 - Question 3

The addition of HCN to a carbonyl compound is an example of

Detailed Solution for EmSAT Chemistry Mock Test- 2 - Question 3
As carbonyl contains pi bond which broke and later get added therefore it is a ncleophilic addtion reaction.
EmSAT Chemistry Mock Test- 2 - Question 4
Acetaldehyde is the rearrangement product of
EmSAT Chemistry Mock Test- 2 - Question 5
The alkene  reacts readily with  and formed the product B which on oxidation with alkaline hydrogen peroxides produces
EmSAT Chemistry Mock Test- 2 - Question 6
The ortho-para directing group among the following is
EmSAT Chemistry Mock Test- 2 - Question 7
Amongst the following, the compound that can be most readily sulphonated is
Detailed Solution for EmSAT Chemistry Mock Test- 2 - Question 7
−CH3 group that has +1 effect and due to its presence, toluene has highest electron density in the benzene ring.
For this reason Toluene can be easily sulphonated.
EmSAT Chemistry Mock Test- 2 - Question 8
Chloroform on warming with Ag powder gives
EmSAT Chemistry Mock Test- 2 - Question 9

Ethyl alcohol gives ethyl chloride with the help of

Detailed Solution for EmSAT Chemistry Mock Test- 2 - Question 9

With SOCl2, alcohols give Haloalkanes the best way and also from NaCl we obtain only Cl- which is weak nucleophile and cannot replace OH- which is a stronger nucleophile.

EmSAT Chemistry Mock Test- 2 - Question 10
Which of the following compound will make precipitate most readily with ?
EmSAT Chemistry Mock Test- 2 - Question 11
Which of the following is responsible for depletion of the ozone layer in the upper strata of the atmosphere?
EmSAT Chemistry Mock Test- 2 - Question 12
7.5 grams of a gas occupy 5.6 litres of volume at STP. The gas is
EmSAT Chemistry Mock Test- 2 - Question 13
The number of water molecules present in a drop of water (volume 0.0018 ml) at room temperature is
Detailed Solution for EmSAT Chemistry Mock Test- 2 - Question 13
The density of water is 1g/cm3 Volume of a drop of water =0.0018ml Mass of water drop=0.0018g Moles of water=0.0001 No of water molecules in 1 drop =0.0001X6.022X10^23 =6.022X10^19 water molecules.
EmSAT Chemistry Mock Test- 2 - Question 14
The correct representation of Charle’s law is given by
EmSAT Chemistry Mock Test- 2 - Question 15
The structure of TlCl is similar to CsCl. What would be the radius ratio in TlCl ?
*Answer can only contain numeric values
EmSAT Chemistry Mock Test- 2 - Question 16

Sulphur trioxide is prepared by the following two reactions:-
S8(s) + 8 O2(g) —→ 8 SO2(g)
2SO2(g) + O2(g) —→ 2 SO3(g)
How many grams of SO3 are produced from 1 mole S8?


Detailed Solution for EmSAT Chemistry Mock Test- 2 - Question 16

from the given reaction, it is clear that 1 mol Swill give 8 moles of SO3.

*Answer can only contain numeric values
EmSAT Chemistry Mock Test- 2 - Question 17

How many elements are more electropositive than Cl?
Be, F, O, S, P, Au, H, Na


Detailed Solution for EmSAT Chemistry Mock Test- 2 - Question 17

6.0
F and O are more electronegative than Cl.

*Answer can only contain numeric values
EmSAT Chemistry Mock Test- 2 - Question 18

How many elements have more ionisation energy as compared to their next higher atomic number element?
Na, Mg, Al, Si, P, S, Cl, Ar


Detailed Solution for EmSAT Chemistry Mock Test- 2 - Question 18

2.0 Order of ionization energy
Na < M g > Al < Si < P > S < Cl < Ar

*Answer can only contain numeric values
EmSAT Chemistry Mock Test- 2 - Question 19

How many of the following compounds are more reactive than benzene towards electrophilic substitution.


Detailed Solution for EmSAT Chemistry Mock Test- 2 - Question 19

*Answer can only contain numeric values
EmSAT Chemistry Mock Test- 2 - Question 20

Number of d-orbitals used in the hybridisation of ICl3 is = x and number of lone pair at central atom = y find x + y = ?


Detailed Solution for EmSAT Chemistry Mock Test- 2 - Question 20


sp3d    [x = 1; y = 2]
lp = 2
x + y = 1 + 2 = 3

EmSAT Chemistry Mock Test- 2 - Question 21

The alcohol manufactured from water gas is

Detailed Solution for EmSAT Chemistry Mock Test- 2 - Question 21

Water gas and H2 reacts to produce methanol.

EmSAT Chemistry Mock Test- 2 - Question 22

One gm of oxygen at NTP occupies the volume

Detailed Solution for EmSAT Chemistry Mock Test- 2 - Question 22

We know that the atomic weight of oxygen is 16. At NTP volume of 16 gm of oxygen is 22.4 litre. Hence, volume of 1 gm of oxygen at NTP

EmSAT Chemistry Mock Test- 2 - Question 23

Number of unpaired electrons in 1s2, 2s2 2p3 is

Detailed Solution for EmSAT Chemistry Mock Test- 2 - Question 23

1 s2 2s2 2p3 can be shown as 

Therefore, there are 3 unpaired electrons.

EmSAT Chemistry Mock Test- 2 - Question 24

When primary amine is heated with CS2 in presence of excess of mercuric chloride, it produce isothiocyanate. This reaction is known as

Detailed Solution for EmSAT Chemistry Mock Test- 2 - Question 24

Primary amine on heating with CS2 is presence of excess of HgCI2 produce ethyl isothiocyanate which has smell of mustard oil. Therefore, it is known as Hoffmann’s mustard oil reaction.

EmSAT Chemistry Mock Test- 2 - Question 25

The most stable carbonium ion is

Detailed Solution for EmSAT Chemistry Mock Test- 2 - Question 25

The most stable carbonium ion is triphenyl methyl carbonium ion because the π-electrons of three benzene rings are delocalized with tb vacant π-orbital of central carbon atom. Therefore, it is stabilized by resonance.

EmSAT Chemistry Mock Test- 2 - Question 26

Total number of electrons in all the p-orbitals of bromine will be

Detailed Solution for EmSAT Chemistry Mock Test- 2 - Question 26

The electronic configuration of bromine atom is
1s2, 2s2 2p6, 3s2 3p6 3d10,4s2 4p5
Hence, total number of p-electrons is 17.

EmSAT Chemistry Mock Test- 2 - Question 27

Flux is used to remove

Detailed Solution for EmSAT Chemistry Mock Test- 2 - Question 27

Flux is used to remove silica and undesirable metal oxide. It is an external material added during smelting to convert infusible impurities into an easily fusible material known as slag.

EmSAT Chemistry Mock Test- 2 - Question 28

Ionization constant of acetic acid is 1.8 * 10-5. The concentration of H+ ions in 0.1 M solution is

Detailed Solution for EmSAT Chemistry Mock Test- 2 - Question 28

Since, acetic acid is a weak electrolyte, hence

EmSAT Chemistry Mock Test- 2 - Question 29

Acetone and acetaldehyde can be identified by

Detailed Solution for EmSAT Chemistry Mock Test- 2 - Question 29

Acetaldehyde and acetone both comes under carbonyl group. Both respond to 2, 4-dinitrophenyl hydrazine to produce yellow or orange precipitate. Aldehydes produce colour with Schiff’s reagent while ketones do not respond to this test.

EmSAT Chemistry Mock Test- 2 - Question 30

On heating one end of a piece of metal, tlhe other end becomes hot because of

Detailed Solution for EmSAT Chemistry Mock Test- 2 - Question 30

On heating the one end of the metal piece the other end becomes hot this is due to the movement of energised electrons from one end to other end.

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