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Full Mock Test & Solutions: GATE Engineering Sciences Mock Test - 2 (65 Questions)

You can boost your GATE Engineering Sciences 2026 exam preparation with this GATE Engineering Sciences Mock Test - 2 (available with detailed solutions).. This mock test has been designed with the analysis of important topics, recent trends of the exam, and previous year questions of the last 3-years. All the questions have been designed to mirror the official pattern of GATE Engineering Sciences 2026 exam, helping you build speed, accuracy as per the actual exam.

Mock Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 180 minutes
  • - Total Questions: 65
  • - Analysis: Detailed Solutions & Performance Insights
  • - Sections covered: General Aptitude, Engineering Mathematics (XE-A), Engineering Sciences (XE-B) & (XE-E)

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GATE Engineering Sciences Mock Test - 2 - Question 1

Gauri mentioned that she is able to play the keyboard __________ her sister.

GATE Engineering Sciences Mock Test - 2 - Question 2

During a press conference regarding the recent scam, the minister stated, "The responsibility lies here." What was the meaning conveyed by the minister's remark?

Detailed Solution: Question 2

If you say 'The buck stops here' or 'the buck stops with me' you mean that you have to take responsibility for something and will not try to pass the responsibility onto someone else. Therefore the right option is 'C'. He will assume final responsibility.

GATE Engineering Sciences Mock Test - 2 - Question 3

Select the pair that most closely represents the relationship found in the capitalized pair.
DRILL: BORING ::

Detailed Solution: Question 3

(THING AND PURPOSE) A drill is a tool used for boring; a die is tool used for shaping.

GATE Engineering Sciences Mock Test - 2 - Question 4

The act of listening to music while exercising is known to enhance performance and lessen discomfort. Researchers investigated the impact of music on students' learning capabilities while studying, but the findings were inconclusive. Students who required external stimulation for effective studying performed worse, whereas those who did not need any external stimulation experienced benefits from music.

Which of the following statements represents the CORRECT inference from the passage above?

GATE Engineering Sciences Mock Test - 2 - Question 5

Consider the equation represented by
If , what is the value of α?

Detailed Solution: Question 5

Given: 

From the third equation: x₁ - x₂ = 1
⇒ x₁ = x₂ + 1

Substitute x₁ = x₂ + 1 into the first equation: 2(x₂ + 1) - 4x₂ = -1
2x₂ + 2 - 4x₂ = -1
-2x₂ + 2 = -1
-2x₂ = -3
x₂ = 3/2

Now substitute x₂ = 3/2 back into x₁ = x₂ + 1: x₁ = 3/2 + 1 = 5/2

Finally, substitute x₁ = 5/2 and x₂ = 3/2 into the second equation to find α: x₁ + x₂ = α
5/2 + 3/2 = α
α = 4

*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 2 - Question 6

An individual, who tells the truth 3 out of 4 times, rolls a fair six-sided die and reports that the result is 5. What is the probability that the actual result is indeed 5? (Round your answer to three decimal places.)


GATE Engineering Sciences Mock Test - 2 - Question 7

The expression (with m > 0 and n being a natural number) is equal to what?

Detailed Solution: Question 7

First of all note that, the integrand f(x) = xm(ln x)n has no meaning at x  = 0.
It can be made continuous on the interval [0,1] for any m > 0 and n > 0, by putting f(0) = 0. Indeed,

Hence, in particular, it follows that the integral In exists at m > 0, n > 0. To compute it we integrate by parts, putting

Hence,


The formula obtained reduces In to In-1 In particular, with a natural n, taking into account that 

we get,

GATE Engineering Sciences Mock Test - 2 - Question 8

Consider the function f(x, y) = x4 y4 − 2x2 4xy − 2y2 α, which is a real-valued function. Which of the following statements is TRUE for every value of α?

*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 2 - Question 9

Consider the line segment C1 extending from the point (0, 1) to and the arc C2 of the circle defined by x2 y2 = 1, which stretches from (0, 1) to . If
where , then determine the value of α2 β2 (rounded to two decimal places).


*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 2 - Question 10

Consider I as the identity matrix of order 7, and let A be a 7 × 7 real matrix whose characteristic polynomial is given by CA(λ) = λ2(λ - 1)α(λ 2)β, where α and β are positive integers. Given that A is diagonalizable and satisfies the condition rank(A) = rank(A 2I), determine the value of rank(A - I) ____________ (as an integer).


GATE Engineering Sciences Mock Test - 2 - Question 11

Match List - I with List - II and choose the correct answer from the codes provided below the lists:
List - I
P. Stokes law
Q. Bluff body
R. Streamline body
S. Karman Vortex Street
List - II
1. Strouhal number
2. Creeping motion
3. Pressure drag
4. Skin friction drag

Detailed Solution: Question 11

- Stokes law → In Creeping motion this law is applied.
i.e. Reynolds Number less than unity
- Bluff body → Pressure drag is dominated in flow over this body.
- Stream line body → Friction drag dominates for flow over streamlined body.
- Kannan vortex street → Strouhal Number = Oscillating flow of wires experiences vortex shedding

GATE Engineering Sciences Mock Test - 2 - Question 12

Which of the following statements is CORRECT?

*Multiple options can be correct
GATE Engineering Sciences Mock Test - 2 - Question 13

Which of the following criteria must be met for a fluid to be in a steady state condition?

Detailed Solution: Question 13

In a steady flow, the properties do not change with respect to time and they may vary with position.

*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 2 - Question 14

A spherical ball is being held steady against the force of gravity by an upward jet of air, as depicted in the accompanying figure. Assume the acceleration due to gravity is g = 10 m/s2. The rate of air mass flow directed towards the ball is 0.01 kg/s, and the air has an upward velocity of 3 m/s when it reaches the ball. Ignoring the buoyancy force and applying the principle of integral momentum balance, determine the mass (in grams, rounded to one decimal place) of the ball is ____.


GATE Engineering Sciences Mock Test - 2 - Question 15

A Newtonian fluid flows in a one-dimensional manner through a circular pipe.

The velocity distribution for laminar flow is expressed as:
ν(r) = umax [1 − (r2 / R2)]

Here, R = 0.08 m represents the radius of the pipe, while r indicates the radial distance from the pipe's center. The maximum velocity, umax, is found at the center of the pipe.

The drag force acting on the pipe (in N) is:

Consider ρfluid = 0.0010 Pa·s, L = 30 m, and umax = 7 m/s.

Detailed Solution: Question 15

Given velocity profile u(r) = umax [1 − (r² / R²)]

The maximum velocity occurs at the center, r = 0.

The shear stress at the pipe surface is:
τw = −μ (du/dr)|(r=R)
= − μ d/dr [1 − (r² / R²)]|
(r=R)
= −μumax (−2r / R)|(r = R)

τw = (2μumax) / R

The friction drag FD = τw · As

∴ FD = (2μumax / R) × (2πRL)

FD = 4πμLumax

FD = 4π × 0.0010 × 30 × 7

FD = 2.638 N

FD ≈ 2.64 N

GATE Engineering Sciences Mock Test - 2 - Question 16

A cylindrical container with a diameter of 150 mm is completely filled with glycerin, and a pipe with a diameter of 50 mm is submerged in the glycerin to a depth of 300 mm. When kerosene is introduced into the pipe, the glycerin displaced by the kerosene spills over the top, ensuring that the kerosene does not exit from the bottom end of the pipe.

The volume of kerosene inside the pipe (in m³) is:

Given ρker = 814 kg/m³ and ρgly = 1260 kg/m³.

Detailed Solution: Question 16

From manometric balance:
Patm + ρkghk − ρg1ghg1 = Patm

⇒ hke = (ρgL / ρke) × hgL

From diagram, hg1 = 0.3 m

And hke = (h + 0.3) m

∴ hke = (ρgL / ρke) × hgL

(h + 0.3) = (1260 / 814) × 0.3

⇒ h = 0.1644 m

∴ hke = h + 0.3 = 0.1644 + 0.3 = 0.4644 m

Volume of kerosene in the pipe:
V = πr²hke
= π × (0.025)² × 0.4644
⇒ V = 0.912 × 10⁻³ m³

GATE Engineering Sciences Mock Test - 2 - Question 17

A vertical jet with a velocity of 10 m/s is directed at a horizontal plate that has a total load of 200 N. The fluid used is oil with a density of 800 kg/m³, and the diameter of the nozzle exit is 60 mm. Calculate the height necessary to elevate the plate and keep it stationary (in m):

Detailed Solution: Question 17

From the diagram, we can say that V2 < V1.

Applying Bernoulli's equation between points 1 and 2:
(P1/γ) + (V1²/2g) + z1 = (P2/γ) + (V2²/2g) + z2

Since P1 = P2 = Patm:
(V1²/2g) = (V2²/2g) + (z2 - z1)

V2 = √(V1² - 2gh) ...(1)

Applying the linear momentum equation in the y-direction:

(ΣF)y = (ṁv)f − (ṁv)i = weight of the fluid
= ṁ(vf − (−vi))

(ΣF)y = ṁvi

(ΣF)y = ρaV1(V2)

200 = 800 × π/4 × (60/1000)² × 10 × V2

⇒ V2 = 8.85 m/s

From equation (1):
v2 = √(v1² − 2gh)

(8.85)² = v1² − 2gh 
⇒ 2gh = 100 − 78.33
⇒ h = 1.112 m ≈ 1.12 m

GATE Engineering Sciences Mock Test - 2 - Question 18

The radius of a circular duct is described by the equation:

r = 0.06(1 - √x) m, where x is measured in meters.

At point A, the flow of water is given as Q = 0.03 m³/s at t = 0, with an increase rate of dQ/dt = 0.003 m²/s². If a water particle is located at x = 0.3 m when t = 0.4 s, what is the acceleration at that point (in m/s²)?

Assume average velocities at the cross-section.

Detailed Solution: Question 18

The discharge as a function of time t is:

Q = 0.003 m³/s + (0.003 m³/s²)t
Q = [0.003(1 + t)] m³/s

The cross-sectional area of the flow as a function of x is:

Thus the velocity of the flow is

The acceleration can be determined using

a = ∂u/∂t + u(∂u/∂x)

Here

At x = 0.3 m and t = 0.4 s

Also, u = 1.815 m/s. Then:

a = 1.2968 m/s² + (1.815 m/s)(7.3286/s)
a = 14.60 m/s² = 14.6 m/s²

GATE Engineering Sciences Mock Test - 2 - Question 19

Air moves through a very broad duct as illustrated in the figure. To sustain a consistent free stream velocity of 0.5 m/s across the central core of 200 mm, if the flow is laminar, the displacement thickness is δ* = (1.721x) / √Rex, and in the case of turbulent flow, the displacement thickness is δ* = (0.020x) / (Rex)1/7. Determine the necessary value of a (in mm) when x = 4 m. Assume steady flow and take v = 18.9 × 10-6 m2/s.

Detailed Solution: Question 19

The Reynolds number at x = 4m is

Since Rex < (Rex)cr = 5(10⁵), the boundary layer is laminar throughout the entire length of the duct.

Thus, the displacement thickness is:

The dimension of the square duct at x = 4 m is:

a = 200 mm + 2δ*
= 200 mm + 2(21.16 mm)
= 242 mm

*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 2 - Question 20

A certain part of cast iron piping of a water distribution system involves a parallel section. Both parallel pipes have a diameter of 30 cm, and the flow is fully turbulent. One of the branches (pipe A) is 1500 m long, while the other branch (pipe B) is 2500 m long. If the flow rate through pipe A is 0.4 m³/s, determine the flow rate (in m³/s) through pipe B, assuming no minor losses.

(Correct up to three decimal places)


Detailed Solution: Question 20

The average velocity in pipe A:

VA = Ṽ / Ac = Ṽ / (πD² / 4) = 0.4 m³/s / (π(0.30 m)² / 4) = 5.659 m/s

When two pipes are parallel in a piping system, the head loss for each pipe must be the same. When the minor losses are disregarded, the head loss for fully developed flow in a pipe of length L and diameter D is 

In case of parallel pipe fluid flow problems, head losses are the same:

(hL)A = (hL)B

fA × (LA / DA) × (VA² / 2g) = fB × (LB / DB) × (VB² / 2g)

VB = VA × √(LA / LB) = (5.659 m/s) × √(1500 m / 2500 m) = 4.383 m/s

Then the flow rate in pipe B becomes:
VḂ = AB × VB = [πD² / 4] × VB = [π(0.3 m)² / 4] × (4.383 m/s) = 0.310 m³/s

*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 2 - Question 21

A conical pipe has a diameter of 30 cm at point A (elevation 2 m) and a diameter of 40 cm at point B (elevation 10 m). The kinetic energy correction factors at sections A and B are 1.1 and 1.3, respectively. The head loss through the pipe can be disregarded. Given that the pressure at point A is 100 kPa and the flow rate is 0.4 m3/s of water, what is the pressure at point B (in kPa)?


Detailed Solution: Question 21

In the given problem, we do not know the direction of flow but we need not to worry as mentioned that
we can neglect the losses. Given : DA = 0.3 m, ZA = 2 m, DB = 0.4 m, ZB = 10 m 


By applying Bernoulli equation


⇒ PB = 32.51kPa

*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 2 - Question 22

Water is moving through a horizontal circular pipe with a flow rate of Q. In the venturi section (Section-1 in the diagram), a low pressure is created, causing water to be drawn upward from a reservoir through a connecting pipe as illustrated. Assume the acceleration due to gravity, g, is 10 m/s2. Given that the flow rate Q = 0.1 m3/s, D1 = 8 cm, and D2 = 20 cm, determine the maximum height (h, in meters, rounded to one decimal place) of the venturi above the reservoir that is just sufficient to lift the liquid to Section-1 is _____.


*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 2 - Question 23

Air with a density of 0.5 kg/m3 flows horizontally into a jet engine at a constant velocity of 200 m/s through an inlet area of 1.0 m2. After entering the engine, the air moves through the combustion chamber, and the exhaust gases exit the jet engine horizontally at a steady speed of 700 m/s. The mass flow rate of the fuel introduced into the combustion chamber is insignificant compared to the mass flow rate of the air. Additionally, disregard the pressure difference between the incoming air and the exhaust gases. The absolute magnitude of the horizontal force (in kN, rounded to one decimal place) acting on the jet engine is__________.


*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 2 - Question 24

In a fully-developed, incompressible laminar flow of a Newtonian fluid within a pipe, as illustrated in the figure, the velocity distribution across a cross-section is represented by  where U denotes a constant value. The length of the pipe is L and the dynamic viscosity of the fluid is µ. The power P needed to maintain this flow is given by the equation P = cμLU2, with c being a dimensionless constant. Determine the value of the constant c (to one decimal place) as _________.
\n


GATE Engineering Sciences Mock Test - 2 - Question 25

A steel tank holds 6 kg of propane (both liquid and vapor) at a temperature of 20°C, occupying a volume of 0.015 m³. The critical specific volume vc is 0.00454 m³/kg. As the tank is gradually heated, what will occur to the liquid level within?

  • Mass is 6 kg
  • Mass is 1 kg instead of 6 kg

Detailed Solution: Question 25

Consider volume and mass to be constant.

V₂ = V₁ = V / m = 0.015 / m = 0.0025 m³/kg
∴ Vc = 0.00454 > V₁
∴ Eventually reaches saturated liquid, and level rises to the top.

V₁ = V₂ = V / m = 0.015 / 1 = 0.015 m³/kg
∴ V₁ > Vc
It will reach saturated vapour, and the liquid level falls to the bottom.

GATE Engineering Sciences Mock Test - 2 - Question 26

A quantity of 1 kg of air at a pressure of 1 bar and a temperature of 27°C is subjected to heating in a closed system, maintaining constant pressure, until it reaches a temperature of 177°C. The heat is supplied from a reservoir that maintains a constant temperature of 577°C. Assume the surrounding atmospheric temperature is 20°C. Calculate the percentage of heat added per kg of air as the available energy (in %):
Take Cp = 1.005 kJ/kgK

Detailed Solution: Question 26

The heat transferred to air at constant pressure:

Qs = mCp(T2 - T1)
Qs = 1 × 1.005 × (177 - 27)
Qs = 150.75 kJ

Unavailable energy (UAE) = Qs × (T0 / TH)
UAE = 150.75 × (293 / 850)
UAE = 51.96 kJ

Available energy (AE) = Qs - UAE
AE = 150.75 - 51.96
AE = 98.8 kJ

Percentage of heat added as available energy = (AE / Qs) × 100
= (98.8 / 150.75) × 100
= 65.53%

*Multiple options can be correct
GATE Engineering Sciences Mock Test - 2 - Question 27

A single mole of a monoatomic ideal gas undergoes four distinct thermodynamic processes.

Detailed Solution: Question 27

Process 1 can be adiabatic/polytropic, so we cannot say that no heat is exchanged.

W₂ = 3P₀(3V₀ - V₀) = 6P₀V₀

Process 3, volume is constant, so work is zero.

Process 4, product (PV) is the same at initial and final states, so T = constant.

*Multiple options can be correct
GATE Engineering Sciences Mock Test - 2 - Question 28

A perfect gas occupying 55 l at a pressure of 125 kPa and a temperature of 300 K is subjected to isentropic compression until its temperature reaches 380 K. The work performed during this process is 5.1 kJ. Given that the characteristic gas constant R is 260 J/kg·K.

Detailed Solution: Question 28

V₁ = 55 l = 0.055 m³

Mass of the perfect gas:
m = (P₁V₁) / (RT₁)
m = (125 × 10³ × 0.055) / (260 × 300)
m = 0.088 kg

Work interaction during the compression:
W = (mR(T₁ - T₂)) / (γ - 1)
-5.1 × 10³ = (0.088 × 260 × (300 - 380)) / (γ - 1)
γ = 1 + (0.088 × 260 × 80) / 5.1 × 10³
γ = 1.358

Specific heat at constant volume:
Cv = R / (γ - 1) = 260 / 0.358 = 726.25 J/kgK

Specific heat at constant pressure:
Cp = Cv + R = 726.25 + 260 = 986.25 J/kgK

For a perfect gas undergoing an isentropic process:
TV^(γ - 1) = constant
T2V2^(γ - 1) = T1V1^(γ - 1)
V2 = (T1 / T2)^(1 / (γ - 1)) × V1
V2 = (300 / 380)^(1 / (1.358 - 1)) × 55
V2 = 28.44 l

*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 2 - Question 29

A commercial refrigeration unit functions between pressures of 1.24 bar and 13.672 bar. If the liquid is cooled to 10°C after the condensation process, what is the percentage increase in the coefficient of performance (COP) (in %)?

Use data:
h1 = 176.48 kJ/kg
h2 = 220.6 kJ/kg
hf = 79.73 kJ/kg
h'f = 90.28 kJ/kg


Detailed Solution: Question 29

*Answer can only contain numeric values
GATE Engineering Sciences Mock Test - 2 - Question 30

A container has a double wall where the wall cavity is filled with carbon dioxide at room temperature and pressure. When the container is filled with a cryogenic liquid at 100 K, the carbon dioxide will freeze so that the wall cavity has a mixture of solid and vapor carbon dioxide at the sublimation pressure. At -90°C, Psub = 38.1 kPa and hfg = 574.5 kJ/kg.

The pressure in the wall cavity at 100 K is __________ × 10⁻² Pa.
Assume R = 0.188 kJ/kgK. (Round off to two decimal places)


Detailed Solution: Question 30

Given:
T₁ = -90°C = 183 K
P₁ = 38.1 kPa
hfg = 574.5 kJ/kg
T₂ = 100 K

From Clausius-Clapeyron equation:

ln(P₂ / P₁) = (hfg / R) * [(1 / T₁) - (1 / T₂)]ₛₐₜ

= 574.5 / 0.188 * [(1 / 183) - (1 / 100)]

ln(P₂ / P₁) = -13.858

P₂ = 3.68 × 10⁻² Pa

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