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Class 5 Exam  >  Class 5 Tests  >  Math Olympiad for Class 5  >  HOTs for Maths Olympiad - 2 - Class 5 MCQ

HOTs for Maths Olympiad - 2 - Class 5 MCQ


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10 Questions MCQ Test Math Olympiad for Class 5 - HOTs for Maths Olympiad - 2

HOTs for Maths Olympiad - 2 for Class 5 2024 is part of Math Olympiad for Class 5 preparation. The HOTs for Maths Olympiad - 2 questions and answers have been prepared according to the Class 5 exam syllabus.The HOTs for Maths Olympiad - 2 MCQs are made for Class 5 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for HOTs for Maths Olympiad - 2 below.
Solutions of HOTs for Maths Olympiad - 2 questions in English are available as part of our Math Olympiad for Class 5 for Class 5 & HOTs for Maths Olympiad - 2 solutions in Hindi for Math Olympiad for Class 5 course. Download more important topics, notes, lectures and mock test series for Class 5 Exam by signing up for free. Attempt HOTs for Maths Olympiad - 2 | 10 questions in 10 minutes | Mock test for Class 5 preparation | Free important questions MCQ to study Math Olympiad for Class 5 for Class 5 Exam | Download free PDF with solutions
HOTs for Maths Olympiad - 2 - Question 1
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Fill in the blanks and select the correct option.
(i) The sum of 372 and 648 is P.
(ii) The difference between 987 and 543 is Q.
(iii) The product of 25 and 4 is R.

Detailed Solution for HOTs for Maths Olympiad - 2 - Question 1

(i) 372 + 648 = 1020, so P = 1020.
(ii) 987 - 543 = 444, so Q = 444.
(iii) 25 * 4 = 100, so R = 100.

HOTs for Maths Olympiad - 2 - Question 2
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Fill in the blanks and select the correct option.
(i) The greatest common divisor of 48 and 64 is P.
(ii) The next prime number after 17 is Q.
(iii) The square of 12 is R.

Detailed Solution for HOTs for Maths Olympiad - 2 - Question 2

(i) The GCD of 48 and 64 is 16, so P = 16.
(ii) The next prime number after 17 is 19, so Q = 19.
(iii) The square of 12 is 144, so R = 144.

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HOTs for Maths Olympiad - 2 - Question 3
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Fill in the blanks and select the correct option.
(i) The area of a rectangle with length 10 cm and width 5 cm is P cm².
(ii) The perimeter of a square with side length 7 cm is Q cm.
(iii) The volume of a cube with side length 3 cm is R cm³.
 

Detailed Solution for HOTs for Maths Olympiad - 2 - Question 3

(i) Area = length * width = 10 * 5 = 50 cm², so P = 50.
(ii) Perimeter = 4 * side length = 4 * 7 = 28 cm, so Q = 28.
(iii) Volume = side³ = 3³ = 27 cm³, so R = 27.

HOTs for Maths Olympiad - 2 - Question 4
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Fill in the blanks and select the correct option.
(i) The average of 8, 12, and 20 is P.
(ii) The median of 4, 15, and 9 is Q.
(iii) The mode of 2, 3, 3, 4, 4, 4, 5 is R.
 
Detailed Solution for HOTs for Maths Olympiad - 2 - Question 4

(i) Average = (8 + 12 + 20) / 3 = 40 / 3 ≈ 13, so P = 13.
(ii) Median = middle number = 9, so Q = 9.
(iii) Mode = most frequent number = 4, so R = 4.

HOTs for Maths Olympiad - 2 - Question 5
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Fill in the blanks and select the correct option.
(i) The smallest 3-digit number divisible by 5 is P.
(ii) The number of days in a leap year is Q.
(iii) The sum of the angles in a triangle is R degrees.
Detailed Solution for HOTs for Maths Olympiad - 2 - Question 5

(i) The smallest 3-digit number divisible by 5 is 100, so P = 100.
(ii) A leap year has 366 days, so Q = 366.
(iii) The sum of the angles in a triangle is 180 degrees, so R = 180.

HOTs for Maths Olympiad - 2 - Question 6
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Fill in the blanks and select the correct option.
(i) The number of edges in a cube is P.
(ii) The number of vertices in a cuboid is Q.
(iii) The number of faces in a pyramid with a square base is R.
Detailed Solution for HOTs for Maths Olympiad - 2 - Question 6

(i) A cube has 12 edges, so P = 12.
(ii) A cuboid has 8 vertices, so Q = 8.
(iii) A pyramid with a square base has 5 faces, so R = 5.

HOTs for Maths Olympiad - 2 - Question 7
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Fill in the blanks and select the correct option.
(i) The next number in the sequence 3, 6, 9, 12, ... is P.
(ii) The total number of minutes in 3 hours is Q.
(iii) The decimal form of 3/4 is R.
Detailed Solution for HOTs for Maths Olympiad - 2 - Question 7

(i) The sequence increases by 3, so the next number is 15, so P = 15.
(ii) 3 hours = 3 * 60 = 180 minutes, so Q = 180.
(iii) 3/4 = 0.75, so R = 0.75.

HOTs for Maths Olympiad - 2 - Question 8
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Fill in the blanks and select the correct option.
(i) The result of 81 ÷ 9 is P.
(ii) The result of 49 ÷ 7 is Q.
(iii) The result of 64 ÷ 8 is R.
Detailed Solution for HOTs for Maths Olympiad - 2 - Question 8

(i) 81 ÷ 9 = 9, so P = 9.
(ii) 49 ÷ 7 = 7, so Q = 7.
(iii) 64 ÷ 8 = 8, so R = 8.

HOTs for Maths Olympiad - 2 - Question 9
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Fill in the blanks and select the correct option.
(i) The next even number after 14 is P.
(ii) The sum of 9 and 6 is Q.
(iii) The difference between 20 and 13 is R.
Detailed Solution for HOTs for Maths Olympiad - 2 - Question 9

(i) The next even number after 14 is 16, so P = 16.
(ii) 9 + 6 = 15, so Q = 15.
(iii) 20 - 13 = 7, so R = 7.

HOTs for Maths Olympiad - 2 - Question 10
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Fill in the blanks and select the correct option.
(i) The number of days in February in a non-leap year is P.
(ii) The total number of sides in a pentagon is Q.
(iii) The product of 7 and 9 is R.
Detailed Solution for HOTs for Maths Olympiad - 2 - Question 10

(i) February has 28 days in a non-leap year, so P = 28.
(ii) A pentagon has 5 sides, so Q = 5.
(iii) 7 * 9 = 63, so R = 63.

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