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HPCL Electrical Engineer Mock Test - 1 - PSSSB Clerk MCQ


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30 Questions MCQ Test HPCL Electrical Engineer Mock Test Series 2024 - HPCL Electrical Engineer Mock Test - 1

HPCL Electrical Engineer Mock Test - 1 for PSSSB Clerk 2024 is part of HPCL Electrical Engineer Mock Test Series 2024 preparation. The HPCL Electrical Engineer Mock Test - 1 questions and answers have been prepared according to the PSSSB Clerk exam syllabus.The HPCL Electrical Engineer Mock Test - 1 MCQs are made for PSSSB Clerk 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for HPCL Electrical Engineer Mock Test - 1 below.
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HPCL Electrical Engineer Mock Test - 1 - Question 1

Two persons start running towards each other, one from A to B and the other from B to A. They cross each other in one hour. The first person reaches B hours before the second person reaches A. If the distance between A and B is 8 km, then find the speed of the faster man.

Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 1

Given:

The distance between A and B is 8 km. And they cross each other in one hour.

Formula:

Speed = Distance/Time

Calculation:

Let the speed of the slower man and faster man be x km/hr and y km/hr respectively.

According to the question

x + y = 8/1

⇒ x + y = 8 →(1)

Again,

8/x – 8/y = 16/15 --- (2)

From (1) and (2), we get

8/x – 8/(8 – x) = 16/15

⇒ 8[1/x - 1/(8 - x)] = 16/15

⇒ 8[{8 - x - x}/x(8 - x)] = 16/15

⇒ [{8 - 2x}/x(8 - x)] = 2/15

⇒ 120 - 30x = 16x - 2x2

⇒ 2x2 - 16x - 30x + 120 = 0

⇒ 2x2 - 46x + 120 = 0

⇒ x2 - 23x + 60 = 0

⇒ (x - 20)(x - 3) = 0

⇒ x = 3 (∵ x = 20 not possible)

The speed of the faster man = y = 8 - x

⇒ y = 8 - 3 = 5 km/hr

∴ The speed of the faster man is 5 km/hr

HPCL Electrical Engineer Mock Test - 1 - Question 2

The distance between stations A and B is 778 kilometres. A train travels from station A to station B at a uniform speed of 84 km/h and then returns to station A at a uniform speed of 56 km/h. What is the train's average speed (in km/h) throughout the journey?

Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 2

Given:

Distance between stations A and B = 778 km

Speed while going from A to B = 84 km/h

Speed while returning from B to A = 56 km/h

Concept Used:

Time =

Calculation:

⇒ Time taken for going from station A to B = hours

⇒ Time taken for returning from B to A = hours

⇒ Total Distance of travel = 778 + 778 = 1556 km

⇒ Average Speed throughout the journey = km/h

Hence, the average speed of the train throughout the journey is 67.2 km/h

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HPCL Electrical Engineer Mock Test - 1 - Question 3

Directions: In this section, each of the following sentences has a blank space and each sentence is followed by four options. Select the most appropriate option to fill the blank space.

Ireland was part of the UK, _____ ?

Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 3

The correct answer is 'wasn't it'.

Key Points

  • The sentence is asking a question about whether Ireland was part of the UK in the past.
  • The question tag "wasn't it" is used to confirm or seek agreement on a statement that is in the past tense.

Therefore, the correct sentence is: 'Ireland was part of the UK, wasn't it?

Additional Information

  • Option 1) "Isn't it" is the present tense of the auxiliary verb "be" (is/are). It is incorrect because the sentence is in the past tense.
  • Option 3) "hasn't it" is the present perfect tense of the auxiliary verb "have" (has/have). It is incorrect because the sentence is simply asking a question about a past event, not about something that happened in the past and continues to the present.
  • Option 4) "weren't it" is the past tense of the auxiliary verb "be" (was/were) used with the pronoun "it." It is incorrect because the subject of the sentence is "Ireland," not "it."
HPCL Electrical Engineer Mock Test - 1 - Question 4

Select the most appropriate ANTONYM of the underlined word.

An autoimmune disease is a condition in which your immune system mistakenly attacks your body.

Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 4

Here the correct answer is Susceptible.

Key Points

  • The word "immune" refers to having protection or resistance against something, such as diseases or infections. In the given context, it specifically refers to the immune system's ability to defend the body against foreign substances and pathogens.("प्रतिरक्षा")
    • Example sentence: Vaccines help to boost your immune system, making you less susceptible to certain diseases.
  • Among the given options:
  • "Susceptible" means vulnerable or prone to something. In the context of immunity, it is the opposite of being immune. If someone is susceptible to a disease, it means their immune system is not able to provide sufficient protection against it.(अतिसंवेदनशील)
  • "Fragile" means delicate or easily broken. It does not convey the opposite meaning of "immune" in the context of the immune system attacking the body.(कमज़ोर)
  • "Sick" means unwell or having an illness. It is not an antonym of "immune."(बीमार)
  • "Sedentary" means characterized by or involving little physical activity. It does not convey the opposite meaning of "immune."(गतिहीन)
  • Among the options, "susceptible" is the best antonym of "immune" as it denotes the lack of immunity or the ability to resist the attacks of the immune system. In the case of autoimmune diseases, the immune system mistakenly attacks the body, indicating a lack of immunity against one's own cells or tissues.
HPCL Electrical Engineer Mock Test - 1 - Question 5

Directions: Each item in this section has a sentence with three underlined parts labelled as (a), (b) and (c). Read each sentence to find out whether there is any error in any underlined part and indicate your response on the answer sheet against the corresponding letter, i.e., (a) or (b) or (c). If you find no error, your response should be indicated as (d).

Many historians argues that (a)/ the primary reason for the collapse of the empire (b)/ was not external invasion but internal discord (c)/ No Error (d).

Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 5

The correct answer is "Many historians argues that".

Key Points

  • The error lies in the subject-verb agreement. "Historians" is a plural noun, so the verb "argues" should be "argue."
  • The presence of "s" in "argues" indicates a singular subject, making it incorrect with the plural subject "historians."
  • Correcting "argues" to "argue" aligns the verb with the plural subject.
  • Such errors are common when the subject's plurality is not matched by the verb, leading to grammatical inconsistency.

Therefore, the correct answer is- Correct answer A.

HPCL Electrical Engineer Mock Test - 1 - Question 6
Direction: Identify the correctly spelt sentence.
Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 6

The correct answer is "Celestial objects are not visible to the naked eye."

Key Points

  • The word "Celestial" means of the sky or of heaven. (आकाश या स्‍वर्ग से संबंधित)
    • Example: The moon is a celestial body.
  • The sentence conveys that the unaided eye cannot see objects in the sky.

  • Hence, option 4 is the correct answer.

HPCL Electrical Engineer Mock Test - 1 - Question 7
Simplify the following expression .
Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 7

Given:

Calculation:

⇒ 0.144 × 25

⇒ 3.6

∴ Required answer 3.6.

HPCL Electrical Engineer Mock Test - 1 - Question 8
A bus covers a distance of 30 km in 36 minutes. If its speed is decreased by 10 km/hr, then what will be the time taken by it to cover the same distance?
Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 8

Given:

The distance = 30 km

The time = 36 minutes

Concept:

Speed = Distance/Time

Calculation:

⇒ Let speed of bus be S

⇒ S = 30/(36/60) = (30 × 60)/36 = 50 km/h

⇒ Now, speed reduce by 10 km/h then time taken by bus to cover same distance

⇒ Time = 30/(50 - 10) = 30/40 = 3/4 hours = (3/4) × 60 = 45 minutes

∴ The required result will be 45 minutes.

HPCL Electrical Engineer Mock Test - 1 - Question 9

Find the altitude of an equilateral triangle whose side is cm.

Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 9

GIVEN:
Side of triangle = cm

FORMULA USED:
Altitude of equilateral triangle = (√3)/2 × side

CALCULATION:

Altitude =

Altitude = 4 cm

HPCL Electrical Engineer Mock Test - 1 - Question 10
Complete the sentence with correct connector. Husna was in pain _____ She did not tell anyone of her predicament.
Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 10

The correct answer is 'Option 1' - however.

Key Points

  • The connective 'however' is used to introduce a sentence, or part of a sentence, which surprising or which contrasts with what has just been said.
  • In this scenario, it's surprising or unexpected that Husna did not tell anyone about her pain, hence 'however' is the suitable connector.
  • It shows that despite Husna being in pain, she did not share her predicament with anyone.
  • Therefore, 'however' is the appropriate connector in this context.

Therefore, the correct answer is - 'Option 1' - however.

Additional Information

  • In Spite of (Option 2): This phrase is used to show that something happens or is true even though something else might have prevented it. However, it is not suitable in this sentence, because a contrast between two independent clauses is being emphasized.
  • Because (Option 3): This is used to introduce a reason or justification, which is not suitable in this context.
  • But (Option 4): While 'but' can be used to introduce a phrase or clause contrasting with what has already been mentioned, 'however' would be the more appropriate choice in this formal context.
  • The remaining questions will be answered in separate responses following the same format.
HPCL Electrical Engineer Mock Test - 1 - Question 11

Directions: In this section, each of the following sentences has a blank space and each sentence is followed by four options. Select the most appropriate option to fill the blank space.

The cows, as well as the horse, _____ on the grass in the field.

Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 11

The correct answer is "are grazing."

Key Points

  • "Subject verb agreement" means that a singular subject (she, Raj, star) takes a singular verb (is, goes, shines), whereas a plural subject takes a plural verb.
  • In the given sentence, we will use a modal auxiliary verb as a helping verb with the main verb.
  • When two subjects are joined by as well as, the verb agrees which comes is plural verb.
    • Example: The employees of the organization, as well as the CEO, have an interest in the project’s success.
  • Thus, we will use plural verb for the respective subjects.
  • Thus, the correct verb to use in the blank is "are grazing."
  • The correct sentence: The cow, as well as the horse, are grazing on the grass in the field.

Hence, the correct answer is option 3.

HPCL Electrical Engineer Mock Test - 1 - Question 12

Complete the sentence using appropriate option "Shyam and his brothers" ________ a famous sweet shop in our neighbourhood.

Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 12

The correct answer is: Option 4 ("Shyam and his brothers" is a famous sweet shop in our neighbourhood.)

Key Points

The correct answer is "is".

The sentence is talking about Shyam and his brothers as a group. The verb "is" is used for singular subjects, while the verb "are" is used for plural subjects. In this case, the subject is "Shyam and his brothers", which is a plural subject. However, we are talking about them as a group, so we use the singular verb "is".

HPCL Electrical Engineer Mock Test - 1 - Question 13
What least number must be added to 6072 to make it a perfect square?
Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 13

Calculation:

Here, 5929 < 6072 < 6084

⇒ (77)2 < 6072 < 782

Here, 6072 is much closer to 6084 than 5929

∴ We will subtract 6072 from 6084 to get the required number,

⇒ (6084 - 6072) = 12

∴ When we add 12 to 6072, we get 6084, which is perfect square of 78.

∴ Required number is 12.

HPCL Electrical Engineer Mock Test - 1 - Question 14

A marked price of an article is 20% above than the cost price of an article. A shopkeeper allows a discount of 10%. A selling price of an article is 2160. Find the profit percentage.

Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 14

Given:

Marked price of an article = 20% above than the cost price of an article

Discount = 10%

Selling price = Rs. 2160.

Calculation:

Marked price of an article = 2160 × 100/90 = Rs.2400

Cost price of an article = 2400 × 100/120 = Rs.2000

Profit = 2160 - 2000 = Rs.160

Required percentage = 160/2000 × 100 = 8%

∴ The profit percentage is 8%.

HPCL Electrical Engineer Mock Test - 1 - Question 15

In a certain code language, “dom pull ta” means - “bring hot food”, “pull tir sop” means “food is good” and “tak da sop” means “good bright boy”. Which of the following means “hot” in the same code language?

Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 15

According to the given information:

Code for "hot" is dom or ta.

As none of the options is dom or ta so we cannot determine exactly whether the code is dom or ta.

Hence, the correct answer is "Can not be accessed".

HPCL Electrical Engineer Mock Test - 1 - Question 16

If P denotes '+', Q denotes '-', R denotes '×' and S denotes '÷', then which of the following is correct?

Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 16

After replacing the Letter by their meaning we get,

Option 1:-

=16 x 12 + 49 ÷ 7 - 9

=16 x 12 + 7 - 9

=192 +7-9

=190 200

= L.H.S R.H.S

Option 2:-

= 32 ÷ 8 x 9 = 160 - 12 x 12

= 4 x 9 = 160 -12 x 12

= 36 = 160 - 144

= 36 16

= L.H.S R.H.S

Option 3:-

8 X 8 + 8 ÷ 8 - 8

= 8 X 8 + 1 -8

= 64 -7

=57

Here, L.H.S = R.H.S.

Hence, the correct answer is Option 3.

HPCL Electrical Engineer Mock Test - 1 - Question 17

Six boys Vansh, Ritik, Surya, Kapil, Pawan and Mihir are sitting on a straight bench facing the North. Kapil is sitting at the extreme right end. Pawan is sitting to the left of Surya and to the right of Mihir. Vansh is sitting to the right of Surya and to the left of Ritik. Who is sitting at the second position from the left end?

Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 17

Given:

Six boys Vansh, Ritik, Surya, Kapil, Pawan and Mihir are sitting on a straight bench facing the North.

1) Pawan is sitting to the left of Surya and to the right of Mihir.

2) Vansh is sitting to the right of Surya and to the left of Ritik.

3) Kapil is sitting at the extreme right end.

So, "Pawan" is sitting at the second position from the left end.

Hence, the correct answer is "Pawan".

HPCL Electrical Engineer Mock Test - 1 - Question 18

Read the following question and decide which of the statement(s) is/are sufficient to answer the question?

Question :

J, K, N and O are standing in a row. If we rank them in order from tallest to smallest, who will stand first?

Statement:

1. J is taller than K.

2. N is the smallest among them.

3. K is taller than O.

Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 18

J, K, N and O are standing in a row. If we rank them in order from tallest to smallest.

1. J is taller than K.

J > K

Here, there is no information given about N and O. Therefore, statement 1 alone is not sufficient.

2. N is the smallest among them.

No information is given about J, K, and O. Therefore, statement 2 alone is not sufficient.

3. K is taller than O.

K > O

Here, there is no information given about J and N. Therefore, statement 3 alone is not sufficient.

From statements 1, 2, and 3 together then:-

So, J stands first in the above row.

Hence, "option 3" is the correct answer.

HPCL Electrical Engineer Mock Test - 1 - Question 19

Refer to the given number, symbol series and answer the question that follows.

(Left) 3 * @ 5 % 3 + = 3 3 % 8 7 & 5 $ 7 5 & # * 8 2 @ 5(Right)

How many such symbols are there (from left to right) which are immediately preceded by a number and also immediately followed by a number?

Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 19

Given: (Left) 3 * @ 5 % 3 + = 3 3 % 8 7 & 5 $ 7 5 & # * 8 2 @ 5(Right)

Now,

Symbols, which are immediately preceded by a number and also immediately followed by a number.

So, Needed pattern is: Number - Symbol - Number.

There are 5 Symbols which are preceded by a number and also immediately followed by a number.

Hence, the correct answer is 'Option 2'.

HPCL Electrical Engineer Mock Test - 1 - Question 20
The wattmetric relay with directional characteristic is used for the protection of generator against
Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 20
  • The wattmetric relay with directional characteristic is used for the protection of generator against failure of prime mover.
  • An over speed relay is used for the protection of generator against over speed.
  • Earth fault relay is used for the protection of generator against rotor filed ground faults.
  • A protective scheme employing offset mho or directional impedance relay is used for the protection of generator against loss of excitation.
HPCL Electrical Engineer Mock Test - 1 - Question 21
A power station has a maximum demand of 2 MW. The annual load factor is 40% and the plant capacity factor is 15%. What is the reserve capacity of the plant?
Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 21

Concept:

Load factor: The ratio of average load to the maximum demand during a given period is known as the load factor.

Considered the plant is in the operation for T hours

Plant capacity factor: It is the ratio of actual energy produced to the maximum possible energy that could have been produced during a given period.

  • The plant capacity factor is an indication of the reverse capacity of the plant.
  • A power station is so designed that it has some reserve capacity for meeting the increased load demand in the future.
  • The installed capacity of the plant is always somewhat greater than the maximum demand on the plant.


Reserve capacity = Plant capacity – Maximum demand

Calculation:

Plant capacity factor

∴ Plant capacity = 5.33 MW

∴ Reserve capacity

= Plant capacity – Peak load

= 5.333 – 2 = 3.333 MW = 3333 kW
HPCL Electrical Engineer Mock Test - 1 - Question 22

Consider the following statements:

In the above figure, the curves pertain to the DC motor

A. Speed vs Armature current characteristic of a DC shunt motor

B. Torque vs Armature current characteristic of a DC shunt motor

C. Speed vs Armature current characteristic of a DC series motor

D. Torque vs Armature current characteristic of a DC series motor

Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 22
  • Curve 1 represents the Speed vs Armature current characteristic of a DC series motor
  • Curve 2 represents the Torque vs Armature current characteristic of a DC series motor
  • Curve 3 represents the Torque vs Armature current characteristic of a DC shunt motor
  • Curve 4 represents the Speed vs Armature current characteristic of a DC shunt motor

 

Speed vs Torque characteristic of the DC motor is shown below:

Torque vs Armature current characteristic of DC motor is shown below:

Speed vs Armature current characteristic of DC motor is shown below:

HPCL Electrical Engineer Mock Test - 1 - Question 23

If capacitor is energized by a symmetrical square wave current source, then the steady state voltage across the capacitor will be a

Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 23

We know that the current (ic) flows through a capacitor is given by

Where vc is the voltage applied across the capacitor.

Given that the capacitor is energized by a symmetrical square wave current source.

Then the voltage across the capacitor will be as shown below.

The steady-state voltage across the capacitor is a triangular wave.

HPCL Electrical Engineer Mock Test - 1 - Question 24

In the figure shown above, if AOB is the conductor, A and B are points of supports. Then which of the following is expression to calculate sag? (assume all other quantities with usual notations)

Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 24

The Correct Answer is option (1)

Detailed Explanation:

Sag in a Transmission Line:

  • It is defined as the vertical difference in level between points of support (most commonly transmission towers) and the lowest point of the conductor.
  • The calculation of sag and tension in a transmission line depends on the span of the overhead conductor.
  • Sag is mandatory in transmission line conductor suspension because it protects the conductor from excessive tension.
  • In order to permit a safe level of tension in the conductor, conductors are not fully stretched; rather they are allowed to have sagged.
  • If the conductor is stretched fully during installation, wind exerts pressure on the conductor, hence the conductor gets a chance to be broken or detached from its end support. Thus sag is allowed to have during conductor suspension.

When calculating sag in a transmission line, two different conditions need to be considered:

When supports are at equal level

Fig: Supports are at the same level

Let us suppose: AOB is the conductor. A and B are points of supports.

Point O is the lowest point and the midpoint.

Let, L = length of the span, i.e. AB

w is the weight per unit length of the conductor

T is the tension in the conductor.

We have chosen any point on the conductor, say point P.

The distance of point P from the Lowest point O is x.

y is the height from point O to point P.

Equating two moments of two forces about point O as per the figure above we get,

Now, ---1

When y = S and x = L / 2

Substituting value of y and x in equation (1) we get,

HPCL Electrical Engineer Mock Test - 1 - Question 25

Fill in the blank with the CORRECT option:

A voltmeter is connected in ______ to the device for measuring its voltage, while an ammeter is connected in ______ with the device to measure its current.

Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 25

A voltmeter is connected in parallel to the device for measuring its voltage, while an ammeter is connected in series with the device to measure its current.

Voltmeter:

  • The instrument which measures the voltage or potential difference in volts is known as the voltmeter.
  • It works on the principle that the torque is generated by the current which induces because of measurand voltage and this torque deflects the pointer of the instrument.
  • The deflection of the pointer is directly proportional to the potential difference between the points.
  • The voltmeter is represented by the alphabet 'V' inside the circle along with the two terminals as shown in the figure given below.

Connection of Voltmeter in the circuit:

  • The voltmeter constructs in such a manner that its internal resistance always remains high.
  • If it connects in series with the circuit, it minimizes the current which flows because of the measurand voltage.
  • Thus, disturbing the reading of the voltmeter.
  • The parallel connection of the voltmeter with the circuit is shown below

  • The voltmeter always connects in parallel with the circuit so that the same voltage drop occurs across it.
  • The high resistance of the voltmeter combines with the impedance of the element across which it is connected.
  • And the overall impedance of the system is equal to the impedance that the element had.
  • Thus, no obstruction occurs in the circuit because of the voltmeter, and the meter gives the correct reading.

Types of Voltmeter:

  • The voltmeter is classified in three ways.
  • The classification of the voltmeter is shown in the figure below.

Ammeter:

  • The meter used for measuring the current is known as the ammeter. The current is the flow of electrons whose unit is ampere.
  • Hence the instrument which measures the flows of current in an ampere is known as the ampere meter or ammeter.
  • The ideal ammeter has zero internal resistance.
  • But practically the ammeter has small internal resistance.
  • The measuring range of the ammeter depends on the value of resistance.

Symbolic representation:

  • The capital alphabet 'A' represents the ammeter in the circuit as shown below.

Connection of Ammeter in the circuit:

  • The ammeter is connected in series with the circuit so that the whole electrons of the measurand current pass through the ammeter.
  • The power loss occurs in the ammeter because of the measurand current and their internal resistance.
  • The ammeter circuit has low resistance so that a small voltage drop occurs in the circuit.
  • Series connection of the ammeter with the circuit is shown below

  • The resistance of the ammeter is kept low because of two reasons.
    • The whole measure current passes through the ammeter.
    • The low voltage drop occurs across the ammeter.
HPCL Electrical Engineer Mock Test - 1 - Question 26

False turn-on of SCR by large dv/dt can be prevented by using a _______ with the SCR.

Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 26

dv/dt Protection:

  • When the SCR is forward biased, junctions J1 and J3 are forward biased and junction J2 is reverse biased. This reverse biased junction J2 exhibits the characteristics of a capacitor.
  • If the rate of forward voltage applied is very high across the SCR, charging current flows through the junction J2 is high. This current is enough to turn ON the SCR even without any gate signal.
  • This is called as dv/dt triggering of the SCR. This can be reduced by using RC snubber network across the SCR.
  • A snubber circuit consists of a series combination of resistance Rs and capacitance Cs in parallel with the thyristor.
  • False turn – ON of an SCR by large dv/dt, even without application of gate signal can be prevented by using a snubber circuit.

HPCL Electrical Engineer Mock Test - 1 - Question 27

Consider the following circuit and find the current (I) due to 1 A source only

Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 27

The correct answer is option '2'.

Concept:

Superposition theorem:

  • It states that in any linear, active, bilateral network having more than one source, the response across any element is the sum of the responses obtained from each source considered separately and all other sources are replaced by their internal resistance.
  • It is used to solve the network where two or more sources are present and connected.
  • In this taking one source at a time the independent current source replaced opened circuit and independent voltage is replaced by a short circuit by connecting its internal resistance.

Given:

In above circuit a current source of 1 A and voltage source of 5 V is connected.

Needed to find the current I when only 1 A current source is active.

Calculation:

  • The above circuit can be solved by using the superposition theorem.
  • Taking only 1 A current source, the voltage of 5 V will be replaced by short circuit.
  • Nodes 1, 2, 0 are specified.

In the above circuit the and resistors between node 2 and 0 are in parallel.

The above circuit can be reduced to

By current division, the 'I' across will be,

I = 0.4 A

HPCL Electrical Engineer Mock Test - 1 - Question 28

Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 28

The Correct Answer is option (3)

Generally, the diameter of the conductor can be calculated by,

D = (2n - 1)d

Where D = Diameter of n-layered stranded conductor

d = Diameter of each strand.

HPCL Electrical Engineer Mock Test - 1 - Question 29
When compared with BJTs, MOSFETs have lesser turn-off time, enabling them to operate at high operating frequencies. What is the reason that can be attributed to that property?
Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 29
  • MOSFET is a unipolar device hence current through it is only because of Majority carriers but not of Minority carriers.
  • BJT is a Bipolar device hence current through it is because of both Majority carriers and Minority carriers.
  • Therefore, when compared to BJT, MOSFET has lesser turn-off time and enabling them to operate at higher operating frequencies.
  • MOSFET has lowest switching off time in the order of nanoseconds. BJT has the turn-off time in the order of nanoseconds to microseconds.

Important Points:

HPCL Electrical Engineer Mock Test - 1 - Question 30
A balanced RYB-sequence, Y-connected (star connected) source with VRN = 100 volts is connected to a Δ-connected (delta connected) balanced load of (8 + j6) ohms per phase. Then the phase current and line current values respectively, are
Detailed Solution for HPCL Electrical Engineer Mock Test - 1 - Question 30

Concept:

In star connection,

IL = Iph

In delta connection,

VL = Vph

Calculation:

VRN = 100 V

VphY = 100 V

VLY = 100√3 V

V= 100√3 V

VphΔ = 100√3 V

Load impedance, ZL = (8 + j6) Ω/phase

I= √3 IphΔ = 30 A
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