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HPCL Mechanical Engineer Mock Test - 10 - Mechanical Engineering MCQ


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30 Questions MCQ Test HPCL Mechanical Engineer Mock Test Series 2024 - HPCL Mechanical Engineer Mock Test - 10

HPCL Mechanical Engineer Mock Test - 10 for Mechanical Engineering 2024 is part of HPCL Mechanical Engineer Mock Test Series 2024 preparation. The HPCL Mechanical Engineer Mock Test - 10 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The HPCL Mechanical Engineer Mock Test - 10 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for HPCL Mechanical Engineer Mock Test - 10 below.
Solutions of HPCL Mechanical Engineer Mock Test - 10 questions in English are available as part of our HPCL Mechanical Engineer Mock Test Series 2024 for Mechanical Engineering & HPCL Mechanical Engineer Mock Test - 10 solutions in Hindi for HPCL Mechanical Engineer Mock Test Series 2024 course. Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free. Attempt HPCL Mechanical Engineer Mock Test - 10 | 170 questions in 150 minutes | Mock test for Mechanical Engineering preparation | Free important questions MCQ to study HPCL Mechanical Engineer Mock Test Series 2024 for Mechanical Engineering Exam | Download free PDF with solutions
HPCL Mechanical Engineer Mock Test - 10 - Question 1

Directions: In the following question, a sentence is given with a blank. You have to fill the blank with one of the words given as options in order to make the sentence contextually and grammatically correct.

Human monkey pox was first identified in 1970 and named after the disease caused by the virus was _______________ in captive monkeys more than a decade before.

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 1

The segment is in passive voice, thus only a verb in third form is eligible for the blank. Among all the given options, only ‘discovered’ fits the blank as the virus already existed in the monkeys but was found in 1970.

Hence, option D is correct.

HPCL Mechanical Engineer Mock Test - 10 - Question 2

The average of 31 numbers is 57. The average of the first 10 numbers is 50 and that of the last 20 numbers is 61. What is the 11th number?

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 2

Last 20 number = 12th to 31st
So remaining is 11th number.
So the answer = 31 × 57 – 10 × 50 – 20 × 61 = 47
Hence, Option D is correct.

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HPCL Mechanical Engineer Mock Test - 10 - Question 3

Top surface of a raised platform is in the shape of regular octagon as shown in the figure. Find the area of the octagonal surface.

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 3

HPCL Mechanical Engineer Mock Test - 10 - Question 4

If the side of the cube is 2 m, then the surface area of the cube is  

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 4

Surface area of cube = 6 * Side of cube2  
Let a = side of cube.
a = 2m.
Surface area of cube = 6 * 2 * 2
     => 24 m2 .
Hence option C is correct.

HPCL Mechanical Engineer Mock Test - 10 - Question 5

The value of  is:

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 5

It's 1 because of a0= 1.
So 1×1/1 = 1

HPCL Mechanical Engineer Mock Test - 10 - Question 6

The average number of visitors in a museum on each Sunday is 420 and the average number of visitors in the museum on any other day is 210. What is the average number of per day visitors in the whole month of April, which starts on Saturday?

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 6

Sundays → 2nd, 9th, 16th, 23rd and 30th (5 Sundays)

Hence, Option C is correct.

HPCL Mechanical Engineer Mock Test - 10 - Question 7

What is the area of the largest circle that can be made inside a rectangle with 50 meters length and 42 meters breadth?

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 7

Diameter of the circle = breadth of the rectangle = 42 meters
Radius of the circle

So the answer 

Hence, Option D is correct.

HPCL Mechanical Engineer Mock Test - 10 - Question 8

If  a = 1/ (3-2√2)  &  b =  1/ ( 3+2√2)  then the value of a2 +b2 is :-

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 8

a = 1/ (3-2√2) 

b =  1/ ( 3+2√2) 

∴ ab =  1/(3-2√2) * 1/ (3+2√2) 

=>  1/ (9-8) 

=> 1 

We know; 

(a+b)2 = a2 + b+ 2ab

And, a2+ b2 = (a+b)2 - 2ab

=> [ 1/(3-2√2) + 1/(3+2√2) ]2 -2*1

=> [3+2√2+3-2√2 / 1]^2 -2 

=> (6)2 - 2 

=>  36 - 2
=>  34

HPCL Mechanical Engineer Mock Test - 10 - Question 9

Directions to Solve

In each word of the following questions consists of pair of words bearing a relationship among these, from amongst the alternatives, pick up the pair that best illustrate a similar relationship.

Question -

Silence : Noise

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 9

As Silence is opposite to noise, similarly Baldness is opposite to Hair.

HPCL Mechanical Engineer Mock Test - 10 - Question 10

If the following numbers are written in ascending order then what will be the middle digit of the middle term?

815, 686, 795, 835, 765, 822, 719

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 10

Ascending order:
686,   719,   765,   795,   815,   822,   835

Middle Number

Middle digit of 795 is 9.

HPCL Mechanical Engineer Mock Test - 10 - Question 11

Directions to Solve

Each of the following questions has a group. Find out which one of the given alternatives will be another member of the group or of that class.

Question -

Carpenter, Plumber, Electrician

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 11

Carpenter, Plumber, Electrician and Blacksmith are in same working category.

HPCL Mechanical Engineer Mock Test - 10 - Question 12
To qualify for a job P, maximum age can be of 30 years, 10th marks should be more than 50% and work experience should be at least 3 years. To qualify for job Q, one should have a minimum age of 25 years, 10th marks should be more than 60% and work experience of at least 1 year. Rahul has 48% marks in 10th an age of 28 years and. work experience of 5 years. For which of these jobs does he qualify?
Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 12

The logic follows here is:

It is given that Rahul has 48% marks in 10than age of 28 years, and work experience of 5 years.

It is clearly mentioned in the criteria that 10th marks should be greater than 50% for job P and greater than 60% for job Q. Rahul got 48% marks in 10th.

Therefore, Rahul, neither qualifies for job P nor for job Q.

Hence, the correct answer is "Neither P nor Q".

HPCL Mechanical Engineer Mock Test - 10 - Question 13

If a Paper (Transparent Sheet ) is folded in a manner and a design or pattern is drawn. When unfolded this paper appears as given below in the answer figure. Choose the correct answer figure given below.

How will it look like when a transparent paper with given figure is folded on the dotted line as shown?

Question Figure

Answer Figure

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 13

HPCL Mechanical Engineer Mock Test - 10 - Question 14

In a Die-cutting operation, punching several holes in a sheet is called

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 14
Shearing is a cutting operation used to remove a blank of required dimensions from a large sheet. The shearing operations which make use of a die include punching, blanking, piercing, notching, trimming, and nibbling.

Punching/Blanking: Punching or blanking is a process in which the punch removes a portion of material from the larger piece or a strip of sheet metal. If the small removed piece is discarded, the operation is called punching, whereas if the small removed piece is the useful part and the rest is scrap, the operation is called blanking.

Piercing: It is a process by which a hole is cut (or torn) in metal. It is different from punching in that piercing does not generate a slug.

Perforating: It is an operation in which a number of uniformly spaced holes are punched in a sheet of metal. The holes may be of any size or shape. They usually cover the entire sheet of metal.

Nothing: It is an operation in which a specified small amount of metal is cut from the edges.

Lancing: It is an operation of cutting a sheet metal through a small length and then bending this cut portion.

HPCL Mechanical Engineer Mock Test - 10 - Question 15

In case of power failure, a battery is used to light a bulb, run a fan, and heat an electric iron (each of 100 W rating) for 10 minutes. In this process, the work done and heat supplied by the battery is given by :

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 15

Work = electrical work

=3×100W

=3×100×10×60J

Work (W)=180kJ

Heat transfer, Q=0 (no heat transfer from/to battery)

HPCL Mechanical Engineer Mock Test - 10 - Question 16

Which of the following processes is the wire drawing process?

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 16
Wire drawing is a cold working process to obtain wires from rods of bigger diameters through a die. The wire is subjected to tension only.

Coining is essentially a cold‐forging operation except that the flow of the metal occurs only at the top layers and not the entire volume. In the coining process, compressive forces are there.

In blanking, the piece being punched out becomes the workpiece, and any major burrs or undesirable features should be left on the remaining strip. Blanking is a shearing operation.

Drawing when cup height is more than half the diameter is termed deep drawing. During deep drawing, in the flange of blank, there is bi‐axial tension and compression stresses.

HPCL Mechanical Engineer Mock Test - 10 - Question 17

The standard sea level atmospheric pressure is equivalent to

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 17
Pressure at sea level = 101.325 kPa

Checking according to given options.

P = hρg

a) ⇒ 10.2 m of fresh water (ρ = 998 kg/m3)

P = 10.2 × 998 × 9.81 = 99861.87 Pa = 99.861 kPa

b) ⇒ 10.1 m of saline water (ρ = 1025 kg/m3)

P = 10.1 × 1025 × 9.81 = 101.558 kPa

c) ⇒ 12.5 m of kerosene of ρ = 800 kg/m3

P = 12.5 × 800 × 9.81 = 98.1 kPa

d) ⇒ 6.4 m of carbon tetrachloride of ρ = 1590 kg/m3

⇒ 6.4 × 1590 × 9.81 = 99.826 kPa

So option b is nearest, so correct

HPCL Mechanical Engineer Mock Test - 10 - Question 18

The main alloying elements in high-speed steel are:

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 18
The composition of high-speed tools or high-speed steel (HSS) is 18% W, 4% Cr, 1% V, 0.7% C, and rest Fe. High-speed tool steels are used for the most common types of cutting tools, including single-point lathe tools, drills, reamers, taps, milling cutters, end mills, hobs, saws, and broaches.

Properties of HSS:

  • High working hardness

  • High wear resistance

  • Excellent toughness

  • High retention of hardness and hot hardness.

HPCL Mechanical Engineer Mock Test - 10 - Question 19

A 1 kg block is resting on a surface with coefficient of friction μ = 0.1. A force of 0.8 N isapplied to the block as shown in the figure. The friction force is

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 19

HPCL Mechanical Engineer Mock Test - 10 - Question 20

What is the heat required to raise the temperature of 1 kg mass of a substance by 1° C?

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 20

The energy required to raise a mass of 1 centigrade (K or ºC) is the specific massic heat of the substance, multiplied by its mass and 1 centigrade. In the case of 1 kilogram of water: E = (4180 J/(kg×K)) ×1 kg × 1K = 4180 J. You can also use the specific molar heat with the number of moles.

HPCL Mechanical Engineer Mock Test - 10 - Question 21

Hardness of steel depends upon the amount of

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 21
The maximum hardness of a steel is a function of its Carbon content. It increases as the percentage of carbon increases.

Cementite: Cementite or Iron Carbide has the chemical formula Fe3C and contains 6.67% carbon by weight. It is the hardest structure that appears in the iron-carbon equilibrium diagram. Cementite has an orthorhombic crystal structure and is extremely hard and brittle as compared to austenite and ferrite.

Martensite: It is a metastable phase of steel formed by the transformation of austenite below 320°C. Martensite is an interstitial supersaturated solid carbon solution in α – Iron and has a body-centred tetragonal lattice. It has a carbon content of up to 2% and is extremely hard and brittle. It is a product of rapid cooling (quenching) and possesses an acicular or needle-like structure.

The hardness of steel depends upon the amount of cementite. Martensite was obtained after hardening treatment of steel.

Steels with low carbon content do not respond appreciably to hardening treatment because the main constituent is soft ferrite. If hypo-eutectoid steel is cooled rapidly, martensite is formed.

HPCL Mechanical Engineer Mock Test - 10 - Question 22

Which of the following devices is used to find the composition of exhaust gases from IC engines?

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 22

Fuel gas analysis refers to the determination of the composition of exhaust gases. It can be done theoretically and experimentally.

Various devices available for measuring the composition of products of combustion (flue gas) are Orsat Analyzer, Gas chromatograph, Infrared analyzer, and Flame ionization detector, etc.

Orsat Apparatus: It is used for carrying out volumetric analysis of dry products of combustion.

Bomb Calorimeter: It is used to determine the higher calorific value of solid and liquid fuels.

Barometer: A barometer is used to measure local atmospheric pressure.

Rope dynamometer: A rope brake dynamometer is used to test the power of engines.

HPCL Mechanical Engineer Mock Test - 10 - Question 23

Hot coffee stored in a well insulated thermos flask is an example of

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 23

As the hot coffee remains hot for a long time so neither heat nor mass is exchanged with the surroundings and hence it is an example of isolated system.

HPCL Mechanical Engineer Mock Test - 10 - Question 24

An Ideal gas at 27ºC is heated at constant pressure till the volume becomes three times. The temperature of the gas will then be

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 24

HPCL Mechanical Engineer Mock Test - 10 - Question 25

In an IC engine, combustion was found to proceed during the expansion stroke also. The reason could be:

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 25

Lean mixture: Mixture which contains more air than the stoichiometric requirement. There is more oxygen than required to burn the amount of fuel completely; after combustion, there is excess oxygen in the exhaust gases.

Rich Mixture: Mixture which contains less air than the stoichiometric requirement. There is not enough air to completely burn the amount of fuel; after combustion, there is unburnt fuel in the exhaust gases.

Spark advance/Ignition Advance:

The purpose of the spark advance mechanism is to assure that under every condition of engine operation, ignition takes place at the most favorable instant in time, i.e., most favorable from the standpoint of engine power, fuel economy, and minimum exhaust dilution. By means of these mechanisms, the advance angle is accurately set so that ignition occurs before the TDC point of the piston.

Ignition timing is the correct instant for the introduction of a spark near the end of the compression stroke in the cycle. Several factors affect the ignition timing of an engine, like compression ratio, Engine speed, Engine load, Quality of fuel, Mixture strength, etc.

In the case of a rich mixture, the combustion rate is faster and less ignition advanced is required. And in the case of a lean mixture, the combustion rate will be slower, thus requiring more ignition advances.

When ignition occurs early in the compression stroke, the engine is said to be advanced. A retardation ignition takes place when the piston is just near the compression stroke.

If the ignition is advanced too much, it will be completed before the end of the compression stroke. Under these conditions, the crankshaft and connecting rod will have to push the piston upward, compressing the gases. In such a case, the force might not be sufficient to overcome the pressure and the engine would stop or stall.

If the ignition is retarded too much, the combustion of fuel will continue during the power stroke of the piston (Expansion stroke), and the maximum pressure will not be developed. Less work will be obtained from heat energy. Under these conditions, comparatively more exhaust gases will be going out of the engine cylinder overheating the exhaust valve.

Conclusion:

Rich Mixture with ignition advance: It can complete before the compression stroke

Weak Mixture without ignition advance: Combustion can be found to proceed during the expansion stroke

The rich mixture should have retarded ignition advance, and the lean mixture should have more ignition advance.

HPCL Mechanical Engineer Mock Test - 10 - Question 26

In an Otto cycle, the heat addition and heat rejection take place at

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 26
Otto cycle: The standard air cycle used in the spark ignition (SI) engines or petrol engines.

Different processes of the Otto cycle are as follows:

Process 1-2: Isentropic compression

Process 2-3: Constant volume heat addition

Process 3-4: Isentropic expansion

Process 4-1: Constant volume heat rejection.

HPCL Mechanical Engineer Mock Test - 10 - Question 27

A mass of 10 kg is resting on a rough table. The friction force required just to make the block move_____

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 27
It has been observed that when a body, lying over another body, is gently pushed, it does not move because of the frictional force, which prevents the motion.

If the applied force exceeds this limit, the force of friction cannot balance it, and the body begins to move in the direction of the applied force. This maximum value of frictional force, which comes into play when a body just begins to slide over the surface of the other body, is known as limiting friction.

Friction Force:

f = μN = µs × mg

µs is known as the coefficient of static friction

So without knowing the value of µs, we cannot determine friction force.

HPCL Mechanical Engineer Mock Test - 10 - Question 28

A mandrel is used to hold

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 28

Mandrel is used to hold a hollow bar or a bar with a bore wen turning between live centre and dead cente of a lathe. A moving mandrel is also used for tube drawing

HPCL Mechanical Engineer Mock Test - 10 - Question 29

A reservoir containing water has two orifices of the same size at depths of 4 m and 9 m below the free surface of the water. The ratio of discharges through these orifices is

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 29

For the same orifice at different height:

Q ∝ √h

HPCL Mechanical Engineer Mock Test - 10 - Question 30

The electrolyte in ECM is an aqueous solution of

Detailed Solution for HPCL Mechanical Engineer Mock Test - 10 - Question 30

In ECM, both the tool electrode and the workpiece are submerged in an electrically conductive electrolyte, usually an aqueous salt solution such as sodium chloride (NaCl) or sodium nitrate (NaNO3). A constant potential is applied between the two electrodes ensuring the workpiece becomes the anode (positive electrode).

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