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Indian Navy MR Mock Test - 1 - Airforce X Y / Indian Navy SSR MCQ


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30 Questions MCQ Test Indian Navy MR Mock Test Series 2024 - Indian Navy MR Mock Test - 1

Indian Navy MR Mock Test - 1 for Airforce X Y / Indian Navy SSR 2024 is part of Indian Navy MR Mock Test Series 2024 preparation. The Indian Navy MR Mock Test - 1 questions and answers have been prepared according to the Airforce X Y / Indian Navy SSR exam syllabus.The Indian Navy MR Mock Test - 1 MCQs are made for Airforce X Y / Indian Navy SSR 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Indian Navy MR Mock Test - 1 below.
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Indian Navy MR Mock Test - 1 - Question 1

The profit percentage by way of selling an article for Rs. 180 is the same as the loss percentage by selling it for Rs. 120. How much is the profit or loss percentage?

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 1

Let the cost price of the article be Rs. x, then
According to the question,
180 – x = x – 120
⇒ x + x = 180 + 120
⇒ 2x = 300
⇒ x = (300/2) = 150
Cost Price of the article = Rs. 150
Profit = 180 – 150 = 30
Profit percentage = (30/150) x 100 = 20%

Indian Navy MR Mock Test - 1 - Question 2

While working 8 hours a day, Anu can prepare a book for 18 days. If the same work is to be completed within 12 days, how many hours will an Anu be working every day?

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 2

The given details are:
Working 8 hours a day, Ashu can complete work in = 18 days
Working 1 hour a day, Ashu can complete the work in = 18×8 = 144 days
∴ Number of hours Ashu should work to complete the work in 12 days:
= 144/12 = 12 hours/day

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Indian Navy MR Mock Test - 1 - Question 3

If x = 3 is a root of the polynomial, f(x) = 4x3+2x2+5x−a. Find the value of x.

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 3

Given:
f(x) = 4x3+2x2+5x−a
and x = 3
When we put the value of root in the polynomial, then the value of the polynomial is equal to zero.
F(3) = 4(3)+ 2(3)+ 5(3) − a
⇒ 0 = 108 + 18 + 15 − a
⇒ 0 = 141 − a
⇒ a = 141
∴ Value of a is 141.

Indian Navy MR Mock Test - 1 - Question 4

Find the value of the expression x4 - 3x3 + 4x2 - 3x + 5 at x = 3.

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 4

Given:
x4 - 3x3 + 4x2 - 3x + 5 and x = 3
(3)4 - 3(3)3 + 4(3)2 - 3(3) + 5
⇒ 81 - 81 + 36 - 9 + 5
⇒ 27 + 5
⇒ 32

Indian Navy MR Mock Test - 1 - Question 5

What of the following properties belong(s) to sodium metal?

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 5

Sodi­um is an el­e­ment in the 1 group of the 3 pe­ri­od of the Pe­ri­od­ic Ta­ble. It is a sil­very-white met­al. It is quite mal­leable and soft (metal­lic sodi­um can eas­i­ly be cut with a knife or scalpel, and a fresh cut shines in the air). It has high ­con­duc­tiv­i­ty.
It has a low melting point and reacts vigorously with water.
Chemical reaction:
2Na(s) + 2H2O → 2NaOH(aq) + H2(g)

Indian Navy MR Mock Test - 1 - Question 6

A solid metallic ball of radius 9 cm is melted to form cylinders of radius 6 mm and height 1 cm. Find the number of such solid cylinders that can be formed.

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 6

Let, 'n' be the number of cylinders that can be formed;
∴ Volume of spherical ball = n × Volume of one cylinder

⇒ n = 2700.

Indian Navy MR Mock Test - 1 - Question 7

Raju lent Rs. 400 to Ajay for 2 years and Rs. 100 to Manoj for 4 years and received together from both Rs. 60 as interest. Find the rate of interest, simple interest being calculated.

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 7

Let rate is R%
According to the question,

So, R = 5%

Indian Navy MR Mock Test - 1 - Question 8

In a circle, the length of a chord is 24 cm. The chord is 5 cm away from the centre of the circle. Find the diameter of the circle.

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 8


Let AB be the chord and O be the center of the circle.
Also OP perpendicular to AB
In ΔOPB,
OB2 = PB2 + OP2
⇒ OB2 = 122 + 52
⇒ OB2 = 169
⇒ OB = 13
Diameter = 2 × OB = 26

Indian Navy MR Mock Test - 1 - Question 9

If Rs. 3162 is divided in the ratio of 3 : 7 : 11 : 13 among A, B, C and D respectively, what will be the share of D?

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 9

Given:
Ratio of A, B, C and D = 3 : 7 : 11 : 13
Let, share of A = Rs. 3x
Share of B = Rs. 7x
Share of C = Rs. 11x
Share of D = Rs. 13x
According to question,
⇒ 3x + 7x + 11x + 13x = 3162
⇒ 34x = 3162
⇒ x = 93
∴ Share of D = 13 × 93 = Rs. 1209

Indian Navy MR Mock Test - 1 - Question 10

What is Dry Ice?

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 10

Dry ice is the common name for the solid form of carbon dioxide.

  • It's called dry ice because it doesn't melt into a wet liquid.
  • Dry ice sublimates, which means it goes from its solid form directly to its gaseous form.
Indian Navy MR Mock Test - 1 - Question 11

What will be the thermal resistance of an ideal conductor?

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 11

The substances in which heat is transmitted easily and rapidly through the conduction method are called good conductors. The thermal conductivity of an ideal conductor is infinite and the thermal resistance is zero. For example, gold, silver, copper, aluminum, etc. Silver has the highest thermal conductivity.

Indian Navy MR Mock Test - 1 - Question 12

A train leaves from a station and moves at 40 km/hr. After 2 hours, another train leaves from the same station and moves in the same direction at a certain speed. If the second train catches up with the first train in 4 hours, what is the speed of the second train?

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 12

Distance covered by the first train in 2 hrs = 40 × 2 = 80 km
Let the speed of the second train be x km/hr
According to the question
Speed = Distance/Time
⇒ (x – 40) = 80/4
⇒ x – 40 = 20
⇒ x = 20 + 40
∴ x = 60 km/hr.

Indian Navy MR Mock Test - 1 - Question 13

Find the value of (999)2 - 22.

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 13

Given:
(999)2 - 22
We know that,
a2 – b2 = (a + b) × (a – b)
According to the formula used,
(999)2 - 22
= (999 + 2) × (999 – 2)
= (1001) × (997)
= (1000 + 1) × (997)
= (1000 × 997) + (1 × 997)
= 997000 + 997
= 997997
∴ The value of (999)2 – 22 is 997997.

Indian Navy MR Mock Test - 1 - Question 14

Length of chord MN is 40 cm. Distance of chord MN from the centre is 15 cm. What will be the radius of this circle?

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 14

Given:
The distance of chord MN from the center is 15 cm
The length of chord MN is 40 cm
Concept:
Chord length using perpendicular distance from the centre = 2 × √ (r2 – d2) [∵ r = radius, d = perpendicular distance]
Calculation:

Length of Chord = 2 × √ (r2 – d2)
40 =  2 × √ (r2 – 152) = 25 cm
∴ Option 4 is the correct answer.

Indian Navy MR Mock Test - 1 - Question 15

If 20% of P = 30% of Q = 1/6 of R, then P ∶ Q: R is 

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 15

Given:
20% of P = 30% of Q = 1/6 of R
Calculation:
20% of P = 30% of Q = 1/6 of R

Similarity, 

∴ P : Q : R = 15 : 10 : 18

Indian Navy MR Mock Test - 1 - Question 16

An object of mass 10 kg is moving with a uniform velocity of 5 ms-1. How much kinetic energy has that object held?

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 16
  • Kinetic energy (K.E): The energy possessed by a body by the virtue of its motion is called kinetic energy.

The expression for kinetic energy is given by:
KE = (1/2)mv2
Where m = mass of the body and v = velocity of the body

  • Momentum (p): The product of mass and velocity is called momentum.

Momentum (p) = mass (m) × velocity (v)

Indian Navy MR Mock Test - 1 - Question 17

Simplify the following expression.

25 ÷ 5 of 12 × 2 − 9 ÷ 27 of 3 × 5 − 14 ÷ 28 × 4 

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 17

Given:
25 ÷ 5 of 12 × 2 − 9 ÷ 27 of 3 × 5 − 14 ÷ 28 × 4 
Concept used:
Bodmas 

Calculation:
Here, using the rule of bodmas , we have 
25 ÷ 5 of 12 × 2 - 9 ÷ 27 of 3 × 5 - 14 ÷ 28 × 4 
⇒ 25 ÷ 60 × 2 - 9 ÷ 81 × 5 - 14 ÷ 28 × 4 
⇒ 25/60 × 2 - 9 /81` × 5 - 14/28 × 4
⇒ 5/12 × 2 - 1/9 × 5 - 1/2 × 4 
⇒ 5/6 - 5/9 - 2 
⇒ (15−46)/18  = -31/18 
Hence, the required value is -31/18.

Indian Navy MR Mock Test - 1 - Question 18

If 2 men and 8 women can do a piece of work in 5 days while 3 men and 4 women can do the same work in 6 days, then the time taken by 1 man and 2 women in doing the same work is ______.

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 18

Given:
2m + 8w = 5 days
3m + 4w = 6 days
Formula used:
Total work = Efficiency × days 
Calculations:
⇒ (2m + 8w)5 = (3m + 4w)6
⇒ 10m + 40w = 18m + 24w
⇒ 16w = 8m
⇒ m/w = 2/1
⇒ Total work = (2 × 2 + 8 × 1) × 5
⇒ Total work = 12 × 5 = 60
Time taken by 1m and 2 w = 60/(1 × 2 + 2 × 1)
⇒ 15 days
∴ Time taken by 1 man and 2 woman is 15 days.

Indian Navy MR Mock Test - 1 - Question 19

Pooja sells an article to Shweta at 10% profit and then Shweta sells the same article to Barkha for 20% profit. If Barkha buys the article at Rs. 660, then find the price at which Pooja buys the same article. (in Rs.)

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 19

Pooja sells an article to Shweta at a% profit and then Shweta sells the same article to Barkha for b% profit. If Barkha buys the article at Rs. x,
The price at which Pooja buys the same article = y
Then,
⇒ x = (100% + a%) × (100% + b%) × y
According to the question,
⇒ 660 = (100% + 10%) × (100% + 20%) × y
⇒ 660 = 110% × 120% × y
⇒ 660 = 1.1 × 1.2 × y
⇒ 660 = 1.32 × y
⇒ y = Rs. 500
Therefore, 'Rs. 500' is the required answer.

Indian Navy MR Mock Test - 1 - Question 20

A boy of mass 50 kg climbs 41 steps in 10 seconds. If the height of each ladder is 15 cm, find its power. (given g = 10 ms–2)?

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 20
  • Given mass of body (m) = 50 kg
  • h = 41×15 = 615 cm = 6.15 m
  • t = 10 s, g = 10 ms–2
  • Potential energy = mgh
    • = 50 × 10 × 6.15
    • = 3075
  • Power = Workdone/time
    • = (3075/10) 
    • = 307.5 W
Indian Navy MR Mock Test - 1 - Question 21

The area of a square inscribed in a circle, whose diagonal is 16 cm, is:

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 21

Given:
Diagonal of the square = 16 cm

Concept used:
Diagonal of a square = a√2
Area of a square = a2
where a is the length of its side.
Calculation:
Side of the square = 16 ÷ √2 = 8√2
Area of the square = (8√2)2 = 128 cm2
∴ The area of a square inscribed in a circle, whose diagonal is 16 cm, is 128 cm2.

Indian Navy MR Mock Test - 1 - Question 22

The value of (sin4 45°+ cos4 60°) + (tan4 45°+ cot4 45°) is:

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 22

Given:
(sin4 45°+ cos4 60°) + (tan4 45°+ cot4 45°) 
Concept Used:

Calculation:
⇒ According to the question,
⇒ (sin4 45°+ cos4 60°) + (tan4 45°+ cot4 45°) 
⇒ Putting the values of the angles in the above equation we get,

Therefore, the value of (sin4 45°+ cos4 60°) + (tan4 45°+ cot4 45°) is 37/16. 

Indian Navy MR Mock Test - 1 - Question 23

Arrange the optical mediums in ascending order according to optically denser.

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 23
  • Glass is optically denser than water.
  • Refractive indices of materials in ascending order are Air, Water, and Glass.
  • The Refractive index is the ratio of the speed of mild in a vacuum to its velocity in a specific medium.
  • Air has the bottom refractive index. Diamond has the best refractive index.
  • A medium is more uncommon when the speed of light increments when the light goes through that medium.
  • The speed of light in air is more than the speed of light in the glass, and that implies air is optically more uncommon than glass.
Indian Navy MR Mock Test - 1 - Question 24

Energy can neither be created nor destroyed, but it can be converted into one another. It is called _______.

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 24
  • Energy can neither be created nor destroyed, but it can be converted into one another. It is called the Law of conservation of energy.
  • The law of conservation of energy states that “In a closed system, i.e., a system that is isolated from its surroundings, the total energy of the system is conserved.”
Indian Navy MR Mock Test - 1 - Question 25

The number of unpaired electrons in carbon atom is-

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 25
  • The carbon atom is tetravalent even though it has unpaired electrons.
  • It is determined that the floor kingdom of a neutral carbon atom does indeed contain two unpaired electrons.
  • The Co2+ ion in an aqueous answer is octahedrally coordinated and paramagnetic, with 3 unpaired electrons.
Indian Navy MR Mock Test - 1 - Question 26

What J. B. Dunlop invented?

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 26

J. B. Dunlop invented the Pneumatic rubber tyre.
John Boyd (J.B.) Dunlop (5 February 1840 – 23 October 1921) was a Scottish inventor and veterinary surgeon who spent most of his career in Ireland. Familiar with making rubber devices, he re-invented pneumatic tyres for his child's tricycle and developed them for use in cycle racing. 

Indian Navy MR Mock Test - 1 - Question 27

Choose the correct pair of the country - capital from the given alternative.

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 27

The correct pair of the country - capital are: Cuba - Havana

  • Cuba officially the Republic of Cuba is a country comprising the island of Cuba, as well as Isla de la Juventud and several minor archipelagos. Cuba is located where the northern Caribbean Sea, Gulf of Mexico, and Atlantic Ocean meet.
  • Havana is the capital and largest city of Cuba. The heart of the La Habana province, Havana is the country's main port and leading commercial center. The city has a population of 2.1 million inhabitants, and it spans a total of 781.58 km2 (301.77 sq mi) – making it the largest city by area, the most populous city, and the fourth largest metropolitan area in the Caribbean region.
Indian Navy MR Mock Test - 1 - Question 28

Match the following:

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 28

The correct match is A - 1, B - 4, C - 2, D - 3.

Dandi March or Salt Satyagraha, major nonviolent protest action in India led by Mahatma Gandhi in March–April 1930.
The Poorna Swaraj declaration was promulgated by the Indian National Congress on 26 January 1930, resolving the Congress and Indian nationalists to fight for Poorna Swaraj, or complete self-rule independent of the British Empire. The flag of India was hoisted by Jawaharlal Nehru on 31 December 1929 on the banks of Ravi river, in Lahore.
Red Shirt movement was started by Abdul Ghaffar Khan of the North-West Frontier Province of India in 1930. His followers were pledged to nonviolence, and they derived their popular title from the red colour of their shirts.
The Bardoli Satyagraha, 1928 was a movement in the independence struggle led by Sardar Vallabhai Patel for the farmers of Bardoli against the unjust raising of taxes.

Indian Navy MR Mock Test - 1 - Question 29

Who among the following is known as Grand Old man of India?

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 29

Dadabhai Naoroji is known as Grand Old man of India.
Dadabhai Naoroji was born on 4 September 1825 in a poor Parsi family in Bombay. He was an Indian political leader, merchant, scholar and writer. He is also called the 'unofficial ambassador of India' and has played a huge role in India gaining independence from the British.

Indian Navy MR Mock Test - 1 - Question 30

Lavani is the traditional dance form of ___________.

Detailed Solution for Indian Navy MR Mock Test - 1 - Question 30

Lavani is the traditional dance form of Maharashtra.

  • It is a combination of traditional song and dance that has performed especially with the Dholki beats which is a percussion instrument.
  • It has made a significant contribution to the growth of Marathi folk theatre.
  • This dance form began in the 17th Century.
  • The songs are sung at a fast tempo.
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