Which of the following is correct some θ such that 0° ≤ θ < 90°
The sides of a right angled triangle form a geometric progression, find the cosines of the acute angles. (If a,b,c are in G.P. ⇒ b2= ac)
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cot 36° cot 72° is equal to :
The value of cos2 15° – cos2 30° + cos2 45° – cos2 60° + cos2 75° is :
If x = sin2 θ cos θ and y = cos2 θ sin θ, then :
If x = secθ – tanθ and y = cosecθ + cotθ, then xy + 1 is equal to :
If 5 sinθ = 3, then secθ tanθ /secθ – tanθ is equal to :
The value of the expression
Given that sin A=1/2 and cos B=1/√2 then the value of (A + B) is:
If m = tanθ + sinθ and n = tanθ – sinθ, then (m2 – n2)2 is equal to :
If x = a cos θ + b sin θ and y = a sin θ – b cos θ then a2 + b2 is equal to :
If cosθ + sinθ + 1 = 0 and sinθ – cosθ – 1 = 0 then + is equal to :
ABC is a triangle, right angled at A. If the length of hypotenuse is 2 √2 times the length of perpendicular from A on the hypotenuse, the other angles of the triangle are :
If sin A + cos A = m and sin3A + cos3A = n, then
The quadratic equation whose roots are sin 18° and cos 36° is :
If cosθ + sectθ = 2, then the value of cos2θ + sec2θ is :
If sin (A – B) = cos (A + B) =1/2, then the values of A and B lying between 0° and 90° are respectively:
If m2 + m'2 + 2mm' cosθ = 1, n2 + n'2 + 2nn' cos θ = 1, and mn + m'n' + (mn' + m'n) cos θ = 0, then m2 + n2 is equal to :
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5 videos|292 docs|59 tests
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