JEE Main Chemistry Mock Test- 1 - JEE MCQ

Alcohols are soluble in water. This is due to the hydroxyl group in the alcohol which is able to form hydrogen bonds with water molecules. Alcohols with a smaller hydrocarbon chain are very soluble. As the length of the hydrocarbon chain increases, the solubility in water decreases.

The chemical bond formed between amino acids, constituting the primary linkagein all protein structures. In a peptide bond, the carboxyl group (COOH) of one amino acid bonds with the amino group (NH2) of another, forming the sequence CONH and releasing water (H2O).

A chemical equilibrium is dynamic in nature which in other words means that reactions continue to occur in both forward as well as backward direction with the same speed. As a result, the amount of product formed immediately reacts backward to give reactants and so there is no change in concentration of reactant or product with the passage of time.

Ecell = E right - E left
= E•Cu²⁺/Cu - E•Zn²⁺/Zn
= (+0.34v) - (-0.76v)
=0.34+0.76
=1.1v

Correct option is A)

If rate is given by: rate =k[A]x[B]y

then the order =x+y.

This order can be a positive, negative no., zero or even fractional. It can be determined only experimentally and does not depend on stoichiometric coefficients of reactants.

The chemical formula for methane is CH4 and its molecular mass is calculated as the sum of Mass of the carbon atom and Mass of hydrogen atoms. The molar mass of carbon is 12g/mol and the mass of hydrogen atom is 1g. Therefore, the Molar mass of methane is:
12+4×1=16g/mol
As we know, 10 gram of methane on combustion gives 560 KJ of heat. So 1 gram of methane on combustion gives = 560/10KJ of heat.

Hence, 16 gram of methane on combustion give=560/10×16=896KJ

Thus the heat of combustion of methane is -896KJ/mol. Therefore, the negative sign in the answer.

The electronegativity values for the representative elements decreses down a group because of the increase in atomic radius as well as screening effect. Thus, carbon has highest electronegativity in a group.

A Ziegler–Natta catalyst, named after Karl Ziegler and Giulio Natta, is a catalyst used in the synthesis of polymers of 1-alkenes (alpha-olefins).

Hint: For Na⁺, GEW=GAW

CH₃COONa undergoes anionic hydrolysis and gives basic solution (pH ≈ 9

The pH of a solution is equal to the base 10 logarithm of the H+ concentration, multiplied by -1. If you know the pH of a water solution, you can use this formula in reverse to find the antilogarithm and calculate the H+ concentration in that solution.

 CH₃COOH does not ionise or dissociate completely and hence it is a weak electrolyte.

o-cresol (o−(CH3​)C6​H4​−(OH)) is least acidic.  −OH group and C​H3​ groups are electron releasing group. It increases the electron density on a benzene ring and does not delocalize the negative charge of phenoxide ion.

Hence, it decreases the acidity of phenol. −Cl and −NO2​ groups are electron-withdrawing groups. They delocalize the electron density of phenoxide ion. It increases the acidity of phenol.

Lewis Acid is one that accepts electrons. So, usually a compound with positive charge would be acid. Also, a compound with empty orbitals. 

Lewis Base is one that donates electrons. So, usually a compound with negative charge would be considered base. Also, a compound with lone pairs. 
 

SiF4​,FeCl3​ and BF3​ are lewis acids becuase all these compounds are having vacant orbitals to accept electon pairs
 

C2​H2​ is not a lewis acid.It's a Lewis base, as it can use a pair of electrons from the pi bond to donate to a Lewis acid.
 

Hence option A is correct.

A polymer sample contains chains of varying lengths and therefore molecular mass is always expressed as an average.The molecular weight of polymers are very high,due to which they are expressed in two ways:-

Number average molecular mass and weight average molecular mass.

In CsCl structure the distance the closest approach between the cation and anion is equal to half of the body of the diagonal of a cube.
Body diagonal = 3–√×3× Edge Length

=3–√×404

=699.74pm
The distance of the closest approach = 1/2× Body diagonal
=1/2×699.74 = 349.87 pm = 349.9pm

More comparable the size of anion and cation, more is the chance of Schottky defect and Na⁺ and Cl^- ions are almost comparable in size hence m ore probability to show  Schottky defect.

In pyrrole, the lone pair of electrons belonging to the nitrogen is part of the aromatic ring. However, in pyridine it is part of an sp2-hybridized orbital.

Zn + 2NaOH → Na₂ZnO₂ + H₂ ↑
2AI + 2NaOH + H₂O → 2NaAlO₂ + 3H₂ ↑
Sn + 2NaOH + H₂O → NaSnO₃ + 2H_2­ ↑
Pb + 2NaOH + H₂O → Na₂SiO₃ + 2H₂ ↑
S₈ + 12NaOH — → 4Na₂S + 4Na₂S₂O₃ + 6H₂O ↑
P₄ + 3NaOH + 3H₂O → PH₃­↑ + 3NaH₂PO₂­

Molecular formula from calculation comes to be C₃H₆O i.e., it stands for the following compounds.

VD × 2 = MM
= 29 × 2 = 58
∴ 58 g of ether combines with 2 × 80g Br₂
∴  2.9 g of ether will combines with 

Y = 9 and X = 8
Y – X = 9 – 8 = 1

(i) give NO₂        (ii) NH₄NO₃
(iii) gives NO₂     (iv) Give NO₂
(v) give NO₂          (vi) Given N₂O    
(vii) Gives NO₂     (viii) Gives NO₂    
(ix) Gives NO

x = 4
y = 6
z = 6
Ans. (3)