Explore Exams
Login Signup
Sign in Open App
JEE Exam  >  JEE Test  >   Main & Advanced Mock Test Series 2026  >  JEE Main Practice Test- 17 - JEE MCQ

JEE Main & Advanced Practice Test- 17 Free Online Test 2026


MCQ Practice Test & Solutions: JEE Main Practice Test- 17 (90 Questions)

You can prepare effectively for JEE JEE Main & Advanced Mock Test Series 2026 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "JEE Main Practice Test- 17". These 90 questions have been designed by the experts with the latest curriculum of JEE 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 180 minutes
  • - Number of Questions: 90

Sign up on EduRev for free to attempt this test and track your preparation progress.

JEE Main Practice Test- 17 - Question 1
Save

In a LCR circuit capacitance is changed from C to 2C. For the resonant frequency to remain unchanged, the inductance should be changed from L to

Detailed Solution: Question 1

JEE Main Practice Test- 17 - Question 2
Save

A transformer is employed to reduce 220 V to 11 V. The primary draws a current of 5 A and the secondary 90 A. The efficiency of the transformer is

Detailed Solution: Question 2

Primaray  power = 220 *5 = 1100 w 
Secondary power = 11*90 = 990 w
So , efficiency = 990w/1100w = 90 %

Clear all your doubts with EduRev
JEE Main Practice Test- 17 - Question 3
Save

Moderator used in nuclear reactor is

Detailed Solution: Question 3

Heavy water is used in certain types of nuclear reactors, where it acts as a neutron moderator  to slow down neutrons so that they are more likely to react with the fissile uranium-235 than with uranium-238, which captures neutrons without fissioning. 

JEE Main Practice Test- 17 - Question 4
Save

The unit of intensity of electric field is

Detailed Solution: Question 4

The SI unit of electric field strength is newtons per coulomb (N/C) or volts per meter (V/m). The force experienced by a very small test charge q placed in a field E in a vacuum is given by E = F/q, where F is the force experienced.

JEE Main Practice Test- 17 - Question 5
Save

In a hydrogen atom, when an electron jumps from second orbit to first orbit, the wavelength of spectral line emitted by hydrogen atom is

JEE Main Practice Test- 17 - Question 6
Save

“If a particle of mass m is projected from the lowest point of smooth vertical circle of radius 'A' with velocity √(5ag) the force at its lowest point will be”

Detailed Solution: Question 6

At lowest point centrifugal force is equal to mv2/a in downward direction

=> total downward force = mg + mv2/a
= mg + m 5ag/a
= mg + 5 mg
= 6mg

JEE Main Practice Test- 17 - Question 7
Save

A particle of mass m and charge q is placed at rest in a uniform electric field E and then released. The kinetic energy attained by the particle after moving a distance y is

Detailed Solution: Question 7

By conservation of energy, the increase in kinetic energy will be the decrease in potential energy.

Thus, the kinetic energy obtained is simply: qEy

JEE Main Practice Test- 17 - Question 8
Save

An electron having charge e and mass m is moving in a uniform electric field E. Its acceleration will be

Detailed Solution: Question 8

JEE Main Practice Test- 17 - Question 9
Save

25 N force is required to raise 75 kg mass from a pulley. If rope is pulled 12 m, then the load is lifted to 3 m, the efficiency of pulley system will be

Detailed Solution: Question 9

Efficiency = output/input = (75x3) / (25x12)
                                       =75/100 =75%

JEE Main Practice Test- 17 - Question 10
Save

Two wires of same length are shaped into a square and a circle. If they carry same current, ratio of the magnetic moments is

Detailed Solution: Question 10


Let magnetic moment of square wire be μ1  = I1A1
Let magnetic moment of circle wire be μ2= I2A2 
If the wires carry same current then the ratio of their magnetic moments will be
 

JEE Main Practice Test- 17 - Question 11
Save

In a capillary tube, water rises by 1.2 mm. The height of water that will rise in another capillary tube having half the radius of the first, is

Detailed Solution: Question 11

JEE Main Practice Test- 17 - Question 12
Save

Three forces start acting simultaneously on a particle moving with velocity v → . These forces are represented in magnitude and direction by the three sides of a triangle ABC (as shown). The particle will now move with velocity

Detailed Solution: Question 12


According to triangle law of vector addition, if three vectors are represented by three sides of a triangle taken in same order, then their resultant will be zero. Here, three forces acting on the particle are represented by the three sides of a triangle taken in one order, thus the resultant is zero. So, in presence of zero external force, the particle's velocity remains unchanged. 

JEE Main Practice Test- 17 - Question 13
Save

Four bodies P, Q, R and S are projected with equal velocities having angles of projection 15º, 30º, 45º and 60º with the horizontal respectively. The body having shortest range is

Detailed Solution: Question 13

When the angle of projection is very far from 45° then range will be minimum.

JEE Main Practice Test- 17 - Question 14
Save

 An electric current of 5 A is same as

Detailed Solution: Question 14

Hence 5A of current is same as 5 C/sec

JEE Main Practice Test- 17 - Question 15
Save

The nucleus of 56Ba141 contains ---- neutrons

Detailed Solution: Question 15

Given , 

=> atomic mass=141

=>atomic number=56

So, neutrons=atomic mass-atomic number

=141-56 

=85

JEE Main Practice Test- 17 - Question 16
Save

Assertion : The work done during a round trip is always zero.
Reason : No force is required to move a body in its round trip.

Detailed Solution: Question 16

In a round trip work done is zero only when the force is conservative in nature.  Force is always required to move a body in a conservative or non-conservative field

JEE Main Practice Test- 17 - Question 17
Save

In the following question, a Statement of Assertion (A) is given followed by a corresponding Reason (R) just below it. Read the Statements carefully and mark the correct answer-
Assertion(A): Study of Fraunhofer lines in the spectrum of sun led to the discovery of hydrogen.
Reason(R):Fraunhofer lines are dark lines in the continuous solar spectrum.

Detailed Solution: Question 17

In 1868 Lockyer observed a line among the Fraunhofer lines which could not be traced in the spectrum of any element on earth. So it was assumed that there was some new element in the sun's chromsphere. It was named helium. In 1895 Ramsay found this gas on earth. Thus, the study of Fraunhofer lines led to the discovery of new elements.

JEE Main Practice Test- 17 - Question 18
Save

A body A of mass M while falling vertically downwards under gravity breaks into two parts, a part B of mass M/3 and body C of mass 2M/3. The centre of mass of the bodies B and C taken together

Detailed Solution: Question 18

No horizontal external force is acting
∴ acm = 0
since vcm = 0
∴ Δxcm = 0

JEE Main Practice Test- 17 - Question 19
Save

A Carnot engine used first an ideal monoatomic gas and then an ideal diatomic gas. If the source and sink temperature are 411ºC and 69ºC respectively and the engine extracts 1000 J of heat in each cycle, then area enclosed by the P-V diagram is

Detailed Solution: Question 19

JEE Main Practice Test- 17 - Question 20
Save

The Martians use force (F), acceleration (A) and time (T) as their fundamental physical quantities. The dimensions of length on Martians system are

Detailed Solution: Question 20

Acceleration

JEE Main Practice Test- 17 - Question 21
Save

Wave optics is based on wave theory of light put forward by Huygen and modified later by

Detailed Solution: Question 21

The Huygens–Fresnel principle (named after Dutch physicist Christiaan Huygens and French physicist Augustin-Jean Fresnel) is a method of analysis applied to problems of wave propagation both in the far-field limit and in near-field diffraction.

It states that every point on a wavefront is itself the source of spherical wavelets. The sum of these spherical wavelets forms the wavefront.

JEE Main Practice Test- 17 - Question 22
Save

Doppler's effects in sound and light are

Detailed Solution: Question 22

An apparent change in the frequency of waves, as of sound or light, occurring when the source and observer are in motion relative to each other, with the frequency increasing when the source and observer approach each other anddecreasing when they move apart.

JEE Main Practice Test- 17 - Question 23
Save

The ray of light

Detailed Solution: Question 23

A perpendicular drawn to the surface of a wavefront at any point in the direction of propagation of light is called as wave normal. The direction of propagation of a wave front is given by a ray of light. Therefore, a wave normal represents a ray of light.

JEE Main Practice Test- 17 - Question 24
Save

The phase difference between two points separated by 0.8 m in a wave of frequency 120 Hz is 90º. Then the velocity of wave will be

Detailed Solution: Question 24

Here, path difference Δx=0.8m Frequency n =120 Hz Phase difference is ϕ=0.5π The phase difference is given by  

 Hence, the wave velocity is given by v = nλ (where λ is the wavelength of wave) =120 × 2.3 = 384m/s

JEE Main Practice Test- 17 - Question 25
Save

Which of the following is not a statement?

JEE Main Practice Test- 17 - Question 26
Save

When the electron in a hydrogen atom of mass M undergoes transition from an orbit of higher quantum number n2 to an orbit of lower quantum number n1, the recoil velocity acquired by the atom is (Rydberg's constant = R, Planck's constant = h)

Detailed Solution: Question 26

The wave number of the photon emitted because of the electron transition is

ν' = 1/λ = R(1/(n1)2 – 1/(n2)2) where λ is the wave length of the photon and R is Rydberg’s constant.

The momentum of the photon is p = h/λ = hR(1/(n1)2 – 1/(n2)2) where h is Planck’s constant.

When the photon is emitted with this momentum, the atom recoils (like a gun firing a bullet) with an equal and opposite momentum. Therefore, the recoil velocity of the atom is given by

v = p/M = (hR/M)(1/(n1)2 – 1/(n2)2).

JEE Main Practice Test- 17 - Question 27
Save

A 5.0 μ F capacitor is charged to a potential difference of 800 V and discharged through a conductor. The energy given to the conductor during the discharge is

Detailed Solution: Question 27

JEE Main Practice Test- 17 - Question 28
Save

A stone of mass 1 kg tied to a light inextensible string of length L = 10/3 m is whirling in a circular path of radius L in a vertical plane. If the ratio of the maximum tension in the string to the minimum tension in the string is 4 and if g is taken to be 10 m/sec2, the speed of the stone at the highest point of the circle is

Detailed Solution: Question 28

The ratio of maximum (T2) to the minimum tension is

Now, the difference between the two tensions should be 6 mg.

Hence, we have

Now, the tension at the top of the circle is 


JEE Main Practice Test- 17 - Question 29
Save

If six identical cells each having an e.m.f of 6V are connected in parallel, the E.M.F of the combination is

Detailed Solution: Question 29

 In parallel combination  Eeq=E=6V

JEE Main Practice Test- 17 - Question 30
Save

There are 20 divisions in 4 cm of the main scale. The vernier scale has 10 divisions. The least count of the instrument is

View more questions
1 videos|238 docs|217 tests
Join Course
Information about JEE Main Practice Test- 17 Page
In this test you can find the Exam questions for JEE Main Practice Test- 17 solved & explained in the simplest way possible. Besides giving Questions and answers for JEE Main Practice Test- 17, EduRev gives you an ample number of Online tests for practice
Download as PDF

About this JEE Practice Test

This test contains 90 MCQs on JEE Main Practice Test- 17 with detailed solutions for each question. It is part of the JEE Main & Advanced Mock Test Series 2026 course on EduRev, designed to align with the current JEE syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

Explore more JEE Study Resources

If you found this JEE Main Practice Test- 17 MCQ Test helpful, you can further enhance your JEE preparation with in-depth courses on EduRev, for all the subjects and topics available in JEE Main & Advanced Mock Test Series 2026 course. The course offers:
  • Video Lectures: covering all the topics of JEE Main & Advanced Mock Test Series 2026
  • Notes for Revision: offering revision notes, important questions, summaries, flashcards, cheatsheets & more for JEE preparation
  • MCQ Test: variety of questions as per the pattern of JEE exam
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup