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JEE Exam  >  JEE Tests  >  KIITEE Mock Test Series 2024  >  KIITEE Mock Test - 4 - JEE MCQ

KIITEE Mock Test - 4 - JEE MCQ


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30 Questions MCQ Test KIITEE Mock Test Series 2024 - KIITEE Mock Test - 4

KIITEE Mock Test - 4 for JEE 2024 is part of KIITEE Mock Test Series 2024 preparation. The KIITEE Mock Test - 4 questions and answers have been prepared according to the JEE exam syllabus.The KIITEE Mock Test - 4 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for KIITEE Mock Test - 4 below.
Solutions of KIITEE Mock Test - 4 questions in English are available as part of our KIITEE Mock Test Series 2024 for JEE & KIITEE Mock Test - 4 solutions in Hindi for KIITEE Mock Test Series 2024 course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt KIITEE Mock Test - 4 | 120 questions in 180 minutes | Mock test for JEE preparation | Free important questions MCQ to study KIITEE Mock Test Series 2024 for JEE Exam | Download free PDF with solutions
KIITEE Mock Test - 4 - Question 1
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In a common-base amplifier, the phase difference between the input signal voltage and output voltage is

Detailed Solution for KIITEE Mock Test - 4 - Question 1

A common-emitter amplifier is shown in the figure (A).
In this Circuit , the output signal is an amplified version of the input signal and is 180 degrees out of phase with the input signal.

     
Common emitter Amplifier
     

     
Common Base Amplifier
     
Figure (B) is a common-base amplifier. In this circuit the output signal is an amplified version of the input signal and is in phase with the input signal. In both of these circuits, the output signal is controlled by the base-to-emitter bias. As this bias changes (because of the input signal) the current through the transistor changes.

KIITEE Mock Test - 4 - Question 2
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An n - type and p - silicon can be obtained by doping pure silicon with:

Detailed Solution for KIITEE Mock Test - 4 - Question 2

For obtaining ‘n’ type semi conductor V group element is doped with silicon.
Ex: Phosphorus
For obtaining ‘p’ type semiconductor III group element is doped with silicon.
Ex: Indium

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KIITEE Mock Test - 4 - Question 3
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For a transistor working as common-base amplifier, the emitter current is 7.2 mA. If the current gain is 0.96, then the collector current is

KIITEE Mock Test - 4 - Question 4
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Transistor can be used as
KIITEE Mock Test - 4 - Question 5
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A rectifier converts
KIITEE Mock Test - 4 - Question 6
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A zener diode works on the principle of
KIITEE Mock Test - 4 - Question 7
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In forward bias, the width of potential barrier in a p-n junction diode
KIITEE Mock Test - 4 - Question 8
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In an intrinsic - semiconductor the charge carriers responsible for electrical conduction are
KIITEE Mock Test - 4 - Question 9
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To obtain p - type extrinsic semiconductor, the impurity element to be added to Germanium should be of valence
KIITEE Mock Test - 4 - Question 10
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The current gain for a transistor working as common-base amplifier is 0.96. If the emitter current is 7.2 mA, then the base current is
KIITEE Mock Test - 4 - Question 11
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The function of base layer in a transistor is similar to that --- in a vacuum triode.
KIITEE Mock Test - 4 - Question 12
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Application of a forward bias to a p-n junction
KIITEE Mock Test - 4 - Question 13
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Rectifier is used to convert
KIITEE Mock Test - 4 - Question 14
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If the pressure and absolute temperatre of 2 litres of CO₂ are doubles, the volume of CO₂ would become
KIITEE Mock Test - 4 - Question 15
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Silicon is an important constituent of
KIITEE Mock Test - 4 - Question 16
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Which of the following is used in the preparation of aerated water (soda)?
KIITEE Mock Test - 4 - Question 17
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The internal energy of one mole of an ideal gas is given by
KIITEE Mock Test - 4 - Question 18
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Gun metal is an alloy of
KIITEE Mock Test - 4 - Question 19
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50 mL of hydrogen diffuses out through a small hole of a vessel, in 20 minutes. The time taken by 40 mL of oxygen to diffuse out is
KIITEE Mock Test - 4 - Question 20
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If sin2x+sin4x=2sin3x, then x=
Detailed Solution for KIITEE Mock Test - 4 - Question 20

KIITEE Mock Test - 4 - Question 21
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If 5cos2θ+2cos2(θ/2)+1=0, -π<θ<π, then θ=
KIITEE Mock Test - 4 - Question 22
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The vertex of the parabola
y2 = 4(a' - a) (x - a) is
KIITEE Mock Test - 4 - Question 23
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The equation of the sphere concentric with the sphere x2+y2+z2 - 4x - 6y - 8z - 5 = 0 and which passes through the point (0, 1, 0) is
KIITEE Mock Test - 4 - Question 24
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The general value of θ which satisfies tanθ=-1 and cosθ=(1/√2) the equations is
KIITEE Mock Test - 4 - Question 25
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The general solution of tan2θ = 3 is
KIITEE Mock Test - 4 - Question 26
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The equation y2 - x2+ 2x - 1 = 0 represents
KIITEE Mock Test - 4 - Question 27
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If the planes x+2y+Kz=0 and 2x+y-2z=0 are at right angles, then the value of K is
KIITEE Mock Test - 4 - Question 28
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The line (p + 2q) x + (p - 3q) y = p - q for different values of p and q passes through the fixed point
KIITEE Mock Test - 4 - Question 29
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The distance of the point (2, 1, -1) from the plane x - 2y + 4z = 9 is
KIITEE Mock Test - 4 - Question 30
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If α is a root of 25cos2θ + 5cosθ - 12 = 0, (π/2)<α<π, then sin2α is equal to
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