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JEE Exam  >  JEE Test  >  KIITEE Mock Test Series 2026  >  KIITEE Mock Test - 4 - JEE MCQ

KIITEE Mock Test - 4 Free Online Test 2026


Full Mock Test & Solutions: KIITEE Mock Test - 4 (120 Questions)

You can boost your JEE 2026 exam preparation with this KIITEE Mock Test - 4 (available with detailed solutions).. This mock test has been designed with the analysis of important topics, recent trends of the exam, and previous year questions of the last 3-years. All the questions have been designed to mirror the official pattern of JEE 2026 exam, helping you build speed, accuracy as per the actual exam.

Mock Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 180 minutes
  • - Total Questions: 120
  • - Analysis: Detailed Solutions & Performance Insights
  • - Sections covered: Physics, Chemistry, Maths

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KIITEE Mock Test - 4 - Question 1
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If a full wave rectifier circuit is operating from 50 Hz mains, then fundamental frequency in the ripple will be

KIITEE Mock Test - 4 - Question 2
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In a common-base amplifier, the phase difference between the input signal voltage and output voltage is

Detailed Solution: Question 2

A common-emitter amplifier is shown in the figure (A).
In this Circuit , the output signal is an amplified version of the input signal and is 180 degrees out of phase with the input signal.

     
Common emitter Amplifier
     

     
Common Base Amplifier
     
Figure (B) is a common-base amplifier. In this circuit the output signal is an amplified version of the input signal and is in phase with the input signal. In both of these circuits, the output signal is controlled by the base-to-emitter bias. As this bias changes (because of the input signal) the current through the transistor changes.

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KIITEE Mock Test - 4 - Question 3
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Application of a forward bias to a p-n junction

KIITEE Mock Test - 4 - Question 4
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Pick out the incorrect statement regarding reverse saturation current in a p - n junction diode.

KIITEE Mock Test - 4 - Question 5
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The dominant mechanism for motion of charge carriers in forward and reverse biased silicon p-n junction are

KIITEE Mock Test - 4 - Question 6
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In an n-p-n transistor, p-acts as a/an

KIITEE Mock Test - 4 - Question 7
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For a transistor working as common-base amplifier, the emitter current is 7.2 mA. If the current gain is 0.96, then the collector current is

KIITEE Mock Test - 4 - Question 8
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In a transistor, the emitter-base junction and the collector-base junction are

KIITEE Mock Test - 4 - Question 9
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If a half wave rectifier is used to convert 50HZ a.c into d.c number of pulses present in the rectified output voltage is

KIITEE Mock Test - 4 - Question 10
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A rectifier converts

KIITEE Mock Test - 4 - Question 11
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The method of connecting the negative pole of battery to p - material and positive pole to n - material of a p - n junction is called

KIITEE Mock Test - 4 - Question 12
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A zener diode works on the principle of

KIITEE Mock Test - 4 - Question 13
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If the lattice parameter for a crystalline structure is 3.6 Å , then the atomic radius in fcc crystal is

KIITEE Mock Test - 4 - Question 14
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In forward bias, the width of potential barrier in a p-n junction diode

KIITEE Mock Test - 4 - Question 15
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In an intrinsic - semiconductor the charge carriers responsible for electrical conduction are

KIITEE Mock Test - 4 - Question 16
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A p-n photodiode is fabricated from a semiconductor with band gap of 2.8 eV. Which of the following wavelengths it can detect?

Detailed Solution: Question 16

KIITEE Mock Test - 4 - Question 17
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The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain without feedback will be

Detailed Solution: Question 17

Correct answer: A. The gain without feedback is 100.

Let A be the gain without feedback, Af the gain with feedback and β the feedback factor.

For negative feedback the relation is Af = A / (1 + Aβ).

Here Af = 10 and β = 9% = 0.09. Substitute into the formula:

10 = A / (1 + 0.09A)

10(1 + 0.09A) = A

10 + 0.9A = A

10 = 0.1A

Therefore A = 100. Hence option A is correct.

KIITEE Mock Test - 4 - Question 18
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In a common-base amplifier, the phase difference between the input signal voltage and output voltage is

Detailed Solution: Question 18

A common-emitter amplifier is shown in the figure (A).
In this Circuit , the output signal is an amplified version of the input signal and is 180 degrees out of phase with the input signal.


Common emitter Amplifier
     

     
Common Base Amplifier
     
Figure (B) is a common-base amplifier. In this circuit the output signal is an amplified version of the input signal and is in phase with the input signal. In both of these circuits, the output signal is controlled by the base-to-emitter bias. As this bias changes (because of the input signal) the current through the transistor changes.

KIITEE Mock Test - 4 - Question 19
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Use of hot air balloons in sports and metereological observations is an application of

KIITEE Mock Test - 4 - Question 20
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In any right angled triangle hypotenuse is equal to 2√2 times the perpendicular drawn from the opposite vertex on it, then other angles are

Detailed Solution: Question 20

Option C is correct.

Let the hypotenuse be c and the perpendicular (altitude) from the right-angled vertex to the hypotenuse be h.

Given c = 2√2·h, so h/c = 1/(2√2).

In a right triangle with acute angles A and B, the legs are c·sin A and c·sin B. The altitude from the right angle satisfies h = (ab)/c = c·sin A·sin B.

Thus sin A·sin B = h/c = 1/(2√2). Since B = π/2 - A, we have sin B = cos A, so sin A·cos A = 1/(2√2).

Using the identity sin A·cos A = (1/2)·sin 2A, we get (1/2)·sin 2A = 1/(2√2), hence sin 2A = 1/√2.

So 2A = π/4 or 2A = 3π/4, giving A = π/8 or A = 3π/8. The corresponding other acute angle is B = π/2 - A, i.e., the pair of angles is (π/8, 3π/8).

Therefore the correct choice is option C.

KIITEE Mock Test - 4 - Question 21
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The general value of θ which satisfies tanθ = -1 and cosθ = 1/√2 is

Detailed Solution: Question 21

Option C is correct.

For tan θ = -1, the general solution is θ = -π/4 + nπ, where n is any integer.

For cos θ = 1/√2, the solutions are θ = ±π/4 + 2kπ; explicitly θ = π/4 + 2kπ or θ = -π/4 + 2kπ, with k an integer.

The common values are those of the form θ = -π/4 + 2kπ, since these satisfy both conditions simultaneously.

Writing -π/4 as 7π/4 modulo 2π, the general solution becomes θ = 2kπ + 7π/4, which matches option C.

Therefore the required general value is θ = 2nπ + 7π/4 (option C).

KIITEE Mock Test - 4 - Question 22
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The normal to the curve x = a(1+cosθ), y = a sinθ at θ always passes through the fixed point

Detailed Solution: Question 22

Eliminating θ we get (x – a)2 + y2 = a2
Hence normal always pass through (a, 0)

KIITEE Mock Test - 4 - Question 23
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If √3 cos θ − sin θ = 1 then θ =

KIITEE Mock Test - 4 - Question 24
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If m1, m2 are slopes of the two tangents that are drawn from (2, 3) to the parabola y2 = 4x, then the value of [(1/m1) + (1/m2)] is

KIITEE Mock Test - 4 - Question 25
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If sin2x+sin4x=2sin3x, then x=

Detailed Solution: Question 25

KIITEE Mock Test - 4 - Question 26
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The equation of the parabola whose focus is (1,-1) and directrix is x + y + 7 = 0 is

KIITEE Mock Test - 4 - Question 27
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If the pair of lines ax2+ 2hxy + by2 + 2gx + 2fy + c = 0 intersect on the y-axis then

KIITEE Mock Test - 4 - Question 28
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The radius of the circle
3x (x - 2) + 3y (y + 1) = 4 is

KIITEE Mock Test - 4 - Question 29
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Locus of mid point of the portion between the axes of x cosα + y sinα = p where p is constant is

KIITEE Mock Test - 4 - Question 30
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If α is a root of 25cos2θ + 5cosθ - 12 = 0, (π/2)<α<π, then sin2α is equal to

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About this JEE Mock Test

This mock test contains 120 questions designed to replicate the pattern, difficulty level and time pressure of the actual JEE exam. It is part of KIITEE Mock Test Series 2026 on EduRev, covering all the topics that are being asked as per the current JEE syllabus. Attempting this test under timed conditions will help you assess your exam readiness, identify subject-wise weak areas, and improve your speed and accuracy before the actual exam.

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If you found this KIITEE Mock Test - 4 helpful, you can further enhance your JEE preparation with complete mock tests, previous year questions & practice tests available in KIITEE Mock Test Series 2026 course on EduRev. The course offers:
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