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Liquid state - 2 - JEE MCQ


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30 Questions MCQ Test Chemistry for JEE Main & Advanced - Liquid state - 2

Liquid state - 2 for JEE 2024 is part of Chemistry for JEE Main & Advanced preparation. The Liquid state - 2 questions and answers have been prepared according to the JEE exam syllabus.The Liquid state - 2 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Liquid state - 2 below.
Solutions of Liquid state - 2 questions in English are available as part of our Chemistry for JEE Main & Advanced for JEE & Liquid state - 2 solutions in Hindi for Chemistry for JEE Main & Advanced course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt Liquid state - 2 | 30 questions in 60 minutes | Mock test for JEE preparation | Free important questions MCQ to study Chemistry for JEE Main & Advanced for JEE Exam | Download free PDF with solutions
Liquid state - 2 - Question 1


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Liquid state - 2 - Question 2


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Liquid state - 2 - Question 3

Molal depression constant for a solvent is 4.0 K kg mol–1. The depression in the freezing point of the solvent for 0.03 mol kg–1 solution of K2OS4 is : (Assume complete dissociation of the electrolyte)

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Liquid state - 2 - Question 10

The vapour pressures of pure liquids A and B are 400 and 600 mmHg, respectively at 298 K. On mixing the two liquids, the sum of their initial volumes is equal to the volume of the final mixture. The mole fraction of liquid B is 0.5 in the mixture. The vapour pressure of the final solution, the mole fractions of components A and B in vapour phase, respectively are -

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Liquid state - 2 - Question 26

Elevation of boiling point of 1 molar aqueous glucose solution (density = 1.2 g/ml) is

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