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SSC CGL Exam  >  SSC CGL Test  >  Quantitative Aptitude  >  MCQ: Approximation - 2 - SSC CGL MCQ

Approximation - 2 - Free MCQ Practice Test with solutions, SSC CGL Quant


MCQ Practice Test & Solutions: MCQ: Approximation - 2 (15 Questions)

You can prepare effectively for SSC CGL Quantitative Aptitude for SSC CGL with this dedicated MCQ Practice Test (available with solutions) on the important topic of "MCQ: Approximation - 2". These 15 questions have been designed by the experts with the latest curriculum of SSC CGL 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 15 minutes
  • - Number of Questions: 15

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MCQ: Approximation - 2 - Question 1
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Directions: What approximate value will come in place of the question mark (?) in the following question?

(2.992 – 8.042) – ? = 6.512 – 209.24

Detailed Solution: Question 1

(2.992 – 8.042) – ? = 6.512 – 209.24
(32 – 82) – ? ≈ 6.502 – 209
(9 – 64) – ? ≈ 42 – 209
– 55 – ? ≈ – 167
? ≈ 167 – 55 = 112
? ≈ 110
Hence, Option A is correct.

MCQ: Approximation - 2 - Question 2
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Directions: What approximate value will come in place of the question mark (?) in the following question?

√(1450) × √(255) = ?

Detailed Solution: Question 2

√(1450) × √(255) = ?
√(1444) × √(256) ≈ ?
38 × 16 ≈ ?
608 ≈ ?
610 ≈ ?
Hence, Option B is correct.

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MCQ: Approximation - 2 - Question 3
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Directions: What approximate value will come in place of the question mark (?) in the following question?

9540 ÷ 18 ÷ 13 = ? × 8 × 5

Detailed Solution: Question 3

9540 ÷ 18 = 530
530 ÷ 13 ≈ 40.77

So the left side is about 40.77.
On the right side ? × 8 × 5 = ? × 40

We need ? × 40 ≈ 40.77,
so ? ≈ 40.77 ÷ 40 ≈ 1.02

Rounded to the nearest whole number gives 1.

Answer: (a) 1

MCQ: Approximation - 2 - Question 4
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Directions: What approximate value will come in place of the question mark (?) in the following question?
– (14.99)3 + (49.98)2 + (5.01)4 = ? 

Detailed Solution: Question 4

– (14.99)3 + (49.98)2 + (5.01)4 = ?
– (15)3 + (50)2 + (5)4 ≈ ?
– 3375 + 2500 + 625 ≈ ?
– 250 ≈ ?
Hence, Option A is correct.

MCQ: Approximation - 2 - Question 5
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Directions: What approximate value will come in place of the question mark (?) in the following question?

√(4230) + (4)3 = ?3

Detailed Solution: Question 5

Step 1: Approximate the square root
• 4230 is very close to 4225, whose square root is 65
• So √4230 ≈ 65

Step 2: Compute 4³
• 4³ = 64

Step 3: Add them
• √4230 + 4³ ≈ 65 + 64 = 129

Step 4: Find which number cubed is about 129
• 5³ = 125, 6³ = 216
• 129 is very close to 125, so the cube root of 129 is about 5

Answer: 5

MCQ: Approximation - 2 - Question 6
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Directions: What approximate value will come in place of the question mark (?) in the following question?

(19)2 ÷ √325 = 25% of ?

Detailed Solution: Question 6

(19)2 ÷ √325 = 25% of ?
361 ÷ √324 ≈ 25% of ?
361 ÷ 18 ≈ 25% of ?

80 ≈ ?
Hence, Option A is correct.

MCQ: Approximation - 2 - Question 7
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Directions: What approximate value will come in place of the question mark (?) in the following question?

√(1000) + √(800) = ? 

Detailed Solution: Question 7

√(1000) + √(800) = ?
31.50 + 28.50 ≈ ?
60 ≈ ?
Hence, Option D is correct.

MCQ: Approximation - 2 - Question 8
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Directions: What approximate value will come in place of the question mark (?) in the following question?

(1874.689 ÷ 25)% of 4001% of 20 = ? + 500

Detailed Solution: Question 8

(1874.689 ÷ 25)% of 4001% of 20 = ? + 500
(1875 ÷ 25)% of 4001% of 20 ≈ ? + 500
75% of 4000% of 20 ≈ ? + 500
600 – 500 ≈ ?
100 ≈ ?
Hence, Option C is correct.

MCQ: Approximation - 2 - Question 9
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Directions: What approximate value will come in place of the question mark (?) in the following question?

90.97 ÷ 12.99 × 14.99 + √228 = ? 

Detailed Solution: Question 9

90.97 ÷ 12.99 × 14.99 + √228 = ?
91 ÷ 13 × 15 + √228  ≈ ?
105 + 15 ≈ ?
120 ≈ ?
Hence, Option A is correct.

MCQ: Approximation - 2 - Question 10
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Directions: What approximate value will come in place of the question mark (?) in the following question?

720.01 ÷ 15.99 × 2.99 + ?3 = 650

Detailed Solution: Question 10

720.01 ÷ 15.99 × 2.99 + ?3 = 650
720 ÷ 16 × 3 + ?3 ≈ 650
135 + ?3 ≈ 650
?3 ≈ 515
? = 8
Hence, Option C is correct.

MCQ: Approximation - 2 - Question 11
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Directions: What approximate value will come in place of the question mark (?) in the following question?

[(9.99)2 – (13.01)2 + (4.01)3]2 = ? 

Detailed Solution: Question 11

[(9.99)2 – (13.01)2 + (4.01)3]2 = ?
[(10)2 – (13)2 + (4)3]2 ≈ ?
[100 – 169 + 64]2 ≈ ?
[– 5]2 ≈ ?
25 ≈ ?
Hence, Option C is correct.

MCQ: Approximation - 2 - Question 12
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Directions: What approximate value will come in place of the question mark (?) in the following question?

√(2200) × √(2490) ÷ √(630) = ?

Detailed Solution: Question 12

√(2200) × √(2490) ÷ √(630) = ?
√(2209) × √(2500) ÷ √(625) ≈ ?

94 ≈ ?
95 ≈ ?
Hence, Option B is correct.

MCQ: Approximation - 2 - Question 13
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Directions: What approximate value will come in place of the question mark (?) in the following question?

100 ÷ 3.03 × 4.99901 = ? 

Detailed Solution: Question 13

100 ÷ 3.03 × 4.99901 = ?
99 ÷ 3 × 5 ≈ ?
33 × 5 ≈ ?
165 ≈ ?
Hence, Option D is correct.

MCQ: Approximation - 2 - Question 14
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Directions: What approximate value will come in place of the question mark (?) in the following question?

18% of 1888 – (700 ÷ 65) = ?

Detailed Solution: Question 14

18% of 1888 – (700 ÷ 65) = ?
18 × 19 – (11) ≈ ?
330 ≈ ?
Hence, Option A is correct.

MCQ: Approximation - 2 - Question 15
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Directions: What approximate value will come in place of the question mark (?) in the following question?

(49.97% of 881) + ? + (400% of 8.001) = 875

Detailed Solution: Question 15

(49.97% of 881) + ? + (400% of 8.001) = 875
(50% of 880) + ? + (400% of 8) ≈ 875
440 + ? + 32 ≈ 875
? ≈ 403
Hence, Option B is correct.

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About this SSC CGL Practice Test

This test contains 15 MCQs on MCQ: Approximation - 2 with detailed solutions for each question. It is part of the Quantitative Aptitude for SSC CGL course on EduRev, designed to align with the current SSC CGL syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

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