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Math Olympiad Test: Circles- 2 - Free MCQ with solutions Class 10


MCQ Practice Test & Solutions: Math Olympiad Test: Circles- 2 (15 Questions)

You can prepare effectively for Class 10 Olympiad Preparation for Class 10 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Math Olympiad Test: Circles- 2". These 15 questions have been designed by the experts with the latest curriculum of Class 10 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 15 minutes
  • - Number of Questions: 15

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Math Olympiad Test: Circles- 2 - Question 1

The perimeter of a sector of a circle of radius 5.2 cm is 16.4 cm, then what is area of sector?

Detailed Solution: Question 1

Let O be the centre of a circle of radius 5.2 cm. Let OABO be the sector with perimeter 16.4 cm.

OA + O B + arc AB = 27.2
5.2 + 5 .2 + arc AB = 16.4
⇒ arc AB = 16.4 - 16.4 = 6 cm
Area of sector OACBO

Math Olympiad Test: Circles- 2 - Question 2

A bicycle wheel makes 5000 revolutions in moving 11 km. What is the radius  of the wheel?

Detailed Solution: Question 2

Distance moved by wheel 
= 2 × π × r × 5000 = 11000 m

= 35 cm

Math Olympiad Test: Circles- 2 - Question 3

What is the length of tangent drawn from a point whose distance from the centre of a circle is 25 cm, if radius of the circle is 7 cm?

Detailed Solution: Question 3

PT2 + OT2 = OP2
⇒ PT2 = (25)2 -(7)2
⇒ PT = = 24 cm.

Math Olympiad Test: Circles- 2 - Question 4

A bucket is raised from a well by means of a rope which is wound round a wheel of diameter 77 cm. Given that the bucket ascends in 1 minute 28 seconds with a uniform speed of 1.1 m/s. What is the number of complete revolutions the wheel makes in raising the bucket?

Detailed Solution: Question 4

Distance moved by rope
= (1.1) × (60 + 28)
∴ No. of revolutions = 

Math Olympiad Test: Circles- 2 - Question 5

What is the value of y and x respectively in the given figure?

Detailed Solution: Question 5

In ΔABO,
∠y + 25° + 100° = 180°
⇒ y = 55°
∠C + ∠A = 180° [∵ ABCD is cycle]
⇒ ∠ = 80°
In ΔPBC,
∠x + 55° + 80° = 180°
⇒ ∠x = 45°

Math Olympiad Test: Circles- 2 - Question 6

AB is a tangent to the circle at E. If EC = ED and ∠CDE = 62°. Find angle ∠AED.

Detailed Solution: Question 6

∵ EC = ED
∴ ∠ECD = ∠EDC = 62°
∴ ∠DEC = 180° - (2 × 62°) =56°

∴ ∠AED = ∠CED + ∠AEC
= 56° + 62° = 118°

Math Olympiad Test: Circles- 2 - Question 7

In the given figure AD is diameter of the circle. If ∠BCD = 130°. What is the value of ∠DAB?

Detailed Solution: Question 7

∵ A, B, C and D are on the circumference of the circle
∴ ABCD is a cyclic quadrilateral, i.e.,
∠A + ∠C = 180°
⇒ ∠A = 180° - ∠C = 180° - 130° = 50°
∴ ∠DAB= 50°.

Math Olympiad Test: Circles- 2 - Question 8

What is the area of quadrant of a circle whose circumference is 22 cm?

Detailed Solution: Question 8

Let r be the radius
2πr = 22

Area of quadrant = 

Math Olympiad Test: Circles- 2 - Question 9

In a circle of radius 10.5 cm, the minor arc is one-fifth of the major arc. What is the area of major arc?

Detailed Solution: Question 9

Let the major arc be x cm
Length of minor arc = x/5
Circumference = 
⇒ 
⇒ 
⇒ x = 55 cm
Required area = 
=    288.75 cm2.

Math Olympiad Test: Circles- 2 - Question 10

A Pendulum swings through an angle of 30° and describes an arc 8.8 cm in length, then what is the length of the Pendulum?

Detailed Solution: Question 10

Length of pendulum
= radius of the sector = x cm
Arc length = 8.8 cm
⇒ 

Math Olympiad Test: Circles- 2 - Question 11

The minute hand of a clock is 12 cm long. Find the area of the face of the clock described by the minute hand in 35 minutes.

Detailed Solution: Question 11

Angle described by the minute hand in 35 minutes = 
θ = 210º, r = 12 cm
Area of the sector = 

= 264 cm2.

Math Olympiad Test: Circles- 2 - Question 12

In the given figure, ΔABC is right angled at A with AB = 6 cm and AC = 8 cm. A circle with centre O has been inscribed inside the triangle. Find the value of the radius of the inscribed circle.

Detailed Solution: Question 12



(area ΔOAC) + (area ΔOAB) + (area ΔOBC)
= area (ΔABC)



⇒ 8r + 6r + 10r = 48
⇒ 24r = 48 ⇒ r = 2

Math Olympiad Test: Circles- 2 - Question 13

A chord of a circle of radius 14 cm makes a right angle at the centre. Find the area of minor segment of the circle.

Detailed Solution: Question 13

Area of the sector OACBO,

= 154 cm2.
Area of ΔOAB = 

∴ Area of minor segment of circle
= 154 - 98 = 56 cm2.

Math Olympiad Test: Circles- 2 - Question 14

A field is in the form of a circle. The cost of ploughing the field at Rs. 1.50 per m2 is Rs. 5775. Find the cost of fencing the field at Rs. 8.50 per meter.

Detailed Solution: Question 14

Area of the circular filed = 
πr2 = 3850

r = 35 m
Circumference = 2πr = = 220 m
Cost of fencing = 220 × 8.50 = Rs. 1870

Math Olympiad Test: Circles- 2 - Question 15

What is the area of shaded region if ABCD is a square of side 14 cm and APD and BPC are semi circles?

Detailed Solution: Question 15

Area of the shaded region = Area of square ABCD - Area of two semicircles

= 196 - 154 = 42 cm2

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