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CBSE Class 9  >  Class 9 Test  >  Mathematics Olympiad  >   Math Olympiad Test: Statistics- 2 - Class 9 MCQ

Math Olympiad Test: Statistics- 2 - Free MCQ with solutions Class 9 Mathematics


MCQ Practice Test & Solutions: Math Olympiad Test: Statistics- 2 (15 Questions)

You can prepare effectively for Class 9 Mathematics Olympiad for Class 9 with this dedicated MCQ Practice Test (available with solutions) on the important topic of " Math Olympiad Test: Statistics- 2". These 15 questions have been designed by the experts with the latest curriculum of Class 9 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 15 minutes
  • - Number of Questions: 15

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Math Olympiad Test: Statistics- 2 - Question 1
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The no. of class intervals, if the magnitude of class interval is 4 will be:
Data: 31, 23, 19, 29, 20, 16, 22, 10, 13, 34, 33, 38, 36, 24, 18, 15, 12, 30, 27, 23, 20

Detailed Solution: Question 1

Range = 38 – 10 = 28
∴ number of class intervals = 28/4 = 7 

Math Olympiad Test: Statistics- 2 - Question 2
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The class marks of a distribution are:
52, 47, 57, 67, 62, 72, 82, 87, 97, 92, 102.
Q. The lower and upper limits of first class interval will be:

Detailed Solution: Question 2

 Upper limit = 

Lower limit = 
= 44.5
[h = difference between any two marks = 52 – 47 = 5] 

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Math Olympiad Test: Statistics- 2 - Question 3
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Tallys are usually marked in a bunch of:

Detailed Solution: Question 3

Tallies are usually marked in groups of five. The first four tallies are marked vertically and the fifth tally is marked diagonally across the first 4.

Math Olympiad Test: Statistics- 2 - Question 4
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The mid–value and upper limit of a class interval are 41 and 47 respectively. The class size will be:

Detailed Solution: Question 4

Upper limit = mid value + 
47 = 41 + 

∴ Class size = (47 – 41) × 2
= 12

Math Olympiad Test: Statistics- 2 - Question 5
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The x-and y-axes in the histogram represent:

Detailed Solution: Question 5

x-axis represents class interval, y-axis represents frequency. 

Math Olympiad Test: Statistics- 2 - Question 6
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In the ‘more–than’ type of ogive the cumulative frequency is plotted against:

Detailed Solution: Question 6

More than distribution of cumulative frequency plot is a kind of Ogive frequency distribution in which the frequencies are decreasing from top to bottom. 
So, we consider lower limits as abscissa and more than cumulative frequencies as ordinate.

Math Olympiad Test: Statistics- 2 - Question 7
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The frequency of students is highest in the class interval:

Detailed Solution: Question 7

∵ The class interval, 30 – 40, has highest peak,
∴ It has highest frequency. 

Math Olympiad Test: Statistics- 2 - Question 8
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The mean of x1, x2, ……., xn is , then the value of:

Detailed Solution: Question 8


⇒ x1 + x2 + x3 + x4 ……. + xn = n
⇒ x1 + x2 + x3 …… + xn

Math Olympiad Test: Statistics- 2 - Question 9
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If each number in (Prob - 17) is multiplied by k, the new mean will be: 

Detailed Solution: Question 9

Given 

Math Olympiad Test: Statistics- 2 - Question 10
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The mean of 10 numbers is 16. If two consecutive numbers are excluded, the new mean is 18. The sum of the excluded numbers is: 

Detailed Solution: Question 10


⇒ x1 + x2 …… + x10 = 16 ……. (i)
Let x2 and x3 are removed, then,

⇒ x1 + x4 + ….. + x10 = 144 …….(ii) 
Now, Eq. (i) – (ii) 
x2 + x3 = 160 – 144 = 16

Math Olympiad Test: Statistics- 2 - Question 11
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The sum of deviations of a set of n values x1, x2, …… xn measured from 50 is – 10 and the sum of deviations of the values from 46 is 70. The value of n is: 

Detailed Solution: Question 11

…(i)
…(ii)
Subtracting eq. (i), from eq. (ii),
46n – (–50 n) = 70 – (–10) 
⇒ 4n = 80
⇒ n = 20

Math Olympiad Test: Statistics- 2 - Question 12
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The mean of the following distribution is:

Detailed Solution: Question 12


Math Olympiad Test: Statistics- 2 - Question 13
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Total = 120
Mean =  50
f1, f2 =

Detailed Solution: Question 13

f1 + f2 + 17 + 32 + 19 = 120
⇒ f1 + f2 = 52 …(i)
Mean

⇒ 50 × 120 = 170 + 1600 + 1710 + + 30f1 + 70f2
⇒ 30f1 + 70f2 = 2520
⇒ 371 + 7f2 = 252 ……..(ii)
From eq (i) and eq (ii).
f1 = 28, f2 = 24

Math Olympiad Test: Statistics- 2 - Question 14
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The new median, of the following data, if 37 is replaced by 5.
7, 9, 16, 25, 31, 36, 37, 39, 40, 42, 43

Detailed Solution: Question 14

If 37 ⟶ 5, then, the new data will be:
5, 7, 9, 16, 25, 31, 36, 39, 40, 42, 43
∵ No. of numbers = 11
∴ = 6th number will be the median. 

Math Olympiad Test: Statistics- 2 - Question 15
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The mode of the following data is:
29, 40, 41, 46, 45, 44, 43, 29, 40, 41, 46, 44,  44, 47, 49, 53, 29, 57, 44, 43, 41, 28, 16, 26.

Detailed Solution: Question 15

∵ 44 is repeated 4 times, i.e., maximum no. of times.
∴ Mode = 44

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About this Class 9 Practice Test

This test contains 15 MCQs on Math Olympiad Test: Statistics- 2 with detailed solutions for each question. It is part of the Mathematics Olympiad for Class 9 course on EduRev, designed to align with the current Class 9 syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

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