Explore Exams
Login Signup
Sign in Open App
Mechanical Engineering Exam  >  Mechanical Engineering Test  >  RRB JE Mock Test Series (ME) 2026  >   Mensuration - MCQ 2 - Mechanical Engineering MCQ

RRB JE Mensuration - MCQ 2 Free Online Test 2026


MCQ Practice Test & Solutions: Mensuration - MCQ 2 (20 Questions)

You can prepare effectively for Mechanical Engineering RRB JE Mock Test Series for Mechanical Engineering (ME) 2026 with this dedicated MCQ Practice Test (available with solutions) on the important topic of " Mensuration - MCQ 2". These 20 questions have been designed by the experts with the latest curriculum of Mechanical Engineering 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 40 minutes
  • - Number of Questions: 20

Sign up on EduRev for free to attempt this test and track your preparation progress.

Mensuration - MCQ 2 - Question 1
Save

The length of a rectangle wall is 3/2 times of its height. If the area of the wall is 600m². What is the sum of the length and height of the wall?

Detailed Solution: Question 1

length = 2x
height = 3x
Area of the wall = 3x * 2x = 6x² = 600
x = 10; Sum of the length and height of the wall = 50

Mensuration - MCQ 2 - Question 2
Save

If the area of a circle is 616cm² whose diameter is equal to radius of a semicircle. Find the perimeter of the semicircle?

Detailed Solution: Question 2

Area of a circle = 616cm²
πr² = 616; r = 14
D = Radius of Semi Circle = 28
Perimeter of the semicircle = πr + 2r = 144cm

Clear all your doubts with EduRev
Mensuration - MCQ 2 - Question 3
Save

One side of rectangular ground is 8m and its diagonal is 17m. Find the area of ground?

Detailed Solution: Question 3

d = √(l² + b²)
17 = √(l² + 8²)
l² = 17² – 8² ⇒ l = 289 – 64 = 225
l = 15 Area = 15 * 8 = 120m²

Mensuration - MCQ 2 - Question 4
Save

The side of a square shaped garden is 8√2 . Find the maximum possible distancce between any two corners

Detailed Solution: Question 4

d = a√2
a = 8√2
d = 16m

Mensuration - MCQ 2 - Question 5
Save

A rectangular ground 16m long and 10m breadth. It has a gravel path 2.5m wide all around it on the outside. What is the area of the path?

Detailed Solution: Question 5

Area of ground = 16 * 10 = 160
Total area (ground + path) = (16 + 5)*(10 + 5) = 315
Area of path = 315 – 160 = 155 m²

Mensuration - MCQ 2 - Question 6
Save

If the side of the square is increased by 30%, then how much % does its area get increased?

Detailed Solution: Question 6

Area of the plot = 1.3 * 1.3 = 1.69 = 69%

Mensuration - MCQ 2 - Question 7
Save

A ladder is resting with one end in contact with the top of the wall of height 15m and the other end of the ground is at a distance 8m from the wall. The length of the ladder is?

Detailed Solution: Question 7

Hypotenuse = √(base)² + (altitude)²
√(8)² + (15)² = √289 = 17m

Mensuration - MCQ 2 - Question 8
Save

The perimeter of a square is equal to twice the perimeter of a rectangle of length 10 cm and breadth 4 cm. What is the circumference of a semi-circle whose diameter is equal to the side of the square?

Detailed Solution: Question 8

Perimeter of square = 2(l + b)
= 2 * 2(10 + 4) = 2 * 28 = 56 cm
Side of square = 56/4 = 14 cm
Radius of semi circle = 14/2 = 7cm
Circumference of the semi-circle = 22/7 * 7 + 14 = 36 cm

Mensuration - MCQ 2 - Question 9
Save

The length of a rectangle is 3/5th of the side of a square. The radius of a circle is equal to side of the square. The circumference of the circle is 132 cm. What is the area of the rectangle, if the breadth of the rectangle is 15 cm?

Detailed Solution: Question 9

Circumference of the circle = 132
2πR = 132; R = 21 cm
Side of square = 21 cm
Length of the rectangle = 3/5 * 21 = 63/5
Area of the rectangle = 63/5 * 15 = 189 cm²

Mensuration - MCQ 2 - Question 10
Save

Smallest side of a right angled triangle is 13 cm less than the side of a square of perimeter 72 cm. Second largest side of the right angled triangle is 2 cm less than the length of the rectangle of area 112 cm² and breadth 8 cm. What is the largest side of the right angled triangle?

Detailed Solution: Question 10

Side of square = 72/4 = 18 cm
Smallest side of the right angled triangle = 18 – 13 = 5 cm
Length of rectangle = 112/8 = 14 cm
Second side of the right angled triangle = 14 – 2 = 12 cm
Hypotenuse of the right angled triangle = √(25 + 144) = 13cm

Mensuration - MCQ 2 - Question 11
Save

In a rectangle the ratio of the length and breadth is 3:2. If each of the length and breadth is increased by 4m their ratio becomes 10:7. The area of the original rectangle in m² is?

Detailed Solution: Question 11

[3x + 4 / 2x + 4] = 10/7
x = 12
Area of the original rectangle = 3x * 2x = 6x²
Area of the original rectangle = 6 * 144 = 864m²

Mensuration - MCQ 2 - Question 12
Save

The perimeter of a rectangle and a square is 160 cm each. If the difference between their areas is 500 cm. If the area of the rectangle is less than that of a Square then find the area of the rectangle?

Detailed Solution: Question 12

Perimeter of rectangle = Perimeter of Square = 160
4a = 160 ⇒ a = 40 Area of square = 1600
1600 – lb = 500
lb = 1100 cm²

Mensuration - MCQ 2 - Question 13
Save

Circumference of a circle A is 22/7 times perimeter of a square. Area of the square is 441 cm². What is the area of another circle B whose diameter is half the radius of the circle A(in cm²)?

Detailed Solution: Question 13

Area = 441 cm²
a = 21 cm
Perimeter of Square = 4 * 21
Circumference of a Circle = 4 * 21 * 22/7
2πr = 4 * 3 * 22
r = 12 * 22 * 7 / 2 * 22 = 42 cm
Radius of Circle B = 42/4 = 10.5 cm
Area of Circle = πr² = 22/7 * 10.5 * 10.5 = 346.5 cm²

Mensuration - MCQ 2 - Question 14
Save

The area of a rectangle is equal to the area of a square whose diagonal is 12√2 metre. The difference between the length and the breadth of the rectangle is 7 metre. What is the perimeter of rectangle ? (in metre).

Detailed Solution: Question 14

d = a√2
12√2 = a√2
a = 12
l * b = a² = (12²) = 144
l – b = 7 ; l = b + 7
(b + 7)*(b) = 144
b² + 7b – 144 = 0
b = 9; l = 16
2(l + b) = 2(16 + 9) = 50m

Mensuration - MCQ 2 - Question 15
Save

The area of a rectangle gets reduced by 9 square units,if its length is reduced by 5 units and breadth is increased by 3 units. If we increase the length by 3 units and breadth by 2 units, then the area is increased by 67 square units. Find the area of the rectangle?

Detailed Solution: Question 15

Length = x; Breadth =y
xy – (x-5)(y+3) = 9
3x – 5y – 6 = 0 —(i)
(x+3)(y+2) – xy = 67
2x + 3y -61 = 0 —(ii)
solving (i) and (ii)
x = 17m ; y = 9m
Area of the Rectangle = 153 m

Mensuration - MCQ 2 - Question 16
Save

The length of a plot is four times its breath. A playground measuring 900 square meters occupies one fourth of the total area of a plot. What is the length of the plot in meter.?

Detailed Solution: Question 16

Area of the plot = (4 x 900) m²
= 3600 m²
Breadth = y meter
Length = 4y meter
Now area = 4y x y = 3600 m²
⇒ y² = 900 m²
⇒ y = 30 m
∴ Length of plot = 4y =120 m

Mensuration - MCQ 2 - Question 17
Save

The sum of the radius and height of a cylinder is 19m. The total surface area of the cylinder is 1672 m², what is the radius and height of the cylinder?(in m)

Detailed Solution: Question 17

r + h = 19 m
2πr(r + h) = 1672
r = 1672 * 7/ 2 * 22 * 19 = 14
r = 14 ; h = 5

Mensuration - MCQ 2 - Question 18
Save

If each side pair of opposite sides of a square is increased by 20 m, the ratio of the length and breadth of the rectangular so formed becomes 5:3. The area of the old square is?

Detailed Solution: Question 18

(x+20) / x = 5 / 3
3x + 60 = 5x
x = 30m; Area = 900m²

Mensuration - MCQ 2 - Question 19
Save

The length of a park is four times of its breadth. A playground whose area is 1024 m² covers 1/4th part of the park. The length of the park is?

Detailed Solution: Question 19

l = 4b
Area of the park = 4 * 1024 m²
l * b = 4 * 1024
l * l/4 = 4 * 4 * 1024
l² = 1024 * 16; l = 32 * 4 = 128 m

Mensuration - MCQ 2 - Question 20
Save

The width of a rectangular piece of land is 1/4 th of its length. If the perimeter of the piece of land is 320 m its length is?

Detailed Solution: Question 20

length = l ; breadth = l/4
2(l + b) = 320
2(l + l/4) = 320
l = 320 * 4/10 = 128m

158 tests
Join Course
Information about Mensuration - MCQ 2 Page
In this test you can find the Exam questions for Mensuration - MCQ 2 solved & explained in the simplest way possible. Besides giving Questions and answers for Mensuration - MCQ 2, EduRev gives you an ample number of Online tests for practice
Download as PDF
;

About this Mechanical Engineering Practice Test

This test contains 20 MCQs on Mensuration - MCQ 2 with detailed solutions for each question. It is part of the RRB JE Mock Test Series for Mechanical Engineering (ME) 2026 course on EduRev, designed to align with the current Mechanical Engineering syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

Explore more Mechanical Engineering Study Resources

If you found this Mensuration - MCQ 2 MCQ Test helpful, you can further enhance your Mechanical Engineering preparation with in-depth courses on EduRev, for all the subjects and topics available in RRB JE Mock Test Series for Mechanical Engineering (ME) 2026 course. The course offers:
  • Video Lectures: covering all the topics of RRB JE Mock Test Series for Mechanical Engineering (ME) 2026
  • Notes for Revision: offering revision notes, important questions, summaries, flashcards, cheatsheets & more for Mechanical Engineering preparation
  • MCQ Test: variety of questions as per the pattern of Mechanical Engineering exam
Signup on EduRev and stay on top of your study goals
10M+ students crushing their study goals daily