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NCERT Based Test: Magnetic Field on the Axis of a Circular Current Loop


MCQ Practice Test & Solutions: NCERT Based Test: Magnetic Field on the Axis of a Circular Current Loop (5 Questions)

You can prepare effectively for NEET NCERT Based Tests for NEET with this dedicated MCQ Practice Test (available with solutions) on the important topic of "NCERT Based Test: Magnetic Field on the Axis of a Circular Current Loop". These 5 questions have been designed by the experts with the latest curriculum of NEET 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 5 minutes
  • - Number of Questions: 5

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NCERT Based Test: Magnetic Field on the Axis of a Circular Current Loop - Question 1

A circular loop of radius 3 cm is having a current of 12.5 A. The magnitude of magnetic field at a distance of 4 cm on its axis is

Detailed Solution: Question 1


Here, I = 12.5 A, R = 3 cm = 3 x 10-2
x = 4 cm = 4 x 10-2 m
∴ 

NCERT Based Test: Magnetic Field on the Axis of a Circular Current Loop - Question 2

A straight wire carrying a current of 13 A is bent into a semi-circular arc of radius 2 cm as shown in figure. The magnetic field is 1.5 x 10-4 T at the centre of arc, then the magnetic field due to straight segment is

Detailed Solution: Question 2

Since dl and r for each element of the straight segments are parallel. Therefore

Hence, B is also zero.

NCERT Based Test: Magnetic Field on the Axis of a Circular Current Loop - Question 3

A circular coil of wire consisting of 100 turns each of radius 9 cm carries a current of 0.4 A. The magnitude of magnetic field at the centre of the coil is

Detailed Solution: Question 3

Here N = 100
R = 9 cm = 9 x 10-2 m and I = 0.4 A 
Now, 
 0.279 x 10-3 T = 2.7 9 x 10-4 T 

NCERT Based Test: Magnetic Field on the Axis of a Circular Current Loop - Question 4

The magnitude of the magnetic field at the centre of the tightly wound 150 turn coil of radius 12 cm carrying a current of 2 A is

Detailed Solution: Question 4

Here, N = 150, R = 12 cm = 12 x 10-2 m, I = 2 A 

= 1.57 x 10-3T = 15.7 x 10-4 T = 15.7 G

NCERT Based Test: Magnetic Field on the Axis of a Circular Current Loop - Question 5

A tightly wound 90 turn coil of radius 15 cm has a magnetic field of 4 x 10-4 T at its centre. The current flowing through it is

Detailed Solution: Question 5

Here, N = 90
R = 15 cm = 15 x 10-2m, B = 4 x 10-4 T
∵ B = μ0NI/2R 

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