All Courses
Get the App Signup / Login
Sign in Open App
Electronics and Communication Engineering (ECE) Exam  >  Electronics and Communication Engineering (ECE) Tests  >  RRB JE Mock Test Series for ECE 2025  >  RRB JE ECE (CBT I) Mock Test- 9 - Electronics and Communication Engineering (ECE) MCQ

RRB JE ECE (CBT I) Mock Test- 9 - Electronics and Communication Engineering (ECE) MCQ


Test Description

30 Questions MCQ Test RRB JE Mock Test Series for ECE 2025 - RRB JE ECE (CBT I) Mock Test- 9

RRB JE ECE (CBT I) Mock Test- 9 for Electronics and Communication Engineering (ECE) 2024 is part of RRB JE Mock Test Series for ECE 2025 preparation. The RRB JE ECE (CBT I) Mock Test- 9 questions and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus.The RRB JE ECE (CBT I) Mock Test- 9 MCQs are made for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for RRB JE ECE (CBT I) Mock Test- 9 below.
Solutions of RRB JE ECE (CBT I) Mock Test- 9 questions in English are available as part of our RRB JE Mock Test Series for ECE 2025 for Electronics and Communication Engineering (ECE) & RRB JE ECE (CBT I) Mock Test- 9 solutions in Hindi for RRB JE Mock Test Series for ECE 2025 course. Download more important topics, notes, lectures and mock test series for Electronics and Communication Engineering (ECE) Exam by signing up for free. Attempt RRB JE ECE (CBT I) Mock Test- 9 | 100 questions in 90 minutes | Mock test for Electronics and Communication Engineering (ECE) preparation | Free important questions MCQ to study RRB JE Mock Test Series for ECE 2025 for Electronics and Communication Engineering (ECE) Exam | Download free PDF with solutions
RRB JE ECE (CBT I) Mock Test- 9 - Question 1
Save

The height of a square base right prism is 15 cm. If the total surface area of the prism is 608 cm2, then what will be the volume of the prism?

Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 1
Let the side of the square base be ‘a’.

Now, total surface area = Perimeter of square base × Height

+ 2 × Area of square base.

⇒ 608 = 4a × 15 + 2 × a2 ⇒ a2 + 30a –304 = 0 ⇒ a = 8

∴Volume of prism = Area of base × Height

= a2 × 15 = 8 × 8 × 15 = 960 cm3

RRB JE ECE (CBT I) Mock Test- 9 - Question 2
Save

If the angles of a pentagon are in the ratio 1 : 3 : 6 : 7 : 10, then the smallest angle is:

Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 2
Suppose the angles of a pentagon are

x°, 3x°, 6x°, 7x°, 10x°

But x° + 3x° + 6x° + 7x° + 10x° = (2x5 -4) x 90°

or 27x° = 6 x 90°

or x = 20°

1 Crore+ students have signed up on EduRev. Have you? Download the App
RRB JE ECE (CBT I) Mock Test- 9 - Question 3
Save

What will be the value of x in the infinite series

Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 3

Or x2 = 6 + x

Or x2 - x 6 = 0

Or (x-3) (x+2) = 0

∴ x = 3

RRB JE ECE (CBT I) Mock Test- 9 - Question 4
Save

If a (tanθ + cotθ) = 1, sinθ + cosθ = b with 0° < θ < 90°, then the relation between a and b is:
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 4

a (tanθ + cotθ) = 1[Given]

sinθ + cosθ = b[Given]

a = sinθ cosθ.................(i)

Also, sinθ + cosθ = b

Squaring both sides,

sin2θ + cos2θ + 2sinθ cosθ = b2

1 + 2 a = b2 ⇒ 2a = b2 – 1[From ⇒ equ. (i)]

RRB JE ECE (CBT I) Mock Test- 9 - Question 5
Save

The driver of an ambulance sees a school bus 40 meters ahead of him. After 20 seconds, the school bus is 60 meters behind. If the speed of the ambulance is 30 km/hr, then what is the speed of the school bus?
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 5
Relative Speed,

= (Total.distance/Total.time)

=60+40/20

= 5 m/s =5×18/5 = 18 kmph

Relative Speed = (speed of ambulance - speed of school bus)

Speed of school bus = speed of ambulance - relative speed.

= 30-18 = 12 kmph.

RRB JE ECE (CBT I) Mock Test- 9 - Question 6
Save

At what percent above the cost price must an article be marked so that the seller gains 33% after allowing the customer a discount of 5% ?
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 6
Let the marked price be ₹x

Let the Cost price be ₹y

Selling Price = x - 5% of x

x = 95x/100 = 19x/20

y + 33% of y = 19x/20

7y = 5x

x = 7/5 y = y + 2/5 y = y + 40% of y

RRB JE ECE (CBT I) Mock Test- 9 - Question 7
Save

If (x11+1) is divided by (x+1), then the remainder is :
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 7

p(x) = x11 +1

Divisor = x+1

∴ Remainder = p(−1)=(−1)11 +1= −1 + 1 = 0

RRB JE ECE (CBT I) Mock Test- 9 - Question 8
Save

Evaluate : cos80o/sin10o + cos 59o cosec 31o
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 8

RRB JE ECE (CBT I) Mock Test- 9 - Question 9
Save

The measurement of each angle of a polygon is 160°. The number of its sides is:
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 9
Let n be the sides of the polygon

or 16n = (2n - 4) x 9

or 16n = 18n - 36

2n = 36 ⇒ n = 18

∴ the number of sides of polygon are 18.

RRB JE ECE (CBT I) Mock Test- 9 - Question 10
Save

Two towers of the same height stand on opposite sides of a road 100 m wide. At a point on the road between the towers, the elevations of the towers are 30° and 45°. Find the height of the towers and the position of the point from the farthest tower.
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 10

Let AB, CD are towers

E is the point between road BC.

Then in △DCE

CD = EC = X = AB

IN △ABE

BE= √3x then

Position of the farthest tower from point = 63.4 mtr.

RRB JE ECE (CBT I) Mock Test- 9 - Question 11
Save

If (a/b)x−1 = (b/a)x−3 ,then the value of x is:
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 11

(a/b)x−1 = (b/a)x−3 = (a/b)−(x−3) = (a/b)3−x

∴ x - 1 = 3 - x or 2x = 4

∴ x = 2

RRB JE ECE (CBT I) Mock Test- 9 - Question 12
Save

If the perimeter of an equilateral triangle is 36.9 metre and the length of an altitude is 8 metre, then the area of the triangle is:
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 12
Perimeter of the equilateral triangle of side x = 36.9 m

∴ side of equilateral triangle x = 36.9/3 = 12.3 m

height = 8

hence area = 1/2×12.3×8 = 49.2 m2

RRB JE ECE (CBT I) Mock Test- 9 - Question 13
Save

In what ratio Martina should mix two varieties of juice worth Rs. 52 per liter and Rs. 74 per liter, so that by selling the mixture at Rs.71.28 per liter she can earn a profit of 8%?
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 13

RRB JE ECE (CBT I) Mock Test- 9 - Question 14
Save

40% of the students in a school are girls. If the number of boys is 1680, then what is the total number of students?
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 14

% of boys = 100 – 40 = 60%

60% of x = 1680

x = (1680 × 100)/60

x = 2800

RRB JE ECE (CBT I) Mock Test- 9 - Question 15
Save

Prem invested a certain sum of money in a simple interest. It amounts to Rs 300 at the end of 3 years and to Rs 400 at the end of 8 year. What was the rate of interest in which he invested his sum?
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 15

Let principal be P and rate of interest be r%

At the end of another 5 years means 3 + 5 = 8 Years.

On subtracting Eq. (i) from Eq. (ii)

∴ p x r = 2,000

240 x r = 2000

r = 8.33%

RRB JE ECE (CBT I) Mock Test- 9 - Question 16
Save

10 men can complete a work in 8 days. 20 women can complete the same work in 6 days. In how many days 16 men and 18 women can complete the same work, working together ?
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 16

10m → 8 days ⇒ 20m → 4 days ⇒ 1m → 80 days

20w → 6 days ⇒ 20w → 6 days ⇒ 1w → 120 days

∴ 2m = 3w

Thus, 16m + 18w = 24w + 18w = 42w

20w x 6 = 42w x

(Where x is the number of days taken by 42 women)

∴ x = 20/7 days ⇒ 2(6/7) days

RRB JE ECE (CBT I) Mock Test- 9 - Question 17
Save

461 + 462 + 463 + 464 + 465 is divisible by:
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 17

461 [1+4+42+43+44] = 461 [1+4+ 16 + 64 +256] = 461 x 341

Since 341 is divisible by 11, then the given expression is also divisible by 11.

RRB JE ECE (CBT I) Mock Test- 9 - Question 18
Save

A cane contains a mixture of two liquids 'A' and 'B' in the ratio 7 : 5. When 9 liters of mixture are drawn off and the cane is filled with 'B', the ratio of 'A' and 'B' becomes 7 : 9 liters. Liter of Liquid 'A' contained by the cane initially was?
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 18

According to the question

4 units = 9 litres

1 unit = 9/4 litres

12 units = 94×12 = 27 litres

Initially solution was = 27+9 = 36litres

Quantity of liquid 'A' initially = ‘712×36 = 21 litres

RRB JE ECE (CBT I) Mock Test- 9 - Question 19
Save

DIRECTIONS: DIRECTIONS: Study the following graph carefully and answer the questions that follow:

No. of students appearing for aptitude test from various cities (in thousands).

What is the average number of students appearing for aptitude tests from all the cities together?
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 19

(30 + 22.5 + 37.5 + 17.5 + 32.5)/5 = 28

RRB JE ECE (CBT I) Mock Test- 9 - Question 20
Save

DIRECTIONS: DIRECTIONS: Study the following graph carefully and answer the questions that follow:

No. of students appearing for aptitude test from various cities (in thousands).

What is the ratio of the number of students appearing for the aptitude test for city B to that of city A?
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 20

22.5 : 30

3 : 4

RRB JE ECE (CBT I) Mock Test- 9 - Question 21
Save

DIRECTIONS: DIRECTIONS: Study the following graph carefully and answer the questions that follow:

No. of students appearing for aptitude test from various cities (in thousands).

The number of students appearing for the aptitude test from city D is approximately what percentage of the number of students appearing for the aptitude test from city C?
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 21

17.5×100/37.5 = 47%

RRB JE ECE (CBT I) Mock Test- 9 - Question 22
Save

DIRECTIONS: DIRECTIONS: Study the following graph carefully and answer the questions that follow:

No. of students appearing for aptitude test from various cities (in thousands).
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 22

55 : 80

= 11 : 16

RRB JE ECE (CBT I) Mock Test- 9 - Question 23
Save

The batting average of a batsman in 57 innings is 58 runs. He was out for a duck in 7 innings. His batting average for remaining innings is :
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 23
Total runs of 57 innings = 57 x 58

∴ Average of remaining (57-7) or 50 innings

= 57×58/50 = 66.12

RRB JE ECE (CBT I) Mock Test- 9 - Question 24
Save

If sin(x+y)/sin(x−y) = a+b/a−b , then the value of tan x/tan y is:
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 24

RRB JE ECE (CBT I) Mock Test- 9 - Question 25
Save

A and B can do a piece of work in 15 days. B and C can do the same work in 12 days and C and A in 10 days. How many days will A take to complete the work alone?
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 25

Thus, A completes 2.5 unit work in a day.

Thus, total time required by A = 60/25 = 24 days.

RRB JE ECE (CBT I) Mock Test- 9 - Question 26
Save

If 2 men and 3 women can do a piece of work in 8 days and 3 men and 2 women in 7 days. In how many days can the work be done by 5 men and 4 women working together?
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 26

|2 x 8 - 3 x 7| men’s work = |3x 8 - 2 x 7| women’s work.

∴ 5 men’s work = 10 women’s work

∴ 1 men’s work = 2 women’s work

2 men’s work = 4 women’s work

∴ Days taken by 5 men + 4 women = 14 women are 7x8/14 = 4 days

RRB JE ECE (CBT I) Mock Test- 9 - Question 27
Save

If a and b are two distinct positive numbers, then which of the following is true?
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 27

Let α = 16 & b = 9

Option (α) : LHS =

Hence, option (α) is wrong.

Option (α) : LHS =

Hence, option (b) is wrong.

RRB JE ECE (CBT I) Mock Test- 9 - Question 28
Save

5 year ago, the father’s age was 3 times his son’s age. 5 years hence the ratio between the ages of the father and the son becomes 11: 5. Find the father’s present age.
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 28

Father Son

Old ratio 3 : 1

New ratio 11 : 5

Let, 5 years age father’s age was 3x years, where

x=(5+5)×(11−5)/3×5−1×11 =10×6/4 =15

∴ Father’s age (5 years ago) = 3 × 15 = 45 years

∴ His present age = 45 + 5 = 50 years

RRB JE ECE (CBT I) Mock Test- 9 - Question 29
Save

P and Q starting simultaneously from two different places proceed towards each other at a speed of 20 km/hour and 30 km/hour respectively. By the time they meet each other, Q has covered 36 km more than P. The distance (in k.m.) between the two places is:
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 29
Let the distance = x km

Let them meet when P travels y km.

then, Q travels in the same time x – y km

from question,

(x – y) – y = 36

x – 2y = 36 .......(i)

Also, 20 × y = 30 (x–y) [∵Time is same]

∴y/x−y−=3/2

2y = 3x – 3y

5y = 3x ........(ii)

Putting the value of y from (ii) to (i),

x−6x/5=36⇒−x/5=36⇒x=180 km

RRB JE ECE (CBT I) Mock Test- 9 - Question 30
Save

A man walks from A to B at the rate of 5 km per hour and returns back at the rate of 3 kmph. What is the average speed for the whole journey ?
Detailed Solution for RRB JE ECE (CBT I) Mock Test- 9 - Question 30
We know that

Average speed = 2xy / x+y

Here, x= 5 km per hour

y = 3 km per hour

therefore, Average speed = 2*5*3 / 5+3 = 30/8 = 15 kmph.

View more questions
161 tests
Join Course
Information about RRB JE ECE (CBT I) Mock Test- 9 Page
In this test you can find the Exam questions for RRB JE ECE (CBT I) Mock Test- 9 solved & explained in the simplest way possible. Besides giving Questions and answers for RRB JE ECE (CBT I) Mock Test- 9, EduRev gives you an ample number of Online tests for practice

Top Courses for Electronics and Communication Engineering (ECE)

Download as PDF

Top Courses for Electronics and Communication Engineering (ECE)

Important Questions for RRB JE ECE (CBT I) Mock Test- 9

Find all the important questions for RRB JE ECE (CBT I) Mock Test- 9 at EduRev.Get fully prepared for RRB JE ECE (CBT I) Mock Test- 9 with EduRev's comprehensive question bank and test resources. Our platform offers a diverse range of question papers covering various topics within the RRB JE ECE (CBT I) Mock Test- 9 syllabus. Whether you need to review specific subjects or assess your overall readiness, EduRev has you covered. The questions are designed to challenge you and help you gain confidence in tackling the actual exam. Maximize your chances of success by utilizing EduRev's extensive collection of RRB JE ECE (CBT I) Mock Test- 9 resources.

RRB JE ECE (CBT I) Mock Test- 9 MCQs with Answers

Prepare for the RRB JE ECE (CBT I) Mock Test- 9 within the Electronics and Communication Engineering (ECE) exam with comprehensive MCQs and answers at EduRev. Our platform offers a wide range of practice papers, question papers, and mock tests to familiarize you with the exam pattern and syllabus. Access the best books, study materials, and notes curated by toppers to enhance your preparation. Stay updated with the exam date and receive expert preparation tips and paper analysis. Visit EduRev's official website today and access a wealth of videos and coaching resources to excel in your exam.

Online Tests for RRB JE ECE (CBT I) Mock Test- 9 RRB JE Mock Test Series for ECE 2025

Practice with a wide array of question papers that follow the exam pattern and syllabus. Our platform offers a user-friendly interface, allowing you to track your progress and identify areas for improvement. Access detailed solutions and explanations for each test to enhance your understanding of concepts. With EduRev's Online Tests, you can build confidence, boost your performance, and ace RRB JE ECE (CBT I) Mock Test- 9 with ease. Join thousands of successful students who have benefited from our trusted online resources.
© EduRev
Education Revolution
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup