SSC GD Constable Mock Test - 1 Free Online Test 2026

In the second image, the arrow rotates 90° clockwise from the previous position.
In the third image, the arrow rotates 180° clockwise from the previous position.
So, in the fourth image, the arrow will rotate by 270° from the previous position. Thus, the arrow will be pointing downwards.
Hence, option A is the correct answer.

Penurious means poor.
Impecunious means lack of money.
Indigent means poor.
Opulent means rich.
Hence, Opulent is the odd one out.

The place values of B and D are 2 and 2² = 4
The place values of E and Y are 5 and 5² = 25
The place values of C and I are 3 and 3² = 9
But the place values of D and U are 4 and 21. Hence, Option B is correct answer.

97 # 56 @ 4 & 6 ! 11 would mean 97 - 56/4 + 6*11 = 97 - 14 + 66 = 149
Hence, option C is right choice.

The arrows in the figure rotate anti clock wise by 90 from quadrant 1 to 4.
So, (?) must have the arrow facing South-East Direction.
Thus, only option A and C are possible.
Now, the first quadrant has 1 dark bar, second has 2, and third has 3. Thus, fourth must have 4 bars.
Among A and C, only C has 4 dark bars. Thus, C is the correct answer.

Dolorous and grief are synonyms. Truculent means to be quick to argue or fight. Thus, aggressive is the synonym of truculent.
Hence, option C is the correct option.

Option A is the mirror image of “RSEURRECT”
Option B is the mirror image of “RESRURECT”
Option C is the mirror image of “RESURRCET”
Thus these three options can be eliminated.
Option D is the mirror image of “RESURRECT” and is thus the answer.

1 ⇒ 4 ⇒ 9 ⇒ 16
Sixteenth letter from O will be E. Hence, option B is the correct answer.

The area common to the circle and triangle but not common to the square represents the police sportsperson who did not represent the country in the Olympics.
The number of such persons is 6. Therefore, option A is the right answer.

Consider following possibility as shown in the diagram:

Thus, I follows and II does not necessarily follow.
Hence, option A is the right answer.

In the coded word, the letters at the odd positions are replaced by the letters which follow them in the english alphabets.
For example: B is coded as C, E is coded as F and K is coded as L.
The letters at even positions are replaced by letters which precede them. For ex: R is coded as Q and A is coded as Z.
Using the same logic, we get
Q should be coded as R, U should be coded as T, I should be coded as J, T should be coded as S and E should be coded as F.
Hence, the required code word will be RTJSF. Hence, option C is correct.

In the given series the first three letters are +2 of the previous pair in every next pair and the last letter is the vowel in ascending order.
Hence, 'XVVU' is the correct answer.

The family tree will be like this:-

It is given that Raina's mother is the only daughter of Mohini's father means Mohini is Raina's mother then Mohini's husband will be Raina's father.
Hence, option (1) is the correct answer.

The paper will appear as the figure given in option (1) when it is unfolded.

Hence, option (1) is the correct answer.

As, A dozen is a group of Twelve items.
Similarly, a score is a group of twenty items.
Thus, Twenty is related to Score in the same way as the second word is related to the first word.
Hence, option (1) is the correct answer.

According to the arrangement in the alphabetical order, ‘Minimalist’ will come in the middle.
E:  Mandamus
A: Manipulate
B: Minimalist
D: Ministerial
C: Minority

Hence, 'FMN' is the correct answer.

From the given dice,
Only A and C follow the given condition.
Hence, option(1) is the correct answer.

Let the length of each of the square = x
Average speed = total distance travelled/total time taken
= 4x/(x/100 + x/50 + x/150 + x/200) = 4/(25/600) = 24 ∗ 4 = 96 km/hr.

So the answer is option B.

Let us assume the cost price of 1 litre of milk to be Rs.10. Therefore, the selling price will be Rs. 11.
Let us assume that the milkman buys 5 litres of milk and then adds 1 litre of water.
Cost of procuring milk = 5*10 = Rs. 50
Net revenue = 6*11 = Rs. 66
Profit = 66 - 50 = Rs. 16
Profit percentage = (16/50)*100 = 32%.
Therefore, option B is the right answer.

Production cost for 1 ton of fertilizers = 20000
Production cost for 200 ton of fertilizers = 20000*200 = 4000000
Expenditure incurred on labour costs = 25 % = 4000000*.25 = 1000000
If the labour wages are increased by 20 percent then new labour costs will be= 1000000*.1.2 = 1200000
So per head salary will be 1200000/200 = 6000

Sum of all 57 numbers = 57*26 = 1482.
After adding the new number, the total number count will be = 57 + 1 = 58.
We want the average to go up by 1. Therefore, the new average is 26 +1 = 27.
Sum of all the numbers including the newly added number = 58 * 27 = 1566.
Hence, the newly added number will be 1566 - 1482 = 84.
Therefore, option D is the right answer.

Let the money received by A, B and C be a, b and c respectively.
We have, a+b+c=7550
We are given that b=2.4c therefore a = (2/3) × 2.4c = 1.6c
Therefore,
⇒ 1.1.6c+2.4c+c=7550
⇒ 5c = 7550
⇒ c = 1510
Therefore total prize money received by A and B together = 1.6c + 2.4c = 4*1510 = Rs. 6040
Hence we can say that option D is the correct answer.

p : q = 12 : 7 and a : b = 3p : 4q
So, a : b = 12*3 : 4*7 = 9 : 7
Now (ap​/bq) = (9∗12​)/(7∗7) = 108/49
Hence, option C is the right answer.

Let the amount lent by Chandan be Rs. x

Subtracting (1) from (2)

Plugging (3) in (1)
x+(4×50) = 720
⇒ x = 520
Hence, Option C is correct.

(1-0.13)(1-0.25)(X) = 2610
(0.87)(0.75)(X) = 2610
(0.6525)(X) = 2610
X = 4000
So the answer is option D.

The given numbers are
A. 2^(1/6)​ B. 3^(1/9)​ C. 4^(1/12)​ D. 5^(1/18)
The denominators of the powers are 6, 9, 12 and 18.
Let’s raise their powers to 36 (their LCM) to convert their exponents to integers.
The numbers then will be,
A. 64, B. 81, C. 64, D. 25
Hence, B is the largest.