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SSC Stenographer Practice Test - 10 - SSC Stenographer MCQ


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30 Questions MCQ Test SSC Stenographer Mock Test Series 2024 - SSC Stenographer Practice Test - 10

SSC Stenographer Practice Test - 10 for SSC Stenographer 2024 is part of SSC Stenographer Mock Test Series 2024 preparation. The SSC Stenographer Practice Test - 10 questions and answers have been prepared according to the SSC Stenographer exam syllabus.The SSC Stenographer Practice Test - 10 MCQs are made for SSC Stenographer 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for SSC Stenographer Practice Test - 10 below.
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SSC Stenographer Practice Test - 10 - Question 1

A boy facing north turns 60’ in clockwise direction and then turns 150’ in anti clockwise. In which direction now he is facing.

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 1

SSC Stenographer Practice Test - 10 - Question 2

Akshey starts from his school facing West and walks 50 m straight. He then takes a right and walks 50 m. Further, he takes a left turn and walks 20 m. In which direction is Akshey now from the starting point?

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 2

Akshey is now in the North–West direction.

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SSC Stenographer Practice Test - 10 - Question 3

 

Which one will replace the question mark ?

 

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 3

3 x 5 x 4 = 60

and 5 x 7 x 4 = 140

Therefore, 4 x 4 x ? = 96

? = (96/16) = 6.

SSC Stenographer Practice Test - 10 - Question 4

 

Which one will replace the question mark ?

 

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 4

(5 x 6) + 2 = 32

(7 x 6) + 2 = 44

(7 x 5) + 2 = 37.

SSC Stenographer Practice Test - 10 - Question 5

Which one will replace the question mark ?

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 5

Sum of numbers in lower half of the circle = 11 + 9 + 3 + 7 = 30

Sum of numbers in upper half of the circle = ? + 4 + 5 + 6 = ? + 15

Upper half = Lower half

30 = ? + 15

? = 30 - 15

? = 15.

Threfore, 15 is the answer.

 

SSC Stenographer Practice Test - 10 - Question 6

Which one will replace the question mark ?

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 6

 

How the number is obtained?

 

2 + 4 = 6

5 + 9 = 14

Similarly,

3 + 5 = 8

Therefore, the answer is K8.

SSC Stenographer Practice Test - 10 - Question 7

(A) Whether you make progress or not, the clock is ticking. So you might as well make the full utilization of the available time. 
(B) High usage of electricity during festive time in the urban areas leads to perennial shortage of electricity in the rural areas 
(C) Is not it ironical that in our country, we have to look both ways to cross a one-way road?. 
(D) The Theseus’ paradox is a thought experiment that raises the question of whether an object which has had all its components replaced remains fundamentally the same object.

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 7

J – This author has stated his opinion.
I – ‘High usage of electricity’ is the fact from which ‘perennial shortage of electricity in the rural areas’ is inferred.
J – The irony of this situation is the opinion of the author.
F – This is a verifiable fact.

SSC Stenographer Practice Test - 10 - Question 8

A clock is so placed that at 12 noon, its minute hand points towards Northeast. In which of the following directions does its hour hand point at 1.30 pm?

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 8


Clearly, Hour hand will point in East direction at 1.30 pm.

SSC Stenographer Practice Test - 10 - Question 9

At what time between 7 o'clock and 8 o'clock will the hands of a clock be in a straight line but not together?

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 9

Using formula: 

SSC Stenographer Practice Test - 10 - Question 10

A tutor teaches 8 days consecutively and then takes off on the ninth day. If he starts teaching on Monday, then on what day of the week will he get his 12th off day?  

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 10

He teaches for 8 consecutive days and takes an off on the 9th day.
For each off day, 8 teaching days + 1 off day = 9 days passed
So, on the 12th off day, there are 9 x 12 = 108 days passed
We have to find the day of the week on 12th off day.
So, we have to deduct a day.
Number of odd days = (108 - 1)/7 = 107/7 = 2
He started teaching on Monday.
So, the 12th off day is Monday + 2 = Wednesday

SSC Stenographer Practice Test - 10 - Question 11

An antique grandfather's clock, which gains uniformly, is 10 minutes slow at 9:00 a.m. in the morning on Monday and 10 minutes 48 seconds fast at 9:00 p.m. on the following Monday. When was it correct?  

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 11

From 9:00 a.m. Monday to 9:00 p.m. on the following Monday, total hours = 24  7 + 12 = 180 hours
The clock has gained in 180 hours
minutes in 180 hours
To gainminutes, the clock needs 180 hours.
To gain 10 minutes, the clock needs

= 3 days 14.53 hours
= 3 days 14 hours 32 minutes (approx.)
Thus, the clock will be correct after 3 days 14 hours 32 minutes from Monday morning.
i.e. 11:32 p.m. Thursday

SSC Stenographer Practice Test - 10 - Question 12

Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

Question -

Country : President :: State : ?

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 12

As President is the nominal head of a country, similarly Governer is the nominal head of a State.

SSC Stenographer Practice Test - 10 - Question 13

Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

Question -

ZRYQ : KCJB :: PWOV : ?

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 13

SSC Stenographer Practice Test - 10 - Question 14

Directions to Solve
In each of the following questions find out the alternative which will replace the question mark.
Question -
ACEG : ? :: BDFH : KMOQ

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 14

SSC Stenographer Practice Test - 10 - Question 15

Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

Question -

Eye : Myopia :: Teeth : ?

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 15

The given analogy is:

Eye : Myopia

Here, "Myopia" is a condition affecting the eyes.

Now, we need to find a condition that affects the teeth:

Teeth : ?

Let's consider the options:

  1. Pyorrhoea - This is a condition that affects the teeth and gums.
  2. Cataract - This is a condition that affects the eye.
  3. Trachoma - This is a condition that affects the eye.
  4. Eczema - This is a condition that affects the skin.

The correct condition affecting the teeth is:

1. Pyorrhoea

SSC Stenographer Practice Test - 10 - Question 16

Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

Question -

3 : 12 :: 5 : ?

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 16

SSC Stenographer Practice Test - 10 - Question 17

Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

Question -

In this pyramid number if: 11 22 31 : 12 21 32 :: 9 12 21 : ?

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 17

If we see diagonally we will get 11 22 31 and the next diagonal series is 12 21 32. Similarly the next diagonal series after 9 12 21 is 8 13 20.

SSC Stenographer Practice Test - 10 - Question 18

Directions to Solve

In each word of the following questions consists of pair of words bearing a relationship among these, from amongst the alternatives, pick up the pair that best illustrate a similar relationship.

Question -

Silence : Noise

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 18

As Silence is opposite to noise, similarly Baldness is opposite to Hair.

SSC Stenographer Practice Test - 10 - Question 19

Directions to Solve

In each word of the following questions consists of pair of words bearing a relationship among these, from amongst the alternatives, pick up the pair that best illustrate a similar relationship.

Question -

Chalk : Blackboard

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 19

As chalk is used to write on the blackboard similarly the Ink is used to write on the paper.

SSC Stenographer Practice Test - 10 - Question 20

Directions to Solve

Each of the following questions has a group. Find out which one of the given alternatives will be another member of the group or of that class.

Question -

Volleyball, Hockey, Football

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 20

Baseball is like volleyball, Hockey and Football.

SSC Stenographer Practice Test - 10 - Question 21

'Ophthalmia' is related to 'Eye' in the same way as 'Rickets' is related to:

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 21

As 'Ophthalmia' is a disease of 'Eye' in the same way 'Rickets' is the disease of 'Bone'.

SSC Stenographer Practice Test - 10 - Question 22

'Forest' is related to 'Vivarium' in the same way as 'sea' is related to:

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 22

As 'Forest' and 'Vivarium' have the same meaning in the same 'Sea' and 'Aquarium' have the same meaning.

SSC Stenographer Practice Test - 10 - Question 23

Find the solution for the pair of solution x > 1 and x > -1

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 23

x > 1 and x > -1
Take two points 1,-1 on number line
Therefore x > 1

SSC Stenographer Practice Test - 10 - Question 24

If 5x+6<2x-3, then

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 24

5x + 6 < 2x - 3
5x - 2x < - 3- 6
⇒ 3x < -9
x < -3

SSC Stenographer Practice Test - 10 - Question 25

A beaker contains 640 litres of 8% solution of Boric acid. This is to be diluted by adding a 2% Boric acid solution to it.

Based on the above data, answer the following question.

Q. The initial amount of acid in the beaker is ........... litres.

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 25

Amount of acid =

= 51.2 litres

SSC Stenographer Practice Test - 10 - Question 26

Given below is an inequality, which of the following condition is TRUE?

If P ≤ Q ≥ R; E ≥ Q; L < Q = D

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 26

Given inequality is: P ≤ Q ≥ R; E ≥ Q; L < Q = D

1. L < P → P ≤ Q, L < Q, data is not sufficient to determine the relation → False

2. E ≥ R → E ≥ Q ≥ R, E ≥ R → True.

3. E < D → E ≥ Q, L < Q = D, E ≥ D → False.

4. Q < R → Q ≥ R → False.

Hence, E ≥ R, is the correct inequality.

SSC Stenographer Practice Test - 10 - Question 27

If a < b, then the solution of x2 - (a + b) x + ab < 0 is

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 27

x2 - (a + b) x + ab < 0
(x - a) (x - b) < 0
a < x < b

SSC Stenographer Practice Test - 10 - Question 28

|x2 – 2x| < x

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 28

At x = 1 and x = 3 LHS = RHS. At x = 2 inequality is satisfied.
At x = 0.1 inequality is not satisfied.
At x = 2.9 inequality is satisfied.
At x = 3.1 inequality is not satisfied.
Thus, option (a) is correct. 

SSC Stenographer Practice Test - 10 - Question 29

How many pairs of natural numbers at (x, y) satisfy the inequality 3x + 5y < 20?  

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 29

(x, y) pairs satisfying the condition are (1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (3, 1), (3, 2) and (4, 1).
So, total 8 pairs are there.

SSC Stenographer Practice Test - 10 - Question 30

If 2y - x > 2x - y, and 0 ≤ y ≤ 20, how many non-negative integer pairs of x and y satisfy the given inequalities?  

Detailed Solution for SSC Stenographer Practice Test - 10 - Question 30

2y - x > 2x - y ⇒ y > x
i.e. y = 0, x < 0 ⇒ No pair exists.
y = 1, x = 0, ⇒ Number of pairs = 1
y = 2, x = 0, 1 ⇒ Number of pairs = 2
y = 3, x = 0, 1, 2 ⇒ Number of pairs = 3



If y = 20, x = 0 to 19 ⇒ Number of pairs
= 20
Total number of pairs = 1 + 2 + 3 + …… + 20 = 210

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