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SSC Stenographer Exam  >  SSC Stenographer Tests  >  SSC Stenographer Mock Test Series 2024  >  SSC Stenographer Practice Test - 7 - SSC Stenographer MCQ

SSC Stenographer Practice Test - 7 - SSC Stenographer MCQ


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30 Questions MCQ Test SSC Stenographer Mock Test Series 2024 - SSC Stenographer Practice Test - 7

SSC Stenographer Practice Test - 7 for SSC Stenographer 2024 is part of SSC Stenographer Mock Test Series 2024 preparation. The SSC Stenographer Practice Test - 7 questions and answers have been prepared according to the SSC Stenographer exam syllabus.The SSC Stenographer Practice Test - 7 MCQs are made for SSC Stenographer 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for SSC Stenographer Practice Test - 7 below.
Solutions of SSC Stenographer Practice Test - 7 questions in English are available as part of our SSC Stenographer Mock Test Series 2024 for SSC Stenographer & SSC Stenographer Practice Test - 7 solutions in Hindi for SSC Stenographer Mock Test Series 2024 course. Download more important topics, notes, lectures and mock test series for SSC Stenographer Exam by signing up for free. Attempt SSC Stenographer Practice Test - 7 | 200 questions in 120 minutes | Mock test for SSC Stenographer preparation | Free important questions MCQ to study SSC Stenographer Mock Test Series 2024 for SSC Stenographer Exam | Download free PDF with solutions
SSC Stenographer Practice Test - 7 - Question 1
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Directions: Study the following information carefully and answer the questions given below:

M, V, K, D, T, J, and R are seven friends studying different classes III, IV, V, VI, VII, VIII, and IX standards. Each of them has different favourite colours-yellow, blue, red, white, black, green, and violet. J likes red and studies in class V. R likes violet and studies in Class III. M studies in Class VIII and does not like either green or yellow. K likes white and does not study either in VII or in IV. D studies in VI and likes black, T does not study in IV. V does not like green.

Q. Who studies in class IX?

Detailed Solution for SSC Stenographer Practice Test - 7 - Question 1

SSC Stenographer Practice Test - 7 - Question 2
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Directions: Study the following information carefully and answer the questions given below:

M, V, K, D, T, J and R are seven friends studying different classes III, IV, V, VI, VII, VIII and IX standards. Each of them has different favourite colours-yellow, blue, red, white, black, green and violet. J likes red and studies in class V. R likes violet and studies in Class III. M studies in Class VIII and does not like either green or yellow. K likes white and does not study either in VII or in IV. D studies in VI and likes black, T does not study in IV. V does not like green.

Q.​ What is M’s favourite colour?

Detailed Solution for SSC Stenographer Practice Test - 7 - Question 2

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SSC Stenographer Practice Test - 7 - Question 3
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Directions: Study the following information carefully and answer the questions given below:

M, V, K, D, T, J and R are seven friends studying different classes III, IV, V, VI, VII, VIII and IX standards. Each of them has different favourite colours-yellow, blue, red, white, black, green and violet. J likes red and studies in class V. R likes violet and studies in Class III. M studies in Class VIII and does not like either green or yellow. K likes white and does not study either in VII or in IV. D studies in VI and likes black, T does not study in IV. V does not like green.

Q.​​ What is V’s favourite colour?

Detailed Solution for SSC Stenographer Practice Test - 7 - Question 3

SSC Stenographer Practice Test - 7 - Question 4
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Directions: Study the following information carefully and answer the questions given below:

M, V, K, D, T, J, and R are seven friends studying different classes III, IV, V, VI, VII, VIII, and IX standards. Each of them has different favourite colours-yellow, blue, red, white, black, green, and violet. J likes red and studies in class V. R likes violet and studies in Class III. M studies in Class VIII and does not like either green or yellow. K likes white and does not study either in VII or in IV. D studies in VI and likes black, T does not study in IV. V does not like green.

Q.​​ In which standard does ‘V’ study?
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 4

SSC Stenographer Practice Test - 7 - Question 5
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Directions: Study the following information carefully and answer the questions given below:

M, T, J, R, D, W and Q are seven friends traveling in three cars – X, Y, and Z with at least two persons in each car. There are three female members among them with at least one in each car. T travels only with her boyfriend Q in car Y. M travels in his car X. D, a male, and W do not travel in car Z. J is not a female member and W is a female.

Q. J travels in which car?
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 5

M-travels in car X
T-+Q as given in Y
J-no female, and travels in Z
R-car X(sequential)
D-car Y
W-female with Z
Q-X
hence correct option is C.

SSC Stenographer Practice Test - 7 - Question 6
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Which one will replace the question mark ?

 
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 6

(5 x 6 x 4)/10 = 12

and (6 x 7 x 5)/10 = 21

Therefore (4 x 8 x 10)/10 = 32.

SSC Stenographer Practice Test - 7 - Question 7
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(A) The 236 run partnership between Sachin and Rahul played a major role in propelling India towards victory. 
(B) Sachin Tendulkar has scored 18426 runs in One Day Internationals (ODIs) and 15921 runs in Tests. 
(C) Sachin Tendulkar is the greatest batsmen ever. 
(D) Though Yuvraj played a major role in helping India grab the inaugural T20 World Cup, India could have won the tournament even without his help.
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 7

I – The ‘236-run partnership’ is a fact whereas ‘major role in propelling . . .’ is an inference.
F – This is a verifiable fact.
J – ‘Greatest batsmen’ is an opinion on which people may agree or disagree. Thus, this is a judgment.
J – ‘India could have won the tournament even without his help’ is only an opinion.

SSC Stenographer Practice Test - 7 - Question 8
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If January 1, 1990 was Monday, then what day of the week will it be on January 1, 1991?
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 8

1990 was not a leap year and had only 1 odd day.
Therefore, January 1, 1991 will be Tuesday.

SSC Stenographer Practice Test - 7 - Question 9
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At what time between 4:15 a.m. and 5:05 a.m. will the angle between the hour hand and the minute hand of a clock be the same as the angle between the hands at 8:45 p.m.?
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 9

Hour hand rotates 360° in 12 hrs, so it rotates 30° in 1 hour.
So, in 1 min, it rotates 0.5°.
Minute hand rotates 6° in 1 min.
So, angle at 8:45 = 0.25 × 30° = 7.5°
At 4:15, angle will be 0.25 × 30° + 30° = 7.5° + 30° = 37.5°
So, 37.5° + 0.5t + 7.5° = 6t
45 = 5.5t

Hence clock makes same angle at 23minutes past 4 o'clock

SSC Stenographer Practice Test - 7 - Question 10
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How many times during a day will the hour hand and the minute hand of a clock be six minutes apart?  
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 10

Note that at 1:00, the minute hand and hour hand are 5 minutes apart from each other. Then, between 1:00 and 2:00, only once, i.e. some time after 1:10, minute hand and hour hand will be 6 minutes apart from each other. Similarly, at 11:00, the minute hand and hour hand are 5 minutes apart from each other. Then, between 11:00 and 12:00, only once, i.e. some time before 11:50, minute hand and hour hand will be 6 minutes apart from each other. It can be observed twice that the hour hand and minute hand are 6 minutes apart from each other. Therefore, the answer is 44 times.

SSC Stenographer Practice Test - 7 - Question 11
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There are clocks A and B. The hands of clock A move normally as clockwise, while in clock B (due to reverse connection), they move anticlockwise. Initially, the two hands of both clocks are at mark showing 12. If after some time, the angle between the directions of two hour hands is 90º (for the first time), then at the same instant, the angle between the directions of minute hand will be
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 11

The angle between the two hour hands after some time is 90°.
As they both start at 12 o'clock, the hour hand of clock A makes 45° and the hour hand of clock B makes 45° from their initial position.
The hour hand of clock A moved 45° from its initial position. Therefore, number of minutes the hour hand makes is 45 × 2 = 90 minutes
In 90 minutes, the minute hand makes an angle of 90 × 6° = 540°
360° is a complete revolution ⇒ 540° = 360° + 180° from its initial position.
As both hands move 180° in either direction, the minute hands of two clocks coincide i.e. the angle between them is zero degree.

SSC Stenographer Practice Test - 7 - Question 12
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Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

Question -

Tree : Forest :: Grass : ?
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 12

As Tree is found in Forest similarly Grass is found in Lawn.

SSC Stenographer Practice Test - 7 - Question 13
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Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

Question -

AZBY : CXDW :: EVFU : ?
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 13

SSC Stenographer Practice Test - 7 - Question 14
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Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

Question -

BLOCKED : YOLXPVW :: ? : OZFMXS
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 14

SSC Stenographer Practice Test - 7 - Question 15
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Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

Question -

Carbon : Diamond :: Corundum : ?
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 15

As Diamond is made of Carbon similarly Ruby is made of Corundum.

SSC Stenographer Practice Test - 7 - Question 16
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Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

Question -

MO : 13 11 :: HJ : ?
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 16

In this analogy, subtract the position number of each alphabet from 26.
M ⇒ 26 - 13 = 13
O ⇒ 26 - 15 = 11
⇒ MO : 13 11
Similarly,
H ⇒ 26 - 8 = 18
J ⇒ 26 - 10 = 16
So, right answer is 18 16

SSC Stenographer Practice Test - 7 - Question 17
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Directions to Solve

In each of the following questions find out the alternative which will replace the question mark.

Question -

8 : 24 :: ? : 32
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 17

24 → 2 x 4 = 8

32 → 3 x 2 = 6

SSC Stenographer Practice Test - 7 - Question 18
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Directions to Solve

In each word of the following questions consists of pair of words bearing a relationship among these, from amongst the alternatives, pick up the pair that best illustrate a similar relationship.

Question -

Lawyer : Court
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 18

As the working field of lawyer is Court, similarly the working field of chemist is laboratory.

SSC Stenographer Practice Test - 7 - Question 19
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Directions to Solve

In each word of the following questions consists of pair of words bearing a relationship among these, from amongst the alternatives, pick up the pair that best illustrate a similar relationship.

Question -

Platform : Train
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 19

First is the place where Second stops.

SSC Stenographer Practice Test - 7 - Question 20
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Directions to Solve

Each of the following questions has a group. Find out which one of the given alternatives will be another member of the group or of that class.

Question -

Lungs, Liver, Kidney
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 20

As Lungs, Liver and Kidney are internal part of the body, in the same way 'heart' is also an internal organ.

SSC Stenographer Practice Test - 7 - Question 21
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Directions to Solve

Each of the following questions has a group. Find out which one of the given alternatives will be another member of the group or of that class.

Question -

Clutch, Brake, Horn
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 21

All these are part of a vehicle.

SSC Stenographer Practice Test - 7 - Question 22
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'Jackal' is related to 'Howl' in the same way as 'Cow' is related to:
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 22

As the sound of 'Jackal' is 'Howl' similarly the sound of 'Cow' is 'Moo'.

SSC Stenographer Practice Test - 7 - Question 23
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By solving inequality 3(a - 6) < 4 + a, answer will be
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 23

Numbers obtained in three throws are 5,3 and 6
Let the number obtained in fourth throw be x
Now, Sum > 20
5 + 3 + 6 + x > 20
14 + x > 20
x > 6(never wins)

SSC Stenographer Practice Test - 7 - Question 24
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The solution to 5x-3<3x+1, when x is an integer, is
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 24

We have 5x−3<3x+1
⇒ 5x − 3 + 3 < 3x + 1 + 3
⇒ 5x < 3x + 4
⇒ 5x − 3 × < 3x + 4 − 3x
⇒ 2x < 4 ⇒ x < 2
 When x is an integer the solutions of the given inequality are {.............,−4,−3,−2,−1,0,1}

SSC Stenographer Practice Test - 7 - Question 25
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A beaker contains 640 litres of 8% solution of Boric acid. This is to be diluted by adding a 2% Boric acid solution to it.

Based on the above data, answer the following question.

Q. If the resulting mixture is to be more than 4% but less than 6% boric acid, then the range of x is ..........
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 25

4(640 + x) ≤ 8 × 640 + 2x ≤ 6(640 + x)

2560 + 4x ≤ 5120 + 2x ≤ 3840 + 6x

2560 + 4x ≤ 5120 + 2x

⇒ 2x ≤ 2560

⇒ x ≤ 1280 ...(i)

5120 + 2x ≤ 3840 + 6x

⇒ – 4x ≤ –1280

⇒ 320 ≤ x ...(ii)

From (i) and (ii),

320 ≤ x ≤ 1280

SSC Stenographer Practice Test - 7 - Question 26
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Given below is an inequality, which of the following condition is TRUE?

If A > B > C > D = F ≥ G < H
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 26

From the given conditions, A > B > C > D = F ≥ G < H.

1. G > C → C > D = F ≥ G, C > G → False.

2. B > F → B > C > D = F, B > F → True.

3. G > F → D = F ≥ G < H, F ≥ G → False.

4. D < G → D = F ≥ G, D ≥ G → False.

So, B > F is the correct inequality.

SSC Stenographer Practice Test - 7 - Question 27
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The number of solutions of the equation |x2 - 4| = 4 + x2 is
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 27

|x2 - 4| = 4 + x2
Case I: If x2 - 4 ≥ 0
i.e. x ≤ -2 and x ≥ 2
Then, |x2 - 4| = x2 - 4
⇒ The given equation becomes x2 - 4 = 4 + x2.
⇒ -4 = 4; which is not possible.
Case II: If x2 - 4 < 0
⇒ -2 < x < 2
Then, |x2 - 4| = - (x2 - 4)
Thus, the given equation becomes - (x2 - 4) = 4 + x2.
Or 2x2 = 0
⇒ x = 0
Hence, the given equation has only one solution.

SSC Stenographer Practice Test - 7 - Question 28
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x2 – 3x + 5 > 0
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 28

The given quadratic equation has imaginary roots and is hence always positive.
Thus, option (d) is correct 

SSC Stenographer Practice Test - 7 - Question 29
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If f(x) = x3 - 4x + p and f(0) and f(1) have opposite signs, then which of the following is necessarily true?
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 29

f(0) = p and f(1) = p - 3
Since f(0) and f(1) have opposite signs, so if p < 0, then p - 3 > 0, i.e. p > 3, which is not possible.
Or, p > 0 and p - 3 < 0
⇒ p < 3
⇒ 0 < p < 3
Hence, answer option 2 is correct.

SSC Stenographer Practice Test - 7 - Question 30
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It is given that m and n are two real numbers. Which of the following is true for all possible values of m and n?  
Detailed Solution for SSC Stenographer Practice Test - 7 - Question 30

(m - n)2 + (m - 1)2 + (n - 1)2 ≥ 0 [Any square is always non-negative]
⇒ m2 - 2mn + n2 + m2 - 2m + 1 + n2 - 2n + 1 ≥ 0
⇒ 2m2 + 2n2 + 2 ≥ 2mn + 2m + 2n
⇒ m2 + n2 + 1 ≥ mn + m + n {Dividing both sides by 2}

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