Class 10 Exam  >  Class 10 Tests  >  Olympiad Preparation for Class 10  >  Science Olympiad Test: Periodic Classification of Elements- 2 - Class 10 MCQ

Science Olympiad Test: Periodic Classification of Elements- 2 - Class 10 MCQ


Test Description

15 Questions MCQ Test Olympiad Preparation for Class 10 - Science Olympiad Test: Periodic Classification of Elements- 2

Science Olympiad Test: Periodic Classification of Elements- 2 for Class 10 2024 is part of Olympiad Preparation for Class 10 preparation. The Science Olympiad Test: Periodic Classification of Elements- 2 questions and answers have been prepared according to the Class 10 exam syllabus.The Science Olympiad Test: Periodic Classification of Elements- 2 MCQs are made for Class 10 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Science Olympiad Test: Periodic Classification of Elements- 2 below.
Solutions of Science Olympiad Test: Periodic Classification of Elements- 2 questions in English are available as part of our Olympiad Preparation for Class 10 for Class 10 & Science Olympiad Test: Periodic Classification of Elements- 2 solutions in Hindi for Olympiad Preparation for Class 10 course. Download more important topics, notes, lectures and mock test series for Class 10 Exam by signing up for free. Attempt Science Olympiad Test: Periodic Classification of Elements- 2 | 15 questions in 15 minutes | Mock test for Class 10 preparation | Free important questions MCQ to study Olympiad Preparation for Class 10 for Class 10 Exam | Download free PDF with solutions
Science Olympiad Test: Periodic Classification of Elements- 2 - Question 1

The element with atomic number 14 is hard and forms acidic oxide and a covalent halide. To which of the following categories does the element belong?

Detailed Solution for Science Olympiad Test: Periodic Classification of Elements- 2 - Question 1

Since the element with atomic number 14 i.e., Si forms an acidic oxide and a covalent halide, it must be metalloid.

Science Olympiad Test: Periodic Classification of Elements- 2 - Question 2

What type of oxide would Eka-aluminium form?

Detailed Solution for Science Olympiad Test: Periodic Classification of Elements- 2 - Question 2

Eka-aluminium i.e ., gallium lies in group III of the Mendeleev’s periodic table. Therefore, it has a valency of 3 and forms on oxide having molecular formula E2O3.

1 Crore+ students have signed up on EduRev. Have you? Download the App
Science Olympiad Test: Periodic Classification of Elements- 2 - Question 3

Which of the following does not increase while moving down the group of the periodic table?

Detailed Solution for Science Olympiad Test: Periodic Classification of Elements- 2 - Question 3

In a group valency of all elements is fixed because of having the same outer shell electronic configuration while all the remaining three properties increase down the group.

Science Olympiad Test: Periodic Classification of Elements- 2 - Question 4

Which of the following elements will form an acidic oxide?

Detailed Solution for Science Olympiad Test: Periodic Classification of Elements- 2 - Question 4

Element with atomic number 7 has electron configuration 2, 5 which means it can gain 3 electrons and is an electronegative element. It should be a non-metal and non-metals will form acidic oxide.

Science Olympiad Test: Periodic Classification of Elements- 2 - Question 5

Arrange the following elements in the order of the their increasing non-metallic character Li, O, C, Be, F

Detailed Solution for Science Olympiad Test: Periodic Classification of Elements- 2 - Question 5

The non-metallic character is the tendency of an element to accept electrons and form negative ions or anions. Chlorine and oxygen are the most electronegative elements.

  • Li is on the left of in the 2nd period of the modern periodic table followed by beryllium.
  • Fluorine is right next to Neon.
  • Fluorine shows maximum non-metallic characters followed by Oxygen, Berrylium, carbon and Lithium.
Science Olympiad Test: Periodic Classification of Elements- 2 - Question 6

Elements A, B and C Constitute a Dobereiner’s triad. If the atomic mass of element A is 7 and that of element C is 39, then what is the atomic mass of element B?

Detailed Solution for Science Olympiad Test: Periodic Classification of Elements- 2 - Question 6

A, B and C are the elements of a Dobereiner's triad. If the atomic masses of A and C are 7 and 39 respectively, then according to Dobereiner's triad law, the atomic mass of B is the average of the atomic masses of A and C.
So, the average of the atomic masses of A and C 

Therefore, the atomic mass of B is 23.

Science Olympiad Test: Periodic Classification of Elements- 2 - Question 7

X and Y are two elements having similar properties which obey Newland’s Law of Octaves. The minimum and maximum number of elements in between X and Y, respectively are

Detailed Solution for Science Olympiad Test: Periodic Classification of Elements- 2 - Question 7

X and Y are two elements having similar properties which obey Newlands’s Law of Octaves. The minimum and maximum number of elements in between X and Y respectively are 6 and 8.

Science Olympiad Test: Periodic Classification of Elements- 2 - Question 8

The two elements for which Mendeleev left blank places in his original periodic table were

Detailed Solution for Science Olympiad Test: Periodic Classification of Elements- 2 - Question 8
  • Though only 63, elements were known at the time when Mendeleev started his work, he left some places vacant for elements to be discovered later.
  • While developing his Periodic Table of the elements,he named aka-Aluminum to the element just below of Aluminium.
  • Mendeleev gave the name eka-Aluminium to a compound which contains aluminium, a mixture of aluminium and an unknown element.
  • The unknown element he predicted would have properties similar to those of aluminium and which have rare isotope of aluminium.
  • It was later discovered as Gallium with an atomic weight of 68 and atomic number of 31.
  • Germanium was named as Aka-Silicon first and was later discovered.
  • Germanium has atomic number 32 and an atomic weight of 72.

Hence, Mendeleev left the gaps for the elements with predicted atomic weight 68 & 72 respectively are discovered later as Gallium & Germanium.

Science Olympiad Test: Periodic Classification of Elements- 2 - Question 9

Which of the following statement(s) about the modern periodic table are incorrect
(i) The elements in the modern periodic table are arranged on the basis of their decreasing atomic number.
(ii) Isotopes are placed in adjoining group(s) in the periodic table
(iii) The elements in the modern period table are arranged on the basis of their increasing atomic masses.
(iv) The elements in the modern periodic table are arranged on the basis of their increasing atomic number.

Detailed Solution for Science Olympiad Test: Periodic Classification of Elements- 2 - Question 9

Elements in the Modern Periodic Table are arranged based on their increasing atomic number hence option (i) is wrong. In the modern periodic table atomic mass is not a criteria hence option (ii) is wrong. Isotopes are given the same position in the periodic table hence option (iii) is wrong.

Science Olympiad Test: Periodic Classification of Elements- 2 - Question 10

The elements A, B, C, D and E have atomic number 9, 11, 17, 12 and 13 respectively. Which pair of elements belong to the same group?

Detailed Solution for Science Olympiad Test: Periodic Classification of Elements- 2 - Question 10

Let us take a look at the electronic configurations of the given elements, 
A: (2, 7)
B: (2, 8, 1) 
C: (2, 8, 7)
D: (2, 8, 2)
E: (2, 8, 3)
We can see that elements A and C both have 7 valence electrons. Thus, both the elements belong to the same group.
So, the correct option is A.

Science Olympiad Test: Periodic Classification of Elements- 2 - Question 11

Which of the following statements about the modern period table is correct?

Detailed Solution for Science Olympiad Test: Periodic Classification of Elements- 2 - Question 11

A tabular arrangement of elements in groups and periods that highlights the regular trends in properties of elements is defined as the periodic table.

  • The modern periodic table has 18 groups and 7 periods. Columns are called groups and rows are called periods.
  • Modern periodic law states that the properties of elements are dependent on their atomic numbers and elements show similar properties at regular intervals of increasing atomic numbers.
Science Olympiad Test: Periodic Classification of Elements- 2 - Question 12

Which one of the following elements exhibit maximum number of valence electrons?

Detailed Solution for Science Olympiad Test: Periodic Classification of Elements- 2 - Question 12
  • Electronic configuration of Na, Al, Si and P are 2, 8 1, 2, 8, 3, 2, 8, 4, and 2, 8, 5 respectively. 
  • Valence electrons in Na, Al, Si and P are 1,3,4 and 5.
  • Hence phosphorus has maximum number of valence electrons.
Science Olympiad Test: Periodic Classification of Elements- 2 - Question 13

Which of the following gives the correct increasing order of the atomic radii of O, F and N?

Detailed Solution for Science Olympiad Test: Periodic Classification of Elements- 2 - Question 13

Atomic radius decreases across a period because nuclear charges increase across a period. When the charge increases, the electrons are pulled towards the nucleus with greater force decreasing the size of the atomic radius. Hence Fluorine has the least radius as its atomic number is larger than oxygen and nitrogen. The same case is with oxygen, it has more number of positive charges than nitrogen. Hence nitrogen has the largest size than oxygen and then fluorine.

Science Olympiad Test: Periodic Classification of Elements- 2 - Question 14

Which of the following are the characteristics of isotopes of an element?
(i) Isotopes of an element have same atomic masses
(ii) Isotopes of an element have same atomic number
(iii) Isotopes of an element show same chemical properties
(iv) Isotopes of an element show same physical properties

Detailed Solution for Science Olympiad Test: Periodic Classification of Elements- 2 - Question 14

Isotopes of an element have same atomic number but different atomic masses. They show same chemical properties but different physical properties.

Science Olympiad Test: Periodic Classification of Elements- 2 - Question 15

Three elements B, Si and Ge are

Detailed Solution for Science Olympiad Test: Periodic Classification of Elements- 2 - Question 15

The metalloids; boron (B), silicon (Si), germanium (Ge), arsenic (As), antimony (Sb), tellurium (Te), polonium (Po) and astatine (At) are the elements found along the step like line between metals and non-metals of the periodic table.

13 videos|44 docs|187 tests
Information about Science Olympiad Test: Periodic Classification of Elements- 2 Page
In this test you can find the Exam questions for Science Olympiad Test: Periodic Classification of Elements- 2 solved & explained in the simplest way possible. Besides giving Questions and answers for Science Olympiad Test: Periodic Classification of Elements- 2, EduRev gives you an ample number of Online tests for practice

Top Courses for Class 10

13 videos|44 docs|187 tests
Download as PDF

Top Courses for Class 10