SAT Exam  >  SAT Tests  >  Digital SAT Mock Test Series 2024  >  Test - 10 - SAT MCQ

Test - 10 - SAT MCQ


Test Description

15 Questions MCQ Test Digital SAT Mock Test Series 2024 - Test - 10

Test - 10 for SAT 2024 is part of Digital SAT Mock Test Series 2024 preparation. The Test - 10 questions and answers have been prepared according to the SAT exam syllabus.The Test - 10 MCQs are made for SAT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test - 10 below.
Solutions of Test - 10 questions in English are available as part of our Digital SAT Mock Test Series 2024 for SAT & Test - 10 solutions in Hindi for Digital SAT Mock Test Series 2024 course. Download more important topics, notes, lectures and mock test series for SAT Exam by signing up for free. Attempt Test - 10 | 15 questions in 25 minutes | Mock test for SAT preparation | Free important questions MCQ to study Digital SAT Mock Test Series 2024 for SAT Exam | Download free PDF with solutions
Test - 10 - Question 1

A certain shipping company charges $3.99 per pound for packages of 15 pounds or less, and $3.49 per pound for packages weighing more than 15 pounds. If Lyle sends two 10-pound packages, and Gretchen sends one 20-pound package, what is the difference between their total costs?

Detailed Solution for Test - 10 - Question 1

Lyle's cost is 2 packages × 10 pounds × $3.99 = $79.80. Gretchen's cost is 20 pounds × $3.49 = $69.80, and the difference between them is $79.80 - $69.80 = $10.

Test - 10 - Question 2

What is the result when -8 is subtracted from 10?

Detailed Solution for Test - 10 - Question 2

The tricky part here is the phrase "subtracted from." "Two subtracted from five," for example, means 5 - 2, not 2 - 5. Take care not to write (-8) - 10 for this problem. Instead, do 10 - (-8) = 10 + 8 = 18.

A bunch of phrases signal subtraction — "subtracted from," "less than," and "fewer than" are the most common — and they all require you to switch the order of the quantities being subtracted.

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test - 10 - Question 3

Rick and Jacob play a game in which each one rolls two six-sided dice (each die is numbered from one to six). Rick's score is the sum of his two rolls. Jacob's score is three times the lower number that he rolls; for example, if he rolls a 2 and a 5, his score is 6. On his first roll, Rick rolls a 4 and a 5. Find the probability that Jacob's rolls will result in his having exactly the same score as Rick.

Detailed Solution for Test - 10 - Question 3

Rick's score was 9 (because it's 4 + 5). For Jacob to have the same score, three times his lowest roll must also be 9, so his lowest roll must be 3. So he could roll a 3 and a 3, a 3 and a 4, a 3 and a 5, or a 3 and a 6. Ah, but be careful. To roll a 3 and a 4, for example, he could roll 3 then 4 or 4 then 3. Jacob can really roll 7 possible combinations: (3, 3); (3, 4); (4, 3); (3, 5); (5, 3); (3, 6); or (6, 3). So 7 is the numerator (the top half of the fraction). Now what? You have to find the denominator (the bottom half of the fraction), which counts the total number of possibilities. Using the counting principle, you multiply the number of possibilities for each action. In this case, there are 6 possibilities for each die, so there are 6 × 6 = 36 total possibilities, and your answer is 7/36.

Test - 10 - Question 4

If vw = x, wx = y, and xy = z, which of the following would be equal to yz?

Detailed Solution for Test - 10 - Question 4

The answer choices have only v and w in them, so you need to start this problem by turning everything into those letters. You already know that x = vw, so y = wx = w(vw) = vw2. To continue, you need to remember two things: First, the ws both have an "invisible 1" as their exponents, and second, you need to add exponents when you multiply powers of the same bases. Because z = xy, z = (vw)(vw2) = v2w3. You're looking for yz, which your work tells you equals (vw2)(v2w3) = v3w5.

Test - 10 - Question 5

At 1 p.m., a 5-foot-tall boy casts a shadow that is 1 foot, 3 inches long. How tall is a tree that casts a shadow that is 7 feet long at the same time?

Detailed Solution for Test - 10 - Question 5

This is a classic ratio problem, made more complicated by the presence of both feet and inches. You could convert everything to inches, but because I like fractions (a sad but true statement about my life), I'm going to change 1 foot 3 inches to 11/4 feet. So the ratio says that . Notice that the top numbers stand for the shadows, while the bottom ones stand for the heights of the objects in question. Doing that crazy cross-multiplication thing gives you (11/4)(x) = (5)(7) or 11/4x = 35. Now don't be scared: You have to divide both sides by 11/4, or 5/4. To divide 35 by 5/4, multiply by the reciprocal, or 4/5: 35 × 4/5 = 140/5 = 28.

Test - 10 - Question 6

If a line were drawn connecting f(3) and f(-2), the slope of this line would be
 

Detailed Solution for Test - 10 - Question 6

The first step in answering this problem is drawing the line in question:

After you draw the line, don't jump the gun and start calculating the slope. Doing so is a waste of time because the question doesn't ask for the slope. All you have to do is look at the graph to determine that the slope is positive and then mark Choice (A).

To figure out what kind of slope a line has, imagine an ant walking on the line from left to right. If it's going uphill, the slope is positive. If it's going downhill, the slope is negative. The ant isn't going up or down when the line is horizontal (flat), so a horizontal line has a slope of zero. And, finally, the ant could be going up or down on a vertical line, so a vertical line has no slope.

Test - 10 - Question 7

The number of solutions to f(x) = 0 is

Detailed Solution for Test - 10 - Question 7

When f(x) = 0, the graph has a height of 0; in other words, it crosses the x-axis. As you can see from the graph, it crosses the x-axis in three places. Notice that you don't actually need to know where it crosses the x-axis. You just need to count the number of times it does so.

Test - 10 - Question 8

The three-digit number ABC has the following properties:

The middle digit is the sum of the first and last digits.

None of the digits repeat.

ABC is divisible by 5.

Which of the following could equal B?

Detailed Solution for Test - 10 - Question 8

Start with the last fact given in the question, that the three-digit number ABC is divisible by 5. Every number that's divisible by 5 ends in either 0 or 5, so C must be one of those numbers. The first and second facts make it impossible for C to be zero, because, if C were zero, A and B would be equal to each other, which is illegal. Therefore, C must be 5. Because B = A + C, and A must be at least 1, B must be at least 6.

Test - 10 - Question 9

Find the shaded area in this figure, where O is the center of the circle.

Detailed Solution for Test - 10 - Question 9

LM is a diameter, which means it divides the circle into two 180° arcs. Because N is an inscribed angle (it's on the edge of the circle), its measure is half of the lower 180° arc, or 90°. Yep, it's a right triangle! Because you know the lengths of two sides of the triangle, you can find the third. Remember that 26 is the hypotenuse, so your equation should be x2 + 242 = 262, which gives you x2 + 576 = 676, x2 = 100, and x = 10. Now for the real problem — finding the area of the shaded portion of the circle, which equals the area of the circle minus the area of the triangle. The circle's diameter is 26, so its radius is 13, and the area of a circle = πr2 = π(13)2 = 169π. The triangle's area is 1/2 × base × height, but you need to be careful. Twenty-six isn't the base because you don't have a height to go with it. Instead, you need to use the two legs of the right triangle as the base and height. (It may help to rotate the book if you have trouble visualizing this concept.) So the triangle's area is 1/2(10)(24) = 120, and the answer is 169π - 120.

Test - 10 - Question 10

Which of the following equations would have a graph that passes through the point (-1, 4)?

Detailed Solution for Test - 10 - Question 10

Don't waste your time trying to draw graphs to solve this problem. If the graph of an equation passes through a point, then the coordinates of the point are a solution to the equation. So you need to plug in -1 for x and 4 for y in each of the equations given in the answer choices. Solve the equations. In the equation in Choice (C), the key is that -(-1) = 1, so the equation becomes 1 + 3 = 4, which is a correct equation.

Make sure you don't mix up the numbers. For example, if you carelessly put -1 in for y and 4 in for x in the equation y = x - 5 in Choice (A), you'd end up choosing Choice (A) as the correct answer — and you'd be wrong!

Test - 10 - Question 11

Getting ready for a party, Nandan expected to set up 1/3 of the tables needed. Unfortunately, one of the people helping him did not show up. As a result, he now had to set up 1/2 of the tables. If he had to set up 4 more tables than he expected, what was the total number of tables set up for the party?

Detailed Solution for Test - 10 - Question 11

 You could write an algebra equation for this problem, but reasoning it out works fine, too. The fraction of the tables that Nandan had to set up changed from 1/3 to 1/2. In math, change is always a cue to subtract, and 1/2 - 1/3 = 1/6. (Solve this without a calculator just for the practice.) So Nandan had to set up 1/6 more tables than he expected — 4 tables, according to the problem. If 4 is 1/6 of the total, then the total number of tables is 4 × 6 = 24.

Test - 10 - Question 12

How many hours are in w weeks and d days?

Detailed Solution for Test - 10 - Question 12

You know there are 24 hours in a day, so to find the number of hours in a week, calculate 24 hours × 7 days = 168 hours. Now you have 168w hours. Add 24d for the leftover days. Another approach: In w weeks and d days, there are 7w + d total days. Multiplying by 24 hours in a day gives you 24(7w + d), and distributing gives you 168w + 24d.

Test - 10 - Question 13

A train leaves the station at 10:45 p.m. and arrives at its destination at 2 a.m. the next day (without changing time zones). The train was stopped for 1/2 hour while it had engine trouble; the rest of the time, its average speed was 80 miles per hour. What total distance did the train travel?

Detailed Solution for Test - 10 - Question 13

From 10:45 p.m. to midnight is 1 hour 15 minutes, and from midnight to 2 a.m. is another 2 hours. Thus, the train was moving for 3 hours 15 minutes minus the 30 minutes (1/2 hour) it was stopped, for a total of 2 hours 45 minutes. Two hours × 80 miles per hour is 160 miles. Because 45 minutes is 3/4 of an hour, you need to add another 3/4 × 80 = 60 miles, giving you 220 miles.

Test - 10 - Question 14

Given that o is odd and that e is even, which of the following must be odd?

Detailed Solution for Test - 10 - Question 14

All the answer choices involve multiplication, and the only way to get an odd number as the answer to a multiplication problem is to multiply two odd numbers. Thus, you can throw out Choices (A) and (E) right away because you multiply by e in both of them. Choices (C) and (D) are also no good: If o is odd, o - 1 and o + 1 are both even. These calculations leave you with Choice (B). As always, check to make sure that your answer really does work. An odd plus or minus an even is always odd, so both o - e and o + e are odd, and the product must also be odd.

Test - 10 - Question 15

A coat was on sale for 50% off. Katie bought the coat, using a "$10 off the current price" coupon. If she paid $35 for the coat, what was its original price?

Detailed Solution for Test - 10 - Question 15

The easiest approach to this problem is to start at the end: Katie used her $10 coupon and paid $35, so the price was $45 without the coupon. Because this price was 50% off the original price, it originally cost twice as much, or $90.

8 docs|22 tests
Information about Test - 10 Page
In this test you can find the Exam questions for Test - 10 solved & explained in the simplest way possible. Besides giving Questions and answers for Test - 10, EduRev gives you an ample number of Online tests for practice

Top Courses for SAT

Download as PDF

Top Courses for SAT