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Test: Arithmetic Operation - Electronics and Communication Engineering (ECE) MCQ


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10 Questions MCQ Test Digital Circuits - Test: Arithmetic Operation

Test: Arithmetic Operation for Electronics and Communication Engineering (ECE) 2024 is part of Digital Circuits preparation. The Test: Arithmetic Operation questions and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus.The Test: Arithmetic Operation MCQs are made for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Arithmetic Operation below.
Solutions of Test: Arithmetic Operation questions in English are available as part of our Digital Circuits for Electronics and Communication Engineering (ECE) & Test: Arithmetic Operation solutions in Hindi for Digital Circuits course. Download more important topics, notes, lectures and mock test series for Electronics and Communication Engineering (ECE) Exam by signing up for free. Attempt Test: Arithmetic Operation | 10 questions in 30 minutes | Mock test for Electronics and Communication Engineering (ECE) preparation | Free important questions MCQ to study Digital Circuits for Electronics and Communication Engineering (ECE) Exam | Download free PDF with solutions
Test: Arithmetic Operation - Question 1

What is the addition of the binary numbers 11011011010 and 010100101?

Detailed Solution for Test: Arithmetic Operation - Question 1

The rules for Binary Addition are :
0 + 0 = 0
0 + 1 = 1
1 + 0 = 1
1 + 1 = 0 (Carry 1)

Test: Arithmetic Operation - Question 2

Perform binary subtraction: 101111 – 010101 = ?

Detailed Solution for Test: Arithmetic Operation - Question 2

The rules for Binary Subtraction are :
0 – 0 = 0
0 – 1 = 1 ( Borrow 1)
1 – 0 = 1
1 – 1 = 0

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Test: Arithmetic Operation - Question 3

Perform multiplication of the binary numbers: 01001 × 01011 = ?

Detailed Solution for Test: Arithmetic Operation - Question 3

The rules for binary multiplication are:
0 * 0 = 0
0 * 1 = 0
1 * 0 = 0
1 * 1 = 1

Therefore, 01001 × 01011 = 001100011.

Test: Arithmetic Operation - Question 4

On multiplication of (10.10) and (01.01), we get ____________

Detailed Solution for Test: Arithmetic Operation - Question 4

The rules for binary multiplication are:
0 * 0 = 0
0 * 1 = 0
1 * 0 = 0
1 * 1 = 1

Therefore, 10.10 x 01.01 = 011.0010.

Test: Arithmetic Operation - Question 5

Divide the binary number (011010000) by (0101) and find the quotient.

Detailed Solution for Test: Arithmetic Operation - Question 5


Therefore, the quotient of 011010000 ÷ 1001 = 101001.

Test: Arithmetic Operation - Question 6

Perform binary addition: 101101 + 011011 = ?

Detailed Solution for Test: Arithmetic Operation - Question 6

The rules for Binary Addition are :
0 + 0 = 0
0 + 1 = 1
1 + 0 = 1
1 + 1 = 0 ( Carry 1)

Therefore, the addition of 101101 + 011011 = 1001000.

Test: Arithmetic Operation - Question 7

Binary subtraction of 100101 – 011110 is?

Detailed Solution for Test: Arithmetic Operation - Question 7

The rules for Binary Subtraction are :
0 – 0 = 0
0 – 1 = 1 ( Borrow 1)
1 – 0 = 1
1 – 1 = 0

Therefore, The subtraction of 100101 – 011110 = 000111.

Test: Arithmetic Operation - Question 8

100101 × 0110 = ?

Detailed Solution for Test: Arithmetic Operation - Question 8

The rules for binary multiplication are:
0 * 0 = 0
0 * 1 = 0
1 * 0 = 0
1 * 1 = 1

Therefore, 100101 x 0110 = 011011110.

Test: Arithmetic Operation - Question 9

Divide the binary numbers: 111101 ÷ 1001 and find the remainder.

Detailed Solution for Test: Arithmetic Operation - Question 9

Binary Division is accomplished using long division method.

Therefore, the remainder of 111101 ÷ 1001 = 0111.

Test: Arithmetic Operation - Question 10

Binary subtraction of 101101 – 001011 = ?

Detailed Solution for Test: Arithmetic Operation - Question 10

The rules for binary subtraction are:
0 – 0 = 0
0 – 1 = 1 ( Borrow 1)
1 – 0 = 1
1 – 1 = 0

Therefore, the subtraction of 101101 – 001011 = 100010.

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