NEET Exam  >  NEET Test  >  Physics Class 12  >  Test: Atoms - NEET MCQ

Atoms - NEET Physics Class 12 Free MCQ Test with solutions


MCQ Practice Test & Solutions: Test: Atoms (25 Questions)

You can prepare effectively for NEET Physics Class 12 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Atoms". These 25 questions have been designed by the experts with the latest curriculum of NEET 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 25 minutes
  • - Number of Questions: 25

Sign up on EduRev for free to attempt this test and track your preparation progress.

Test: Atoms - Question 1

According to ‘plum pudding model’ atoms on the whole are electrically neutral because

Detailed Solution: Question 1

The plum pudding model is one of several scientific models of the atom. According to J.J. Thomson atomic models the positive particles in the atom form something like the "batter" in a plum pudding, while the negative electrons are scattered through this "batter".

Test: Atoms - Question 2

Emission line spectra of different elements

Detailed Solution: Question 2

A spectrum is an assembly of energy levels in the form of radiations emitted by an atom in its excited state. Every atom gives discontinuous line spectra. Each line in the spectra corresponds to a specific wavelength and it is unique to a given element so no two elements give the same pattern of lines in their spectra.

Test: Atoms - Question 3

What is the shortest wavelength present in the Paschen series of spectral lines?

Detailed Solution: Question 3

Using formula for Paschen series,
1/λ=R[(1/32)-1/n22],n2=4,5,6….
For shortest wavelength, n2=∞
∴1/λ=R[(1/32)-1/∞2],n2=R/9 or λ=9/R ≈ 820.4 nm

Test: Atoms - Question 4

The average angle of deflection of α-particles by a thin gold foil as predicted by Thomson’s model is

Detailed Solution: Question 4

In Thomson’s plum pudding model, the positive charge is spread out uniformly across the atom, so α-particles passing through would experience only very small, gentle deflections, leading to a small average angle of deflection.

In contrast, Rutherford’s nuclear model postulates a dense, positively charged nucleus. While most α-particles pass through undeflected, a small number undergo large-angle scattering, which increases the overall average deflection angle.

Therefore, the average angle of deflection predicted by Thomson’s model is less than that predicted by Rutherford’s model.

Test: Atoms - Question 5

Which of these statements about Bohr model is correct?

Detailed Solution: Question 5

Bohr model of the hydrogen atom attempts to plug in certain gaps as suggested by Rutherford’s model by including ideas from the newly developing Quantum hypothesis. According to Rutherford’s model, an atom has a central nucleus and electron/s revolve around it like the sun-planet system.
However, the fundamental difference between the two is that, while the planetary system is held in place by the gravitational force, the nucleus-electron system interacts by Coulomb’s Law of Force. This is because the nucleus and electrons are charged particles. Also, an object moving in a circle undergoes constant acceleration due to the centripetal force.
Further, electromagnetic theory teaches us that an accelerating charged particle emits radiation in the form of electromagnetic waves. Therefore, the energy of such an electron should constantly decrease and the electron should collapse into the nucleus. This would make the atom unstable.
The classical electromagnetic theory also states that the frequency of the electromagnetic waves emitted by an accelerating electron is equal to the frequency of revolution. This would mean that, as the electron spirals inwards, it would emit electromagnetic waves of changing frequencies. In other words, it would emit a continuous spectrum. However, actual observation tells us that the electron emits a line spectrum.
 

Test: Atoms - Question 6

Which of these statements about Bohr model hypothesis is correct?

Detailed Solution: Question 6

Bohr never assumed stable electron orbits with the electronic angular momentum quantized as l=mvr=(nh/2π)​ Quantization of angular momentum means that the radius of the orbit and the energy will be quantized as well. Bohr assumed that the discrete lines seen in the spectrum of the hydrogen atom were due to transitions of an electron from one allowed orbit/energy to another.

Test: Atoms - Question 7

Which of these statements about Bohr model applied to hydrogen atom correct?

Detailed Solution: Question 7

A hydrogen atom has magnetic properties because the motion of the electron acts as a current loop. The energy levels of a hydrogen atom associated with orbital angular momentum are split by an external magnetic field because the orbital angular magnetic moment interacts with the field.

Test: Atoms - Question 8

Probability of backward scattering (i.e., scattering of α -particles at angles greater than 90∘) predicted by Thomson’s model is

Detailed Solution: Question 8

In Rutherford's model we have a large massive core called the nucleus whereas, in Thomson's model we do not have. Thus the probability of backward scattering by Thomson's model is much less than that predicted by Rutherford model.

Test: Atoms - Question 9

In Geiger-Marsden experiment very small deflection of the beam was expected because

Detailed Solution: Question 9

In the Geiger-Marsden experiment very small deflection of the beam was expected because positive charge and the negative electrons are distributed through the whole atom reducing electric field inside the atom.

Test: Atoms - Question 10

Suppose you are given a chance to repeat the alpha-particle scattering experiment using a thin sheet of solid hydrogen in place of the gold foil. (Hydrogen is a solid at temperatures below 14 K.) What results do you expect?

Detailed Solution: Question 10

In the alpha-particle scattering experiment, if a thin sheet of solid hydrogen is used in place of a gold foil, then the scattering angle would not be large enough. This is because the mass of hydrogen (1.67×10−27) is less than the mass of incident α−particles (6.64×10−27). Thus, the mass of the scattering particle is more than the target nucleus (hydrogen). As a result, the α−particles would not bounce back if solid hydrogen is used in the α−particle scattering experiment.

Test: Atoms - Question 11

It is found experimentally that for small thickness t, the number of α-particles scattered at moderate angles is proportional to t. What clue does this linear dependence on t provide?

Detailed Solution: Question 11

For small thickness t, the linear dependence of the number of α-particles scattered at moderate angles on t suggests that scattering is primarily due to a single collision.

  • This observation indicates that the probability of scattering increases directly with the thickness of the material.
  • Since the relationship is linear, it implies that each α-particle is likely to interact with the material only once before being deflected.
  • In scenarios where multiple collisions were significant, we would expect a more complex relationship rather than a simple proportionality.
  • This reinforces the idea that the scattering process is straightforward and dominated by individual interactions.

Test: Atoms - Question 12

An electron collides with a hydrogen atom in its ground state and excites it to a state of n = 3. How much energy was given to the hydrogen atom in this inelastic collision?

Detailed Solution: Question 12

Energy at ground state E1​=−13.6 eV
Energy at n=3: E3​=−13.6/9​=1.5 eV
To excite it to n=3 energy given to electron is E3​−E1​=12.1 eV

Test: Atoms - Question 13

Which of these statements correctly describe the atomic model according to classical electromagnetic theory ?

Detailed Solution: Question 13

In classical electromagnetic theory, atoms and molecules are considered to contain electrical charges (i.e. electrons, ions) which are regarded as oscillating about positions of equilibrium, each with its appropriate natural frequency, v0 . When placed in a radiation field of frequency v , each oscillator in the atom or molecule is set into forced vibration with the same frequency as that of the radiation. The amplitude of the forced vibration is small, but as v approaches v0 , the amplitude of the forced vibration increases rapidly. To account for the absorption of energy from the radiation field, it is necessary to assume that the oscillator in the atom or molecule must overcome some frictional force proportional to its velocity during its forced motion. For small amplitudes of forced oscillation, the frictional force, and therefore the absorption of energy, is negligible. Near resonance , the amplitude of oscillation becomes large, with a correspondingly large absorption of energy to overcome the frictional force. Therefore, the radiation of frequencies near the natural frequency of the oscillator corresponds to an absorption band.

Test: Atoms - Question 14

Reason why there are many lines in an atomic spectrum is because

Detailed Solution: Question 14

Lines in the spectrum were due to transitions in which an electron moved from a higher-energy orbit with a larger radius to a lower-energy orbit with smaller radius. The orbit closest to the nucleus represented the ground state of the atom and was most stable; orbits farther away were higher-energy excited states.

Test: Atoms - Question 15

In the ground state of which model electrons are in stable equilibrium with zero net force?

Detailed Solution: Question 15

In Thomson's model, the atom is composed of electrons surrounded by a soup of positive charge to balance the electrons' negative charges, like negatively charged “plums” surrounded by positively charged “pudding”. The 1904 Thomson model was disproved by Hans Geiger and Ernest Marsden's 1909 gold foil experiment.

Test: Atoms - Question 16

A triply ionized beryllium ion Be3+, (a beryllium atom with three electrons removed), behaves very much like a hydrogen atom except that the nuclear charge is four times as great. For the hydrogen atom, the wavelength of the photon emitted in the n =2 to n=1 to transition is 122 nm. What is the wavelength of the photon emitted when a Be3+ ion undergoes this transition?

Detailed Solution: Question 16

1/ λ =Z2. (both have same transition so same value of n)
λ /122=1/16
λ =122/16
=7.62nm

Test: Atoms - Question 17

In Geiger-Marsden experiment, at the point of closest approach

Detailed Solution: Question 17

In the Geiger-Marsden experiment, at the point of closest approach the kinetic energy is zero and the electrical potential equals the initial kinetic energy supplied.

Test: Atoms - Question 18

In which of the models An atom has a nearly continuous mass distribution?

Detailed Solution: Question 18

An atom has a nearly continuous mass distribution in Thomson’s model, but has a highly non-uniform mass distribution in Rutherford’s model.

Test: Atoms - Question 19

Find the longest wavelength present in the Balmer series of hydrogen, corresponding to the H- line.

Detailed Solution: Question 19

For single electron species,
1/λ​=RZ2[(1/n12​​)−(1/n22​​])
where, R = Rydberg constant =  1.097×107×10−9nm−1=1.097×10−2nm−1
For Hydrogen atom, Z = Atomic number = 1
For Balmer series, n1​ = 2 and for longest wavelength in Balmer series, minimum energy transition is to be considered because wavelength is inversely proportional to Energy.
So, n2​ = 3
∴1/λ​=1.097×10−2nm−1×12[(1/22)​−(1/32)]
⇒λ=656nm

Test: Atoms - Question 20

According to Bohr model radiation takes place when

Detailed Solution: Question 20

In 1913 Bohr proposed his quantized shell model of the atom to explain how electrons can have stable orbits around the nucleus. The motion of the electrons in the Rutherford model was unstable because, according to classical mechanics and electromagnetic theory, any charged particle moving on a curved path emits electromagnetic radiation; thus, the electrons would lose energy and spiral into the nucleus. To remedy the stability problem, Bohr modified the Rutherford model by requiring that the electrons move in orbits of fixed size and energy. The energy of an electron depends on the size of the orbit and is lower for smaller orbits. Radiation can occur only when the electron jumps from one orbit to another. The atom will be completely stable in the state with the smallest orbit, since there is no orbit of lower energy into which the electron can jump.
 hν = Ef−Ei

Test: Atoms - Question 21

To produce an emission spectrum of hydrogen

Detailed Solution: Question 21

An emission spectrum is produced when atoms or molecules in a gaseous state are excited (e.g., by heat or electrical energy) and emit light as electrons transition from higher to lower energy levels. For hydrogen:

  • In a glowing gaseous state, hydrogen atoms absorb energy, become excited, and emit specific wavelengths of light corresponding to their unique spectral lines (e.g., Balmer series).

  • This process does not require external white light; the gas itself emits light.

Why Other Options Are Incorrect:

  • B (Cold with white light): This describes an absorption spectrum, where cold gas absorbs specific wavelengths from a continuous light source.

  • C (Cool liquid): Liquids lack the atomic/molecular freedom to produce discrete emission lines.

  • D (Hot with white light): Shining white light through hot gas would complicate observations and does not directly produce an emission spectrum.

The emission spectrum of hydrogen is generated when the gas is excited and glowing, making A the correct choice.

Test: Atoms - Question 22

According to Bohr model allowed values of angular momentum are

Detailed Solution: Question 22

The angular momentum (L) of an electron in a Bohr orbit is given as L= nh /2π ​. It is an integral multiple of h/2π​.

Test: Atoms - Question 23

Which of these statements about Bohr model hypothesis is correct?

Detailed Solution: Question 23

The Bohr model of the atom makes several important hypotheses about electrons in stable orbits.

  • Angular momentum is quantized, meaning electrons can only occupy specific energy levels.
  • Electrons in a stable orbit do not emit electromagnetic waves, which allows them to maintain their energy levels without losing energy.
  • However, the velocity of electrons is not quantized; rather, it changes depending on the energy level.
  • Electrons in stable orbits do not emit quanta of light unless they transition to a different energy level.

Thus, the key aspect of the Bohr model is that electrons in stable orbits do not radiate energy, which is crucial for understanding atomic stability.

Test: Atoms - Question 24

In a Geiger -Marsden experiment, what is the distance of closest approach d to the nucleus of a 7.7 MeV α−particle before it comes momentarily to rest and reverses its direction?

Detailed Solution: Question 24

The distance of closest approach is given as
r0= (1/4πε0)(2Ze2/E)
Here,
Z= 75
e = 1.6x10-19 C
E = 7.7 MeV = 7.7 × 106X 1.6 X 10-9 J = 1.2×10−12J
1/4πε0 = 9x109 Nm2C-1
 so,
r0 = [9x109 x 2x79x(1.6x10-19)2] / [1.2  X 10-12] m
r0=30x10−15 m
r0=30

Test: Atoms - Question 25

Absorption line spectrum is obtained

Detailed Solution: Question 25

If light from a continuous spectrum passes through a cool, transparent gas we observe dark lines appear in the spectrum. The lines occur where atoms of the gas have absorbed specific wavelengths of light. Hence we call this type of spectrum an absorption spectrum.
 

74 videos|347 docs|82 tests
Information about Test: Atoms Page
In this test you can find the Exam questions for Test: Atoms solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Atoms, EduRev gives you an ample number of Online tests for practice
74 videos|347 docs|82 tests
Download as PDF