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Test: Averages (January 23) - CAT MCQ


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10 Questions MCQ Test Daily Test for CAT Preparation - Test: Averages (January 23)

Test: Averages (January 23) for CAT 2024 is part of Daily Test for CAT Preparation preparation. The Test: Averages (January 23) questions and answers have been prepared according to the CAT exam syllabus.The Test: Averages (January 23) MCQs are made for CAT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Averages (January 23) below.
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Test: Averages (January 23) - Question 1
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A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500?

Detailed Solution for Test: Averages (January 23) - Question 1

Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.

 Required sale = Rs. [ (6500 x 6) - 34009 ]

   = Rs. (39000 - 34009)

   = Rs. 4991.

Test: Averages (January 23) - Question 2
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The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, what is the weight of B?

Detailed Solution for Test: Averages (January 23) - Question 2

Let A, B, C represent their respective weights. Then, we have:

A + B + C = (45 x 3) = 135 .... (i)

A + B = (40 x 2) = 80 .... (ii)

B + C = (43 x 2) = 86 ....(iii)

Adding (ii) and (iii), we get: A + 2B + C = 166 .... (iv)

Subtracting (i) from (iv), we get : B = 31.

 B's weight = 31 kg.

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Test: Averages (January 23) - Question 3
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If the average marks of three batches of 55, 60 and 45 students respectively is 50, 55, 60, what is the average marks of all the students?

Detailed Solution for Test: Averages (January 23) - Question 3

Test: Averages (January 23) - Question 4
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The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. What is the present age of the husband?
Detailed Solution for Test: Averages (January 23) - Question 4

Sum of the present ages of husband, wife and child = (27 * 3 + 3 * 3) years = 90 years.
Sum of the present ages of wife and child = (20 * 2 + 5 * 2) years = 50 years.
Husband's present age = (90 - 50) years 
= 40 years

Test: Averages (January 23) - Question 5
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The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What is the weight of the new person?
Detailed Solution for Test: Averages (January 23) - Question 5

The average weight of 8 persons increases by 2.5 kg
Total weight of 8 persons increased = 8 × 2.5 kg = 20 kg.
New person comes in place of one of them weighing 65 kg.
Hence the increase of weight of 8 persons together is because of new person replacing the person having 65 kg weight. Accordingly
Weight of new person = 65 + 20 kg = 85 kg
Thus the person replacing the 65 kg person should have 85 kg weight, which causes increase of weight of the group together by 2.5 kg .

Test: Averages (January 23) - Question 6
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There are two divisions A and B of a class, consisting of 36 and 44 students respectively. If the average weight of divisions A is 40 kg and that of division b is 35 kg. What is the average weight of the whole class?
Test: Averages (January 23) - Question 7
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A batsman makes a score of 87 runs in the 17th inning and thus increases his averages by 3. What is his average after 17th inning?
Detailed Solution for Test: Averages (January 23) - Question 7

Test: Averages (January 23) - Question 8
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A student needed to find the arithmetic mean of the numbers 3, 11, 7, 9, 15, 13, 8, 19, 17, 21, 14 and x. He found the mean to be 12. What is the value of x?
Detailed Solution for Test: Averages (January 23) - Question 8

As, Mean = Total Sum of Observations / No. of Observations

Clearly, we have (3 + 11 + 7 + 9 + 15 + 13 + 8 + 19 + 17 + 21 + 14 + x) / 12 = 12.

or  137 + x = 144

⇒ x = 144 - 137 = 7.

Test: Averages (January 23) - Question 9
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Arun obtained 76, 65, 82, 67 and 85 marks (out in 100) in English, Mathematics, Chemistry, Biology and Physics. What is his average mark?
Detailed Solution for Test: Averages (January 23) - Question 9

Average = (76 + 65 + 82 + 67 + 85 )/ 5 = 375/5 =  75.
 

Test: Averages (January 23) - Question 10
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Distance between two stations A and B is 778 km. A train covers the journey from A to B at 84 km per hour and returns back to A with a uniform speed of 56km per hour. Find the average speed of the train during the whole journey?
Detailed Solution for Test: Averages (January 23) - Question 10

Avg speed of train = 2xy/x+y
⇒ [2(84)(56)]/(84+56)
⇒ [2(84)(56)]/140
= 67.2km/hr

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