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Test: CSIR-NET Chemical Sciences Mock Test - 2 - CSIR NET Chemical Science MCQ


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30 Questions MCQ Test CSIR-UGC (NET) Chemical Science Mock Test Series 2024 - Test: CSIR-NET Chemical Sciences Mock Test - 2

Test: CSIR-NET Chemical Sciences Mock Test - 2 for CSIR NET Chemical Science 2024 is part of CSIR-UGC (NET) Chemical Science Mock Test Series 2024 preparation. The Test: CSIR-NET Chemical Sciences Mock Test - 2 questions and answers have been prepared according to the CSIR NET Chemical Science exam syllabus.The Test: CSIR-NET Chemical Sciences Mock Test - 2 MCQs are made for CSIR NET Chemical Science 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: CSIR-NET Chemical Sciences Mock Test - 2 below.
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Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 1

How many similiar words can be made by the words 'AERT' while every word should be used only one time.

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 1

TEAR, RATE, TARE
3 words can be made.

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 2

How many letters are there in english alphabet in between 8 letter from left and 7 letters from right ?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 2

8th  letter from left is H and 7th  letters from right is T.
Between H and T there are 11 letters between them.

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Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 3

In a certain code language NOIDA is written as STNIF. How will MEERUT will be written in that code language ?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 3

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 4

Find out the word from the following which can be formed by using the following letters.
VENTURESOME

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 4

VENTURESOME
SERMON - use all letters from Venturesome.

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 5

Which substances turn red litmus paper into blue?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 5

Bases are those substances that turn red litmus paper into the blue.
It is bitter in taste and gives hydroxyl ions (OH) in an aqueous solution. For example, ammonia gas turns red litmus paper blue because it is a base and has a pH of 11.6.

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 6

In the given figure AB =9m, AC = 11cm and the perpendicular AD = 4 cm. Find out the radius of the circumcircle.

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 6

Area of triangle

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 7

What is the next number in the following sequence?
39, 42, 46, 50, ...

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 7

The given sequence will follow the pattern 3, 4 4, 3 ..........
These are the difference between two consecutive numbers of the sequence.
So.

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 8

Shoba is good at swordsmanship. Poonam is good at horse riding and shooting but not good at swordsmanship. Madhu is good at shooting. Anjali is good at shooting and swordsmanship. Who is good at horse riding and shooting not swordsmanship?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 8

From the given information, we can draw the Venn diagram as follows:

From the above Venn diagram it is clear that Poonam is good at horse riding and shooting not swordsmanship.

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 9

The difference (in Rs.) between a discount of 35% on Rs. 3,600 and two successive discounts of 30% and 5% on the same amount is: 

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 9

Given:
Marked price (M.P) = Rs.3600
Concept used:
Discount% = M.P × D%
Effective discount (D) = (D1) + (D2) - (D1 × D2)/100
Calculation:
Discount (D1) = 3600 × 35%
⇒ 36 × 35 = Rs.1260
Effective discount = 30 + 5 - (30 × 5)/100
⇒ 35 - 1.5 = 33.5%
Discount (D2) = 3600 × 33.5% = Rs.1206
Difference between two discount = (1260 - 1206) = Rs.54
∴ The correct answer is Rs.54.

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 10

Find the value of ∠P + ∠Q + ∠R + ∠S + ∠T + ∠U in the figure shown below:

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 10

Concept used:
The sum of interior angles of any triangle = 180° 
Calculation:
In the figure, PRT and UQS forms a triangle.
⇒ ∠P + ∠R + ∠T = 180°
⇒ ∠U + ∠Q + ∠S = 180° 
On adding the above two, we get
⇒ ∠P + ∠Q + ∠R + ∠S + ∠T + ∠U = 180° + 180° = 360° 
∴ ∠P + ∠Q + ∠R + ∠S + ∠T + ∠U = 360°

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 11

A thief steals a scooter at 11.00 AM, and drives it at a speed of 50 km/h. At 2 : 30 PM, the theft is detected and the owner of the scooter goes in a car traveling at 80 km/h in the same direction to catch the thief. At what time will the owner overtake (catch) the thief?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 11

Given:
Speed of the scooter of thief = 50 km/h
Speed of the scooter of owner = 80 km/h
Formula Use:
Speed = Distance/Time
Calculation:
We know,
Speed of the scooter of thief = 50 km/h
Since the thief is discovered at 2:30 P.M
The distance travel by thief in 3 : 30 hour = 7/2 × 50 = 175 km
Speed of the scooter of owner = 80 km/h
So, the relative speed of the owner = (80 - 50) km/h
⇒ 30 km/h
175 km, is the distance that has to be covered by the owner to catch the thief.
We have,
Speed = Distance / Time
⇒ 30 = 175 / Time
⇒ Time = 175/30 = 35/6 = 5 hr 50 min
Therefore, the time required to catch the thief will be 5 hr 50 min.
The owner will catch the thief at = 2:30 P.M + 5 hr 50 min = 8 : 20 P.M
So, The owner will catch the thief at  8 : 20 P.M
Hence, the correct answer is  8 : 20 P.M

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 12

The current ages of Sudhir and Ashish are in the ratio 5 ∶ 7. Twelve years ago, the ratio of their ages was 1 ∶ 2. What will be the age of Sudhir after five years from now? 

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 12

Given: 
12 years ago, Sudhir and Ashish = 1 : 2
Current age of Sudhir and Ashish = 5: 7
Concept used:
We will be using the concept of ratio.
Calculation:
Let the ages of Sudhir and Ashish 12 years ago = 1x and 2x respectively,
According to the question,
(1x + 12) / (2x + 12) = 5/7
⇒ 7x + 84 = 10x + 60
⇒ 3x = 24
⇒ x = 8
∴ Present age of Sudhir  = 8 + 12 = 20 year
The age of Sudhir after five years from now = 20 + 5 = 25
The age of Sudhir after five years from now is 25 years.

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 13

A dishonest shopkeeper promise to sell his goods at its C.P but he uses 20% less weight. Find profit %?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 13

Let total weight of goods = 1000 gm 
Let the CP of 1000 gm is Rs. 1000 
∴ CP of 1 gm is Rs. 1 
Shopkeeper uses 20% less weight
Weight uses by shopkeeper = 1000 - 1000 × 20% = 800 gm
CP for shopkeeper = 800 × 1 = 800
SP for shopkeeper = 1000 
Profit = 1000 - 800 = 200 
Profit percentage = (200/1000) × 100 = 25%

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 14

The frustum of a right circular cone has base diameter 10 cm, and on the top the diameter is 6 cm, and its height is 5 cm. Calculate its volume. (Correct to two decimal place) (usе π = 22/7)

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 14

Given:
The frustum of a right circular cone has base diameter 10 cm, and on the top the diameter is 6 cm, and its height is 5 cm. (usе π = 22/7)
Formula used:
The volume of a frustum of a cone:

V = 1/3 π(R2 + r2 + Rr)h
Where:
h is the height of the frustum.
R is the radius of the larger base (the top base) of the frustum.
r is the radius of the smaller base (the bottom base) of the frustum.
Calculation:
According to the question,
R = 10/2 = 5 cm
r = 6/2 = 3 cm
h = 5
Now, on substituting the value of the respective variable in the required formula, we get,

Therefore, "256.67 cm2" is the required answer.

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 15

A student is asked to multiply a number K by 5. But he multiplies K by 1/5 and gets x% error. Next time he multiplies K by 1/25 and gets y% error. Then the percentage increase of y over x is

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 15

The original value was 5K. When the student multiplies by 1/5, the result is 0.2K, which is 96% less than the original value. So, x = 96%.
When the student multiplies by 1/25, the result is 0.04K, which is 99.2% less than the original value. So, y = 99.2%.
The percentage increase of y over x is (y - x)/x × 100 = (99.2 - 96)/96 * 100 = 3.33%.
Therefore, the answer is 3.33%. or 3(1/3)%.

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 16

Which of the region of IR spectra appears between (1400-600) cm-1 ?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 16

Fingerprint region of IR spectra appears between (1400-600) cm-1.

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 17

Which of the following statement is incorrect about the SBR?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 17

SBR has high load bearing capacity, high abrasion resistance, swells in oil and solvent and has low oxidation resistance.

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 18

Extent of a reaction denotes

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 18

It denotes that how much a reaction occurs.

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 19

How many number of moles of KMnO4 will react with 180 gm H2C2O4 according to given reaction?
KMnO4 + H2C2O4 → 2CO2 + Mn2+

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 19


Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 20

A cylinder contains 8 gms of He, 40 gms of Ne and 80 gms of Ar. (Molecular weights of the components are 4, 20 and 40 respectively)
How many moles of Ne are there in the cylinder?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 20

Number of moles = mass / molecular weight.

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 21

The B.E.T. theory was proposed in the year

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 21

Brunauer, Emmett and Teller proposed a theory in 1938 which is known as B.E.T. theory.

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 22

According to Faraday’s first law of electrolysis, the amount of any substance deposited at the electrode is directly proportional to the quantity of

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 22

According to Faraday’s law of electrolysis, the amount of any substance deposited at the electrode is directly proportional to the quantity of electricity passed. It is given by:
m = ( Q / F ) * ( M / Z )
where, m = Mass of the substance liberated at an electrode in grams
Q = Total electric charge passed through the substance in Coulombs
F = Faraday constant
M = Molar mass of the substance in grams per mol
Z = Valency number of ions of the substance
For Faraday’s first law, M, F, and z are constants, so that the larger the value of Q the larger m will be.

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 23

Select the incorrect statement from the following option.

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 23

Meso compounds are internally compensated form whereas racemic mixtures are externally compensated modification. All the other options are correct.

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 24

Which of the following act as a catalyst in the preparation of Buna-S?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 24

Cumene hydroperoxide act as a catalyst in the preparation of Buna-S (Butadiene styrene).

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 25

Select the incorrect statement regarding analytical balance

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 25

It is a very sensitive instrument as it could accurately measure the weight of a particular compound of upto 0.1 mg.

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 26

Reactions which are bimolecular yet following ___________ order kinetics are called pseudo unimolecular reaction.

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 26

Reactions which are bimolecular yet following first order kinetics are called pseudo unimolecular reaction. Pseudo means pretentious. Inversion of cane sugar is an example of pseudo first order reaction.

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 27

The unit of extent of a reaction is

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 27

The unit of extent of a reaction is Moles reacting.

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 28

The main cause of molecular aggregation is

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 28

The main cause of molecular aggregation is inter-molecular interactions. Inter-molecular interactions stem from the electric properties of atoms. Being the cause of molecular aggregation, inter-molecular forces are at the roots of chemistry and are the fabric of the world.

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 29

Excess of KI reacts with CuSO4 solution and then Na2S2O3 solution is added to it. Which of the statement is incorrect for this reaction?

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 29

(1) KI + CuSO4 → I2
(2) I2 + Na2S2O3 → NaI + Na2S2O6
(a) Na2S2O3 is oxidized to Na2S2O6
(b) Cu2I2 is formed as CuI2 disproportionate.

Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 30

Chromatography involves two mutually

Detailed Solution for Test: CSIR-NET Chemical Sciences Mock Test - 2 - Question 30

Chromatography involves two mutually immiscible phases (stationary and mobile phases). The mixture is dissolved in a fluid called the mobile phase, which carries it through a structure holding another material called the stationary phase.

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